Description : In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800
Last Answer : Answer: D Total number of votes = 15000 Given that 40% of Percentage votes were invalid => Valid votes = 60% Total valid votes = 15000* 60/100 1st candidate got 45% of the total valid votes. Hence ... votes that 2nd candidate got = total valid votes x 55/100 =15000*60/100*55/100 =4950
Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298
Last Answer : Answer: D Let the maximum marks be x. Aashika’s marks = 32% of x Aashika secured 1328 marks Therefore, 32% of x = 1328 ⇒ 32/100 × x = 1328 x = (1328 × 100)/32 x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.
Description : In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected ... appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800
Last Answer : Answer: C Pondichery and Tamilnadu had an equal number of candidates appeared In Pondicherry, 18% candidates got selected from the total appeared candidates In tamilnadu, 21% candidates ... > total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000
Description : Ajay sold a motorbike at a profit of 20% to Balu. Balu sold it to Dinesh at a loss of 20%. If the profit made by Ajay was Rs.120 less than the loss made by Balu, find the cost price of Ajay(in Rs.) a)3000 b)3600 c)3900 d)4500
Last Answer : a)3000
Description : A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298
Last Answer : Answer: B Let x be the maximum marks, Then (50% of x)+60 = (75% of x)-40 x/2 +60 = 3x/4 -20 60+20 = 3x/4 – x/ 2 X=320 Hence maximum marks = 320 Minimum pass marks = 320/2 + 60 = 220
Description : While the fuel fired furnace can be used upto a maximum temperature of about 1700°C, the electric furnace can be used upto a temperature of about __________ °C. (A) 2000 (B) 3000 (C) 4500 (D) 6000
Last Answer : (C) 4500
Description : Two equal sums are lent at the same time at 6% and 5 % simple interest respectively. The former is recovered 24 months earlier than the latter. And the amount in each case is Rs. 2400. Find the sum of money lent initially. a) 1500 b) 2000 c) 2400 d) 3000 e) 3600
Last Answer : Let the sum be S, time be ‘n’ years for 6%. n+2 years for 5% 2400 = S + S ×n × 6/100 2400 = S + S × (n+2) × 5/100 So, 6n = 5(n+2) or n = 10 years. 2400 = S + S × 10 × 6/100 = 1.6S S = 2400/1.6 = 1500 Answer: a)
Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98
Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.
Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price = $37.5 - $ 30 = $ 7.5 Therefore, percentage increase in price = Increase in price/ ... = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %
Description : Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800
Last Answer : Answer: A Percentage savings of Supriya = 100 – (35 + 45) = 20% Let her monthly income be x x X 20 /100 = 25750 x = 25750 × 100/20 x = 128750
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5
Last Answer : Answer: D Let the number be m. Decrease = 24 % of m = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594 19m = 594 × 25 19m = 14850 m = 14850/19 m =781.5
Description : By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98
Last Answer : Answer: A Let the number be m Increase in its value = 25 % of m = 25/100 × m = m/4 Therefore, increase value = m + m/4 = (4m + m)/4 = 5m/4 Therefore, the given number must be multiplied by 5/4 to increase the number by 25 %.
Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855
Last Answer : Answer: E Increase = 90 % of 450 = 90/100 × 450 = 40500/100 = 405 Therefore, increase value = 450 + 405 = 855
Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298
Last Answer : Answer: B The number of students with first division = 56 % of 900 = 56/100 × 900 = 50400/100 = 504 And, the number of students with second division = 27 % of 900 = 27/100 × 900 =24300/100 = 243 Therefore, the number of students who just passed = 900 – (504 + 243) = 900- 747 = 153
Description : Brother's weight is 25 % more than that of sister. What percent is brother’s weight less than sister's weight? a) 25% b) 60% c) 45% d) 20% e) 98%
Last Answer : Answer: D Let sister's weight be 100 kg. Then brother's weight = (100 + 25) kg = 125 kg If brother's weight is 125 kg, then sister's weight is 100 kg. If brother's weight is 1 kg, then ... then sister's weight = (100/125 100) kg Therefore, sister's weight is 20 % less than that of brother.
Description : An alloy contains 36 % of bronze. What quantity of alloy is required to get 340 g of bronze? a) 1500 b) 944.4 c) 950 d) 1000 e) 980.5
Last Answer : Answer: B Let the quantity of alloy required = x g Then 36 % of x =340 g ⇒ 36/100 × x = 340 g x = (340 × 100)/36 g x = 34000/36 g x = 944.4 g
Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180
Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45 x = (45 × 100)/25 x = (4500)/25 x = 180 Therefore, the total number of matches played is 180.
Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801
Last Answer : Answer: E Number of boys in the college = 60 % of 1335 = 60/100 × 1335 = 80100/100 = 801 Number of girls in the college = Total number of students in the college - Number of boys = 1335 – 801 =534
Description : Sanjay gets 72 % marks in examinations. If these are 864 marks, find the maximum marks. a) 1050 b) 860 c) 1225 d) 1200 e) 1500
Last Answer : Answer: D Let the maximum marks be s Then 72 % of s = 864 72/100 × s = 864 s = (846 × 100)/72 s = 86400/92 s = 1200 Therefore, maximum marks in the examinations are 1200.
Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5
Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130 = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X
Description : L, M and N started a business in which L invested Rs.15000/- for 2year, M invested Rs 25000/- for 3 years, N invested Rs.35000/- for 4 years. At the end of the profit received by them is Rs.9800/-. What is N’s share?. A) 5600 B) 5000 C) 5500 D) 4500
Last Answer : Answer: A) L = Rs.15000/- per 2 years M= Rs.25000/- per 3 years N = Rs.35000/- per 4 years = 15000 2 : 25000 3 : 35000 4 =30000:75000:140000=30:75:140 =6:15:28 Total = 49 parts -----> Rs. ... ) = 1 part ------> Rs.200/- Then, N's share is = 28 parts = Rs.200 28 parts = Rs.5600
Description : In a business, X,Y and Z inversed Rs.20,000/-,Rs.30,000/- and Rs.40,000/- respectively. After 1 year X adds Rs.10000/- to the initial investment.Y and Z withdrew Rs.10000/- and Rs.15,000/- respectively. After 2 years the total profit is Rs.9900/-. What is X’s share?. A) 3000 B) 2700 C) 3600 D) 4000
Last Answer : Answer: A) X's Share = Rs.20000/- per first 1 year, Next year 10000/- added = Rs.20000/- 1 + Rs.30000/- 1 = Rs.50000/- Y's Share = Rs.30000/- per first 1 year, Next year 10000/- reduced = Rs.30000 ... /- 1 part------> Rs300/- Then, X's share is 10 parts = Rs.300/- 10 parts = Rs.3000/-
Description : On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40
Last Answer : Answer: E 60% of 500 = 300 80% of 250 = 200 No. of correct answers in remaining 250 questions = 300 – 200 = 100 Percentage = 100 x 100/ 250 = 40%
Description : In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98
Last Answer : Answer: A Let the total number of eggs in the basket be x 20 % of the eggs are rotten, and eggs in good condition are 68 Therefore, according to the question, 80% of x = 68 80/100 × x = 68 x = (68 × 100)/80 x = 6800 / 80 x = 85 Therefore, total number of eggs in the basket is 85.
Description : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be ______. (A) 20% (B) 40% (C) 50% (D) 30%
Last Answer : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be 20%.
Description : Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam. A.2500 lbf-ft/lbm B.3300 lbf-ft/lbm C.5400 lbf-ft/lbm D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV
Last Answer : 3300 lbf-ft/lbm
Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989
Last Answer : Answer: C If Gowthaman had scored 26 marks more, he could have scored 25% Therefore, Mike required 424 + 26 = 450 marks Let the maximum marks be x. Then 25 % of x = 450 (25/100) × x = 450 x = (450 × 100)/25 x = 45000/25 x = 1800
Description : What is the wavelength of visible spectrum? (1) 1300 A° -3000 A° (2) 3900 A° - 7600 A° (3) 7800 A° - 8000 A° (4) 8500 A° - 9800 A°
Last Answer : (2) 3900 A° - 7600 A° Explanation: The visible spectrum is the portion of the electromagnetic spectrum that is visible to (can be detected by) the human eye. Electromagnetic radiation in this range of wavelengths ... from about 390 to 750 nm in terms of angstrom it is in between 3900 - 7600 A°.
Description : What is the wavelength of visible spectrum ? (1) 1300 A°–3000 A° (2) 3900 A° – 7600 A° (3) 7800 A° – 8000 A° (4) 8500 A° – 9800 A°
Last Answer : 3900 A° – 7600 A°
Description : Ronit spends his money from his saving in different way that is he spends 25% on travel,15% on food,20% on wages and 17% on shopping a clothes and after that all expenditure he saved 6900.Find the how much he spent on clothes. A) 4400 B) 5100 C) 4000 D) 6000
Last Answer : B) Let the total income of Ronit x then total expenditure from income X x (25%+15%+20%+17%)=X*77% X x 77% =Total savings= X x 23% X = 6900 x 100 / 23 = 30000 expenditure on clothes = 17% so,30000 x 17 / 100 = 5100
Description : An shopkeeper has 15 models of cup and 9 models of saucer. In how many ways can he make a pair of cup and saucer? A) 100 B) 80 C) 110 D) 135
Last Answer : Answer: D) He has 15 patterns of cup and 9 model of saucer A cup can be selected in 15 ways. A saucer can be selected in 9 ways. Hence one cup and one saucer can be selected in 15×9 ways =135 ways
Description : A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450
Last Answer : Answer: A) Number of ways to choose 10 questions from part A = 12C10 Number of ways to choose 8 questions from part B = 12C8 Total number of ways= 12C10 × 12C8 = 12C2 × 12C4 [∵ nCr = nC(n-r)] ={12×11}/{2×1}X{12×11×10×9} / {4×3×2×1} =66×495 =32670
Description : Pramoth has 12 friends and he wants to invite 7 of them to a party. How many times will 4 particular friends never attend the party? A) 8 B) 7 C) 12 D) 15
Last Answer : Answer: A) Remove the 4 particular friends and invite 7 friends from the remaining 8 (12-4) friends . this can be done in 8C7 ways. Therefore , required number of ways = = 8C7 = 8C1 = 8
Description : A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3
Last Answer : Answer: A Total number of fruits shopkeeper bought = 1800 + 1200 = 1000 Number of rotten blackberry = 45% of 1800 = 45/100 1800 = 81000/100 = 810 Number of rotten blueberry = 24% of 1200 ... Therefore Percentage of fruits in good condition = (1902/3000 100) = (190200/3000) = 63.4%
Description : A grating has 6000 lines per cm. How many orders of light of wavelength 4500 A 0 can be seen? A. 1 B. 2 C. 3 D. 4
Last Answer : C. 3
Description : A and B entered into a partnership investing Rs. 16000 and Rs. 12000 respectively. After 3 months, A withdrew Rs. 5000 while B invested Rs. 5000 more. After 3 more months C joins the business with a capital of Rs. 21000 ... of Rs. 26400 after one year by A.Rs. 2400 B.Rs. 3600 C.Rs. 3000 D.Rs. 4800
Last Answer : Answer: B (Rs. 3600) Explanation: A:B: C = 16000 x3 + 11000×9:12000 x 3 + 17000 x 9:21000 x 6 = 147:189:126 = 7:9:6 Difference of B and C’s shares = Rs. [26400 x (9/22) — 26400 x (6/22)) = Rs. 3600.
Description : Listed below are four respiratory capacities (i-iv) and four jumbled respiratory volumes of a normal human adult. Respiratory Respiratory capacities volumes (i) Residual volume 2500 mL (ii) Vital capacity 3500 mL (iii)Inspiratory ... c) (iv) 3500 mL, (i) 1200 mL (d) (i) 4500 mL, (ii) 3500 mL
Last Answer : (c) (iv) 3500 mL, (i) 1200 mL
Description : Two employees X and Y are paid a total of Rs. 4950 per week by their employer. If X is paid 150 percent of the sum paid to Y, how much is Y paid per week? a) 1250 b) 3760 c) 2405 d) 1540 e) 1980
Last Answer : Answer: E Let the amount paid to X per week = x and the amount paid to Y per week = y Then x + y = 4950 But x = 150% of y = 150y/100 = 15y/10 ∴15y/10 + y = 4950 ⇒ y[15/10 + 1] = 4950 ⇒ 25y/10 = 4950 ⇒ 25y = 49500 ⇒ y = 49500/25 y = Rs.1980
Description : The monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio 9 : 7. If each person saves Rs. 500 per month, then what are their monthly incomes? a) Rs 8000 and Rs ... Rs 3750 and Rs 3000 c) Rs 5000 and Rs 4000 d) Rs 4500 and Rs 4000 e) None of the above
Last Answer : Let the incomes of two persons be 5x and 4x let the expenditures of them be 9y and 7y Each person saves Rs. 500 Therefore, 5x - 9y = 500 4x - 7y = 500 Solving the above equations, 20x - 36y = 2000 20x - ... = 500 + 9(500) = 5000 X = 1000 Hence, their salaries are Rs. 5000 and Rs. 4000 Answer: c)
Description : The population of a town is 15000. It increases annually at the rate of 20% p.a. What will be its population after 3 years? a) 65439 b) 25920 c) 37193 d) 41093
Last Answer : Answer: B Formula : ( After =100 denominator ) (Ago = 100 numerator) After 3 years = 15000×(1+20/100)^3 = 15000 ×(120/100)^3 = 15000 ×(1.2)^3 = 15000 ×(1.728) = 25920
Description : Rs.10500 is divided among P, Q and R. So that P receives half as much as Q and Q receives half as much as R. Then then total share of P and R is A) 4500 B) 3000 C) 5000 D) 7500
Last Answer : Answer: D) Let amount received by R is X Amount received by Q is X/2 Amount received by P is X/4 Profit ratio of P,Q &R =X/4:X/2:X =1:2:4 Total share of P&R =10500*5/7 =Rs 7500
Description : If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534
Last Answer : Answer: C Required Production=140(1 + 16/100)2 lakh tones =140(1 + 4/25)2 =140((25 + 4) /25)² =140(29/25)² =140(1.16)² =140×1.3456 =188.384 lakh tonnes
Description : The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272
Last Answer : Answer: E After 2 years required population is = 378000 (1-16/100) (1+10/100) = 378000 (84/100) (110/100) = 378000 (0.84) (1.1) = 3,49,272
Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313
Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000 = (104/100) × (106/100) × (110/100) × 200000 = 1.04×1.06×1.1×200000 = 2,42,528
Description : In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814
Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320 = 75/100 *5320 = 399000/100 = 3990
Description : In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93
Last Answer : Answer: D Total number of votes polled = (2272+15272+23256) =40800 Required percentage = 23256/40800 ×100 = 2325600/40800 = 57
Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800
Last Answer : Answer: D Total number of invalid votes = 55 % of 280000 = 55/100 280000 = 15400000/100 = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000 = 40/100 126000 = 5040000/100 = 50400
Description : A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980
Last Answer : Answer: C Original value is percentage = 100 %. Reduce amount in percentage = 10 % Therefore, Percent value in percentage = 100 % - 10 % = 90 %. According to the problem, 90 % of original value ... Therefore, 100 % of original value = 1080/100 90 = 1200. Thus, the original value was 1200.
Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6
Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %] = 144/168 × 100 = 85.7 %