What is the Next number in the sequence 0.001 0.01 0.1 1?

What is the Next number in the sequence 0.001 0.01 0.1 1?
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10
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In a number sequence what is 0.001 0.01 0.1 1?

Description : In a number sequence what is 0.001 0.01 0.1 1?

Last Answer : Each successive number is ten times the one before it.

The difference in one unit of Rockwell hardness number corresponds to a difference in the depth of indentation of __________ mm. (A) 0.001 (B) 0.01 (C) 0.002 (D) 0.02

Description : The difference in one unit of Rockwell hardness number corresponds to a difference in the depth of indentation of __________ mm. (A) 0.001 (B) 0.01 (C) 0.002 (D) 0.02

Last Answer : Option C

A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

Description : A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is A. 8.0 bit B. 2.0 bit C. 1.9 bit D. 2.1 bit

Last Answer : C. 1.9 bit

A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is a. 8.0 bit b. 2.0 bit c. 1.9 bit d. 2.1 bit

Description : A Huffman code: A = 1, B = 000, C = 001, D = 01 ,P(A) = 0.4, P(B) = 0.1, P(C) = 0.2, P(D) = 0.3 The average number of bits per letter is a. 8.0 bit b. 2.0 bit c. 1.9 bit d. 2.1 bit

Last Answer : c. 1.9 bit

Threshold limit value of copper in the atmospheric air is - (1) 0.001 mg/m3 (2) 0.01 mg/m3 (3) 1.0 mg/m3 (4) 5.0 mg/m3

Description : Threshold limit value of copper in the atmospheric air is - (1) 0.001 mg/m3 (2) 0.01 mg/m3 (3) 1.0 mg/m3 (4) 5.0 mg/m3

Last Answer : (3) 1.0 mg/m3 Explanation: Inspirable copper dust takes a predominantly fibrous effect. The ALV of copper aerosol in the workplace atmosphere is 0.5 mg/m3, while the threshold limit value (TLV) is 1.0 mg/m3.

A micron is equal to – (1) 0.1 ram (2) 0.01 mm (3) 0.001 mm (4) 0.0001 mm

Description : A micron is equal to – (1) 0.1 ram (2) 0.01 mm (3) 0.001 mm (4) 0.0001 mm

Last Answer : (3) 0.001 mm Explanation: 1 micron = 0.001 millimeters. A micrometre (micron) is one-millionth of a metre (or one-thousandth of a millimetre, 0.001 mm). Its unit symbol in the ... is a common unit of measurement for wavelengths of infrared radiation as well as sizes of cells and bacteria.

Period of oscillation of 3 cm microwaves in seconds is (1) 1 x 10¹⁰ (2) 1 x 10⁻¹⁰ (3) 0.01 (4) 0.001

Description : Period of oscillation of 3 cm microwaves in seconds is (1) 1 x 10¹⁰ (2) 1 x 10⁻¹⁰ (3) 0.01 (4) 0.001

Last Answer : (2) 1 x 10⁻¹⁰ Explanation: The period of oscillation of 3 cm microwaves is 1 x 10^-10 (Physics, Volume 1, by Halliday). The period of oscillation is the smallest interval of time in which a system undergoing oscillation returns to the state it was in at the beginning of the oscillation.

A conductor with a cross-sectional area of one circular mil would have a diameter of _____________. A. 0.1 inches B. 0.01 inches C. 0.001 inches D. 0.0001 inches

Description : A conductor with a cross-sectional area of one circular mil would have a diameter of _____________. A. 0.1 inches B. 0.01 inches C. 0.001 inches D. 0.0001 inches

Last Answer : Answer: C

What is the typical separation between the two conductors in a parallel wire line? A. 0.001 to 0.01 m B. 200 to 500 mm C. 0.635 to 15.24 cm D. 2.5 to 5 in.

Description : What is the typical separation between the two conductors in a parallel wire line? A. 0.001 to 0.01 m B. 200 to 500 mm C. 0.635 to 15.24 cm D. 2.5 to 5 in.

Last Answer : C. 0.635 to 15.24 cm

Very low pressure is expressed in microns (μ), which is equal to__________ mm of Hg column (absolute) at 0°C.(A) 0.0001(B) 0.001(C) 0.01(D) 0.1

Description : Very low pressure is expressed in microns (μ), which is equal to__________ mm of Hg column (absolute) at 0°C. (A) 0.0001 (B) 0.001 (C) 0.01 (D) 0.1

Last Answer : (B) 0.001

Carbon content in steel is __________ percent. (A) 0.1-2 (B) 4-6 (C) 2-4 (D) 0.001-0.01

Description : Carbon content in steel is __________ percent. (A) 0.1-2 (B) 4-6 (C) 2-4 (D) 0.001-0.01

Last Answer : (A) 0.1-2

Angstrom (Å) is equal to (a) 0.01 mm (b) 0.001 mm (c) 0.0001 mm (d) 0.00001 mm

Description : Angstrom (Å) is equal to (a) 0.01 mm (b) 0.001 mm (c) 0.0001 mm (d) 0.00001 mm

Last Answer : (b) 0.001 mm

Rotary vacuum pumps can reduce the absolute pressure to as low as __________ mm Hg. (A) 1 (B) 0.1 (C) 0.01 (D) 0.001

Description : Rotary vacuum pumps can reduce the absolute pressure to as low as __________ mm Hg. (A) 1 (B) 0.1 (C) 0.01 (D) 0.001

Last Answer : (C) 0.01

Maximum permissible residual chlorine in treated water should be __________ mg/litre. (A) 0.001 to 0.01 (B) 0.2 to 0.3 (C) 2 to 3 (D) 5 to 10

Description : Maximum permissible residual chlorine in treated water should be __________ mg/litre. (A) 0.001 to 0.01 (B) 0.2 to 0.3 (C) 2 to 3 (D) 5 to 10

Last Answer : (B) 0.2 to 0.3

The void ratio of a soil sample decreases from 1.50 to 1.25 when the pressure is increased from 25 tonnes/m2 to 50 tonnes/m2 , the coefficient of compressibility is (A) 0.01 (B) 0.02 (C) 0.05 (D) 0.001

Description : The void ratio of a soil sample decreases from 1.50 to 1.25 when the pressure is increased from 25 tonnes/m2 to 50 tonnes/m2 , the coefficient of compressibility is (A) 0.01 (B) 0.02 (C) 0.05 (D) 0.001

Last Answer : (A) 0.01

When a constant discharge 2.91 litres/sec. was obtained in a pumping test, the draw downs in the test wells at 3 m and 6.184 m were 2.6 m and 0.3 m respectively. If over-all depth of the pumping well was 16 m, the permeability of the soil, is (A) 0.0005 cm/sec (B) 0.001 cm/sec (C) 0.002 cm/sec (D) 0.01 cm/sec

Description : When a constant discharge 2.91 litres/sec. was obtained in a pumping test, the draw downs in the test wells at 3 m and 6.184 m were 2.6 m and 0.3 m respectively. If over-all depth of the pumping well was 16 m, the ... (A) 0.0005 cm/sec (B) 0.001 cm/sec (C) 0.002 cm/sec (D) 0.01 cm/sec

Last Answer : Answer: Option B

The specific gravity of water is taken as (A) 0.001 (B) 0.01 (C) 0.1 (D) 1

Description : The specific gravity of water is taken as (A) 0.001 (B) 0.01 (C) 0.1 (D) 1

Last Answer : Answer: Option D

Pick up the incorrect statement from the following: (A) Dimensions are measured to the nearest 0.01 m (B) Areas are measured to the nearest 0.01 sq.m (C) Cubic contents are measured to the nearest 0.1 cum (D) Weights are measured to the nearest 0.001 tonnes

Description : Pick up the incorrect statement from the following: (A) Dimensions are measured to the nearest 0.01 m (B) Areas are measured to the nearest 0.01 sq.m (C) Cubic contents are measured to the nearest 0.1 cum (D) Weights are measured to the nearest 0.001 tonnes

Last Answer : (D) Weights are measured to the nearest 0.001 tonnes

The time of closing the cycle, in modern circuit breakers is (a) 0.003 sec (b) 0.001 sec (c) 0.01 sec (d) 0.10 sec (e) none of the above

Description : The time of closing the cycle, in modern circuit breakers is (a) 0.003 sec (b) 0.001 sec (c) 0.01 sec (d) 0.10 sec (e) none of the above

Last Answer : (a) 0.003 sec

The mechanical splice attenuation loss is _____ dB or less ∙ a. 0.1 ∙ b. 0.01 ∙ c. 0.001 ∙ d. 1

Description : The mechanical splice attenuation loss is _____ dB or less ∙ a. 0.1 ∙ b. 0.01 ∙ c. 0.001 ∙ d. 1

Last Answer : a. 0.1

A micron is equal to (1) 0.1 mm (2) 0.01 mm (3) 0.001 mm(4) 0.0001 mm

Description : A micron is equal to (1) 0.1 mm (2) 0.01 mm (3) 0.001 mm(4) 0.0001 mm

Last Answer : 0.001 mm

In a transistor Colpitts oscillator, C1 = 0.001 µF, C2 = 0.01 µF and L = 5 µH. The frequency of oscillation in

Description : In a transistor Colpitts oscillator, C1 = 0.001 µF, C2 = 0.01 µF and L = 5 µH. The frequency of oscillation in MHz will be (a) 2.37 MHz (b) 10.00 MHz (c) 11.54 MHz (d) 9.09 MHz 

Last Answer : c

An alkaline solution is used to reduce the concentration of carbon dioxide in a stream from 10% to 0.1% by absorption with irreversible chemical reaction. The overall number of transfer units based on gas phase is: (A) 9.21 (B) 4.605 (C) 100 (D) 0.001

Description : An alkaline solution is used to reduce the concentration of carbon dioxide in a stream from 10% to 0.1% by absorption with irreversible chemical reaction. The overall number of transfer units based on gas phase is: (A) 9.21 (B) 4.605 (C) 100 (D) 0.001

Last Answer : (B) 4.605

Colburn analogy is applicable for the value of Prandtl number from (A) 0.001 to 1 (B) 0.6 to 120 (C) 0.5 to 5 (D) 120 to 400

Description : Colburn analogy is applicable for the value of Prandtl number from (A) 0.001 to 1 (B) 0.6 to 120 (C) 0.5 to 5 (D) 120 to 400

Last Answer : (B) 0.6 to 120

Prandtl number for most of dry gases is about (A) 0.001(B) 0.72 (C) 70 (D) 150

Description : Prandtl number for most of dry gases is about (A) 0.001 (B) 0.72 (C) 70 (D) 150

Last Answer : (B) 0.72

Mark the correct option a) In case RD account opened between 1st and 15th of the month the subsequent deposit shall be made up to 15th of the next month. b) In case RD account opened between 16th and last date of the month the subsequent deposit shall be made up to end of the month of next month c) The above effect apply all account opened before 01 Jan 2012 and after . d) All the above

Description : Mark the correct option a) In case RD account opened between 1st and 15th of the month the subsequent deposit shall be made up to 15th of the next month. b) In case RD account opened between 16th and ... c) The above effect apply all account opened before 01 Jan 2012 and after . d) All the above

Last Answer : d) All the above

Why do some people have an apoplectic fit if a deli counter item is 0.001 lbs over?

Description : Why do some people have an apoplectic fit if a deli counter item is 0.001 lbs over?

Last Answer : answer:Because some folks have lost what they believed was ‘control’ in their life and compensate for it with shit like that. It’s simple deli tantrums at first but before you know it, if left unchecked, the same people start bombing abortion clinics and want to burn books . . .

If the above tape weights 0.001 kg/ft, sag is a.2.73 ft b.3.13 ft c.2.90 ft d.3.03 ft e.107 dynes

Description : If the above tape weights 0.001 kg/ft, sag is a.2.73 ft b.3.13 ft c.2.90 ft d.3.03 ft e.107 dynes

Last Answer : c. 2.90 ft

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular

Description : A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular

Last Answer : A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale ... (C) 0.053 cm (D) 0.529 cm

What is 9 x 1002 x 103 x 0.1 7 x 0.001 in a decimal?

Description : What is 9 x 1002 x 103 x 0.1 7 x 0.001 in a decimal?

Last Answer : 9 * 1002 * 103 * 0.1 7 * 0.001 = 157.90518

What is 2.5 divided by 0.001?

Description : What is 2.5 divided by 0.001?

Last Answer : 2500

What is 0.000 000 001 in words?

Description : What is 0.000 000 001 in words?

Last Answer : What is the answer ?

What is 0.001 micron?

Description : What is 0.001 micron?

Last Answer : What is the answer ?

Which mass measurement is expressed in exactly four significant figures 0.001 g 0.095 g 1005 g 1000 g?

Description : Which mass measurement is expressed in exactly four significant figures 0.001 g 0.095 g 1005 g 1000 g?

Last Answer : 1005 g

What is 0.9 divided by 0.001 explain?

Description : What is 0.9 divided by 0.001 explain?

Last Answer : 900

The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Description : The specific gravity of urine normally ranges from (A) 0.900–0.999 (B) 1.003–1.030 (C) 1.000–1.001 (D) 1.101–1.120

Last Answer : B

In a cycle the spark lasts roughly for A. 1 sec B. 0.1 sec C. 0.0001 sec D.001 sec

Description : In a cycle the spark lasts roughly for A. 1 sec B. 0.1 sec C. 0.0001 sec D.001 sec

Last Answer : ANSWER : C

If the discharge of a sewer running half is 628 1.p.s., i = 0.001, and n = 0.010, the diameter of the sewer, is A. 1.39 m B. 1.49 m C. 1.59 m D. 1.69 m

Description : If the discharge of a sewer running half is 628 1.p.s., i = 0.001, and n = 0.010, the diameter of the sewer, is A. 1.39 m B. 1.49 m C. 1.59 m D. 1.69 m

Last Answer : ANS: D

H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S has to be reduced from 0.05 to 0.001 mole fraction in the gas side. The height of the tower (in metres) corresponding to an operating line given by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Description : H2S is being absorbed in a gas absorber unit. The height of the transfer unit based on the overall mass transfer coefficient on the gas side is 0.4 m. The equilibrium data is given by, y = 1.5 x. The bulk concentration of H2S ... by, y = 5x + 0.001 is (A) 2.0 (B) 1.56 (C) 1.0

Last Answer : (A) 2.0

A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065

Description : A cantilever shaft has a diameter of 6 cm and the length is 40cm, it has a disc of mass 125 kg at its free end. The Young’s modulus for the shaft material is 250 GN/m2. Calculate the static deflection in nm. a) 0.001 b) 0.083c) 1.022 d) 0.065

Last Answer : a) 0.001

The Hamming distance between 100 and 001 is ________. A) 2 B) 0 C) 1 D) none of the above

Description : The Hamming distance between 100 and 001 is ________. A) 2 B) 0 C) 1 D) none of the above

Last Answer : 2

A periodic signal completes onecycle in 0.001 s. What is thefrequency? A) 1 Hz B) 100 Hz C) 1 KHz D) 1 MHz

Description : A periodic signal completes onecycle in 0.001 s. What is thefrequency? A) 1 Hz B) 100 Hz C) 1 KHz D) 1 MHz

Last Answer : 1 KHz

Solid content in most of the domestic sewage is about __________ percent. (A) 0.001 (B) 0.1 (C) 5 (D) 10

Description : Solid content in most of the domestic sewage is about __________ percent. (A) 0.001 (B) 0.1 (C) 5 (D) 10

Last Answer : (B) 0.1

TLV of mercury in potable (drinking) water is about __________ ppm. (A) 0.001 (B) 0.1 (C) 1 (D) 5

Description : TLV of mercury in potable (drinking) water is about __________ ppm. (A) 0.001 (B) 0.1 (C) 1 (D) 5

Last Answer : (A) 0.001

A decimal equivalent of m second is 1) 0.000001 sec 2) 1000000 sec 3) 0.001 sec 4) 1000 sec

Description : A decimal equivalent of m second is 1) 0.000001 sec 2) 1000000 sec 3) 0.001 sec 4) 1000 sec

Last Answer : 1) 0.000001 sec

If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105 N/mm2 ) when subjected to a twisting moment, produces maximum shear stress of 50 N/mm2 , the angle of twist in radians, is (A) 0.001 (B) 0.002 (C) 0.0025 (D) 0.003

Description : If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105  N/mm2 ) when subjected to a twisting  moment, produces maximum shear stress of 50 N/mm2 , the angle of twist in radians, is  (A) 0.001  (B) 0.002  (C) 0.0025  (D) 0.003 

Last Answer : (C) 0.0025 

Express the following in more simple terms. (a) 250,000 volts, (b) 25,000,000 microvolts, (c) 0.001 millivolt.

Description : Express the following in more simple terms. (a) 250,000 volts, (b) 25,000,000 microvolts, (c) 0.001 millivolt.

Last Answer : (a) 250 kV, (b) 25 V, (c) 1µV

As light is coupled in a multiport deflective device, the power is reduced by ∙ A. 1.5 dB ∙ B. 0.1 dB ∙ C. 0.5 dB ∙ D. 0.001 dB

Description : As light is coupled in a multiport deflective device, the power is reduced by ∙ A. 1.5 dB ∙ B. 0.1 dB ∙ C. 0.5 dB ∙ D. 0.001 dB

Last Answer : C. 0.5 dB

.Aslightis coupledin amultipointreflective device,thepowerisreduced by a. 1.5 dB b. 0.1 dB c. 0.5 dB d. 0.001 dB

Description : .Aslightis coupledin amultipointreflective device,thepowerisreduced by a. 1.5 dB b. 0.1 dB c. 0.5 dB d. 0.001 dB

Last Answer : c. 0.5 dB

0.001 Kg mass will be equivalent to a) 2.50 Giga watt hour b) 25.00 giga watt hour c) 0.26 giga watt hour d) None of the above

Description : 0.001 Kg mass will be equivalent to a) 2.50 Giga watt hour b) 25.00 giga watt hour c) 0.26 giga watt hour d) None of the above

Last Answer : b) 25.00 giga watt hour