What is the average of 96 95 92 89 88?

What is the average of 96 95 92 89 88?
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What is the approximate percentage of candidates successful to enrolled from institute A? a) 92 b) 89 c) 86 d) 96 e) 88

Description : What is the approximate percentage of candidates successful to enrolled from institute A? a) 92 b) 89 c) 86 d) 96 e) 88

Last Answer : c) 86

In the following partial sequence of mRNA, a mutation of the template DNA results in a change in codon 91 to UAA. The type of mutation is 88 89 90 91 92 93 94 GUC GAC CAG UAG GGC UAA CCG (A) Missene (B) Silent (C) Nonsense (D) Frame shit

Description : In the following partial sequence of mRNA, a mutation of the template DNA results in a change in codon 91 to UAA. The type of mutation is 88 89 90 91 92 93 94 GUC GAC CAG UAG GGC UAA CCG (A) Missene (B) Silent (C) Nonsense (D) Frame shit

Last Answer : Answer : B

Which of the four data sets have more dispersion? (A) 88 91 90 92 89 91 (B) 0 1 1 0 –1 –2 (C) 3 5 2 4 1 5 (D) 0 5 8 10 –2 –8

Description : Which of the four data sets have more dispersion? (A) 88 91 90 92 89 91 (B) 0 1 1 0 –1 –2 (C) 3 5 2 4 1 5 (D) 0 5 8 10 –2 –8

Last Answer : Answer: D

If the fare of Rajdhani Exp is Rs. 350 and that of Sapt Kranti Exp is Rs. 450 for all classes of passenger then what is the total income of both the trains during 2011 to 2013? 1) Rs. 95 crore 2) Rs. 98 crore 3) Rs. 90 crore 4) Rs. 89 crore 5) Rs. 92.5 crore

Description : If the fare of Rajdhani Exp is Rs. 350 and that of Sapt Kranti Exp is Rs. 450 for all classes of passenger then what is the total income of both the trains during 2011 to 2013? 1) Rs. 95 crore 2) Rs. 98 crore 3) Rs. 90 crore 4) Rs. 89 crore 5) Rs. 92.5 crore

Last Answer : 5) Rs. 92.5 crore

(37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Description : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? (Take 3 digits after the decimal point) a) 95.357 b) 69.567 c) 96.257 d) 78.584 e) 88.598

Last Answer : (37) 0.75 x [(7056) 0.25] ÷ (64) – 2 = (8) ? Sol: 27.75 x 1764 ÷ 64 – 2 = 8 x ? 27.75 x 27.5625 – 2 = 8 x ? 762.859/8=? ? = 95.357 Answer: a)

The system of "Memorandum of Understanding” (MoU) was introduced in - (1) 1989 - 90 (2) 1990 - 91 (3) 1987 - 88 (4) 1988 - 89

Description : The system of "Memorandum of Understanding” (MoU) was introduced in - (1) 1989 - 90 (2) 1990 - 91 (3) 1987 - 88 (4) 1988 - 89

Last Answer : (3) 1987 - 88 Explanation: The System of Memorandum of Understanding was introduced in the Public Sector Enterprises during the year 1987-88 in India. It was based on the report of the Arjuna Sengupta Committee (1984).

Consider a hash table of size m=100 and the hash function h(k) = floor(m(kA mod 1)) for A = (√5 − 1)/2 = 0.618033. Compute the location to which the key k = 123456 is placed in hash table. (A) 77 (B) 82 (C) 88 (D) 89

Description : Consider a hash table of size m=100 and the hash function h(k) = floor(m(kA mod 1)) for A = (√5 − 1)/2 = 0.618033. Compute the location to which the key k = 123456 is placed in hash table. (A) 77 (B) 82 (C) 88 (D) 89

Last Answer : (C) 88

The system of “Memorandum of Understanding” (MoU) was introduced in (1) 1989 – 90 (2) 1990 – 91 (3) 1987 – 88 (4) 1988 – 89

Description : The system of “Memorandum of Understanding” (MoU) was introduced in (1) 1989 – 90 (2) 1990 – 91 (3) 1987 – 88 (4) 1988 – 89

Last Answer : 1987 – 88

Water comprises approximately ____ percent of cleaning and sanitizing solutions. a. 80 to 89 c. 90 to 95 b. 95 to 99 d. 75 to 85

Description : Water comprises approximately ____ percent of cleaning and sanitizing solutions. a. 80 to 89 c. 90 to 95 b. 95 to 99 d. 75 to 85

Last Answer : b. 95 to 99

A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Description : A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Last Answer : a. 500 KJ

Damped natural frequency of a system with ωn =100 Hz and ς = 20% is given by A) 92 Hz B) 94 Hz C) 96 Hz D) 98 Hz

Description : Damped natural frequency of a system with ωn =100 Hz and ς = 20% is given by A) 92 Hz B) 94 Hz C) 96 Hz D) 98 Hz

Last Answer : D) 98 Hz

The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Description : The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Last Answer : Here's ur answer..

The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Description : The mean of 200 items was 50. Later on, it was discovered that the two items were misread as 92 and 8 instead of 192 and 88.find the correct mean. -Maths 9th

Last Answer : Here's ur answer..

Presence of nitrogen in high concentration in contaminated air reduces partial pressure of oxygen in lungs, thereby causing asphyxia (suffocation) leading to death from oxygen deficiency. Concentration of N2 in contaminated air at which it acts as a natural asphyxiate is ≥ __________ percent. (A) 84 (B) 88 (C) 80 (D) 92

Description : Presence of nitrogen in high concentration in contaminated air reduces partial pressure of oxygen in lungs, thereby causing asphyxia (suffocation) leading to death from oxygen deficiency. Concentration of N2 in contaminated air at ... asphyxiate is ≥ __________ percent. (A) 84 (B) 88 (C) 80 (D) 92

Last Answer : (A) 84

In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Description : In a class there are 15 boys and 10 girls. Three students are selected at random. The difference between the probability that 2 boys and 1 girl are selected compared to 1 boy and 2 girls are selected is: a) 23/78 b) 19/88 c) 15/92 d) 4/23 e) 7/46

Last Answer : 2 boys, 1 gi(Prl = (15c2×10c1) / 25c3 = 1050/2300 1 boy, 2 girls = (15c1×10c2) / 25c3 = 675/2300 Difference = (1050 - 675)/2300 = 375/2300 = 15/92 Answer: c)

67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Description : 67,74,78,?,92,94 a) 86 b) 85 c) 83 d) 84 e) 88

Last Answer : The next term is obtained by adding the unit’s digit to the number. Hence the missing number =78+8=86 Answer: a)

180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C and D in ratio 3 : 4. What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Description : 180 sweets are divided among friends A, B, C and D in which B and C are brothers also such that sweets divided between A and B are in the ratio 2 : 3, between B and C in the ratio 2 : 5 and between C ... . What is the number of sweets received by the brothers together? A) 78 B) 84 C) 92 D) 102 E) 88

Last Answer : Answer: B A : B : C : D 2*2*3 : 3*2*3 : 3*5*3 : 3*5*4 4 : 6 : 15 : 20 B and C together = [(6+15)/(4+6+15+20)] * 180 = 84

Are 64 88 96 108 divisible by what number?

Description : Are 64 88 96 108 divisible by what number?

Last Answer : 1, 2 and 4

At what degree does the cutter bar is set for achieving the object ? a) 96 b) 88 c) 69 and half. d) 105

Description : At what degree does the cutter bar is set for achieving the object ? a) 96 b) 88 c) 69 and half. d) 105

Last Answer : 88

In the neutron`-`induced fissioin reaction of `._(92)U^(235)` one of the products if `._(37)Rb^(95),` in this mode, another nuclide and three neutrons

Description : In the neutron`-`induced fissioin reaction of `._(92)U^(235)` one of the products if `._(37)Rb^(95),` in this mode, another nuclide and three neutrons

Last Answer : In the neutron`-`induced fissioin reaction of `._(92)U^(235)` one of the products if `._(37)Rb^(95),` in this ... `._(55)^(145)Co` D. `._(54)^(143)Xe`

If the unit weight of sand particles is 2.696 g/cc. and porosity in loose state is 44%, the critical hydraulic gradient for quick sand condition, is (A) 0.91 (B) 0.92 (C) 0.93 (D) 0.95

Description : If the unit weight of sand particles is 2.696 g/cc. and porosity in loose state is 44%, the critical hydraulic gradient for quick sand condition, is (A) 0.91 (B) 0.92 (C) 0.93 (D) 0.95

Last Answer : (D) 0.95

A soil sample of mass specific gravity 1.92 has moisture content 30%. If the specific gravity of solids is 2.75, the degree of saturation, is (A) 95.4 % (B) 95.5 % (C) 95.6 % (D) 95.7 %

Description : A soil sample of mass specific gravity 1.92 has moisture content 30%. If the specific gravity of solids is 2.75, the degree of saturation, is (A) 95.4 % (B) 95.5 % (C) 95.6 % (D) 95.7 %

Last Answer : Option D

12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these

Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)

When caring for a patient with an uncomplicated, mild urinary tract infection (UTI), the nurse knows that recent studies have shown which of the following drugs to be a good choice for shortcourse (e.g. 3-day) therapy? a) Levofloxacin (Levaquin) Levofloxacin, a floroquinolone, is a good choice for short-course therapy of uncomplicated, mild to moderate UTI. Clinical trial data show high patient compliance with the 3-day regimen (95.6%) and a high eradication rate for all pathogens (96.4%).

Description : When caring for a patient with an uncomplicated, mild urinary tract infection (UTI), the nurse knows that recent studies have shown which of the following drugs to be a good choice for ... to be significantly more effective than TMP-SMX in community-based patients and in nursing home residents.

Last Answer : a) Levofloxacin (Levaquin) Levofloxacin, a floroquinolone, is a good choice for short-course therapy of uncomplicated, mild to moderate UTI. Clinical trial data show high patient compliance with the 3-day regimen (95.6%) and a high eradication rate for all pathogens (96.4%).

Which one of the following statements about the mass spectrum of CH3Br is correct? a. the last two peaks are of equal size and occur at m/z values of 94 and 96 b. the last two peaks have abundances in the ratio 3:1 and occur at m/z values of 94 and 96 c. there is just one peak for the molecular ion with an m/z value of 95 d. there is just one peak for the molecular ion with an m/z value of 44

Description : Which one of the following statements about the mass spectrum of CH3Br is correct? a. the last two peaks are of equal size and occur at m/z values of 94 and 96 b. the last two peaks have abundances in the ... m/z value of 95 d. there is just one peak for the molecular ion with an m/z value of 44

Last Answer : a. the last two peaks are of equal size and occur at m/z values of 94 and 96

The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88

The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Description : The scores of an English test out of 100 of 20 students are given below : 75, 69, 88, 55, 95, 88, 73, 64, 75, 98, 88, 95, 90, 95, 88, 44, 59, 67, 88, 99. -Maths 9th

Last Answer : Median=n=even =n/2=20/2=10th observation =98 Mode =88

I need a prime number that's greater than 88 but less than 95 what should i do?

Description : I need a prime number that's greater than 88 but less than 95 what should i do?

Last Answer : 89, 91 etc.

What is a prime number that is greater than 88 and less than 95?

Description : What is a prime number that is greater than 88 and less than 95?

Last Answer : 89

When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be _______ EL-0018 A. 88.95 milliamps B. 103.45 milliamps C. 11.24 milliamps D. 0.91 amps

Description : When a voltage of 115 VDC is applied to the illustrated circuit with a resistance of 10,230 ohms the current will be _______ EL-0018 A. 88.95 milliamps B. 103.45 milliamps C. 11.24 milliamps D. 0.91 amps

Last Answer : Answer: C

A 2 kg object weighs 1.8 kgf on a spring balance. The value of 'g' at that location in m/sec2is (A) 8.82 (B) 9.81 (C) 10.88 (D) 0.95

Description : A 2 kg object weighs 1.8 kgf on a spring balance. The value of 'g' at that location in m/sec2is (A) 8.82 (B) 9.81 (C) 10.88 (D) 0.95

Last Answer : (A) 8.82

The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Description : The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Last Answer : d. 118.0 to 136.975 MHz

The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Description : The full range of VHF frequencies used for communications is: a. 3 to 30 MHz b. 88 to 108 MHz c. 108.0 to 139.95 MHz d. 118.0 to 136.975 MHz

Last Answer : d. 118.0 to 136.975 MHz

According to the United Nations’ publication, Ending Hunger: An Idea Whose Time Has Come, in the last 88 years, ____ countries have done away with hunger; 41 of these countries have done it since ____. a. 80, 1970 c. 95, 1980 b. 70, 1955 d. 75, 1960

Description : According to the United Nations’ publication, Ending Hunger: An Idea Whose Time Has Come, in the last 88 years, ____ countries have done away with hunger; 41 of these countries have done it since ____. a. 80, 1970 c. 95, 1980 b. 70, 1955 d. 75, 1960

Last Answer : d. 75, 1960

The average heart beat rate per minute in a normal person is - (1) 82 (2) 92 (3) 72 (4) 98

Description : The average heart beat rate per minute in a normal person is - (1) 82 (2) 92 (3) 72 (4) 98

Last Answer : (3) 72 Explanation: The average heart rate for adult humans is about 70 to 75 beats per minute in a normal relaxed mode. While we tend to think of the "normal" heart beat rate as being "72 ... health risk. The "72 beats per minute" that we are familiar with is the normal average heart beat rate.

The ultimate average anchorage bond stress for plain bars in tension is _______ if the grade of concrete is M20 [ A ] 1.60 N/mm2 [ B ] 1.92 N/mm2 [ C ] 2.24 N/mm2 [ D ] 2.40 N/mm2

Description : The ultimate average anchorage bond stress for plain bars in tension is _______ if the grade of concrete is M20 [ A ] 1.60 N/mm2 [ B ] 1.92 N/mm2 [ C ] 2.24 N/mm2 [ D ] 2.40 N/mm2

Last Answer : [ B ] 1.92 N/mm2

The ultimate average anchorage bond stress for plain bars in tension is _______ if the grade of concrete is M20 [ A ] 1.60 N/mm2 [ B ] 1.92 N/mm2 [ C ] 2.24 N/mm2 [ D ] 2.40 N/mm2

Description : The ultimate average anchorage bond stress for plain bars in tension is _______ if the grade of concrete is M20 [ A ] 1.60 N/mm2 [ B ] 1.92 N/mm2 [ C ] 2.24 N/mm2 [ D ] 2.40 N/mm2

Last Answer : [ B ] 1.92 N/mm2

One mg of Lycopodium spores used in quantitative microscopy contains an average of (A) 94,000 spores (B) 92,000 spores (C) 90,000 spores (D) 91,000 spores

Description : One mg of Lycopodium spores used in quantitative microscopy contains an average of (A) 94,000 spores (B) 92,000 spores (C) 90,000 spores (D) 91,000 spores

Last Answer : (A) 94,000 spores

The average heartbeat rate per minute in a normal person is (1) 82 (2) 92 (3) 72 (4) 98

Description : The average heartbeat rate per minute in a normal person is (1) 82 (2) 92 (3) 72 (4) 98

Last Answer : 72

The average heart beat rate per minute in a normal person is (1) 82 (2) 92 (3) 72 (4) 98

Description : The average heart beat rate per minute in a normal person is (1) 82 (2) 92 (3) 72 (4) 98

Last Answer : 72

The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight of the group of 75 women? (rounded off to two digits after decimal) (a) 46.73 kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Description : The average weight of a group of 75 women was calculated as 47 kg. It was later discovered that the weight of one of the women was read as 45 kg, whereas her actual weight was 25kg. What is the actual average weight ... kg (b) 46.64 kg (c) 45.96 kg (d) Cannot be determined (e) None of these

Last Answer : (a) 46.73 kg

A server crashes on the average once in 30 days, that is, the Mean Time Between Failures (MTBF) is 30 days. When this happens, it takes 12 hours to reboot it, that is, the Mean Time to Repair (MTTR) is 12 hours. The availability of server with these reliability data values is approximately: (A) 96.3% (B) 97.3% (C) 98.3% (D) 99.3%

Description : A server crashes on the average once in 30 days, that is, the Mean Time Between Failures (MTBF) is 30 days. When this happens, it takes 12 hours to reboot it, that is, the Mean Time to Repair (MTTR) is 12 ... these reliability data values is approximately: (A) 96.3% (B) 97.3% (C) 98.3% (D) 99.3%

Last Answer : (C) 98.3%

The batting average of runs of a cricket player of 30 innings was 96. How many runs must he make in his next innings so as to increase his average of runs by 12? A) 468 b) 668 C) 648 D) 486

Description : The batting average of runs of a cricket player of 30 innings was 96. How many runs must he make in his next innings so as to increase his average of runs by 12? A) 468 b) 668 C) 648 D) 486

Last Answer : A  Given that the total average runs of a cricket player (30 innings) = 96 After 31 innings = 108 Required number of runs = (108 * 31 – (96 *30) =3348 – 2880 =468

What is the average of 75 and a 88?

Description : What is the average of 75 and a 88?

Last Answer : 81.575 + 88 = 163163 / 2 = 81.5

A batsman average for 20 innings is 25 runs. His highest score exceeds his lowest score by 64 runs. If these 2 innings are excluded, the average of the remaining 18 innings is 24 runs. The highest score of the player is. A) 66 B) 72 C) 77 D) 88

Description : A batsman average for 20 innings is 25 runs. His highest score exceeds his lowest score by 64 runs. If these 2 innings are excluded, the average of the remaining 18 innings is 24 runs. The highest score of the player is. A) 66 B) 72 C) 77 D) 88

Last Answer : A) Let the highest score be ‘x’ Then lowest score = x-64 Then (25 *20)- 18 * 24 = 432 X+X-64=68 X=66

There are two groups of a class consisting of 72 and 88 students respectively. If the average weight of 1st group is 80kg and the weight of 2nd group is 70kg. Find the average weight of whole class? A) 64kg B) 74.5kg C) 84.5kg D) 54kg

Description : There are two groups of a class consisting of 72 and 88 students respectively. If the average weight of 1st group is 80kg and the weight of 2nd group is 70kg. Find the average weight of whole class? A) 64kg B) 74.5kg C) 84.5kg D) 54kg

Last Answer :  B)  Total weight of (72 + 88) = (72*80) + (88 * 70)kg = (5760 + 6160)kg  = 11,920kg  Average weight of the whole class = 11920 / 160  = 74.5 kg

What is the average of 83 87 91 95?

Description : What is the average of 83 87 91 95?

Last Answer : 83 + 87 + 91 + 95 = 356, 356 / 4 = 89. The average of those 4 numbers is 89. You add all of the numbers together and then divide that sum by the number of values.

Average stock of firm is Rs. 80,000, the opening stock is Rs. 10,000 less than closing stock. Find opening stock. (A) Rs. 95,000 (B) Rs. 85,000 (C) Rs. 90,000 (D) Rs. 75,000

Description : Average stock of firm is Rs. 80,000, the opening stock is Rs. 10,000 less than closing stock. Find opening stock. (A) Rs. 95,000 (B) Rs. 85,000 (C) Rs. 90,000 (D) Rs. 75,000

Last Answer : Answer: Rs. 75,000

A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the programmer Rs.60,000 per month and the tester Rs.50,000 per month. The average productivity for the team is 8 FP per person month. Which of the following represents the projected cost of the project? (1) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Description : A software project was estimated at 352 Function Points (FP). A four person team will be assigned to this project consisting of an architect, two programmers, and a tester. The salary of the architect is Rs.80,000 per month, the ... ) Rs.28,16,000 (2) Rs.20,90,000 (3) Rs.26,95,000 (4) Rs.27,50,000

Last Answer : (4) Rs.27,50,000 

The batting average for 20 innings of a cricketer is 25 runs. His highest score exceeds his lowest score by 86 runs. If these two innings are excluded, the average of the remaining 18 innings is 22runs. Find out the highest score of the player. A) 85 B) 90 C) 95 D) 100

Description : The batting average for 20 innings of a cricketer is 25 runs. His highest score exceeds his lowest score by 86 runs. If these two innings are excluded, the average of the remaining 18 innings is 22runs. Find out the highest score of the player. A) 85 B) 90 C) 95 D) 100

Last Answer : C) Total runs scored by the player in 20 innings = 20*25 Total runs scored by the player in 18 innings after excluding two innings = 18 22 Sum of the scores of the excluded innings = 20 25 - 18 22 = 104 Given that ... Now x + 86 + x = 104 => 2x = 18 then x = 9 Highest score = 9+ 86 = 95