A jar full of whiskey contains 52% alcohol. A part of this ****** is replaced by another containing 31% alcohol and now the percentage of alcohol was found to be 38%. The quantity of ****** replaced is a) 3/2 b) 2/3 c) 4/3 d) 2/7 e) None

1 Answer

Answer :

B

Concentration of alcohol in 1st Jar = 52%

Concentration of alcohol in 2nd Jar = 31%

After the mixing, Concentration of alcohol in the mixture = 38%

By rule of allegation,

image

Hence ratio of 1st and 2nd quantities = 7 : 14 = 1 : 2

i.e., 2/3 part of the ****** is replaced.

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