Description : What is the data rate in Mbps of a single satellite transponder considering an S/N of 30 dB? A. 35.8 B. 3.58 C. 358 D. 3580
Last Answer : C. 358
Description : A coherent binary phase shift keyed BPSK transmitter operates at a bit rate of 20 Mbps with a carrier to noise ratio C/N of 8.8dB. Find Eb/No. A. 73 dB B. 62.4 dB C. 81.8 dB D. 8.8 dB
Last Answer : D. 8.8 dB
Description : In the North American TDM system, what is the transmission rate in Mbps of T3 carrier system? A. 44.736 B. 6.312 C. 3.152 D. 274.176
Last Answer : A. 44.736
Description : How many transponder channels are realized in the commercial C-band without frequency re-use? A. 24 B. 12 C. 36 D. 48
Last Answer : B. 12
Description : What is the typical satellite transponder bandwidth? A. 24 MHz B. 500 MHz C. 36 MHz D. 48 MHz
Last Answer : C. 36 MHz
Description : What is the quardband between transponder channels in the commercial C-band for satellite communications? A. 6 MHz B. 36 MHz C. 4 MHz D. 2 MHz
Last Answer : C. 4 MHz
Description : X,Y and Z can do a certain job in 72,108 and 144 days respectively. They started the job but X left 16 days before the completion of the job while Y left 24 days before the completion. The number of days for which Z worked is. a) 12 days b) 24 days c) 36 days d) 48 days
Last Answer : D Suppose the work was finished in a' days Then X's (a - 16) day's work + Y's (a - 24) days + Z's a days work = 1 (a-16)/72 + (a-24)/108 + a/144 =1 lcm of 72,108,144 is 432 (6(a-16) + 4( ... = 432 6a - 96 +4a - 96 =3a = 432 13a - 192 = 432 13a = 624 => a =48 Therefore Z worked in 48 days.
Description : A bag contains one rupee, 50 paise and 25 paise coins in the ratio 2 : 3 : 5. Their total value is Rs. 144. The value of 50-paise coins is: a) Rs. 24 b) Rs. 36 c) Rs. 48 d) Rs. 72 e) None of these
Last Answer : Answer: B Sol. Let the number of one-rupee coins, 50-paise coins and 25-paise coins be 2k, 3k and 5k, respectively. ∴ 2k × 1 + 3k × 0.50 + 5k × 0.25 = 114 ⇒ 2k + 1.50k + 1.25k = 114 ⇒ 4.75k = 114 ⇒ k = 24. 50 paise value = 1.5x = 1.5*24 = 36
Description : In how many different ways can the letters of the word "POMADE" be arranged in such a way that the vowels occupy only the odd positions? a) 72 b) 144 c) 532 d) 36
Last Answer : Answer: D) There are 6 different letters in the given word, out of which there are 3 vowels and 3 consonants. Let us mark these positions as under: [1] [2] [3] [4] [5] [6] Now, 3 vowels can be ... of these arrangements = 3P3 = 3! = 6 ways. Therefore, total number of ways = 6 x 6 = 36.
Description : In ISDN, what is the basic access B channel data rate? A. 32 kbps B. 64 kbps C. 144 kbps D. 16 kbps
Last Answer : B. 64 kbps
Description : What is the data rate of the ISDN Basic access B channel? A. 192 kbps B. 32 kbps C. 64 kbps D. 144 kbps
Last Answer : C. 64 kbps
Description : If a transmitting antenna is 100 meters high and a separate receiving antenna is 64 meters high, what is the maximum space wave communication distance possible between them? A. 18 km B. 72 km C. 164 km D. 656 km
Last Answer : B. 72 km
Description : What satellite subsystem monitors onboard conditions such as temperature and battery voltage and transmits this data back to a ground station for analysis? A. Communications subsystem B. AKM C. TTC D. Transponder
Last Answer : C. TTC
Description : In data communication the transmission of binary signals will require _______. A. Same bandwidth as analog B. More bandwidth than analog C. Less bandwidth than analog D. Bigger cable diameter
Last Answer : B. More bandwidth than analog
Description : In t-carrier system, t3 has a bit rate of A. 560.160 Mbps B. 44.376 Mbps C. 44.736 Mbps D. 560.106 Mbps
Last Answer : C. 44.736 Mbps
Description : What carrier system multiplexes 96 voice band channels into a single 6.312 Mbps data signal? A. T1 carrier system B. T2 carrier system C. T1C carrier system D. T3 carrier system
Last Answer : B. T2 carrier system
Description : In a digital transmission, the receiver clock is 0.1 percent faster than the sender clock. How many extra bits per second does the receiver receive if the data rate is 1 Mbps ? (A) 10 bps (B) 100 bps (C) 1000 bps (D) 10000 bps
Last Answer : (C) 1000 bps
Description : Basic speed rate of digital system. A. 144 kbps B. 1,544 kbps C. 64 kbps D. 2,048 kbps
Description : Highest theoretical frequency that can be processed at a sampling rate without aliasing. A. Folding frequency B. Resonant frequency C. Natural frequency D. Critical frequency
Last Answer : A. Folding frequency
Description : What is the bit rate for transmitting uncompressed 800x600 pixel colour frames with 8 bits/pixel at 40 frames/second ? (A) 2.4 Mbps (B) 15.36 Mbps (C) 153.6 Mbps (D) 1536 Mbps
Last Answer : (C) 153.6 Mbps Explanation: The number of bits/sec is just 800x600x40x8 or 153.6 Mbps.
Description : Which of the following is standardized as part of GSM phase 2+ that can offer theoretical data speeds of upto 115 kbit/s? A. EDGE B. GPRS C. WAP D. Bluetooth
Last Answer : B. GPRS
Description : Designed to receive a signal from a transmitting station on the ground and retransmit it to a receiving station located elsewhere A. Communication satellite B. Repeater C. Relay station D. Transponder
Last Answer : A. Communication satellite
Description : Essentially a satellite ___________ is a radio repeater in the sky A. transponder B. comparator C. duplexer D. billboard
Last Answer : A. transponder
Description : The satellite communications channels in a transponder are defined by the A. LNA B. bandpass filter C. mixer D. input signals
Last Answer : B. bandpass filter
Description : Which of the following is not usually a part of a transponder are defined by the A. LNA B. Mixer C. Modulator D. HPA
Last Answer : C. Modulator
Description : The key electronic component in a communications satellite is the A. telemetry equipment B. on-board computer C. command and control system D. transponder
Last Answer : D. transponder
Description : A satellite signal transmitted from a satellite transponder to earth’s station. A. Uplink B. Downlink C. Terrestrial D. Earthbound
Last Answer : B. Downlink
Description : What is the first passive satellite transponder? A. Sun B. Early Bird C. Score D. Moon
Last Answer : B. Early Bird
Description : Which of the following is the basic component of a communications satellite receiver? A. On-board computer B. Reflector C. Telemetry D. Transponder
Last Answer : D. Transponder
Description : Which of the following satellite subsystem provides stabilization in orbit and senses changes in orientation? A. Attitude control subsystem B. TTC C. AKM D. Transponder
Last Answer : A. Attitude control subsystem
Description : Known as the satellite transmitted signal form a satellite transponder to earth’s station. A. Uplink B. Down link C. RHCP D. Vertically polarized
Last Answer : B. Down link
Description : The first passive satellite transponder. A. Early bird B. Score C. Moon D. Sputnik
Last Answer : C. Moon
Description : Combination of modulator, channel and detector. A. Transceiver B. Discrete channel C. T/R channel D. Transponder
Last Answer : B. Discrete channel
Description : Satellite signal transmitted from a satellite transponder to earth’s station. A. Vertically polarized B. Uplink C. Downlink D. RHCP
Last Answer : C. Downlink
Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5
Last Answer : b. 2
Description : Maximum data transfer rate of the optical fiber is……….? a. 50 kbps b. 1000 kbps c. 1000 Mbps d. None of the these
Last Answer : c. 1000 Mbps
Description : Which causes a quantization noise in PCM system? A. Serial transmission errors B. The approximation of the quantized signal C. The synchronization between encoder and decoder D. Binary coding techniques
Last Answer : B. The approximation of the quantized signal
Last Answer : The approximation of the quantized signal
Description : Quantization noise is caused by A. binary coding techniques B. serial transmission errors C. the synchronization between encoder and decoder D. the approximation of the quantized signal
Last Answer : D. the approximation of the quantized signal
Description : What digital carrier transmits a digital signal at 274.176 Mbps? A. T1 B. T3 C. T2 D. T4
Last Answer : D. T4
Description : What medium is used by IBM token ring network that operates at either 4 Mbps or 16 Mbps? A. Twisted pair B. Coaxial cable C. Fiber-optic D. Parallel-wire line
Last Answer : A. Twisted pair
Description : A digital carrier facility used to transmit a DSI-formatted signal at 1.544. Mbps. A. T2 B. T1 C. T4 D. T3
Last Answer : B. T1
Description : Ethernet is baseband system using CSMA/CD operating at A. 20 Mbps B. 10 Mbps C. 30 Mbps D. 40 Mbps
Last Answer : B. 10 Mbps
Description : ECE Board Exam March 1996 The standard that specifies a balanced interface cable that will operate bit rates up to 10 Mbps with in a span distances up to 1200 m. A. RS-423A B. RS-422A C. RS-550A D. RS-449A
Last Answer : B. RS-422A
Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ______. a. 64 Kbps b. 32 Mbps c. 32 Kbps d. 64 MbpS
Last Answer : c. 32 Kbps
Description : If link transmits 4000 frames per second and each slot has 8 bits, the transmission rate of circuit of this TDM is ............... (A) 64 Kbps (B) 32 Mbps (C) 32 Kbps (D) 64 Mbps
Last Answer : (C) 32 Kbps
Description : Find the magnitude of the displacement current density in air at a frequency of 18GHz in frequency domain. Take electric field E as 4 units. a) 18 b) 72 c) 36 d) 4
Last Answer : d) 4
Description : In each of the following questions select the related letters/word/number from the given alternatives. 1. CFIL: ORUX::GDJM: ? (a) HJLN (b) NQST (c) PSVY (d) RTVX 2. BEHK: YVSP::DGJM : ? (a) JGDA (b) ... Chisel (d) Statue 9. MKQO: LNPR:: ?XVTZ (a) YSUW (b) SVWY (c) VTWY (d) WYTS
Last Answer : 1. (c) 2. (c) 3. (c) 4. (c) 5. (d) 6. (b) 7. (d) 8. (d) 9. (a)
Description : In the case of a 70–MHz IF carrier for a transponder bandwidth of 36 MHz, energy must lie between MHz: (1) 34 and 106 (2) 52 and 88 (3) 106 and 142 (4) 34 and 142
Last Answer : In the case of a 70–MHz IF carrier for a transponder bandwidth of 36 MHz, energy must lie between MHz: 52 and 88
Description : Sixteen different levels (symbols) are used to encode binary data. The channel bandwidth is 36 MHz. The maximum channel capacity is
Last Answer : 288 Mbps