232+154?

232+154?
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A line AB with end point A (2,3) & B (7,8) is to be rotated about origin by 300 inclockwise direction. Determine the coordinates of end points S of rotated line. a.(3.232, 2.598) b.(5.232, 3.598) c.(3.232, 1.298) d.(3.232, 1.598)

Description : A line AB with end point A (2,3) & B (7,8) is to be rotated about origin by 300 inclockwise direction. Determine the coordinates of end points S of rotated line. a.(3.232, 2.598) b.(5.232, 3.598) c.(3.232, 1.298) d.(3.232, 1.598)

Last Answer : d.(3.232, 1.598)

if 41,232=4.1232 x10m, then m=?

Description : if 41,232=4.1232 x10m, then m=?

Last Answer : To get from 4.1232 to 41232 the decimal point need to move 4 digits to the right, so the power of 10 is 4, ie: 41232 = 4.1232 × 10⁴ → m = 4.

What is the nearest hundred to 232?

Description : What is the nearest hundred to 232?

Last Answer : 200

`._(90)^(232)Th` disintegrates to `._(82)^(208)Pb`. How many of `beta`-particle are evolved?

Description : `._(90)^(232)Th` disintegrates to `._(82)^(208)Pb`. How many of `beta`-particle are evolved?

Last Answer : `._(90)^(232)Th` disintegrates to `._(82)^(208)Pb`. How many of `beta`-particle are evolved?

The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^

Description : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^

Last Answer : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` ... )Pb` D. `.^(237)Np, .^(209)Bi`

The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^

Description : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` b)`Np^(237),Bi^(209)` c)`U^(235),Pb^

Last Answer : The correct starting material and product of different disintegration series `"is"//"are"` a)`Th^(232), Pb^(208)` ... )Pb` D. `.^(237)Np, .^(209)Bi`

The end product of the series, starting with `._(90)Th^(232)`, is

Description : The end product of the series, starting with `._(90)Th^(232)`, is

Last Answer : The end product of the series, starting with `._(90)Th^(232)`, is A. `._(82)^(208)Pb` B. `._(82)^(209)Bi` C. `._(82)^(206)Pb` D. `._(82)^(207)Pb`

The decay constant for an `alpha-` decay of `Th^(232)` is `1.58xx10^(-10)s^(-1)`. How many `alpha-`decays occur from `1 g` sample in 365 days ?

Description : The decay constant for an `alpha-` decay of `Th^(232)` is `1.58xx10^(-10)s^(-1)`. How many `alpha-`decays occur from `1 g` sample in 365 days ?

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What is 232 rounded to the nearest 10?

Description : What is 232 rounded to the nearest 10?

Last Answer : It is then 230 when rounded to the nearest 10

How many times can 7 go into 232?

Description : How many times can 7 go into 232?

Last Answer : 33 times... with 1 remainder.

What is the fraction 40 over 232 in simplest form?

Description : What is the fraction 40 over 232 in simplest form?

Last Answer : 40/232 = 20/116= 10/58 = 5/29

What is 232 as a fraction in simplest form?

Description : What is 232 as a fraction in simplest form?

Last Answer : 232 is an integer and not a fraction. However, if you must, itcan be represented in fractional form as (232*k)/k where k is anon-zero integer.

Thorium-232 decay by alpha decay . part of the nuclear equation is shown below fill in the blank with a number?

Description : Thorium-232 decay by alpha decay . part of the nuclear equation is shown below fill in the blank with a number?

Last Answer : 228

TSH hormone biochemically is a (A) Protein (B) Fat (C) Glycoprotein (D) Carbohydrate 232 MCQs IN BIOCHEMISTRY

Description : TSH hormone biochemically is a (A) Protein (B) Fat (C) Glycoprotein (D) Carbohydrate 232 MCQs IN BIOCHEMISTRY

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The term District Judge is mentioned in which of the following Article of Constitution? (1) Article 230 (2) Article 231 (3) Article 232 (4) Article 233

Description : The term District Judge is mentioned in which of the following Article of Constitution? (1) Article 230 (2) Article 231 (3) Article 232 (4) Article 233

Last Answer : (4) Article 233 Explanation: In Article 233, the term District Judge has been mentioned in the Indian Constitution.

The isotope of Uranium used in atomic reactors is – (1) U^235 (2) (2) U^236 (3) U^237 (4) U^232

Description : The isotope of Uranium used in atomic reactors is – (1) U^235 (2) (2) U^236 (3) U^237 (4) U^232

Last Answer : (1) U^235 Explanation: A nuclear reactor is a device to initiate and control a sustained nuclear chain reaction. Most commonly they are used for generating electricity and for the propulsion of ships ... fissile atomic nucleus such as U235 or U239 absorbs a neutron, it may undergo nuclear fission.

In the illustrated circuit 'A', what power is consumed by a 3 ohm resistor with a 12 volt source? EL-0041 A. 12 watts B. 48 watts C. 64 watts D. 232 watts

Description : In the illustrated circuit 'A', what power is consumed by a 3 ohm resistor with a 12 volt source? EL-0041 A. 12 watts B. 48 watts C. 64 watts D. 232 watts

Last Answer : Answer: B

In the illustration what is the minimum wattage needed for a 3 ohm resistor with a 12 VDC power source in circuit 'A'? EL-0041 A. 12 watts B. 48 watts C. 64 watts D. 232 watts

Description : In the illustration what is the minimum wattage needed for a 3 ohm resistor with a 12 VDC power source in circuit 'A'? EL-0041 A. 12 watts B. 48 watts C. 64 watts D. 232 watts

Last Answer : Answer: B

Professional Regulations Commission was created under ______. A. PD 323 B. PD 223 C. PD 232 D. RA 223

Description : Professional Regulations Commission was created under ______. A. PD 323 B. PD 223 C. PD 232 D. RA 223

Last Answer : B. PD 223

RS-232, RS-449, RS-530, V, 24 and X.21 are examples of ____________. A. standards for interfaces between modems and transmission facilities B. standards for various types of transmission channels C. standards for interfaces between terminals and modems D. standards for end to end performance of data communications system

Description : RS-232, RS-449, RS-530, V, 24 and X.21 are examples of ____________. A. standards for interfaces between modems and transmission facilities B. standards for various types of ... for interfaces between terminals and modems D. standards for end to end performance of data communications system

Last Answer : C. standards for interfaces between terminals and modems

___________ is a device in data transmission to interface data terminal equipment to an analogue transmission line. A. RS 232 B. Connector C. Modem D. RJ-11 plug

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Last Answer : C. Modem

Fast breeder reactors do not (A) Use Th-232 as fissile fuel (B) Convert fertile material to fissile material (C) Use fast neutrons for fission (D) Use molten sodium as coolant

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Last Answer : (A) Use Th-232 as fissile fuel

Which of the following nuclear materials is fissile? (A) Uranium-238 (B) Thorium-232 (C) Plutonium-239 (D) None of these

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Which of the following isotopes is not present in natural uranium? (A) U-238 (B) U-234 (C) U-235 (D) U-232

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Which of the following undergoes fission reaction easily? (A) U-235 (B) U-238 (C) Th-232 (D) None of these

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Thorium-232 (a fertile material) on absorption of a neutron gets converted into __________ , which is a fissile material. (A) Thorium-233 (B) Uranium-235 (C) Uranium-233 (D) Plutonium-239

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Which of the following signal is not standard RS-232-C signal? a. VDR b. RTS c. CTS d. DSR

Description : Which of the following signal is not standard RS-232-C signal? a. VDR b. RTS c. CTS d. DSR

Last Answer : VDR

Data aresent over pin _____ of the EIA-232 interface. A. 2 B. 3 C. 4 D. All of theabove

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In which of the following terminals the screen is regarded as an array of pixels, where each pixel is either on or off: a) Character Map Terminal b) Bit Map Terminal c) RS 232 C Terminal d) None of The Above

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How many students studying Homeopathy, do not know English? (1) 292 (2) 232 (3) 228 (4) 298

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The RS – 232 interface

Description : The RS – 232 interface

Last Answer : interconnects data sets and the transmission circuits

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Description : 8096 has following features fill up the following, i) ____ Register file, ii) ____ I/O Ports iii) ____ architecture. a) 256 byte, five 8bit, register to register b) 256 byte, four 8bit, register ... c) 232 byte, five 8bit, register to register d) 232 byte, six 8 bit, register to register

Last Answer : c) 232 byte, five 8bit, register to register

8096 has following features fill up the following, i) ____ Register file, ii) ____ I/O Ports iii) ____ architecture. a) 256 byte, five 8bit, register to register b) 256 byte, four 8bit, register to register c) 232 byte, five 8bit, register to register d) 232 byte, six 8 bit, register to register

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Last Answer : d) 232 byte, six 8 bit, register to register

If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241

Description :  If the numerator of a fraction is increased by 400% and the denominator of the fraction is increased by 300%, the resultant fraction is 18/35 . What is the original fraction? a) 72/ 175 b) 87/ 123 c) 56/232 d) 45/241

Last Answer : Answer: A Fraction is x/y (x + 400/100 x ) / (y + 300/100 y) = 18/35 (500/100) x(35) = (400/100)y (18) (5x) × 35 = 18 × 4 y 175 x = 72 y x/y = 72/175

Describe function of each pin of 9 pin RS 232 connector.

Description : Describe function of each pin of 9 pin RS 232 connector.

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State the use of MAX 232 in communication.

Description : State the use of MAX 232 in communication.

Last Answer : MAX 232 is line driver that converts from RS232 voltage levels to TTL voltage levels & vice versa in serial communication 

Why would someone pay $3,154 on interest on a new car loan when they could buy a decent used one for under that amount without a loan (or interest)?

Description : Why would someone pay $3,154 on interest on a new car loan when they could buy a decent used one for under that amount without a loan (or interest)?

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Given that the area of a figure varies as square of mean ordinate. The area of the figure is 154 sq. cm when the mean ordinate is 7 cm. The area of the figure when mean ordinate is 10.5 cm will be a.364.9 cm b.364.5 cm c.360.6 cm d.346.5 cm e.356.3 cm

Description : Given that the area of a figure varies as square of mean ordinate. The area of the figure is 154 sq. cm when the mean ordinate is 7 cm. The area of the figure when mean ordinate is 10.5 cm will be a.364.9 cm b.364.5 cm c.360.6 cm d.346.5 cm e.356.3 cm

Last Answer : d. 346.5 cm

the curved surface area of a cylinder is 154 cm. the total surface area of the cylinder is three times its curved surface area. find the volume of the cylinder. -Maths 9th

Description : the curved surface area of a cylinder is 154 cm. the total surface area of the cylinder is three times its curved surface area. find the volume of the cylinder. -Maths 9th

Last Answer : T.S.A = 3*154 = 462 cm² C.S.A = 154 cm² C.S.A = 2πrh T.S.A = 2πr(r+h) Now, In T.S.A = 2πrr + 2πrh 462 = 2πrr + 2πrh 462 = 2*22/7*r*r + 154 462 - 154 = 2*22/7*r*r 308*7/2*22 = r*r 49 = r*r R = 7 cm ... 7*h 154/44 = h 7/2 =h H = 3.5 cm or 7/2 cm Now volume = πrrh = 22/7 * 7* 7 *7/2 = 11*49 = 539 cm³

A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Description : A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Last Answer : Since 1 cm3 of water weighs 1 g. ∴ Volume of cyclinder vessel = 154 cm3 πr2h = 154 h = 154 × 7 / 22 × 3.5 × 3.5 h ;= 4 cm Hence, the depth of water is 4 cm.

The curved surface area of a cylinder is 154 cm2. -Maths 9th

Description : The curved surface area of a cylinder is 154 cm2. -Maths 9th

Last Answer : Since curved surface area of a cyclinder = 154 cm2 [given] Total surface area of cyclinder = 3 curved surface area 2πrh + 2πr2 = 3 154 154 + 2πr2 = 462 2πr2 = 462 - 154 = 308 r2 = 308 7 / 2 22 = 49 ... 154 / 44 = 3.5 cm ∴ Volume of cyclinder = πr2h = 22 / 7 7 7 3.5 = 539 cm3

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Description : The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Last Answer : Since the class marks are equally spaced. ∴ Class size = 114 - 104 = 10 If a is a class mark and h is size of class interval, then lower limit and upper limit of the class interval area a - h / 2 and a + h / ... are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.

A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Description : A cylindrical vessel can hold 154 g of water. If the radius of its base is 3.5 cm, and 1 cm3 of water weighs lg,find the depth of water. -Maths 9th

Last Answer : Since 1 cm3 of water weighs 1 g. ∴ Volume of cyclinder vessel = 154 cm3 πr2h = 154 h = 154 × 7 / 22 × 3.5 × 3.5 h ;= 4 cm Hence, the depth of water is 4 cm.

The curved surface area of a cylinder is 154 cm2. -Maths 9th

Description : The curved surface area of a cylinder is 154 cm2. -Maths 9th

Last Answer : Since curved surface area of a cyclinder = 154 cm2 [given] Total surface area of cyclinder = 3 curved surface area 2πrh + 2πr2 = 3 154 154 + 2πr2 = 462 2πr2 = 462 - 154 = 308 r2 = 308 7 / 2 22 = 49 ... 154 / 44 = 3.5 cm ∴ Volume of cyclinder = πr2h = 22 / 7 7 7 3.5 = 539 cm3

The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Description : The class marks of a frequency distribution are 104, 114, 124, 134, 144, 154, 164. -Maths 9th

Last Answer : Since the class marks are equally spaced. ∴ Class size = 114 - 104 = 10 If a is a class mark and h is size of class interval, then lower limit and upper limit of the class interval area a - h / 2 and a + h / ... are 99 - 109, 109 - 119, 119 - 129, 129 - 139, 139 - 149, 149 - 159, 159 - 169.

Find the radius of a sphere whose surface area is 154 cm square. -Maths 9th

Description : Find the radius of a sphere whose surface area is 154 cm square. -Maths 9th

Last Answer : Let 'r' be the radius of sphere Surface area of sphere = 4 πr2 ⇒ 154 = 4 πr2 ⇒ 154 = 4 x 22/7 x r2 ⇒ r 2 = 154 x 7/4 x 22 = 49/4 ⇒ r = 7/2 cm = 3.5 cm