Description : On an IQ test consisting of 250 questions, Jasvinder answered 40% of the first 125 questions correctly. What per cent of the other 125 questions does he need to answer correctly for his grade on the entire exam to be 60%? (a) 75% (b) 80% (c) 60% (d) Cannot be determined (e) None of these
Last Answer : (b) 80%
Description : In a plot of 18000 sq. m., only 13500 sq. m. is allowed for construction. What percent of the plot is to be left without construction? a) 25 b) 60 c) 45 d) 40 e) 98
Last Answer : Answer: A Percentage of plot allowed for construction = (13500/18000 × 100) = 75 %. Thus, the percentage of plot to be left without construction = 100 % - 75 % = 25 %.
Description : A mixture of 60 kg of rice and dhal contains 60% of dhal. The new mixture is formed by adding 15 kg of dhal. What is the percentage of rice in the new mixture? a) 25 b) 64 c) 45 d) 32 e) 98
Last Answer : Answer: D 60 kg = 36 kg dhal 24 kg rice -------- 15 kg dhal Total = 15 kg dhal 24 kg rice (new) 24/75×100=32%
Description : What percent of a day in 12 hours? a) 25 b) 60 c) 45 d) 20 e) 50
Last Answer : Answer: E Total hours in a day = 24 Required percent = 12/24 ×100 = 50%
Description : In a test, minimum passing percentage for girls and boys is 60% and 25% respectively. A boy scored 560 marks and failed by 160 marks. How many more marks did a girl require to pass in the test if she scored 216 marks ? a) 2123 b) 1512 c) 2251 d) 1325 e) 3989
Last Answer : Answer: B Total marks in the test = (560 + 160) × 100 /25 = 720 ×100/25 = 72000/25 = 2880 Passing marks for girls =2880 × 60/100 = 1728 Required marks = 1728 – 216 = 1512
Description : Brother's weight is 25 % more than that of sister. What percent is brother’s weight less than sister's weight? a) 25% b) 60% c) 45% d) 20% e) 98%
Last Answer : Answer: D Let sister's weight be 100 kg. Then brother's weight = (100 + 25) kg = 125 kg If brother's weight is 125 kg, then sister's weight is 100 kg. If brother's weight is 1 kg, then ... then sister's weight = (100/125 100) kg Therefore, sister's weight is 20 % less than that of brother.
Description : In an exam Aashika secured 1328 marks. If she secured 32 % marks, find the maximum marks. a) 2250 b) 3600 c) 4400 d) 4150 e) 1298
Last Answer : Answer: D Let the maximum marks be x. Aashika’s marks = 32% of x Aashika secured 1328 marks Therefore, 32% of x = 1328 ⇒ 32/100 × x = 1328 x = (1328 × 100)/32 x =132800/32 x = 4150 Therefore, Aashika got 1328 marks out of 4150 marks.
Description : In trickling filter, B.O.D. is reduced to A. 30 to 40% B. 40 to 60% C. 60 to 80% D. 80 to 90%
Last Answer : ANS: C
Description : In final exam of class IX there are 130 students 20 % students failed. How many students passed to class X? a) 105 b) 112 c) 104 d) 117 e) 104.5
Last Answer : Answer: C) Percentage of students passed to class X = (100 % - 20 %) of 130 = 80 % of 130 =>80 % of 130 => 80/100 × 130 =>10400/100 => 104 Therefore, 104 students passed to class X
Description : Chenna dhal is now being sold at Rs. 70 a kg. Last month, is rate was Rs. 80 per kg. By how much percent should a family reduce its consumption so as to keep the expenditure fixed? a)12.5 b)21.8 c)23 d)18
Last Answer : Answer: A Let a family's monthly consumption of chenna dhal be x kg. To keep the expenditure fixed, their consumption for this month should be 70x/80 = 7x/8. Reduction in consumption = x/8 = 12.5% of x
Description : The price of dhal is increased from $ 30 to $ 37.5 per kg. Find the percentage increase in price. a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: A Price of dhal before = $30 Price of dhal now = $ 37.5 Increase in dhal = current price - original price = $37.5 - $ 30 = $ 7.5 Therefore, percentage increase in price = Increase in price/ ... = 7.5 / 30 100 = 750/100 = 25 % Thus, increase in price= 25 %
Description : A mixture of 90 kg of rava and sugar contains 90% of sugar. The new mixture is formed by adding 30 kg of sugar. What is the percentage of sugar in the new mixture? a) 45 1/2 b) 60 1/5 c) 45 1/2 d) 92 1/2 e) 98 1/2
Last Answer : Answer: D 90 kg = 81 kg sugar 9 kg rava Adding = 30 kg sugar Total = 111kg sugar 9kg rava (new) 111/120 × 100 = 92.5 =92 1 /2
Description : Gugan obtained a total of 1313 marks out of 1400 in an examination. What is his approximate percentage in the examination? a) 25 b) 60 c) 45 d) None e) 98
Last Answer : Answer: D Required percentage = 1313/ 1400 × 100 =131300/1400 =93.7
Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41
Last Answer : Answer: A (i) Percentage scored in Mathematics = 120/180 100 = 12000/180 =1200/18 = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100) = (40000/510) = 4000/51 = 78 22/51 %
Description : A candidate scoring 50% in an examination fails by 60 marks , while another candidate scores 75 % mark, gets 40 marks more than the minimum pass marks . Find the minimum pass mark. a) 125 b) 220 c) 140 d) 260 e) 298
Last Answer : Answer: B Let x be the maximum marks, Then (50% of x)+60 = (75% of x)-40 x/2 +60 = 3x/4 -20 60+20 = 3x/4 – x/ 2 X=320 Hence maximum marks = 320 Minimum pass marks = 320/2 + 60 = 220
Description : In a basket of eggs, 20% of them are rotten and 68 are in good condition. Find the total number of eggs in the basket. a) 85 b) 60 c) 75 d) 40 e) 98
Last Answer : Answer: A Let the total number of eggs in the basket be x 20 % of the eggs are rotten, and eggs in good condition are 68 Therefore, according to the question, 80% of x = 68 80/100 × x = 68 x = (68 × 100)/80 x = 6800 / 80 x = 85 Therefore, total number of eggs in the basket is 85.
Description : Supriya invests 35% of her monthly salary in insurance policies. She spends 45% of her monthly salary in shopping and on household expenses. She saves the remaining amount of `25,750. What is Supriya's monthly income? a) 128750 b) 160050 c) 205200 d) 263400 e) 391800
Last Answer : Answer: A Percentage savings of Supriya = 100 – (35 + 45) = 20% Let her monthly income be x x X 20 /100 = 25750 x = 25750 × 100/20 x = 128750
Description : From the salary of pooja , 40% is deducted as house rent, 20% of rest she spends on children's education and 40% of balance she spends on watching movies. If her savings are Rs.5760/- then hers total salary is: a) 20000 b) 30060 c) 45000 d) 47000 e) 98000
Last Answer : Answer: A Formula: First value = last value×100/(100-p1)×100/(100-p2)× 100/(100-p3) (p=percentage) First value = 5760×100/(100 – 40)×100/(100 – 20)×100/(100 - 40 ) = 5760 × 100/60× 100/80× 100/60 = 5760 × 5/3 × 5/4 × 5/3 = 5760 ×125/36 = 720000/36 = 20000
Description : From the salary of shreya, 15% is deducted as house rent, 15% she spends on children’s education and 20% on watching movies. If her savings are Rs.8450/- then her total salary is: a) 13500 b) 2360 c) 16900 d) 11520 e) 23198
Last Answer : Answer: C She spends = 50% remaining 50% = 8450 Total salary = 8450 × 100 / 50 = 845000 / 50 = 16900
Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4
Last Answer : Answer: D Let the marks secured by them be x and (x + 18) Then sum of their marks = x + (x + 18) = 2x + 18 Given that (x + 18) was 72% of the sum of their marks =>(x+18) = 72/100(2x+18) => ... 11x = 126 x = 11.45 Then (x + 18) = 11.45 + 18 = 29.45 Hence their marks are 11.45 and 29.45
Description : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Last Answer : What is the percentage error when 3 resistors with ratings 100 Ω at 5%, 150 Ω at 6% and 250 Ω at 8% respectively, are connected in series? A) 6.33% B) 6.80% C) 19% D) None of these
Description : Seed germination percentage of rough lemon is: a. 50-60% b. 60-70% c. 70-80% d. 80-90%
Last Answer : 60-70%
Description : The sum of the percentage of tricalcium silicate and dicalcium silicate for Portland cement varies from. (a) 50 to 60% (b) 60 to 70% (c) 70 to 80% (d) 80 to 90%
Last Answer : (c) 70 to 80%
Description : n a chemical factory where dyes are made, wet cake at 30 OC consisting of 60% moisture is put in a dryer to obtain an output having only 5% moisture, at atmospheric pressure. In each batch about 120 ... dryer and the dryer efficiency is 80%. Latent heat of steam at 4 kg/cm2 is 520 kcal/kg.
Last Answer : Given that Qty of material dried per batch - 120 Kgs Moisture at inlet - 60% a. The quantity of moisture removed per batch. Water quantity in a wet batch - 120 x 0.6 = 72 Kgs. Quantity of bone dry ... - 48/0.95 = 50.5 Kgs. Equivalent water in a dry batch - 50.5 - 48 = 2.5 Kgs.
Description : Iron content in Indian iron ore is about __________ percent. (A) 80-85 (B) 60-65 (C) 40-45 (D) 20-25
Last Answer : (B) 60-65
Description : Mithun went to a shop and bought things worth Rs. 75, out of which 90 Paise went on sales tax on taxable purchases. If the tax rate was 18%, then what was the cost of the tax free items? a) 12.5 b) 69.80 c) 19.7 d) 34.5 e) 69.1
Last Answer : Answer: E Total cost of the items he purchased = Rs.75 Given that out of this Rs.75, 90 Paise is given as tax => Total tax incurred = 90 Paise = Rs.90/100 Let the cost of the tax free items = x Given that tax rate = ... −0.9 −x) = 90 ⇒ (75 − 0.9 − x) = 5 x = 75 − 0.9 - 5 X=69.1
Description : A number is increased by 70 % and then decreased by 70 %. Find the net increase or decrease per cent. a) 25 b) 56 c) 45 c) 49 e) 98
Last Answer : Answer: D Let the number be 100. Increase in the number = 70 % = 40 % of 100 = (40/100 100) = 70 Therefore, increased number = 100 + 70 = 170 This number is decreased by 70 % Therefore, decrease ... = 100 - 51 = 49 Hence, net percentage decrease = (49/100 100) = (4900/100) = 49 %
Description : The cost of a stencil is decreased by 30%. If the original cost is $140, find the decrease cost. a) 25 b) 68 c) 45 d) None e) 98
Last Answer : Answer: E Original cost = $140 Decrease in it = 30% of $140 = 30/100 × 140 = 4200/100 = $42 Therefore, decrease cost = $140 - $42 = $98
Description : A foot ball team lost 75 % of the matches it played. If it won 45 matches, find the number of matches it played. a) 120 b) 145 c) 105 d) 140 e) 180
Last Answer : Answer: E Percentage of matches lost = 75 % Therefore Percentage of matches won (100 - 75) % = 25 % Let the number of matches played be x. Then 25 % of x = 45 25/100 × x =45 x = (45 × 100)/25 x = (4500)/25 x = 180 Therefore, the total number of matches played is 180.
Description : Two employees X and Y are paid a total of Rs. 4950 per week by their employer. If X is paid 150 percent of the sum paid to Y, how much is Y paid per week? a) 1250 b) 3760 c) 2405 d) 1540 e) 1980
Last Answer : Answer: E Let the amount paid to X per week = x and the amount paid to Y per week = y Then x + y = 4950 But x = 150% of y = 150y/100 = 15y/10 ∴15y/10 + y = 4950 ⇒ y[15/10 + 1] = 4950 ⇒ 25y/10 = 4950 ⇒ 25y = 49500 ⇒ y = 49500/25 y = Rs.1980
Description : Dhivya, Dinesh and Deepi enter into a partnership and their shares are in the ratio 1/3 :1/4 :1/5. After 2 months, dhivya withdraws half of her capital and after 10 months, a profit of Rs. 462 is divided among them, what is Deepi’s share? A) 123.56 B) 165.45 C) 143.3 D) 146.43
Last Answer : Answer: C) Ratio of initial investments = 1/3 : 1/4 : 1/5 = 20 :15 :12 Let their initial investments be 20x, 15x and 12x respectively Dhivya: Dinesh :Deepi = (20x *2 +10x *10) : (15x *12) : (12x*12) =140x : ... 70:90:72 = 35 : 45 :36 Deepi s share = Rs.462 * 36/116 = Rs(16632/116) =Rs.143.3
Description : An shopkeeper has 15 models of cup and 9 models of saucer. In how many ways can he make a pair of cup and saucer? A) 100 B) 80 C) 110 D) 135
Last Answer : Answer: D) He has 15 patterns of cup and 9 model of saucer A cup can be selected in 15 ways. A saucer can be selected in 9 ways. Hence one cup and one saucer can be selected in 15×9 ways =135 ways
Description : An intense rain is falling at a uniform rate of 7.5 cm/hour for a period of 60 minutes on a basin whose area is 500 hectares. If the average infiltration capacity during the entire rain period is assumed to be 1.5 ... of the basin, is (A) 40 cumecs (B) 60 cumecs (C) 80 cumecs (D) 100 cumecs
Last Answer : Answer: Option C
Description : If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241
Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175
Description : Forty percent of Mouli's annual salary is equal to 160% of Surya's annual salary. Surya's monthly salary is 80%of Gowthaman's monthly salary. If Gowthaman's annual salary is ` 12 lacs, what is Mouli's ... income and in some place monthly income is given.) a) 180000 b) 1200000 c) 320000 d) 250000
Last Answer : Answer: C Gowthaman’s monthly salary = 12,00,000/12 = 1,00,000 Surya’s monthly salary = 1,00,000 x 80/100 = 80,000 Mouli’s monthly salary = 80,000x 1600/40 =3,20,000
Description : By what number must the given number be multiplied to increase the number by 25 %. a) 25 b) 60 c) 50 d) None e) 98
Last Answer : Answer: A Let the number be m Increase in its value = 25 % of m = 25/100 × m = m/4 Therefore, increase value = m + m/4 = (4m + m)/4 = 5m/4 Therefore, the given number must be multiplied by 5/4 to increase the number by 25 %.
Description : In a college of 1335 students, 60 % are boys. Find the number of girls and number of boys in the college? a) 924,221 b) 691,404 c) 802,333 d) 441,564 e) 534,801
Last Answer : Answer: E Number of boys in the college = 60 % of 1335 = 60/100 × 1335 = 80100/100 = 801 Number of girls in the college = Total number of students in the college - Number of boys = 1335 – 801 =534
Description : mouli had $ 3600 left after spending 40 % of the money he took for shopping. How much money did he take along with him? a) 2500 b) 6000 c) 4500 d) 3000 e) 9800
Last Answer : Answer: B Let the money he took for shopping be x. Money he spent = 40 % of x = 40/100 x = 4/10 x Money left with him = x - 4/10 x = (10x - 4x)/10 = 6x/10 But money left with ... 6x/10 = 3600 x = 3600 10/6 x = 36000/6 x = 6000 Therefore, the money he took for shopping is 6000.
Description : to manganese besides other minor elements. a) 0.10 to 0.50% b) 0.20 to 0.60% c) 0.40 to 0.80% d) 0.50 to 0.80%
Last Answer : 0.50 to 0.80%
Description : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be ______. (A) 20% (B) 40% (C) 50% (D) 30%
Last Answer : True value has been 50 whereas measured value is 40 then the percentage error in the reading will be 20%.
Description : A question paper has two parts A and B, each containing 12 questions. If a student needs to choose 10 from part A and 8 from part B, in how many ways can he do that? A) 32670 B) 36020 C) 41200 D) 29450
Last Answer : Answer: A) Number of ways to choose 10 questions from part A = 12C10 Number of ways to choose 8 questions from part B = 12C8 Total number of ways= 12C10 × 12C8 = 12C2 × 12C4 [∵ nCr = nC(n-r)] ={12×11}/{2×1}X{12×11×10×9} / {4×3×2×1} =66×495 =32670
Description : Vasavi spends 50% of her monthly income on grocery, clothes and education in the ratio of 8 : 4 : 10 respectively. If the amount spent on clothes is 2770/–, what is Vasavi's monthly income? a) 15235 b) 65000 c) 55400 d) 30470 e) 98700
Last Answer : Answer: D Ratio of Expenses = 8: 4: 10 therefore amount spend on clothes, i.e. 4x = 2770 x = 692.5 Total exp = (8 + 4 + 10)x = 22x. = 22 × 692.5 = 15235 Monthly income be x. 50% of x = 15235 x = 15235 × 100/ 50 X = 30470
Description : Nandhini scored 996 marks out of 1200 marks and her elder brother kaviyarasan scored 1020 marks out of 1500 marks. Find the scored percentage which is better? a) 68% b) 83% c) 65% d) 85% e) 97%
Last Answer : Answer: A Percentage of marks scored by nandhini = (994/1200 × 100) = (99400/1200) = (994/12) = 83 % Percentage of marks scored by kaviyarasan = (1020/1500 × 100) = (102000/1500) = (1020/15) = 68 % Hence, the percentage marks scored by nandhini is better.
Description : Higher plant efficiency up to______ over the entire load range. a. 30%-50% b. 20%-40% c. 60%-90% d. 50%-80%
Last Answer : a. 30%-50%
Description : Paper grade bamboo contains about __________ percent cellulose. (A) 5 (B) 20 (C) 40 (D) 60
Last Answer : (A) 5
Description : A perfect product (with 100% awareness) starting with a survey score of 100, why is it that at 60% accessibility rating, 80% of customers have access to a product such that survey score declines from ... acquire the product. c. Because accessibility rating is not reliable. d. All of the above.
Last Answer : b. Of the 40% of customers without accessibility, 20% of them would make an extra effort to acquire the product.
Description : Q.61. CA Co manufactures a single product and has drawn up the following flexed budget for the year. 60% 70% 80% Rs Rs Rs Direct materials 120,000 140,000 160,000 Direct labour 90,000 105,000 120,000 Production ... activity? (a) Rs 330,300 (b) Rs 370,300 (c) Rs 373,300 (d) Rs 377,300
Last Answer : (b) Rs 370,300
Description : If the degree of saturation of a partially saturated soil is 60%, then air content of the soil is (A) 40 % (B) 60 % (C) 80 % (D) 100 %
Last Answer : (A) 40 %
Description : The product of 60% of a number and 125% of another number is what percent of the product of the original numbers? 1 : 90% 2 : 75% 3 : 80% 4 : 100% 5 : None of these
Last Answer : 2 : 75%
Description : In a college election between two candidates, one candidate got 25% of the total valid votes. 30% of the votes were invalid. If the total votes were 7600, what is the number of valid votes the other candidate got ? a) 2576 b) 2314 c) 5184 d) 3990 e) 9814
Last Answer : Answer: D Total valid votes = 70% of 7600 = 5320 Number of valid votes to other candidate = 75% of 5320 = 75/100 *5320 = 399000/100 = 3990