From a cask of milk containing 45 litres, 9 litres are drawn out and the cask is filled up with water.If the same process is repeated a second, then a third time, what will be the number of litres of milk left in the cask? a) 31.2 b) 20.9 c) 23.04 d) 12.39 e) 15.36

 From a cask of milk containing 45 litres, 9 litres are drawn out and the cask is filled up with water.If the same process is repeated a second, then a third time, what will be the number of litres of milk left in the cask? a) 31.2 b) 20.9 c) 23.04 d) 12.39 e) 15.36
by

1 Answer

Answer :

C

where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is the

number of processes.

Initial quantity:45

Withdrawn quantity=9

number of times repeated=3

Hence from the above rule it can be say that,

Formula,=[a(1-b/a)n

]

Quantity of milk left after the 3rd operation =45*(45-9)/45)^3

= 23.04 litres.
by

Related questions

A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially? a) 12 b) 21 c) 93 d)17 e) None

Description : A container contains a mixture of two liquids P and Q in the ratio 7 : 5. When 9 litres of mixture are drawn off and the container is filled with Q, the ratio of P and Q becomes 7 : 9. How many litres of liquid P was contained in the container initially? a) 12 b) 21 c) 93 d)17 e) None 

Last Answer : B Let initial quantity of P in the container be 7x and initial quantity of Q in the container be 5x Now 9 litres of mixture is drawn off from the container. Quantity of P in 9 litres of the mixture drawn off ... = 7 : 9 x=16* 21/4*28 Litres of P contained in the container initially =7x = 21

A container contains 55 litres of milk. From this container 5.5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? a) 32 b) 29.16 c) 43 d) 27.12 e) 40.09

Description : A container contains 55 litres of milk. From this container 5.5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container? a) 32 b) 29.16 c) 43 d) 27.12 e) 40.09 

Last Answer : E  Where x is the initial quantity of milk in the cask y is the quantity of milk withdrawn in each process and n is the number of processes. Initial quantity:55 Withdrawn quantity=5.5 number of times repeated ... of milk left after the 3rd operation =55*((55-5.5)/55) ^3  =40.09litres.

How many litres of a 36 litre mixture containing milk and water in the ratio of 4 : 6 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion? a) 3 b) 2 c) 4 d) 7 e) 6

Description : How many litres of a 36 litre mixture containing milk and water in the ratio of 4 : 6 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion? a) 3 b) 2 c) 4 d) 7 e) 6 

Last Answer :  E  The mixture contains 40% milk and 60% water in it.  That is 14.4 litres of milk and 21.6 litres of water.  Now we are replacing the mixture with pure milk so that the amount of milk and water in the ... containing 60% water,  we need to remove ={3.6}/{0.6} litres of the mixture  = 6 litres

A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5? a) 2 b) 3 c) 4 d) 7 e) 6

Description : A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5? a) 2 b) 3 c) 4 d) 7 e) 6 

Last Answer : E Let cost of 1 litre milk be Rs.1 Milk in 1 litre mix in 1st can =3/4 litre Cost Price(CP) of 1 litre mix in 1st can = Rs. 3/4 Milk in 1 litre mix in 2nd can 1/2 litre. Cost Price(CP) of 1 ... 2nd can :mix in 1st can =1/8:1/8=1:1 ie, from each can,1/2* 12 = 6 litre should be taken.

A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal proportions. What is the value of x? a) 6 litres b) 10 litres c) 30 litres d) None of these

Description : A sample of x litres from a container having a 60 litre mixture of milk and water containing milk and water in the ratio of 2 : 3 is replaced with pure milk so that the container will have milk and water in equal ... . What is the value of x? a) 6 litres b) 10 litres c) 30 litres d) None of these

Last Answer : C Another way for solving this sum is by choice The mixture of 60 litres has in it 24 litres of milk and 36 litres of water. (2 : 3 :: milk water) When you remove x litres from it, you ... have 30 litres of milk and 30 litres of water - i.e. milk and water are in equal proportion.

A vessel is filled with liquid, 4 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup? a) 1/3 b) 1/5 c) 1/4 d) 1/7 e) 1/10

Description : A vessel is filled with liquid, 4 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup? a) 1/3 b) 1/5 c) 1/4 d) 1/7 e) 1/10

Last Answer : E Suppose the vessel initially contains 9 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture = 4 - 4x/9 + x litres Quantity of syrup in new mixture = 5 - 5x /9 (4 ... 9  X = 9 / 10 So part of the mixture replaced = 9 / 10 1 / 9  = 1 / 10

In 20 litres of a mixture, the ratio of sugar syrub to honey syrub is 5:1. In order to make the ratio of sugar syrub to honey syrub as 3:1, the quantity of honey syrub that should be added to the mixture will be A) 5 2/3 B) 4 1/3 C) 6 2/3 D) 2 2/9

Description : In 20 litres of a mixture, the ratio of sugar syrub to honey syrub is 5:1. In order to make the ratio of sugar syrub to honey syrub as 3:1, the quantity of honey syrub that should be added to the mixture will be A) 5 2/3 B) 4 1/3 C) 6 2/3 D) 2 2/9

Last Answer : D By the rule of alligation Quantity of honey : Quantity of mixture =1/12:3/4}=1:9 Given that quantity of mixture = 20 litre =>Quantity of honey : 20 = 1 : 9 => Quantity of honey = 20 x1/9  = 2 2/9 litre

How many kg of dal at Rs.8.40 per kg be mixed with32 kg of dall at Rs10.20 per kg to get a mixture worth Rs.9.60 per kg? a) 23 b) 49 c) 43 d) 72 e) 16

Description : How many kg of dal at Rs.8.40 per kg be mixed with32 kg of dall at Rs10.20 per kg to get a mixture worth Rs.9.60 per kg? a) 23 b) 49 c) 43 d) 72 e) 16

Last Answer : E By the rule of allegation ,we have Quantity of 1st kind dall : Quantity of 2nd kind dall = 60 : 120  => Quantity of 1st kind dall:32 = 1:2  Quantity of 1st kind dall =32 *1/2 = 16

A merchant mixes three varieties of rice costing Rs.40/kg, Rs.48/kg and Rs.60/kg and sells the mixture at a profit of 40% at Rs.60 / kg. How many kgs of the second variety will be in the mixture if 4 kgs of the third variety is there in the mixture? a) 1 kg b) 20 kgs c) 3 kgs d) 6 kgs e) 8kgs

Description : A merchant mixes three varieties of rice costing Rs.40/kg, Rs.48/kg and Rs.60/kg and sells the mixture at a profit of 40% at Rs.60 / kg. How many kgs of the second variety will be in the mixture if 4 kgs of the third variety is there in the mixture? a) 1 kg b) 20 kgs c) 3 kgs d) 6 kgs e) 8kgs

Last Answer : D If the selling price of mixture is Rs.60/kg and the merchant makes a profit of 20%, then the cost price of the mixture = 60/1.2 = Rs.50/kg. We need to find out the ratio in which the three varieties are mixed ... QC in step 1 and step 2 = 1 + 5 = 6 Therefore, the ratio = 1 : 25 : 5

Two vessels A and B contain sugar and rava in the ratio 4 : 3 and 2 : 3 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing sugar and rava in the ratio 1 : 2? a) 2:9 b) 3:2 c) 7:9 d) 2:7 e) 7:4

Description : Two vessels A and B contain sugar and rava in the ratio 4 : 3 and 2 : 3 respectively. Find the ratio in which these mixtures be mixed to obtain a new mixture in vessel C containing sugar and rava in the ratio 1 : 2? a) 2:9 b) 3:2 c) 7:9 d) 2:7 e) 7:4

Last Answer : E Let Cost Price(CP) of 1 kg sugar be Rs.1 Quantity of sugar in 1kg mixture from vessel A=4/7 Cost Price(CP) of 1kg mixture from vessel A = Rs. =4/7 Quantity of sugar in 1 kg mixture from vessel ... from vessel C=1/2 Cost Price(CP) of 1 kg mixture from vessel C(Mean Price) = Rs.=1/2

Vessel A contains milk and water in the ratio 3:2. Vessel B contains milk and water in the proportion 4:5.In what proportion should quantities be taken from A & B to form a mixture in which milk and water are in the ratio 7:2? a) 3:2 b) 15:2 c) 4:3 d) 8:15 e) 6:18

Description : Vessel A contains milk and water in the ratio 3:2. Vessel B contains milk and water in the proportion 4:5.In what proportion should quantities be taken from A & B to form a mixture in which milk and water are in the ratio 7:2? a) 3:2 b) 15:2 c) 4:3 d) 8:15 e) 6:18

Last Answer : D For this question, we will consider the proportion of milk in each mixture. In Vessel A, the proportion of milk in 3/((3+2) )=3/5. vessel B, the proportion of milk is 4/(4+5) = 4/9

Redgram worth Rs. 112 per kg and Rs.123 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 142 per kg, the price of the third variety per kg will be a) 153 b) 175.50 c) 43.9 d) 227.9 e) 166.5

Description : Redgram worth Rs. 112 per kg and Rs.123 per kg are mixed with a third variety in the ratio 1: 1 : 2. If the mixture is worth Rs. 142 per kg, the price of the third variety per kg will be a) 153 b) 175.50 c) 43.9 d) 227.9 e) 166.5 

Last Answer : E  Since first second varieties are mixed in equal proportions  so their average price = Rs.(112 + 123/2)  = Rs. 117.5  So, the mixture is formed by mixing two varieties, one at Rs. 117.50 per kg and the ... ratio 2 : 2, i.e., 1 : 1. We have to find x.  By the rule of allgation 

A jar full of whiskey contains 52% alcohol. A part of this ****** is replaced by another containing 31% alcohol and now the percentage of alcohol was found to be 38%. The quantity of ****** replaced is a) 3/2 b) 2/3 c) 4/3 d) 2/7 e) None

Description : A jar full of whiskey contains 52% alcohol. A part of this whisky is replaced by another containing 31% alcohol and now the percentage of alcohol was found to be 38%. The quantity of whisky replaced is a) 3/2 b) 2/3 c) 4/3 d) 2/7 e) None

Last Answer : B Concentration of alcohol in 1st Jar = 52% Concentration of alcohol in 2nd Jar = 31% After the mixing, Concentration of alcohol in the mixture = 38% By rule of allegation, Hence ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2 i.e., 2/3 part of the whisky is replaced.

Find the ratio in which Nuts at Rs. 5.40 a kg be mixed with Nuts at Rs. 3.20 a kg to produce a mixture worth Rs. 4.60 a kg. a) 9:2 b) 2:3 c) 4:3 d) 3:2 e) 7:4

Description : Find the ratio in which Nuts at Rs. 5.40 a kg be mixed with Nuts at Rs. 3.20 a kg to produce a mixture worth Rs. 4.60 a kg. a) 9:2 b) 2:3 c) 4:3 d) 3:2 e) 7:4

Last Answer : E By the rule of allegation  Required ratio = 140 : 80  = 7:4

In what ratio must water be mixed with milk costing Rs.30 per litre in order to get a mixture worth of Rs.18 per litre? a) 3:2 b) 2:3 c) 4:3 d) 2:7 e) 1:2

Description : In what ratio must water be mixed with milk costing Rs.30 per litre in order to get a mixture worth of Rs.18 per litre? a) 3:2 b) 2:3 c) 4:3 d) 2:7 e) 1:2

Last Answer : B  By the rule of allegation  Ratio of water to milk = 12:18 = 2:3

In what ratio must a person mix three kinds of dall costing him Rs 12.25,Rs 12.50 and Rs 12.75 per Kg so that the mixture may be worth Rs 12.65 per Kg? a) 11:7:1 b) 22:3:6 c) 14:3:4 d) 2:7:4 e) 3:12:32

Description : In what ratio must a person mix three kinds of dall costing him Rs 12.25,Rs 12.50 and Rs 12.75 per Kg so that the mixture may be worth Rs 12.65 per Kg? a) 11:7:1 b) 22:3:6 c) 14:3:4 d) 2:7:4 e) 3:12:32

Last Answer : E Step1: Mix dall of first and third kind to get a mixture worth Rs 12.25 per Kg. C.P of 1 Kg dall of 1st kind 1225p C.P of 1 Kg dall of 3rd kind 1275p So they must be mixed in the ... So the Mixed ratio = 3:8 Thus the quantities of dall 1st : 2nd : 3rd  = 3:12:32

In what ratio should a shopkeeper mix two types of rice, one costing 40 rupees/kg and another costing 20 rupees/kg to get a rice variety costing 28 rupees/kg a) 3:2 b) 2:3 c) 4:3 d) 2:7 e) None

Description : In what ratio should a shopkeeper mix two types of rice, one costing 40 rupees/kg and another costing 20 rupees/kg to get a rice variety costing 28 rupees/kg a) 3:2 b) 2:3 c) 4:3 d) 2:7 e) None

Last Answer : B Here also we can use Alligation as follows  X = 40-28 = 4 ; y = 28-20 = 8 The ratio between the type 1 and type 2 rice is 4:6 or 2: 3

The cost of Type 1 material is Rs. 50per kg and Type 2 material is Rs.75 per kg. If both Type 1 and Type 2 are mixed in the ratio of 3:2 then what is the price per kg of the mixed variety of material? a) 32 b) 38 c) 53 d) 62 e) 60

Description : The cost of Type 1 material is Rs. 50per kg and Type 2 material is Rs.75 per kg. If both Type 1 and Type 2 are mixed in the ratio of 3:2 then what is the price per kg of the mixed variety of material? a) 32 b) 38 c) 53 d) 62 e) 60 

Last Answer : E Cost Price (CP) of Type 1 material is Rs. 50 per kg Cost Price (CP) of Type 2 material is Rs. 75 per kg Let Cost Price(CP) of resultant mixture be Rs.x per kg

In what ratio must a person mix three kinds of musted seeds costing Rs.65/kg, Rs.70/kg and Rs.105 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%? a) 1:2:4 b) 3:7:6 c) 1:4:2 d)1:8:6 e) 40 : 8 : 25

Description :  In what ratio must a person mix three kinds of musted seeds costing Rs.65/kg, Rs.70/kg and Rs.105 /kg so that the resultant mixture when sold at Rs.96/kg yields a profit of 20%? a) 1:2:4 b) 3:7:6 c) 1:4:2 d)1:8:6 e) 40 : 8 : 25

Last Answer : E The resultant mixture is sold at a profit of 20% at Rs.96/kg i.e. 1.2 (cost) = Rs.96 => Cost = = Rs.80 / kg. Let the three varities be A, B, and C costing Rs.65, Rs.70 and Rs.105 respectively. The ... be mixed. A:C=4:5 B:C=2:5 The resultant ratio A : B : C :: 40 : 8 : 25. 

In what ratio should wheat at Rs12.60 per kg be mixed with wheat at Rs. 14.60 per kg so that the mixture be worth Rs.13 per kg ? a) 6:8 b) 8:7 c) 4:3 d) 2:7 e) 4:1

Description : In what ratio should wheat at Rs12.60 per kg be mixed with wheat at Rs. 14.60 per kg so that the mixture be worth Rs.13 per kg ? a) 6:8 b) 8:7 c) 4:3 d) 2:7 e) 4:1

Last Answer : E Thus the required ratio = 160 :40 = 4:1

Some amount out of Rs.8500 was lent at 5% per annum and the remaining was lent at 3% per annum. If the total simple interest from both the fractions in4 years was Rs.1500, the sum lent at 5% per annum was a) Rs. 2400 b) Rs. 2200 c) Rs. 2000 d) Rs. 6000

Description : Some amount out of Rs.8500 was lent at 5% per annum and the remaining was lent at 3% per annum. If the total simple interest from both the fractions in4 years was Rs.1500, the sum lent at 5% per annum was a) Rs. 2400 b) Rs. 2200 c) Rs. 2000 d) Rs. 6000

Last Answer : D Total simple interest received , I = Rs.1500 Principal , p = 8500 period, n = 4 years Rate of interest, r = ? Simple Interest, I=PNR/100 1500 = ( 8500 4 r )/ 100  = ... total amount is Rs.8500.  Therefore, the amount lent at 5% per annum (part1 amount) = 8500x12/17  = 6000 

In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg

Description :  In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg e)1kg

Last Answer : E Quantity of the mixture : Quantity of iron = 20 : 20 = 1 : 1 Given that quantity of the mixture = 1 kg Hence quantity of iron to be added = 1 kg

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Two jars having a capacity of 3 and 5 litres respectively are filled with mixtures of milk and water. In the smaller jar 25% of the mixture is milk and in the larger 25% of the mixture is water. The jars are emptied into a 10 litre cask whose remaining capacity is filled up with water. Find the percentage of milk in the cask. a) 55% b) 50% c) 45% d) 25% e) None of these

Description : Two jars having a capacity of 3 and 5 litres respectively are filled with mixtures of milk and water. In the smaller jar 25% of the mixture is milk and in the larger 25% of the mixture is water. The jars are emptied ... the percentage of milk in the cask. a) 55% b) 50% c) 45% d) 25% e) None of these

Last Answer : Answer: D 0.75+3.75=4.5/10+8*100=4.5/18*100=25%

From a vessel containing 100 litres of ****,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of **** and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Description : From a vessel containing 100 litres of wine,10 litres are drawn out and an equal amount of water is added. From the mixture,10 litres is again drawn out and same quantity of water is added. What is the final ratio of wine and water? a) 91 : 9 b) 81 : 19 c) 80 : 20 d) 90 : 10 e) None of these

Last Answer : Quantity of wine after two replacements = 100 l × (90/100)2 =81 l Required ratio = 81 : ( 100 – 81 )= 81 : 19 Answer: b)

A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Description : A vessel contains milk and water in the ratio of 4:3. If 14 litres of the mixture is drawn and filled with water, the ratio changes to 3:4. How much milk was there in the vessel initially? a) 24 b) 32 c) 40 d) 48 e) None of these

Last Answer : Answer: B milk = 4x and water = 3x milk = 4x – 14*4/7 and water = 3x – 14*3/7 + 14 4x – 8: 3x + 8 = 3:4 X = 8, so milk = 8*4 = 32 litres

A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres

Description : A vessel contains 100 litres of milk. From this, 10 litres of milk was taken out and replaced by water. The process was repeated further two times. How much milk is now contained by the vessel? a) 72.9 litres b) 60.4 litres c) 71.6 litres d) 81 litres e) None of these

Last Answer : Milk after three replacement =100 × (90/100)3 = 72.9 litres Answer: a)

Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Description : Given the following data pairs (x, y), find the regression equation. (1, 1.24), (2, 5.23), (3, 7.24), (4, 7.60), (5, 9.97), (6, 14.31), (7, 13.99), (8, 14.88), (9, 18.04), (10, 20.70) a. y = 0.490 x - 0.053 b. y = 2.04 x c. y = 1.98 x + 0.436 d. y = 0.49 x

Last Answer : c. y = 1.98 x + 0.436

In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Description : In a Examination a candidate has to score minimum of 24 marks inorder to clear the exam. The maximum that he can score is 40 marks. Identify the Valid Equivalance values if the student clears the exam. A. 22,23,26 B. 21,39,40 C. 29,30,31 D. 0,15,22

Last Answer : C. 29,30,31

A pack contains 4 blue, 2 red and 3 black pens. If a pen is drawn at random from the pack, replaced and the process repeated 2 more times, what is the probability of drawing 2 blue pens and 1 black pen? a) 16/243 b) 16/283 c) 14/243 d) 23/729

Description : A pack contains 4 blue, 2 red and 3 black pens. If a pen is drawn at random from the pack, replaced and the process repeated 2 more times, what is the probability of drawing 2 blue pens and 1 black pen? a) 16/243 b) 16/283 c) 14/243 d) 23/729

Last Answer : a) 16/243

A shopkeeper has 2 cans of milk. The first contains 30% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the cans so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5? 1) 5 lit, 7 lit. 2) 9 lit, 3 lit. 3) 7.5 lit, 4.5 lit. 4) 4 lit, 8 lit.

Description : A shopkeeper has 2 cans of milk. The first contains 30% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the cans so as to get 12 litres of milk such that the ratio of water to milk ... 7 lit. 2) 9 lit, 3 lit. 3) 7.5 lit, 4.5 lit. 4) 4 lit, 8 lit.

Last Answer : 3) 7.5 lit, 4.5 lit.

A barrier has four inlets A, B, C and D. The barrier can be filled in 24 minutes through the first three inlets and it can be filled in 30 minutes through the second, the third and fourth inlet also it can be filled through the first and the fourth inlet in 40 minutes. How much time required to fill up the barrier by all the four inlets? A) 10 mins B) 15 mins C) 20 mins D) 25 mins E) None of the Above

Description : A barrier has four inlets A, B, C and D. The barrier can be filled in 24 minutes through the first three inlets and it can be filled in 30 minutes through the second, the third and fourth inlet also it can be ... all the four inlets? A) 10 mins B) 15 mins C) 20 mins D) 25 mins E) None of the Above

Last Answer : C (1/A + 1/B + 1/C) = 1/24 …(i) (1/B + 1/C + 1/D) = 1/30 …(ii) (1/A + 1/D) = 1/40…(iii) From eqn (i) and (ii) (1/A – 1/D) = 1/120…(iv) From eqn (iii) and (iv) A=60,D=120. Let the time taken to full the tank = s S(1/A + 1/B +1/C +1/D)= 1 S(1/24+1/120) = 1 S= 20 mins

Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Description : Four pipes can fill a reservoir in 15, 20, 30 and 60 hours respectively. The first one was opened at 6 AM, second at 7 AM, thir da t 8 AM and the fourth at 9 AM. When will the reservoir be filled ? (A) 11 AM (B) 12 Noon (C) 1 PM (D) 1:30 PM

Last Answer : Answer: C

A certain number has three digits. The sum of the three digits equals 36 times this number. Seven times the left digit plus 9 is equal to 5 times the sum of the two other digits. 8 times the second digit minus 9 is equal to the sum of the first and third.What is the number? -Riddles

Description : A certain number has three digits. The sum of the three digits equals 36 times this number. Seven times the left digit plus 9 is equal to 5 times the sum of the two other digits. 8 times the second digit minus 9 is equal to the sum of the first and third.What is the number? -Riddles

Last Answer : This one is fairly easy - 324 is the answer.

Consider a pack contains 2black, 9 white and 3 pink pencils. If a pencil is drawn at random from the pack, replaced and the process repeated 2 more times, What is the probability of drawing 2 black pencils and 1 pink pencil? a)3/ 49 b)3/686 c)3/14 d)3/545

Description : Consider a pack contains 2black, 9 white and 3 pink pencils. If a pencil is drawn at random from the pack, replaced and the process repeated 2 more times, What is the probability of drawing 2 black pencils and 1 pink pencil? a)3/ 49 b)3/686 c)3/14 d)3/545

Last Answer : Answer: B) Here, total number of pencils = 14 Probability of drawing 1 black pencil = 2/14 Probability of drawing another black pencil = 2/14 Probability of drawing 1 pink pencil = 3/14 Probability of drawing 2 black pencils and 1 pink pencil = 2/14 * 2/14 * 3/14 = 3/686

Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39

Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Description : Find the median of the values 37, 31, 42, 43, 46, 25, 39, 45, 32. -Maths 9th

Last Answer : Arranging the data in ascending order, we have 25, 31, 32, 37, 39, 42, 43, 45, 46 Here, number of observations = 9 (odd) Median = value of (9+1 / 2)th Observation = Value of 5th Observation = 39

A cistern is filled by three faucets with uniform flow. The first two faucets operating simultaneously fill the cistern in the same during which the cistern is filled by the third faucet alone. The second faucet fills the cistern 5 hours faster than the first faucet and 4 hours slower than the third faucet. The time required by the first faucet is? A) 6 hrs B) 10 hrs C) 15 hrs D) 30 hrs

Description : A cistern is filled by three faucets with uniform flow. The first two faucets operating simultaneously fill the cistern in the same during which the cistern is filled by the third faucet alone. The second faucet fills the cistern ... by the first faucet is? A) 6 hrs B) 10 hrs C) 15 hrs D) 30 hrs

Last Answer : C Suppose, first faucet alone takes x hours to fill the cistern. Then, second and third faucets will take (x - 5) and (x - 9) hours respectively to fill the cistern. 1/x + 1/(x - 5) = 1/(x - 9) (2x - 5)(x - 9) = x(x - 5) x2 - 18x + 45 = 0 (x- 15)(x - 3) = 0 => x = 15

The power of a wave in a cylindrical waveguide of radius 2m with electric field 12 units is a) 2.39 b) 3.92 c) 9.23 d) 9.32

Description : The power of a wave in a cylindrical waveguide of radius 2m with electric field 12 units is a) 2.39 b) 3.92 c) 9.23 d) 9.32

Last Answer : a) 2.39

The observed N- value from a standard penetration test conducted in saturated sandy strata is 30; the N- value corrected for dilatancy may be taken as : (b) 15 (a) 20 (c) 23 (d) 39

Description : The observed N- value from a standard penetration test conducted in saturated sandy strata is 30; the N- value corrected for dilatancy may be taken as : (b) 15 (a) 20 (c) 23 (d) 39

Last Answer : (c) 23

The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Description : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, 48, 29, 40, 45, 48, 42, 23, 35. Find the average mark

Last Answer : The marks obtained by 15 students in an examination are given below : 40, 20, 24, 19,20, 35, 12, ... , 23, 35. Find the average mark of the students.

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

A well penetrates to 30 m below the static water table. After 24 hours of pumping at 31.40 litres/minute, the water level in a test well at a distance of 80 m is lowered by 0.5 m and in a well 20 m away water is lowered by 1.0 m. The transmissibility of the aquifer, is (A) 1.185 m2 /minute(B) 1.285 m2/minute (C) 1.385 m2/minute (D) 1.485 m2/minute

Description : A well penetrates to 30 m below the static water table. After 24 hours of pumping at 31.40 litres/minute, the water level in a test well at a distance of 80 m is lowered by 0.5 m and in a well 20 m away water is ... 1.185 m2 /minute (B) 1.285 m2 /minute (C) 1.385 m2 /minute (D) 1.485 m2 /minute

Last Answer : Answer: Option C

In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ratio of milk and water ` 5 : 3` ?

Description : In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ratio of milk and water ` 5 : 3` ?

Last Answer : In a solution of 45 litres of milk and water, ` 40%` is water. How many litres of milk must be added to become the ... : 3` ? A. 8 B. 3 C. 7 D. 6

A Bunker has a leak which would empty the completely filled bunker in 20 hours. If the bunker is full of water and a tap is opened which admits 4 litres of water per minutes in the bunker, how many litres does the bunker holds? A) 2400 B) 4500 C) 4800 D) 7200

Description : A Bunker has a leak which would empty the completely filled bunker in 20 hours. If the bunker is full of water and a tap is opened which admits 4 litres of water per minutes in the bunker, how many litres does the bunker holds? A) 2400 B) 4500 C) 4800 D) 7200

Last Answer : C Leak emptied the bunker per hour = 100/20 = 5% of water per hour; Quantity of water emptied per hour = 4*60 = 240; Thus, 5% = 240 liter; Hence, capacity of water, 100% = 240*100/5= 4800 liter.

(?)2 + (9.99)3 = (45.02)2 – (4.01)3 a) 34 b) 19 c) 26 d) 31 e) 12

Description : (?)2 + (9.99)3 = (45.02)2 – (4.01)3 a) 34 b) 19 c) 26 d) 31 e) 12

Last Answer : ?2 + 1000 = 2025 – 64 ?2 = 961  ? = 31 Answer: d)

P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26

Last Answer : 2;

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Description : Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Last Answer : D Part filled in 5 min = 5(1/12 +1/15) = 5*9/60 = ¾ Part emptied in 1 min when all the pumps are opened, = 1/6 – (1/12 + 1/15) = 1/6 – 3/20 = 1/60 Now 1/60 is part emptied in 1 min Therefore ¾ part will be emptied in 60 * ¾ = 45 mins

On Ashok marg, three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are switched on at 9.00 A.M sharp, at what time will they change simultaneously? a) 9 :08 :44 b) 9:08:24 c) 9:08:04 d) 9:08:34

Description : On Ashok marg, three consecutive traffic lights change after 36, 42 and 72 seconds respectively. If the lights are switched on at 9.00 A.M sharp, at what time will they change simultaneously? a) 9 :08 :44 b) 9:08:24 c) 9:08:04 d) 9:08:34

Last Answer : b) 9:08:24