Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.

Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.
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Obtain the formula for acceleration due to gravity at the depth ‘d’ below the Earth’s surface.
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Assuming uniform density of the core, the acceleration due to gravity below the Earth's surface is A. inversely proportional to the square of the distance from the center of the Earth B. inversely proportional to the distance from the center of the Earth C. directly proportional to the square of the distance from the center of the Earth D. directly proportional to the distance from the center of the Earth

Description : Assuming uniform density of the core, the acceleration due to gravity below the Earth's surface is A. inversely proportional to the square of the distance from the center of the Earth ... center of the Earth D. directly proportional to the distance from the center of the Earth

Last Answer : directly proportional to the distance from the center of the Earth

State the formula for acceleration due to gravity at depth ‘d’ and altitude ‘h’ Hence show that their ratio is equal to ((R - d)/(R - 2h))

Description : State the formula for acceleration due to gravity at depth ‘d’ and altitude ‘h’ Hence show that their ratio is equal to ((R - d)/(R - 2h))

Last Answer : State the formula for acceleration due to gravity at depth d' and altitude h' Hence show that ... small as compared to the radius of the Earth.

Draw a graph showing the variation of gravitational acceleration due to the depth and altitude from the Earth’s surface.

Description : Draw a graph showing the variation of gravitational acceleration due to the depth and altitude from the Earth’s surface.

Last Answer : Draw a graph showing the variation of gravitational acceleration due to the depth and altitude from the Earth’s surface.

Show that acceleration due to gravity at height h above the Earth’s surface is gh = g(R/R + h)^2

Description : Show that acceleration due to gravity at height h above the Earth’s surface is gh = g(R/R + h)^2

Last Answer : Show that acceleration due to gravity at height h above the Earth’s surface is gh = g \(\left(\frac{R}{R + h}\right)^2\) gh = g(R/R + h)2

If a body weighs 12N on the surface of the earth, how much will it weigh on the surface of the moon where acceleration due to gravity is only one-sixth of that on earth's surface? (1) 12N (2) 2N (3) 10N (4) 6N

Description : If a body weighs 12N on the surface of the earth, how much will it weigh on the surface of the moon where acceleration due to gravity is only one-sixth of that on earth's surface? (1) 12N (2) 2N (3) 10N (4) 6N

Last Answer : (2) 2N Explanation: Weight is mass x g. Since mass is constant and g is only 16thof that on the earth. The weight on the moon is only 16th of that on the earth.

At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface,

Description : At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of its value at the surface,

Last Answer : At what distance below the surface of the Earth, the acceleration due to gravity decreases by 10% of ... surface, given radius of Earth is 6400 km.

An artificial satellite stays in the orbit around the Earth because (a) The Earth’s gravity does not act on the satellite due to the great distance between them (b) The Earth’s attraction produces the necessary centripetal acceleration (c) The Earth’s attraction is balanced by the attraction of other planets (d) There is an engine in the satellite that constantly applies an upward force to balance its weight

Description : An artificial satellite stays in the orbit around the Earth because (a) The Earth's gravity does not act on the satellite due to the great distance between them (b) The Earth's attraction ... (d) There is an engine in the satellite that constantly applies an upward force to balance its weight

Last Answer : Ans:(b)

The acceleration due to gravity at the equator – (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth's centripetal acceleration

Description : The acceleration due to gravity at the equator – (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth's centripetal acceleration

Last Answer : (1) is less than that at the poles Explanation: The gravity of Earth, denoted g, refers to the acceleration that the Earth imparts to objects on or near its surface. At latitudes nearer the Equator ... ) causes objects at the Equator to be farther from the planet's centre than objects at the poles.

The acceleration due to gravity at the equator (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth’s centripetal acceleration

Description : The acceleration due to gravity at the equator (1) is less than that at the poles (2) is greater than that at the poles (3) is equal to that at the poles (4) does not depend on the earth’s centripetal acceleration 

Last Answer : is less than that at the poles

My first is found on the ocean wave, In the spring, the pit, and the mine; My second below earth’s surface you have, Where seldom the sun can shine. My whole your dinner-table must grace, And seldom fails to obtain a place.What am I? -Riddles

Description : My first is found on the ocean wave, In the spring, the pit, and the mine; My second below earth’s surface you have, Where seldom the sun can shine. My whole your dinner-table must grace, And seldom fails to obtain a place.What am I? -Riddles

Last Answer : Salt-cellar.

Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

Description : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 10^24 kg, R = 6400 km).

Last Answer : Calculate the acceleration due to gravity at a height of 300 km from the surface of the Earth. (M = 5.98 × 1024 kg, R = 6400 km).

How far away from the surface of the Earth does the acceleration due to gravity become ½ of its value at the surface of Earth? It is at a (a) Distance equal to radius (b) Distance equal to half the radius (c) Distance equal to twice the radius (d) Distance equal to 0.414 times the radius

Description : How far away from the surface of the Earth does the acceleration due to gravity become ½ of its value at the surface of Earth? It is at a (a) Distance equal to radius (b) Distance equal to half the radius (c) Distance equal to twice the radius (d) Distance equal to 0.414 times the radius

Last Answer : Ans:(d)

If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Last Answer : (2) Surface area of the bottom of the vessel Explanation: The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity. Static fluid pressure does not depend on the shape, total mass, or surface area of the liquid.

If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is – (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Last Answer : (2) Surface area of the bottom of the vessel Explanation: The pressure exerted by a static fluid depends only upon the depth of the fluid, the density of the fluid, and the acceleration of gravity.

A person can jump higher on the moon's surface than on the earth because – (1) the moon's surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Description : A person can jump higher on the moon's surface than on the earth because – (1) the moon's surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Last Answer : (2) the acceleration due to gravity in moon is smaller than that on the earth. Explanation: The acceleration due to the gravitational field of moon (g' = 1.62631 ms-2) is one-sixth of the acceleration due ... earth. It is due to this reason; a man can jump six times higher on moon than on earth.

An object with a mass of 5 kilograms is a distance of 5 meters above the surface of the earth. If the acceleration due to gravity is 10 meters per second squared, the potential energy of the object relative to the surface of the earth is: w) 10 joules x) 20 joules y) 100 joules z) 250 joules e) none of the above

Description : An object with a mass of 5 kilograms is a distance of 5 meters above the surface of the earth. If the acceleration due to gravity is 10 meters per second squared, the potential energy of the object relative to the ... is: w) 10 joules x) 20 joules y) 100 joules z) 250 joules e) none of the above

Last Answer : ANSWER: Z -- 250 JOULES

A person can jump higher on the moon’s surface than on the earth because : (1) the moon’s surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Description : A person can jump higher on the moon’s surface than on the earth because : (1) the moon’s surface is rough (2) the acceleration due to gravity in moon is smaller than that on the earth. (3) the moon is cooler than earth (4) the moon has no atmosphere

Last Answer : the acceleration due to gravity in moon is smaller than that on the earth.

If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Description : If we want to calculate the pressure of a liquid at the bottom of a vessel, the quantity which is not required to determine it, is (1) Height of the liquid column (2) Surface area of the bottom of the vessel (3) Density of the liquid (4) Acceleration due to gravity at the bottom of the vessel

Last Answer : Surface area of the bottom of the vessel

The rocks which are formed due to cooling of magma at a relatively shallow depth from the earth's surface are called (A) Plutonic rocks (B) Hypabyssal rocks (C) Volcanic rocks (D) Igneous rocks

Description : The rocks which are formed due to cooling of magma at a relatively shallow depth from the earth's surface are called (A) Plutonic rocks (B) Hypabyssal rocks (C) Volcanic rocks (D) Igneous rocks

Last Answer : Answer: Option B

The rocks which are formed due to cooling of magma at a considerable depth from earth's surface are called (A) Plutonic rocks (B) Hypabyssal rocks (C) Volcanic rocks (D) Igneous rocks

Description : The rocks which are formed due to cooling of magma at a considerable depth from earth's surface are called (A) Plutonic rocks (B) Hypabyssal rocks (C) Volcanic rocks (D) Igneous rocks

Last Answer : Answer: Option A

At which place on the Earth’s surface is the gravitational acceleration maximum? Why?

Description : At which place on the Earth’s surface is the gravitational acceleration maximum? Why?

Last Answer : At which place on the Earth’s surface is the gravitational acceleration maximum? Why?

Hydrodynamic pressure due to earthquake acts at a height of (A) 3H/4 above the base (B) 3H/4 below the water surface (C) 4H/3 above the base (D) 4H below the water surface, where H is the depth of water.

Description : Hydrodynamic pressure due to earthquake acts at a height of (A) 3H/4 above the base (B) 3H/4 below the water surface (C) 4H/3 above the base (D) 4H below the water surface, where H is the depth of water.

Last Answer : Answer: Option C

To within 1 pound per square inch, what is the nominal pressure due to water at a depth of 100 feet below the surface of a body of water?

Description : To within 1 pound per square inch, what is the nominal pressure due to water at a depth of 100 feet below the surface of a body of water?

Last Answer : ANSWER: 43.3 POUNDS PER SQUARE INCH (accept 42.3 to 44.3) 

A imaginary planet has half the mass and half the radius of the earth. The acceleration of gravity at its surface would be a.9.8 m/s2 b.107 dynes c.4.9 m/s2 d.19.6 m/s2 e.2.45 m/s2

Description : A imaginary planet has half the mass and half the radius of the earth. The acceleration of gravity at its surface would be a.9.8 m/s2 b.107 dynes c.4.9 m/s2 d.19.6 m/s2 e.2.45 m/s2

Last Answer : d. 19.6 m/s2

raft increases with increase in forward speed for most of the implement, mainly due to a) More rapid acceleration of any soil particles that is moved appreciably b) More working width c) Increased working depth d) Draft decreases with increase in speed of implement

Description : raft increases with increase in forward speed for most of the implement, mainly due to a) More rapid acceleration of any soil particles that is moved appreciably b) More working width c) Increased working depth d) Draft decreases with increase in speed of implement

Last Answer : a) More rapid acceleration of any soil particles that is moved appreciably

The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

Description : The value of acceleration due to gravity is 980 cm/sec2. Its value in meter per (hour)2 will be a.1.27 x 108 b.127 c.1270 d.1.27 x 107 e.1270000

Last Answer : a. 1.27 x 108

State the factors on which acceleration due to gravity depends. -Science

Description : State the factors on which acceleration due to gravity depends. -Science

Last Answer : The acceleration due to gravity depends upon the radius of the earth,mass of the earth and on a constant having unit Nm^2/kg^2.

What is the variation in acceleration due to gravity with altitude?

Description : What is the variation in acceleration due to gravity with altitude?

Last Answer : What is the variation in acceleration due to gravity with altitude?

The value of acceleration due to gravity is maximum at

Description : The value of acceleration due to gravity is maximum at

Last Answer : The value of acceleration due to gravity is maximum at (A) the equator of the Earth (B) the ... . (D) slightly above the surface of the Earth.

The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)

Description : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ± 0.1) cm. If its time period is T = (2 ± 0.01)

Last Answer : The acceleration due to gravity is determined by using a simple pendulum of length l = (100 ... the maximum percentage error in the measurement of g.

When your mass is 96 kg. The acceleration due to gravity is 9.8 ms 2 . How much work against gravity do you do when you climb a flight of stairs 3.8 m high Answer in units of J.?

Description : When your mass is 96 kg. The acceleration due to gravity is 9.8 ms 2 . How much work against gravity do you do when you climb a flight of stairs 3.8 m high Answer in units of J.?

Last Answer : 4

What is the acceleration due to gravity?

Description : What is the acceleration due to gravity?

Last Answer : It's the best way to describe the gravity in any given place. Notice that itdoesn't depend on the object that's being weighed there. Naturally, objectswith more mass will be heavier, and objects with less mass ... On Earth, that number is 9.8 meters (32.2 feet) per second2 .It is just mass then.

At high altitudes it is difficult to cook eggs or vegetables properly because of (a) High boiling point of water and low atmospheric pressure (b) Low boiling point of water and low atmospheric pressure (c) Low value of acceleration due to gravity (d) High atmospheric pressure and low billing point of water

Description : At high altitudes it is difficult to cook eggs or vegetables properly because of (a) High boiling point of water and low atmospheric pressure (b) Low boiling point of water and low atmospheric ... Low value of acceleration due to gravity (d) High atmospheric pressure and low billing point of water

Last Answer : Ans:(b)

A hydrogen filled balloon rises in air because (a) The atmospheric pressure decreases with altitude (b) The acceleration due to gravity decreases with altitude (c) The density of air decreases with altitude (d) The buoyant force exerted by the air on the balloon is greater than the weight of the balloon

Description : A hydrogen filled balloon rises in air because (a) The atmospheric pressure decreases with altitude (b) The acceleration due to gravity decreases with altitude (c) The density of air decreases with ... The buoyant force exerted by the air on the balloon is greater than the weight of the balloon

Last Answer : Ans:(d)

Two planets have the same density of matter, such that their masses are proportional to the cube of their radii. The ratio of their acceleration due to gravity on their surfaces is (a) r2/r1 (b) (r1/r2)2 (c) r1/r2 (d) (r2/r1)2

Description : Two planets have the same density of matter, such that their masses are proportional to the cube of their radii. The ratio of their acceleration due to gravity on their surfaces is (a) r2/r1 (b) (r1/r2)2 (c) r1/r2 (d) (r2/r1)2

Last Answer : Ans:(d) Direction: In the following question, a statement of Assertion (A) is given followed by corresponding Reason (R), just below it. Read the statements carefully and mark the correct answer: (a) If both A and ... true but R is not the correct explanation of A. (c) If A is true but R is false

The sensation of weightlessness in a spacecraft in an orbit is due to the – (1) Absence of gravity outside (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside (3) Presence of gravity outside but not inside the spacecraft (4) Fact that spacecraft in the orbit has no energy

Description : The sensation of weightlessness in a spacecraft in an orbit is due to the - (1) Absence of gravity outside (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside ... of gravity outside but not inside the spacecraft (4) Fact that spacecraft in the orbit has no energy

Last Answer : (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside Explanation: Weightlessness in space is caused by the simple physical factors that cause the limitation of gravity. ... . Many people believe that a lack of gravity is the root cause for weightlessness in space.

The sensation of weightlessness in a spacecraft in an orbit is due to the – (1) Absence of gravity outside (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside (3) Presence of gravity outside but not inside the spacecraft (4) Fact that spacecraft in the orbit has no energy

Description : The sensation of weightlessness in a spacecraft in an orbit is due to the - (1) Absence of gravity outside (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside ... of gravity outside but not inside the spacecraft (4) Fact that spacecraft in the orbit has no energy

Last Answer : (2) Acceleration in the orbit which is equal to the acceleration due to gravity outside Explanation: Weightlessness in space is caused by the simple physical factors that cause the limitation of gravity. ... . Many people believe that a lack of gravity is the root cause for weightlessness in space.

As we go from Equator to North pole the value of `S, the acceleration due to gravity (1) remains the same (2) decreases (3) increases (4) None of the above

Description : As we go from Equator to North pole the value of `S, the acceleration due to gravity (1) remains the same (2) decreases (3) increases (4) None of the above

Last Answer : (3) increases Explanation: The acceleration due to gravity of earth is the rate of increase of velocity of a body falling freely towards the earth. At a given place, the value of acceleration due to gravity ... out at the equator. The value of 'g' is minimum at the equator and maximum at the poles.

Acceleration due to gravity (g) is mini- mum at?

Description : Acceleration due to gravity (g) is mini- mum at?

Last Answer : Equatorial regions

Acceleration due to gravity (g) is maxi- mum at?

Description : Acceleration due to gravity (g) is maxi- mum at?

Last Answer : polar regions

At the Center of earth Acceleration due to gravity (g) is?

Description : At the Center of earth Acceleration due to gravity (g) is?

Last Answer : Zero

If the earth were to skin faster, how does acceleration due to gravity at the poles?

Description : If the earth were to skin faster, how does acceleration due to gravity at the poles?

Last Answer : Remains the same

Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Description : Critical speed of rotation, N (in rps - rotation per second) of a trammel is equal to (where, g = acceleration due to gravity = 9.81 m/sec 2 and, r = radius of trammel, metre.) (A) (1/2π). √(g/r) (B) (1/π). √(g/r) (C) ½ √(g/r) (D) 2π. √(g/r)

Last Answer : (A) (1/2π). √(g/r)

If a student drops a stone from a cliff of height 30 m and the time it takes to reach the ground is 2.6 s, then the acceleration due to gravity isA. 9 m s-2B. 10 m s-2C. 4 m s-2D. 8.8 m s-2

Description : If a student drops a stone from a cliff of height 30 m and the time it takes to reach the ground is 2.6 s, then the acceleration due to gravity isA. 9 m s-2 B. 10 m s-2 C. 4 m s-2 D. 8.8 m s-2

Last Answer : 8.8 m s-2

In Joule's experiment, an insulated container contains 20 kg of waterinitially at 25°C. It is stirred by an agitator, which is made to turn by aslowly falling body weighing 40 kg through a height of 4 m. The process isrepeated 500 times. The acceleration due to gravity is 9.8 ms-2. Neglectingthe heat capacity of agitator, the temperature of water (in °C) is(A) 40.5(B) 34.4(C) 26.8(D) 25

Description : In Joule's experiment, an insulated container contains 20 kg of waterinitially at 25°C. It is stirred by an agitator, which is made to turn by a slowly falling body weighing 40 kg through a height of 4 m. The process is repeated ... temperature of water (in °C) is (A) 40.5 (B) 34.4 (C) 26.8 (D) 25

Last Answer : (B) 34.4

The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Description : The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity g = 10 m/s^2. The natural frequency of this spring-mass system (in rad/s) is A 100 B 150 C 200 D 250

Last Answer : A 100

Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None

Description : Natural frequency of simple pendulum is proportional to A. Length B. Acceleration due to gravity C. Both D. None

Last Answer : B. Acceleration due to gravity

If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Description : If is the speed of a locomotive in km per hour, g is the acceleration due to gravity, is the distance between running faces of the rails and is the radius of the circular curve, the required super elevation is (A) gV²/GR (B) Rg/GV² (C) GR/gV² (D) GV²/gR

Last Answer : (D) GV²/gR

Pick up the incorrect statement from the following. The super-elevation on roads is (A) Directly proportional to width of pavement (B) Directly proportional to velocity of vehicles (C) Inversely proportional to acceleration due to gravity (D) Inversely proportional to the radius of curvature

Description : Pick up the incorrect statement from the following. The super-elevation on roads is (A) Directly proportional to width of pavement (B) Directly proportional to velocity of vehicles (C) Inversely proportional to acceleration due to gravity (D) Inversely proportional to the radius of curvature

Last Answer : Answer: Option B

If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Description : If V is speed of a moving vehicle, r is radius of the curve, g is the acceleration due to gravity, W is the width of the carriageway, the super elevation is (A) WV/gr (B) W²V/gr (C) WV²/gr (D) WV/gr²

Last Answer : Answer: Option C