What is it that can be more than 100%?

What is it that can be more than 100%?
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I have heard of alcohol being more than 100%. Red necks trust in Trump?
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In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected with 240 more than the candidates got selected in Pondicherry. What was the number of candidates appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800

Description : In a competitive examination in Pondicherry, 18% candidates got selected from the total appeared candidates. Tamilnadu and Pondicherry had an equal number of candidates appeared and in Tamilnadu 21% candidates got selected ... appeared from each State? a) 25000 b) 84000 c) 24000 d) 700000 e) 9800

Last Answer : Answer: C  Pondichery and Tamilnadu had an equal number of candidates appeared  In Pondicherry, 18% candidates got selected from the total appeared candidates  In tamilnadu, 21% candidates ... > total appeared candidates in pondicherry = total appeared candidates in tamilnadu = 24000

A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Description :  A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298

Last Answer : Answer: B  Let x be the maximum marks,  Then (50% of x)+60 = (75% of x)-40  x/2 +60 = 3x/4 -20  60+20 = 3x/4 – x/ 2 X=320  Hence maximum marks = 320  Minimum pass marks = 320/2 + 60 = 220

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

Brother's weight is 25 % more than that of sister. What percent is brother’s weight less than sister's weight? a) 25% b) 60% c) 45% d) 20% e) 98%

Description : Brother's weight is 25 % more than that of sister. What percent is brother’s weight less than sister's weight? a) 25% b) 60% c) 45% d) 20% e) 98% 

Last Answer : Answer: D Let sister's weight be 100 kg. Then brother's weight = (100 + 25) kg = 125 kg If brother's weight is 125 kg, then sister's weight is 100 kg. If brother's weight is 1 kg, then ... then sister's weight = (100/125 100) kg Therefore, sister's weight is 20 % less than that of brother.

In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

Description :  In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989

Last Answer : Answer: B  Total marks in the test = (560 + 160) × 100 /25  = 720 ×100/25  = 72000/25  = 2880  Passing marks for girls =2880 × 60/100  = 1728  Required marks = 1728 – 216  = 1512

What causes the differences in the percentage of the work force in different countries?

Description : What causes the differences in the percentage of the work force in different countries?

Last Answer : I blame demography.

Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?

Description : Idiocy admitted to, disclaimer disclaimed, now how do I figure out what the percentage of one number another number is?

Last Answer : Just divide it.

How to Reduce Your Body Fat Percentage ?

Description : How to Reduce Your Body Fat Percentage ?

Last Answer : How to Reduce Your Body Fat Percentage Losing weight doesn't only mean bringing down the numbers on your bathroom scale. Most of the time, people lose more muscles than fat because of misguided weight loss ... body you want. Lose weight safely. Don't fall into the pit of fast weight loss programs.

In a birthday party, every person shakes hand with every other person. If there was a total of 66 handshakes in the party, how many persons were present in the party? A) 9 B) 8 C) 7 D) 12

Description :  In a birthday party, every person shakes hand with every other person. If there was a total of 66 handshakes in the party, how many persons were present in the party? A) 9 B) 8 C) 7 D) 12

Last Answer : Answer: D)  Assume that in a party every person shakes hand with every other person  Number of hand shake = 66  Total number of hand shake is given by nC2  Let n = the total number of persons ... cannot take negative value of n  So, n = 12  Therefore number of persons in the party = 12

An shopkeeper has 15 models of cup and 9 models of saucer. In how many ways can he make a pair of cup and saucer? A) 100 B) 80 C) 110 D) 135

Description : An shopkeeper has 15 models of cup and 9 models of saucer. In how many ways can he make a pair of cup and saucer? A) 100 B) 80 C) 110 D) 135

Last Answer : Answer: D) He has 15 patterns of cup and 9 model of saucer A cup can be selected in 15 ways. A saucer can be selected in 9 ways. Hence one cup and one saucer can be selected in 15×9 ways =135 ways

A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450

Description : A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450

Last Answer : Answer: A)  Number of ways to choose 10 questions from part A = 12C10  Number of ways to choose 8 questions from part B = 12C8  Total number of ways= 12C10 × 12C8  = 12C2 × 12C4 [∵ nCr = nC(n-r)]  ={12×11}/{2×1}X{12×11×10×9} / {4×3×2×1}  =66×495 =32670

Pramoth has 12 friends and he wants to invite 7 of them to a party. How many times will 4 particular friends never attend the party? A) 8 B) 7 C) 12 D) 15

Description :  Pramoth has 12 friends and he wants to invite 7 of them to a party. How many times will 4 particular friends never attend the party? A) 8 B) 7 C) 12 D) 15 

Last Answer : Answer: A)  Remove the 4 particular friends and invite 7 friends from the remaining 8 (12-4) friends . this can be done in 8C7 ways.  Therefore , required number of ways = = 8C7  = 8C1  = 8

If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241

Description :  If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241

Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175

The population of a town is 16200. It decreases annually at the rate of 40% p.a. What was its population 3 years ago? a) 75000 b) 65000 c) 84900 d) 93600

Description : The population of a town is 16200. It decreases annually at the rate of 40% p.a. What was its population 3 years ago? a) 75000 b) 65000 c) 84900 d) 93600

Last Answer : Answer: A  (Ago = 100 numerator)  Ago 3 years = 16200×(100/60×100/60×100/60)  = 75000

The population of a town is 15000. It increases annually at the rate of 20% p.a. What will be its population after 3 years? a) 65439 b) 25920 c) 37193 d) 41093

Description : The population of a town is 15000. It increases annually at the rate of 20% p.a. What will be its population after 3 years? a) 65439 b) 25920 c) 37193 d) 41093

Last Answer : Answer: B Formula :  ( After =100 denominator )  (Ago = 100 numerator)  After 3 years = 15000×(1+20/100)^3  = 15000 ×(120/100)^3  = 15000 ×(1.2)^3  = 15000 ×(1.728)  = 25920

A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3

Description : A shopkeeper bought 1800 blackberry and 1200 blueberry. He found 45% of blackberry and 24% of blueberry were rotten. Find the percentage of fruits in good condition. a) 63.4 b) 32.9 c) 48.5 d) 56.3

Last Answer :  Answer: A Total number of fruits shopkeeper bought = 1800 + 1200 = 1000 Number of rotten blackberry = 45% of 1800  = 45/100 1800  = 81000/100  = 810 Number of rotten blueberry = 24% of 1200 ... Therefore Percentage of fruits in good condition = (1902/3000 100)  = (190200/3000)  = 63.4%

The difference between 45% of a number and 37% of the same number is 896. What is 25% of that number ? a) 1200 b) 2800 c) 2569 d) 3467

Description : The difference between 45% of a number and 37% of the same number is 896. What is 25% of that number ? a) 1200 b) 2800 c) 2569 d) 3467

Last Answer :  Answer: B (45 – 37)% of the number = 896  8 % of the number = 896  Number =896 x100 /8  = 89600/8  = 11200  25% of 11200 = 11200 x 25/100  = 280000 / 100  = 2800

If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534

Description : If the production of a factory grows at a 16% p.a., what will be its production for the year 2016 if its production in 2014 was 140 lakh tonnes? a) 222.734 b) 149.597 c) 188.384 d) 28 3.812 e) 180.534

Last Answer : Answer: C Required Production=140(1 + 16/100)2 lakh tones  =140(1 + 4/25)2  =140((25 + 4) /25)²  =140(29/25)²  =140(1.16)²  =140×1.3456  =188.384 lakh tonnes

The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272

Description : The population of a town is 378000. It decreases by 16% in the 1st year and increases by 10% in the 2nd year. What is the population in the town at the end of 2 years? a) 182574 b) 482576 c) 282674 d) 283574 e) 349272

Last Answer : Answer: E After 2 years required population is  = 378000 (1-16/100) (1+10/100)  = 378000 (84/100) (110/100)  = 378000 (0.84) (1.1)  = 3,49,272

The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000  = (104/100) × (106/100) × (110/100) × 200000  = 1.04×1.06×1.1×200000  = 2,42,528

The value of a machine depreciates at the rate of 20% every year. It was purchased 6 years ago. If its present value is Rs. 17,496, its purchase price was : a) 25023.4 b) 67040.0 c) 34171.8 d) 27337.5

Description : The value of a machine depreciates at the rate of 20% every year. It was purchased 6 years ago. If its present value is Rs. 17,496, its purchase price was : a) 25023.4 b) 67040.0 c) 34171.8 d) 27337.5

Last Answer : Answer: C  Purchase price = 17,496 / (1 -20/ 100)³  = 17,496 × 10/8 × 10/8 ×10/8  = 17496 × 1.25 × 1.25 ×1.25  = 17496 ×1.953  = 34171.8

In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814

Description :  In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814

Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320  = 75/100 *5320 = 399000/100  = 3990

In an election between two candidates, the winner secured 85% of the total votes cast and wins by a majority of 6300 votes. How many votes did the losing candidate get? a) 1350 b) 2479 c) 3467 d) 5789

Description : In an election between two candidates, the winner secured 85% of the total votes cast and wins by a majority of 6300 votes. How many votes did the losing candidate get? a) 1350 b) 2479 c) 3467 d) 5789

Last Answer : Answer: A  Total votes cast = 100%  Winner gets = 85%  Loser gets = 100 – 85 = 15%  Majority = Votes secured by winner – Votes secured by loser  = 85% - 15%  =70% =6300  Votes by the losing candidate = x = 15%  x = (15 * 6300)/70 x =(94500/70) x = 1350

In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93

Description : In an election three candidates received 2272 , 15272, and 23256 votes respectively. What percentage of the total votes did the winning candidate got? a) 25 b) 41 c) 75 d) 57 e) 93

Last Answer : Answer: D Total number of votes polled = (2272+15272+23256)  =40800 Required percentage = 23256/40800 ×100  = 2325600/40800  = 57

In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800

Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800

Last Answer : Answer: D Total number of invalid votes = 55 % of 280000  = 55/100 280000  = 15400000/100  = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000  = 40/100 126000  = 5040000/100  = 50400

In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800

Description : In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800 

Last Answer : Answer: D Total number of votes = 15000 Given that 40% of Percentage votes were invalid => Valid votes = 60% Total valid votes = 15000* 60/100 1st candidate got 45% of the total valid votes. Hence ... votes that 2nd candidate got = total valid votes x 55/100  =15000*60/100*55/100  =4950

A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98

Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98 

Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100  = (40/100 100)  = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100)  = (4900/100)  = 49 %

A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980

Description : A number is reduced by 10%. Its present value is 1080. What was its original value? a) 3250 b) 2600 c) 1200 d) 2300 e) 1980

Last Answer : Answer: C Original value is percentage = 100 %. Reduce amount in percentage = 10 % Therefore, Percent value in percentage = 100 % - 10 % = 90 %. According to the problem, 90 % of original value ... Therefore, 100 % of original value = 1080/100 90 = 1200. Thus, the original value was 1200.

Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5

Description : Find the number which when decreased by 24 % becomes 594. a) 625.8 b) 360.9 c) 465.7 d) 781.5 e) 398.5

Last Answer : Answer: D Let the number be m. Decrease = 24 % of m  = 24/100 × m = 6m /25 Therefore, decrease number = m – 6m/25 = (25m – 6m)/25 = 19m/25 According to the question 19m/25 = 594  19m = 594 × 25  19m = 14850  m = 14850/19  m =781.5

A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

Description : A number 168 was misread as 24. Find the reading error in per cent. a) 25.7 b) 42.8 c) 42.6 d) 85.7 e) 98.6

Last Answer : Answer: D Error = 168 – 24 = 144 Therefore, % error = 144/168 [Since, we know decrease% = decrease in value/original value × 100 %]  = 144/168 × 100  = 85.7 %

A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9

Description : A wooden manufacturing company declares that a wooden is now available for $11200 as against $25200 one year before. Find the percentage reduction in the price of wooden offered by the company. a) 25 1/3 b) 691/3 c) 66 1/3 d) 33 1/3 e) 55 5/9

Last Answer : Answer: E Price of the wooden a year before = $25200 Price of the wooden after a year = $11200 Decrease in price = $(25200 - 11200) = $14000 Therefore, decrease % = 14000/25200 × 100 %  = 55 5/9 %

The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98

Last Answer : Answer: E  Original cost = $140  Decrease in it = 30% of $140  = 30/100 × 140  = 4200/100  = $42  Therefore, decrease cost = $140 - $42 = $98

By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98

Description : By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98 

Last Answer : Answer: A Let the number be m Increase in its value = 25 % of m  = 25/100 × m = m/4 Therefore, increase value = m + m/4  = (4m + m)/4  = 5m/4 Therefore, the given number must be multiplied by 5/4 to increase the number by 25 %.

Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855

Description : Find the increase value if 450 is increased by 90 %. a) 525 b) 715 c) 645 d) 795 e) 855

Last Answer : Answer: E  Increase = 90 % of 450  = 90/100 × 450  = 40500/100  = 405 Therefore, increase value = 450 + 405 = 855

The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8

Description : The population in a small town increases from 50000 to 63750 in one year. Find the percentage increase in population. a) 25 b) 62 c) 6.25 d) 27.5 e) 59.8 

Last Answer : Answer: D Population in a small town last year = 50000 Population in a small town after one year = 63750 Increase in population = 63750 - 50000 = 13750 Therefore,  percentage increase in population = ... /50000 100  = 1375000/50000  = 27.5% Thus, the increase in population is 27.5%

The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98

Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98 

Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price  = $37.5 - $ 30  = $ 7.5 Therefore, percentage increase in price = Increase in price/ ...  = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %

In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Description : In an examination it is required to get 672 aggregate marks to pass. A student gets 70% marks and is declared failed by 126 marks. What are the maximum aggregate marks a student can get? a) 780 b) 840 c) 741 d) 805 e) 983

Last Answer : Answer: A Difference = 672-126 = 546 According to the question, 70% of total aggregate = 546 Total aggregate marks = 546 × 100 /70  = 54600/70  = 780

On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40

Description : On a test consisting of 500 questions, Dhivya answered 80% of the first 250 questions correctly. What percent of the other 250 questions does she need to answer correctly for her grade on the entire exam to be 60% ? a) 20 b) 60 c) 45 d) 80 e) 40

Last Answer : Answer: E  60% of 500 = 300  80% of 250 = 200 No. of correct answers in remaining 250 questions = 300 – 200  = 100  Percentage = 100 x 100/ 250  = 40%

In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298

Description : In an examination, 900 students appeared. Out of these students; 56 % got first division, 27 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed. a) 225 b) 153 c) 245 d) 148 e) 298

Last Answer : Answer: B The number of students with first division = 56 % of 900  = 56/100 × 900 = 50400/100  = 504 And, the number of students with second division = 27 % of 900  = 27/100 × 900  =24300/100  = 243 Therefore, the number of students who just passed = 900 – (504 + 243)  = 900- 747  = 153

In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298

Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298

Last Answer : Answer: D  Let the maximum marks be x.  Aashika’s marks = 32% of x  Aashika secured 1328 marks  Therefore, 32% of x = 1328  ⇒ 32/100 × x = 1328  x = (1328 × 100)/32  x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.

Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989

Description : Gowthaman needs 25% to pass. If he scored 424 marks and falls short by 26 marks, what was the maximum marks he could have got? a) 2725 b) 2650 c) 1800 d) 1750 e) 989 

Last Answer : Answer: C  If Gowthaman had scored 26 marks more, he could have scored 25%  Therefore, Mike required 424 + 26 = 450 marks  Let the maximum marks be x.  Then 25 % of x = 450  (25/100) × x = 450  x = (450 × 100)/25 x = 45000/25 x = 1800

Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800

Description : Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800 

Last Answer : Answer: A  Percentage savings of Supriya = 100 – (35 + 45)  = 20%  Let her monthly income be x  x X 20 /100 = 25750  x = 25750 × 100/20  x = 128750

Vasavi spends 50% of her monthly income on grocery, clothes and education in the ratio of 8 : 4 : 10 respectively. If the amount spent on clothes is 2770/–, what is Vasavi's monthly income? a) 15235 b) 65000 c) 55400 d) 30470 e) 98700

Description : Vasavi spends 50% of her monthly income on grocery, clothes and education in the ratio of 8 : 4 : 10 respectively. If the amount spent on clothes is 2770/–, what is Vasavi's monthly income? a) 15235 b) 65000 c) 55400 d) 30470 e) 98700

Last Answer : Answer: D Ratio of Expenses = 8: 4: 10 therefore amount spend on clothes, i.e. 4x = 2770  x = 692.5  Total exp = (8 + 4 + 10)x  = 22x. = 22 × 692.5 = 15235  Monthly income be x.  50% of x = 15235  x = 15235 × 100/ 50  X = 30470 

Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18

Description : Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18

Last Answer : Answer: A  Let a family's monthly consumption of chenna dhal be x kg.  To keep the expenditure fixed,  their consumption for this month should be 70x/80 = 7x/8.  Reduction in consumption = x/8 = 12.5% of x

From the salary of pooja , 40% is deducted as house rent, 20% of rest she spends on children's education and 40% of balance she spends on watching movies. If her savings are Rs.5760/- then hers total salary is: a) 20000 b) 30060 c) 45000 d) 47000 e) 98000

Description : From the salary of pooja , 40% is deducted as house rent, 20% of rest she spends on children's education and 40% of balance she spends on watching movies. If her savings are Rs.5760/- then hers total salary is: a) 20000 b) 30060 c) 45000 d) 47000 e) 98000 

Last Answer : Answer: A Formula: First value = last value×100/(100-p1)×100/(100-p2)× 100/(100-p3) (p=percentage) First value = 5760×100/(100 – 40)×100/(100 – 20)×100/(100 - 40 )  = 5760 × 100/60× 100/80× 100/60  = 5760 × 5/3 × 5/4 × 5/3  = 5760 ×125/36  = 720000/36  = 20000

The Shopkeeper increased the price of a product by 75% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 140% of the required amount. What is the net difference in the expenditure on that product? a) 12.5 b) 26.0 c) 13.5 d) 17.5 e) 19.8

Description : The Shopkeeper increased the price of a product by 75% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 140% of the required amount. What is the net difference in the ... on that product? a) 12.5 b) 26.0 c) 13.5 d) 17.5 e) 19.8

Last Answer : Answer: D  Quantity×Rate=Price  1x1=1  1.4x1.75=2.45  Decrease in price = (0.175/1) × 100  = 17.5%

Forty percent of Mouli’s annual salary is equal to 160% of Surya’s annual salary. Surya’s monthly salary is 80%of Gowthaman’s monthly salary. If Gowthaman’s annual salary is ` 12 lacs, what is Mouli’s monthly salary ? (At some places annual income and in some place monthly income is given.) a) 180000 b) 1200000 c) 320000 d) 250000

Description : Forty percent of Mouli's annual salary is equal to 160% of Surya's annual salary. Surya's monthly salary is 80%of Gowthaman's monthly salary. If Gowthaman's annual salary is ` 12 lacs, what is Mouli's ... income and in some place monthly income is given.) a) 180000 b) 1200000 c) 320000 d) 250000

Last Answer : Answer: C Gowthaman’s monthly salary = 12,00,000/12  = 1,00,000 Surya’s monthly salary = 1,00,000 x 80/100 = 80,000 Mouli’s monthly salary = 80,000x 1600/40  =3,20,000

From the salary of shreya, 15% is deducted as house rent, 15% she spends on children’s education and 20% on watching movies. If her savings are Rs.8450/- then her total salary is: a) 13500 b) 2360 c) 16900 d) 11520 e) 23198

Description : From the salary of shreya, 15% is deducted as house rent, 15% she spends on children’s education and 20% on watching movies. If her savings are Rs.8450/- then her total salary is: a) 13500 b) 2360 c) 16900 d) 11520 e) 23198 

Last Answer : Answer: C She spends = 50% remaining 50% = 8450  Total salary = 8450 × 100 / 50  = 845000 / 50  = 16900

Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1

Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1

Last Answer : Answer: E  Total cost of the items he purchased = Rs.75  Given that out of this Rs.75, 90 Paise is given as tax  => Total tax incurred = 90 Paise  = Rs.90/100  Let the cost of the tax free items = x  Given that tax rate = ... −0.9 −x) = 90  ⇒ (75 − 0.9 − x) = 5  x = 75 − 0.9 - 5  X=69.1 

Two employees X and Y are paid a total of Rs. 4950 per week by their employer. If X is paid 150 percent of the sum paid to Y, how much is Y paid per week? a) 1250 b) 3760 c) 2405 d) 1540 e) 1980

Description : Two employees X and Y are paid a total of Rs. 4950 per week by their employer. If X is paid 150 percent of the sum paid to Y, how much is Y paid per week? a) 1250 b) 3760 c) 2405 d) 1540 e) 1980

Last Answer : Answer: E Let the amount paid to X per week = x and the amount paid to Y per week = y  Then x + y = 4950  But x = 150% of y  = 150y/100 = 15y/10  ∴15y/10 + y = 4950  ⇒ y[15/10 + 1] = 4950  ⇒ 25y/10 = 4950  ⇒ 25y = 49500  ⇒ y = 49500/25  y = Rs.1980