Description : In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814
Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320 = 75/100 *5320 = 399000/100 = 3990
Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800
Last Answer : Answer: D Total number of invalid votes = 55 % of 280000 = 55/100 280000 = 15400000/100 = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000 = 40/100 126000 = 5040000/100 = 50400
Description : mouli had $ 3600 left after spending 40 % of the money he took for shopping. How much money did he take along with him? a) 2500 b) 6000 c) 4500 d) 3000 e) 9800
Last Answer : Answer: B Let the money he took for shopping be x. Money he spent = 40 % of x = 40/100 x = 4/10 x Money left with him = x - 4/10 x = (10x - 4x)/10 = 6x/10 But money left with ... 6x/10 = 3600 x = 3600 10/6 x = 36000/6 x = 6000 Therefore, the money he took for shopping is 6000.
Description : In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93
Last Answer : Answer: D Total number of votes polled = (2272+15272+23256) =40800 Required percentage = 23256/40800 ×100 = 2325600/40800 = 57
Description : In an election between two candidates, the winner secured 85% of the total votes cast and wins by a majority of 6300 votes. How many votes did the losing candidate get? a) 1350 b) 2479 c) 3467 d) 5789
Last Answer : Answer: A Total votes cast = 100% Winner gets = 85% Loser gets = 100 – 85 = 15% Majority = Votes secured by winner – Votes secured by loser = 85% - 15% =70% =6300 Votes by the losing candidate = x = 15% x = (15 * 6300)/70 x =(94500/70) x = 1350
Description : In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected ... appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800
Last Answer : Answer: C Pondichery and Tamilnadu had an equal number of candidates appeared In Pondicherry, 18% candidates got selected from the total appeared candidates In tamilnadu, 21% candidates ... > total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000
Description : In an election only two candidates Ram and Shyam contested, Ram got `75%` of the total valid votes. `6%` of the polled votes were declared invalid. If
Last Answer : In an election only two candidates Ram and Shyam contested, Ram got `75%` of the total valid ... number of valid votes polled in favour of Shyam.
Description : In a college election a candidate who got 35% of the total votes polled was defeated by his rival by 270 votes. Assuming that there were only two candidates in the election, the total number of votes polled was a) 10000 b) 8000 c) 9000 d) 12000 e) 12500
Last Answer : c) 9000
Description : Two employees X and Y are paid a total of Rs. 4950 per week by their employer. If X is paid 150 percent of the sum paid to Y, how much is Y paid per week? a) 1250 b) 3760 c) 2405 d) 1540 e) 1980
Last Answer : Answer: E Let the amount paid to X per week = x and the amount paid to Y per week = y Then x + y = 4950 But x = 150% of y = 150y/100 = 15y/10 ∴15y/10 + y = 4950 ⇒ y[15/10 + 1] = 4950 ⇒ 25y/10 = 4950 ⇒ 25y = 49500 ⇒ y = 49500/25 y = Rs.1980
Description : L, M and N started a business in which L invested Rs.15000/- for 2year, M invested Rs 25000/- for 3 years, N invested Rs.35000/- for 4 years. At the end of the profit received by them is Rs.9800/-. What is N’s share?. A) 5600 B) 5000 C) 5500 D) 4500
Last Answer : Answer: A) L = Rs.15000/- per 2 years M= Rs.25000/- per 3 years N = Rs.35000/- per 4 years = 15000 2 : 25000 3 : 35000 4 =30000:75000:140000=30:75:140 =6:15:28 Total = 49 parts -----> Rs. ... ) = 1 part ------> Rs.200/- Then, N's share is = 28 parts = Rs.200 28 parts = Rs.5600
Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298
Last Answer : Answer: D Let the maximum marks be x. Aashika’s marks = 32% of x Aashika secured 1328 marks Therefore, 32% of x = 1328 ⇒ 32/100 × x = 1328 x = (1328 × 100)/32 x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.
Description : From the salary of pooja , 40% is deducted as house rent, 20% of rest she spends on children's education and 40% of balance she spends on watching movies. If her savings are Rs.5760/- then hers total salary is: a) 20000 b) 30060 c) 45000 d) 47000 e) 98000
Last Answer : Answer: A Formula: First value = last value×100/(100-p1)×100/(100-p2)× 100/(100-p3) (p=percentage) First value = 5760×100/(100 – 40)×100/(100 – 20)×100/(100 - 40 ) = 5760 × 100/60× 100/80× 100/60 = 5760 × 5/3 × 5/4 × 5/3 = 5760 ×125/36 = 720000/36 = 20000
Description : A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3
Last Answer : Answer: A Total number of fruits shopkeeper bought = 1800 + 1200 = 1000 Number of rotten blackberry = 45% of 1800 = 45/100 1800 = 81000/100 = 810 Number of rotten blueberry = 24% of 1200 ... Therefore Percentage of fruits in good condition = (1902/3000 100) = (190200/3000) = 63.4%
Description : The population of a town is 15000. It increases annually at the rate of 20% p.a. What will be its population after 3 years? a) 65439 b) 25920 c) 37193 d) 41093
Last Answer : Answer: B Formula : ( After =100 denominator ) (Ago = 100 numerator) After 3 years = 15000×(1+20/100)^3 = 15000 ×(120/100)^3 = 15000 ×(1.2)^3 = 15000 ×(1.728) = 25920
Description : Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800
Last Answer : Answer: A Percentage savings of Supriya = 100 – (35 + 45) = 20% Let her monthly income be x x X 20 /100 = 25750 x = 25750 × 100/20 x = 128750
Description : Brother's weight is 25 % more than that of sister. What percent is brother’s weight less than sister's weight? a) 25% b) 60% c) 45% d) 20% e) 98%
Last Answer : Answer: D Let sister's weight be 100 kg. Then brother's weight = (100 + 25) kg = 125 kg If brother's weight is 125 kg, then sister's weight is 100 kg. If brother's weight is 1 kg, then ... then sister's weight = (100/125 100) kg Therefore, sister's weight is 20 % less than that of brother.
Description : The difference between 45% of a number and 37% of the same number is 896. What is 25% of that number ? a) 1200 b) 2800 c) 2569 d) 3467
Last Answer : Answer: B (45 – 37)% of the number = 896 8 % of the number = 896 Number =896 x100 /8 = 89600/8 = 11200 25% of 11200 = 11200 x 25/100 = 280000 / 100 = 2800
Description : A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298
Last Answer : Answer: B Let x be the maximum marks, Then (50% of x)+60 = (75% of x)-40 x/2 +60 = 3x/4 -20 60+20 = 3x/4 – x/ 2 X=320 Hence maximum marks = 320 Minimum pass marks = 320/2 + 60 = 220
Description : The population of a town is 16200. It decreases annually at the rate of 40% p.a. What was its population 3 years ago? a) 75000 b) 65000 c) 84900 d) 93600
Last Answer : Answer: A (Ago = 100 numerator) Ago 3 years = 16200×(100/60×100/60×100/60) = 75000
Description : The winning candidate in the Election of President of India should secure– (1) Majority number of votes polled (2) Sixty six percent of votes polled (3) Fifty percent of votes polled (4) More than fifty percent and majority of the total votes polled
Last Answer : (4) More than fifty percent and majority of the total votes polled Explanation: The winning candidate in the Election of President of India [Article 54] should secure more than fifty percent and majority of the total votes polled. The President is elected by an electoral college.
Description : When does Lok Sabha or a Vidhan Sabha election candidate forfeit his security deposit? (1) When he fails to win the election (2) When he fails to secure even 1/4 of total votes polled (3) When he fails ... even 1/5 of total votes polled (4) When he fails to secure even 1/6 of total votes polled
Last Answer : (4) When he fails to secure even 1/6 of total votes polled Explanation: A deposit is a sum of money that a candidate must pay in return for the right to stand for election to certain political ... he polis less than one-sixth of the total valid votes cast in a First-past-the-post voting system.
Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298
Last Answer : Answer: B The number of students with first division = 56 % of 900 = 56/100 × 900 = 50400/100 = 504 And, the number of students with second division = 27 % of 900 = 27/100 × 900 =24300/100 = 243 Therefore, the number of students who just passed = 900 – (504 + 243) = 900- 747 = 153
Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989
Last Answer : Answer: C If Gowthaman had scored 26 marks more, he could have scored 25% Therefore, Mike required 424 + 26 = 450 marks Let the maximum marks be x. Then 25 % of x = 450 (25/100) × x = 450 x = (450 × 100)/25 x = 45000/25 x = 1800
Description : In accordance with the Constitution, each elector cast _______ votes for any two candidates during the Presidential and Vice Presidential election of 1796.?
Last Answer : two (A+)
Description : If in an election to a state Legislative Assembly, the candidate who is declared elected loses his deposit, it means that? (1) The polling was very poor (2) The election was for a multi- ... over his nearest rival was very marginal. (4) A very large number of candidates contested the election.
Last Answer : (1) The polling was very poor Explanation: A candidate loses his deposit only when he is polled less than 1/6th of votes. It can only be possible when a very large number of candidates contested the elections.
Description : In a birthday party, every person shakes hand with every other person. If there was a total of 66 handshakes in the party, how many persons were present in the party? A) 9 B) 8 C) 7 D) 12
Last Answer : Answer: D) Assume that in a party every person shakes hand with every other person Number of hand shake = 66 Total number of hand shake is given by nC2 Let n = the total number of persons ... cannot take negative value of n So, n = 12 Therefore number of persons in the party = 12
Description : In which type of US election is it possible for the winning candidate to get fewer popular votes than the opposing candidate?
Last Answer : Only in the federal elections for President of the United States can this occur, as the Electoral College vote outcome will supercede the popular vote's.
Description : In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98
Last Answer : Answer: A Let the total number of eggs in the basket be x 20 % of the eggs are rotten, and eggs in good condition are 68 Therefore, according to the question, 80% of x = 68 80/100 × x = 68 x = (68 × 100)/80 x = 6800 / 80 x = 85 Therefore, total number of eggs in the basket is 85.
Description : How do you think candidates would fare if no news station decided to cover any election event or even name a candidate for a whole month?
Last Answer : They’d still get online coverage. In fact many have argued that online campaigns greatly helped Obama get elected the first time round
Description : Ajay sold a motorbike at a profit of 20% to Balu. Balu sold it to Dinesh at a loss of 20%. If the profit made by Ajay was Rs.120 less than the loss made by Balu, find the cost price of Ajay(in Rs.) a)3000 b)3600 c)3900 d)4500
Last Answer : a)3000
Description : Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam. A.2500 lbf-ft/lbm B.3300 lbf-ft/lbm C.5400 lbf-ft/lbm D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV
Last Answer : 3300 lbf-ft/lbm
Description : From the salary of shreya, 15% is deducted as house rent, 15% she spends on children’s education and 20% on watching movies. If her savings are Rs.8450/- then her total salary is: a) 13500 b) 2360 c) 16900 d) 11520 e) 23198
Last Answer : Answer: C She spends = 50% remaining 50% = 8450 Total salary = 8450 × 100 / 50 = 845000 / 50 = 16900
Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7
Description : If the election of the President of India is declared void by the Supreme Court, the acts performed by President Incumbent before the date of such decision of court remain - (1) Valid (2) Invalid (3) Valid Subject to the judicial review (4) Valid Subject to the approval of the parliament
Last Answer : (1) Valid Explanation: If the election of the President of India is declared void by the Supreme Court, the acts performed by President Incumbent before the date of such decision of court remain valid.
Description : The total power of an AM transmitter having a carrier power of 50 W and the percentage of modulation at 80% is A) 50 W B) 66 W C) 68 W D) 70 W
Last Answer : The total power of an AM transmitter having a carrier power of 50 W and the percentage of modulation at 80% is 66 W
Description : What would happen if Libertarian presidential candidate Gary Johnson got enough protest votes to be elected President?
Last Answer : What would happen? He would be President. He has said he will not get hi while in office if he gets elected. Not at all. He said he feels it’s important to be sober 24/7 while president. I saw him recently and he said he hadn’t smoked pot in 6 weeks. It doesn’t seem to me he was or is a daily toker.
Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4
Last Answer : Answer: D Let the marks secured by them be x and (x + 18) Then sum of their marks = x + (x + 18) = 2x + 18 Given that (x + 18) was 72% of the sum of their marks =>(x+18) = 72/100(2x+18) => ... 11x = 126 x = 11.45 Then (x + 18) = 11.45 + 18 = 29.45 Hence their marks are 11.45 and 29.45
Description : On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40
Last Answer : Answer: E 60% of 500 = 300 80% of 250 = 200 No. of correct answers in remaining 250 questions = 300 – 200 = 100 Percentage = 100 x 100/ 250 = 40%
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980
Last Answer : Answer: C Original value is percentage = 100 %. Reduce amount in percentage = 10 % Therefore, Percent value in percentage = 100 % - 10 % = 90 %. According to the problem, 90 % of original value ... Therefore, 100 % of original value = 1080/100 90 = 1200. Thus, the original value was 1200.
Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5
Last Answer : Answer: D Let the number be m. Decrease = 24 % of m = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594 19m = 594 × 25 19m = 14850 m = 14850/19 m =781.5
Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6
Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %] = 144/168 × 100 = 85.7 %
Description : By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98
Last Answer : Answer: A Let the number be m Increase in its value = 25 % of m = 25/100 × m = m/4 Therefore, increase value = m + m/4 = (4m + m)/4 = 5m/4 Therefore, the given number must be multiplied by 5/4 to increase the number by 25 %.
Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180
Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45 x = (45 × 100)/25 x = (4500)/25 x = 180 Therefore, the total number of matches played is 180.
Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801
Last Answer : Answer: E Number of boys in the college = 60 % of 1335 = 60/100 × 1335 = 80100/100 = 801 Number of girls in the college = Total number of students in the college - Number of boys = 1335 – 801 =534
Description : Listed below are four respiratory capacities (i-iv) and four jumbled respiratory volumes of a normal human adult. Respiratory Respiratory capacities volumes (i) Residual volume 2500 mL (ii) Vital capacity 3500 mL (iii)Inspiratory ... c) (iv) 3500 mL, (i) 1200 mL (d) (i) 4500 mL, (ii) 3500 mL
Last Answer : (c) (iv) 3500 mL, (i) 1200 mL
Description : What is the share of population under 15 in the total population? A. 42.3% B. 41% C. 43.40% D. 45%
Last Answer : ANSWER: C
Description : how much of the total energy requirements are fulfilled by the local oil production? A. 40% B. 45% C. 50% D. 55%
Last Answer : ANSWER: B