The Hamming distance between 100 and 001 is ________. A) 2 B) 0 C) 1 D) none of the above

The Hamming distance between 100 and 001 is ________.
A)
2
B)
0
C)
1
D)
none of the above
by

1 Answer

Answer :

2
by

Related questions

In block coding, ifn = 5, the maximum Hamming distance between two codewords is ________. A) 2 B) 3 C) 5 D) none of the above

Description : In block coding, ifn = 5, the maximum Hamming distance between two codewords is ________. A) 2 B) 3 C) 5 D) none of the above

Last Answer : 5

The ________ between two words is the number ofdifferences between corresponding bits. A) Hamming code B) Hamming distance C) Hamming rule D) none of the above

Description : The ________ between two words is the number ofdifferences between corresponding bits. A) Hamming code B) Hamming distance C) Hamming rule D) none of the above

Last Answer : Hamming distance

To guarantee correction of upto t errors, the minimum Hamming distance d min in a block code must be ________. a. t+1 b. t−2 c. 2t−1 d. 2t+1

Description : To guarantee correction of upto t errors, the minimum Hamming distance d min in a block code must be ________. a. t+1 b. t−2 c. 2t−1 d. 2t+1

Last Answer : d. 2t+1

The ________ between two words is the number of differences between corresponding bits A. Hamming code B. Hamming distance C. Hamming rule D. none of the above

Description : The ________ between two words is the number of differences between corresponding bits A. Hamming code B. Hamming distance C. Hamming rule D. none of the above

Last Answer : B. Hamming distance

The Hamming distance between equal codewords is _________. A) 1 B) n C) 0 D) none of the above

Description : The Hamming distance between equal codewords is _________. A) 1 B) n C) 0 D) none of the above

Last Answer : 0

To guarantee correction ofup to 5 errors in all cases, the minimum Hamming distance in a block code must be________. A) 5 B) 6 C) 11 D) none of the above

Description : To guarantee correction ofup to 5 errors in all cases, the minimum Hamming distance in a block code must be________. A) 5 B) 6 C) 11 D) none of the above

Last Answer : 11

To guarantee the detectionof up to 5errors in all cases, the minimum Hamming distance in a block code mustbe _______. A) 5 B) 6 C) 11 D) none of the above

Description : To guarantee the detectionof up to 5errors in all cases, the minimum Hamming distance in a block code mustbe _______. A) 5 B) 6 C) 11 D) none of the above

Last Answer : 6

To guarantee the detection of up to 5 errors in all cases, the minimum Hamming distance in a block code must be _______ A. 5 B. 6 C. 11 D. none of the above

Description : To guarantee the detection of up to 5 errors in all cases, the minimum Hamming distance in a block code must be _______ A. 5 B. 6 C. 11 D. none of the above

Last Answer : B. 6

A periodic signal completes onecycle in 0.001 s. What is thefrequency? A) 1 Hz B) 100 Hz C) 1 KHz D) 1 MHz

Description : A periodic signal completes onecycle in 0.001 s. What is thefrequency? A) 1 Hz B) 100 Hz C) 1 KHz D) 1 MHz

Last Answer : 1 KHz

Error detection ata data link level is achieved by A. bit stuffing B. cyclic redundancy codes C. Hamming codes D. equalization

Description : Error detection ata data link level is achieved by A. bit stuffing B. cyclic redundancy codes C. Hamming codes D. equalization

Last Answer : cyclic redundancy codes

_______ can detect burst error of length less than or equal to degree of the polynomial and detects burst errors that affect odd number of bits. a. Hamming Code b. CRC c. VRC d. None of the above

Description : _______ can detect burst error of length less than or equal to degree of the polynomial and detects burst errors that affect odd number of bits. a. Hamming Code b. CRC c. VRC d. None of the above

Last Answer : b. CRC

Coding schemes can be divided into two broad categories…………, ……A. character coding, integer coding B. hamming coding and block coding C. Hamming coding and convolution coding D. Block Coding and Convolution Coding.

Description : Coding schemes can be divided into two broad categories…………, …… A. character coding, integer coding B. hamming coding and block coding C. Hamming coding and convolution coding D. Block Coding and Convolution Coding.

Last Answer : D. Block Coding and Convolution Coding.

Thus hamming code for the ASCII character “a” is given as ……………… A. 10111001111 B. 10111001000 C. 10111001001 D. 10111001

Description : Thus hamming code for the ASCII character “a” is given as ……………… A. 10111001111 B. 10111001000 C. 10111001001 D. 10111001

Last Answer : C. 10111001001

The bit positionina can be numbered from 1 through 2h, a. Hamming code word b. Hamming distance word c. Both d. None of these

Description : The bit positionina can be numbered from 1 through 2h, a. Hamming code word b. Hamming distance word c. Both d. None of these

Last Answer : a. Hamming code word

Hamming distance between 100101000110 and 110111101101 is (A) 3 (B) 4 (C) 5 (D) 6

Description : Hamming distance between 100101000110 and 110111101101 is (A) 3 (B) 4 (C) 5 (D) 6

Last Answer : (D) 6

Consider a code with five valid code words of length ten : 0000000000, 0000011111, 1111100000, 1110000011, 1111111111 Hamming distance of the code is (A) 5 (B) 10 (C) 8 (D) 9

Description : Consider a code with five valid code words of length ten : 0000000000, 0000011111, 1111100000, 1110000011, 1111111111 Hamming distance of the code is (A) 5 (B) 10 (C) 8 (D) 9

Last Answer : Answer: Marks to all

The Hamming distance between two code-words is

Description : The Hamming distance between two code-words is (A) the number of places the code-words are same (B) same as the Euclidean distance between their decimal representation (C) is maximum of the either code-words (B) the number of places the code-words differ

Last Answer : The Hamming distance between two code-words is the number of places the code-words differ

The BCD equivalent of decimal 912 is ________. 60) A) 1001 0001 0010BCD B) 1001 1000 0001BCD C) 0111 1111 1110BCD D) 0010 001 1001BCD

Description : The BCD equivalent of decimal 912 is ________. 60) A) 1001 0001 0010BCD B) 1001 1000 0001BCD C) 0111 1111 1110BCD D) 0010 001 1001BCD

Last Answer : A) 1001 0001 0010BCD

An alkaline solution is used to reduce the concentration of carbon dioxide in a stream from 10% to 0.1% by absorption with irreversible chemical reaction. The overall number of transfer units based on gas phase is: (A) 9.21 (B) 4.605 (C) 100 (D) 0.001

Description : An alkaline solution is used to reduce the concentration of carbon dioxide in a stream from 10% to 0.1% by absorption with irreversible chemical reaction. The overall number of transfer units based on gas phase is: (A) 9.21 (B) 4.605 (C) 100 (D) 0.001

Last Answer : (B) 4.605

If the baudrate is400 for a QPSK signal, thebit rate is ________ bps. A) 100 B) 400 C) 800 D) 1600

Description : If the baudrate is400 for a QPSK signal, thebit rate is ________ bps. A) 100 B) 400 C) 800 D) 1600

Last Answer : 800

A 3-input neuron is trained to output a zero when the input is 110 and a one when the input is 111. After generalization, the output will be zero when and only when the input is: a) 000 or 110 or 011 or 101 b) 010 or 100 or 110 or 101 c) 000 or 010 or 110 or 100 d) 100 or 111 or 101 or 001

Description : A 3-input neuron is trained to output a zero when the input is 110 and a one when the input is 111. After generalization, the output will be zero when and only when the input is: a) 000 or 110 or 011 or 101 b) 010 or 100 or 110 or 101 c) 000 or 010 or 110 or 100 d) 100 or 111 or 101 or 001

Last Answer : c) 000 or 010 or 110 or 100

Is the cyclic redundancy check better than hamming code?

Description : Is the cyclic redundancy check better than hamming code?

Last Answer : It depends on what you are doing.The cyclic redundancy check will only detect an error, while thehamming code can also correct many types of errors. However toperform this correction the extra ... channels, disk sectors).Normally hamming code is done on individual bytes or words ofcomputer memory.

Hamming codes was developed in _ a 1953 b. 1950 c. 1945 d. 1956

Description : Hamming codes was developed in _ a 1953 b. 1950 c. 1945 d. 1956

Last Answer : b. 1950

Water hamming effect is occurs in a) Surge tank b) Penstock c) Turbine d) Reservoir

Description : Water hamming effect is occurs in a) Surge tank b) Penstock c) Turbine d) Reservoir

Last Answer : Ans: Penstock

In a binary Hamming code the number of check digits is r then number of message digits is equal to: (A) 2r-1 (B) 2r-r-1 (C) 2r-r+1 (D) 2r+r-1

Description : In a binary Hamming code the number of check digits is r then number of message digits is equal to: (A) 2r-1 (B) 2r-r-1 (C) 2r-r+1 (D) 2r+r-1

Last Answer : (B) 2r-r-1

Why do some people have an apoplectic fit if a deli counter item is 0.001 lbs over?

Description : Why do some people have an apoplectic fit if a deli counter item is 0.001 lbs over?

Last Answer : answer:Because some folks have lost what they believed was ‘control’ in their life and compensate for it with shit like that. It’s simple deli tantrums at first but before you know it, if left unchecked, the same people start bombing abortion clinics and want to burn books . . .

If the above tape weights 0.001 kg/ft, sag is a.2.73 ft b.3.13 ft c.2.90 ft d.3.03 ft e.107 dynes

Description : If the above tape weights 0.001 kg/ft, sag is a.2.73 ft b.3.13 ft c.2.90 ft d.3.03 ft e.107 dynes

Last Answer : c. 2.90 ft

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular

Description : A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular

Last Answer : A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale ... (C) 0.053 cm (D) 0.529 cm

What is 9 x 1002 x 103 x 0.1 7 x 0.001 in a decimal?

Description : What is 9 x 1002 x 103 x 0.1 7 x 0.001 in a decimal?

Last Answer : 9 * 1002 * 103 * 0.1 7 * 0.001 = 157.90518

In a number sequence what is 0.001 0.01 0.1 1?

Description : In a number sequence what is 0.001 0.01 0.1 1?

Last Answer : Each successive number is ten times the one before it.

What is 2.5 divided by 0.001?

Description : What is 2.5 divided by 0.001?

Last Answer : 2500

What is the Next number in the sequence 0.001 0.01 0.1 1?

Description : What is the Next number in the sequence 0.001 0.01 0.1 1?

Last Answer : 10

What is 0.000 000 001 in words?

Description : What is 0.000 000 001 in words?

Last Answer : What is the answer ?

What is 0.001 micron?

Description : What is 0.001 micron?

Last Answer : What is the answer ?

Which mass measurement is expressed in exactly four significant figures 0.001 g 0.095 g 1005 g 1000 g?

Description : Which mass measurement is expressed in exactly four significant figures 0.001 g 0.095 g 1005 g 1000 g?

Last Answer : 1005 g

What is 0.9 divided by 0.001 explain?

Description : What is 0.9 divided by 0.001 explain?

Last Answer : 900

The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Description : The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

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In a cycle the spark lasts roughly for A. 1 sec B. 0.1 sec C. 0.0001 sec D.001 sec

Description : In a cycle the spark lasts roughly for A. 1 sec B. 0.1 sec C. 0.0001 sec D.001 sec

Last Answer : ANSWER : C

Threshold limit value of copper in the atmospheric air is - (1) 0.001 mg/m3 (2) 0.01 mg/m3 (3) 1.0 mg/m3 (4) 5.0 mg/m3

Description : Threshold limit value of copper in the atmospheric air is - (1) 0.001 mg/m3 (2) 0.01 mg/m3 (3) 1.0 mg/m3 (4) 5.0 mg/m3

Last Answer : (3) 1.0 mg/m3 Explanation: Inspirable copper dust takes a predominantly fibrous effect. The ALV of copper aerosol in the workplace atmosphere is 0.5 mg/m3, while the threshold limit value (TLV) is 1.0 mg/m3.

A micron is equal to – (1) 0.1 ram (2) 0.01 mm (3) 0.001 mm (4) 0.0001 mm

Description : A micron is equal to – (1) 0.1 ram (2) 0.01 mm (3) 0.001 mm (4) 0.0001 mm

Last Answer : (3) 0.001 mm Explanation: 1 micron = 0.001 millimeters. A micrometre (micron) is one-millionth of a metre (or one-thousandth of a millimetre, 0.001 mm). Its unit symbol in the ... is a common unit of measurement for wavelengths of infrared radiation as well as sizes of cells and bacteria.

Period of oscillation of 3 cm microwaves in seconds is (1) 1 x 10¹⁰ (2) 1 x 10⁻¹⁰ (3) 0.01 (4) 0.001

Description : Period of oscillation of 3 cm microwaves in seconds is (1) 1 x 10¹⁰ (2) 1 x 10⁻¹⁰ (3) 0.01 (4) 0.001

Last Answer : (2) 1 x 10⁻¹⁰ Explanation: The period of oscillation of 3 cm microwaves is 1 x 10^-10 (Physics, Volume 1, by Halliday). The period of oscillation is the smallest interval of time in which a system undergoing oscillation returns to the state it was in at the beginning of the oscillation.

If the discharge of a sewer running half is 628 1.p.s., i = 0.001, and n = 0.010, the diameter of the sewer, is A. 1.39 m B. 1.49 m C. 1.59 m D. 1.69 m

Description : If the discharge of a sewer running half is 628 1.p.s., i = 0.001, and n = 0.010, the diameter of the sewer, is A. 1.39 m B. 1.49 m C. 1.59 m D. 1.69 m

Last Answer : ANS: D

A conductor with a cross-sectional area of one circular mil would have a diameter of _____________. A. 0.1 inches B. 0.01 inches C. 0.001 inches D. 0.0001 inches

Description : A conductor with a cross-sectional area of one circular mil would have a diameter of _____________. A. 0.1 inches B. 0.01 inches C. 0.001 inches D. 0.0001 inches

Last Answer : Answer: C

What is the typical separation between the two conductors in a parallel wire line? A. 0.001 to 0.01 m B. 200 to 500 mm C. 0.635 to 15.24 cm D. 2.5 to 5 in.

Description : What is the typical separation between the two conductors in a parallel wire line? A. 0.001 to 0.01 m B. 200 to 500 mm C. 0.635 to 15.24 cm D. 2.5 to 5 in.

Last Answer : C. 0.635 to 15.24 cm

Very low pressure is expressed in microns (μ), which is equal to__________ mm of Hg column (absolute) at 0°C.(A) 0.0001(B) 0.001(C) 0.01(D) 0.1

Description : Very low pressure is expressed in microns (μ), which is equal to__________ mm of Hg column (absolute) at 0°C. (A) 0.0001 (B) 0.001 (C) 0.01 (D) 0.1

Last Answer : (B) 0.001

Carbon content in steel is __________ percent. (A) 0.1-2 (B) 4-6 (C) 2-4 (D) 0.001-0.01

Description : Carbon content in steel is __________ percent. (A) 0.1-2 (B) 4-6 (C) 2-4 (D) 0.001-0.01

Last Answer : (A) 0.1-2

H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S has to be reduced from 0.05 to 0.001 mole fraction in the gas side. The height of the tower (in metres) corresponding to an operating line given by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Description : H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S ... by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Last Answer : (A) 2.0

Colburn analogy is applicable for the value of Prandtl number from (A) 0.001 to 1 (B) 0.6 to 120 (C) 0.5 to 5 (D) 120 to 400

Description : Colburn analogy is applicable for the value of Prandtl number from (A) 0.001 to 1 (B) 0.6 to 120 (C) 0.5 to 5 (D) 120 to 400

Last Answer : (B) 0.6 to 120

Prandtl number for most of dry gases is about (A) 0.001(B) 0.72 (C) 70 (D) 150

Description : Prandtl number for most of dry gases is about (A) 0.001 (B) 0.72 (C) 70 (D) 150

Last Answer : (B) 0.72

A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065

Description : A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065

Last Answer : a) 0.001