What are the common factors of 11 12 13 14 and 15?

What are the common factors of 11 12 13 14 and 15?
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1 is a common factor of 11, 12, 13, 14 and 15.
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I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 XII=12 XIII=13 XIV=14 XV=15...... Of course, I + XI = X is wrong. You are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Description : I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 ... are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Last Answer : Most people would get to one move at the least, but the real answer is zero moves. If you rotate the whole question around 180 degrees, it will display this: X = IX + I

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

the range of the data 13, 18, 20, 15, 12, 17, 9, 14, 11, and 16 is ________.

Description : the range of the data 13, 18, 20, 15, 12, 17, 9, 14, 11, and 16 is ________.

Last Answer : the range of the data 13, 18, 20, 15, 12, 17, 9, 14, 11, and 16 is ________.

Implement F(A,B,C,D)= Ʃ (1,3,4,11,12,13,14,15) using multiplexer

Description : Implement F(A,B,C,D)= Ʃ (1,3,4,11,12,13,14,15) using multiplexer

Last Answer : • Implementation • Table • Explanation

What is the output of the following? i = 5 while True: if i%0O9 == 0: break print(i) i += 1 a) 5 6 7 8 b) 5 6 7 8 9 c) 5 6 7 8 9 10 11 12 13 14 15 …. d) error

Description : What is the output of the following? i = 5 while True: if i%0O9 == 0: break print(i) i += 1 a) 5 6 7 8 b) 5 6 7 8 9 c) 5 6 7 8 9 10 11 12 13 14 15 …. d) error

Last Answer : d) error

Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by Image (A) {(11,0.8), (13,1), (15,1)} (B) {(11,0.3), (12,0.5), (13,1), (14,1), (15,1), (16,0.5), (17,0.2)} (C) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,1), (16,0.5), (17,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Description : Let A and B be two fuzzy integers defined as: A={(1,0.3), (2,0.6), (3,1), (4,0.7), (5,0.2)} B={(10,0.5), (11,1), (12,0.5)} Using fuzzy arithmetic operation given by (A) {(11,0.8), (13,1), (15,1)} ( ... ,0.2)} (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Last Answer : (D) {(11,0.3), (12,0.5), (13,0.6), (14,1), (15,0.7), (16,0.5), (17,0.2)}

Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB(x))) Then, f(A+B) is equal to (A) {(0.5,12), (0.6,13), (1,14), (0.7,15), (0.7,16), (1,17), (1,18)} (B) {(0.5,12), (0.6,13), (1,14), (1,15), (1,16), (1,17), (1,18)} (C) {(0.3,12), (0.5,13), (0.5,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Description : Compute the value of adding the following two fuzzy integers: A = {(0.3,1), (0.6,2), (1,3), (0.7,4), (0.2,5)} B = {(0.5,11), (1,12), (0.5,13)} Where fuzzy addition is defined as μA+B(z) = maxx+y=z (min(μA(x), μB( ... ,18)} (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)}

Last Answer : (D) {(0.3,12), (0.5,13), (0.6,14), (1,15), (0.7,16), (0.5,17), (0.2,18)} 

In each of the following questions, find the odd number/letters/word from the given alternatives. 10. (a) PQXZ (b) BCQN (c) ABDF (d) MNPR 11. (a) ABYZ (b) CDWX (c) EFUV (d) GHTV 12. (a) 626 (b) 841 (c) 962 (d) 1090 13. (a) 5720 (b) 6710 (c) 2640 (d) 4270 14. (a) Swimming (b) Sailing (c) Dividing (d) Driving 15. (a) Perception (b) Discernment (c) Penetration (d) Insinuation

Description : In each of the following questions, find the odd number/letters/word from the given alternatives. 10. (a) PQXZ (b) BCQN (c) ABDF (d) MNPR 11. (a) ABYZ (b) CDWX (c) EFUV (d) GHTV 12. ... ) Sailing (c) Dividing (d) Driving 15. (a) Perception (b) Discernment (c) Penetration (d) Insinuation 

Last Answer : 10. (b) 11. (d) 12. (b) 13. (d) 14. (d) 15. (d)

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

What is the median of this set of data values 11 13 14 15 18 20 23 26?

Description : What is the median of this set of data values 11 13 14 15 18 20 23 26?

Last Answer : Feel Free to Answer

24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Description : 24 14 26 ? 28 16 30 a) 13 b) 17 c) 15 d) 11 e) 20

Last Answer : The series consists of two series 1 and 2: Series 1 : 24 26 28 30 +2 +2 +2 Series 2 : 14 15 16 +1 +1 Answer: c)

What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Description : What least number would be subtracted from 427398 so that the remaining number is divisible by 15? 1. 13 2. 3 3. 16 4. 11 5. 14

Last Answer : Answer- 2 ( 3) Explanation:- On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted 

Which one of the following array represents a binary max-heap? (A) [26, 13, 17, 14, 11, 9, 15] (B) [26, 15, 14, 17, 11, 9, 13] (C) [26, 15, 17, 14, 11, 9, 13] (D) [26, 15, 13, 14, 11, 9, 17]

Description : Which one of the following array represents a binary max-heap? (A) [26, 13, 17, 14, 11, 9, 15] (B) [26, 15, 14, 17, 11, 9, 13] (C) [26, 15, 17, 14, 11, 9, 13] (D) [26, 15, 13, 14, 11, 9, 17]

Last Answer : (C) [26, 15, 17, 14, 11, 9, 13]

The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Description : The mean of 8 article was found to be 15. On rechecking, it was found that two article were wrongly taken as 11 and 9 instead of 16 and 14 respectively. Find the correct mean. A) 17.25 B) 13.65 C) 16.54 D) 16.25

Last Answer : D) Calculated mean of 8 articles = 15 Incorrect sum of these 8 articles = (15*8) = 120. Correct sum of these 8 articles = (incorrect sum) - (sum of incorrect articles) + (sum of actual articles) = [120 ... (30)] = 130 Therefore, correct mean = 130/8 = 16.25 Hence, the correct mean is 16.25.

A cartoon contains 15 torch lights out of which 3 are defective. Two torch light are chosen at random from this cartoon. The probability that at least one of these is defective is. A) 13/35 B) 14/35 C) 11/35 D) 17/35

Description : A cartoon contains 15 torch lights out of which 3 are defective. Two torch light are chosen at random from this cartoon. The probability that at least one of these is defective is. A) 13/35 B) 14/35 C) 11/35 D) 17/35

Last Answer : Answer: A) P (none is defective) = 12c2/15c2 = (12*11/2*1)/(15*14/2*1) = 66/105=22/35 P (at least one is defective) = (1 – 22/35) =13/35

All active prostaglandins have atleast one double bond between positions: (A) 7 and 8 (B) 9 and 10 (C) 11 and 12 (D) 13 and 14 FATS AND FATTY ACID METABOLISM 95

Description : All active prostaglandins have atleast one double bond between positions: (A) 7 and 8 (B) 9 and 10 (C) 11 and 12 (D) 13 and 14 FATS AND FATTY ACID METABOLISM 95

Last Answer : Answer : A

Process B had no opening inventory. 13,500 units of raw material were transferred in at Rs 4.50 per unit. Additional material at Rs1.25per unit was added in process. Labour and overheads were Rs 6.25 per completed unit and Rs 2.50 per unit incomplete. If 11,750completed units were transferred out, what was the closing inventory in Process B? (a) Rs. 6562.50 (b) Rs. 12,250.00 (c) Rs. 14,437.50 (d) Rs. 25,375.00

Description : Process B had no opening inventory. 13,500 units of raw material were transferred in at Rs 4.50  per unit. Additional material at Rs1.25per unit was added in process. Labour and overheads were Rs 6.25  per completed unit and Rs ... 6562.50 (b) Rs. 12,250.00 (c) Rs. 14,437.50 (d) Rs. 25,375.00

Last Answer : (a) Rs 142,485

Total managerial remuneration cannot exceed ____% of net profit A. 11 B. 12 C. 13 D. 14

Description : Total managerial remuneration cannot exceed ____% of net profit A. 11 B. 12 C. 13 D. 14

Last Answer : A. 11

Aakash and Aravind are partners in a business. Aakash contributes 1/5 of the capital of 16 months and aravind received ¾ of the profit. For how long Aravind money was used? A) 11 months B) 12 months C) 13 months D) 14 months

Description : Aakash and Aravind are partners in a business. Aakash contributes 1/5 of the capital of 16 months and aravind received ¾ of the profit. For how long Aravind money was used? A) 11 months B) 12 months C) 13 months D) 14 months

Last Answer : Answer: B) Let the total profit be Rs z Then, Aravind share = 3z/4 Aakash share = z - 3z/4 = z/4 Aakash : Aravind = Z/4 : 3z/4 = 1:3 Let the total capital be Rs x Suppose Aravind's money was used for y months.then, ... * 16/4/5x * y = 1/3 3 (16x/5) = 4x/5 * y 48 = 4y Y = 48/4 = 12 months.

the median of the data 13, 12, 14, 13, 15, 16, 18, is _______.

Description : the median of the data 13, 12, 14, 13, 15, 16, 18, is _______.

Last Answer : the median of the data 13, 12, 14, 13, 15, 16, 18, is _______.

What is the nth term for 12 13 14 15?

Description : What is the nth term for 12 13 14 15?

Last Answer : Need answer

Which of the following nuclei would be the most stable A. 10 protons , 14 neutrons B. 10 protons, 15 neutrons C. 10 protons, 13 neutrons D. 10 protons, 12 neutrons.?

Description : Which of the following nuclei would be the most stable A. 10 protons , 14 neutrons B. 10 protons, 15 neutrons C. 10 protons, 13 neutrons D. 10 protons, 12 neutrons.?

Last Answer : (Explanation): remember that if an atom has less than 20 protons, the closer the number of neutrons and protons are, the more stable it is. Since 10 is closest to 12 out of these options, D is the correct answer.

How many sahaaba were martyred in Battle of Badar? A. 12 B. 13 C. 14 D. 15

Description : How many sahaaba were martyred in Battle of Badar? A. 12 B. 13 C. 14 D. 15

Last Answer : ANSWER: C

How many sahaaba were martyred in Battle of Badar? A. 12 B. 13 C. 14 D. 15

Description : How many sahaaba were martyred in Battle of Badar? A. 12 B. 13 C. 14 D. 15

Last Answer : ANSWER: C

How many sahaaba were martyred in Battle of Badar? A. 12 B. 13 C. 14 D. 15

Description : How many sahaaba were martyred in Battle of Badar? A. 12 B. 13 C. 14 D. 15

Last Answer : ANSWER: C

Diameter of Sun is-------? A. 12 Lakh kms B. 13 Lakh kms C. 14 Lakh kms (Answer) D. 15 Lakh kms

Description : Diameter of Sun is-------? A. 12 Lakh kms B. 13 Lakh kms C. 14 Lakh kms (Answer) D. 15 Lakh kms

Last Answer : C. 14 Lakh kms (Answer)

To how many degrees did the narrator turn as per the instructions from the Paris Control Room? a) 12 b) 13 c) 14 d) 15

Description : To how many degrees did the narrator turn as per the instructions from the Paris Control Room? a) 12 b) 13 c) 14 d) 15

Last Answer : a) 12

Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Description : Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is: a) 10 b) 14 c) 12 d) 13 e) 15

Last Answer : (A+B+C) - (A+B) (A+B+C) =1/6 and (A+B+C) in 2hrs=2/6 and remaining part 1-2/6=2/3. So (A+B) in 7 hrs is 2/ (3*7) =2/21. 1/6-2/21=1/14 so answer is 14. Answer: b)

Find the number which when multiplied by 13 is increased by 180: 1. 20 2. 15 3. 12 4. 5 5. 14

Description : Find the number which when multiplied by 13 is increased by 180: 1. 20 2. 15 3. 12 4. 5 5. 14

Last Answer : Answer- 2 (15) Explanation:- let no. be X X *13= X+180 !2x=180 x=15

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, 50% of the components were rejected. What is the loss to the manufacture? [TCS recruitment exam question] A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Description : A manufacture undertakes to supply 2000 pieces of a particular component at Rs.25 per piece. According to his estimates, even if 5% fail to pass the quality tests, then he will make a profit of 25%. However as it turned out, ... A. Rs 12,000 B. Rs 13,000 C. Rs 14,000 D. Rs 15,000 E. None f these

Last Answer : Answer - B. Rs 13,000 Explanation: 5% of 2000=100 so 2000-100=1900 so,if he sells 1900 he will get 25% profit cost per piece rs 25 so 25x 1900 don't solve here if 125% . ... /125=38000=CP if 50% rejected,only 1000 pieces sold so 1000 25=25000=SP loss=cp-sp= 38000-25000=13000

A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 12. Two faces measuring 4 cm x 1 cm are coloured in black. 13. Two faces measuring 6 cm x 1 cm are coloured in red. 14. Two faces measuring 6 cm x 4 cm are coloured in green. 15. The block is divided into 6 equal cubes of side 1 cm (from 6 cm side), 4 equal cubes of side 1 cm(from 4 cm side). How many cubes will have 4 coloured sides and two non-coloured sides ? (a)8 (b)4 (c)16 (d)10

Description : A cuboid shaped wooden block has 6 cm length, 4 cm breadth and 1 cm height. 12. Two faces measuring 4 cm x 1 cm are coloured in black. 13. Two faces measuring 6 cm x 1 cm are coloured in red. 14. Two ... How many cubes will have 4 coloured sides and two non-coloured sides ? (a)8 (b)4 (c)16 (d)10

Last Answer : Answer key : (b)

In how many ways can the string A ∩ B - A ∩ B - A be fully parenthesized to yield an infix expression? (A) 15 (B) 14 (C) 13 (D) 12

Description : In how many ways can the string A ∩ B - A ∩ B - A be fully parenthesized to yield an infix expression? (A) 15 (B) 14 (C) 13 (D) 12

Last Answer : (B) 14

The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Description : The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Last Answer : Answer : E Given ratio of number of candidates is 4:5:6 Let the number of candidates for 3 exams be 4k, 5k and 6k respectively. After increasing, number of candidates become (140% of 4k), (160% of 5k) & (185% ... 111k/10 Now, the required new ratio is: 56k/100 : 80k/10 : 111k/10 = 56 : 80 : 111

In the following question, select the odd number from the given alternatives. Options: 1)13-5 2) 15-7 3) 12-6 4) 14-6

Description :  In the following question, select the odd number from the given alternatives.  Options: 1)13-5 2) 15-7 3) 12-6 4) 14-6 

Last Answer : 1 and 2

The average of 12 numbers is 7.9. The average of 5 of them is 6.8, while the average of other five is 7.7. what is the average of the remaining 2 numbers? A) 10.25 B) 11.15 C) 12.65 D) 13.25

Description : The average of 12 numbers is 7.9. The average of 5 of them is 6.8, while the average of other five is 7.7. what is the average of the remaining 2 numbers? A) 10.25 B) 11.15 C) 12.65 D) 13.25

Last Answer : B) Sum of the remaining 2 numbers = [(12 * 7.9) – (586.8) – (5*7.7)]  = 94.8 – 34 – 38.5  = 22.3  Required average = 22.3 / 2  = 11.15

The stoichiometric air fuel ration for petrol is 15:1 . What is the air fuel ratio required for maximum power? (a) 16:1 – 18:1 (b) 15:1 (c) 12:1 – 14:1 (d) 9:1 – 11:1

Description : The stoichiometric air fuel ration for petrol is 15:1 . What is the air fuel ratio required for maximum power? (a) 16:1 – 18:1 (b) 15:1 (c) 12:1 – 14:1 (d) 9:1 – 11:1

Last Answer : Ans :c

Which of the following are uplinks in the Ku band? A. 14 to 14.5 GHz B. 11.7 to 12.2 GHz C. 14 to 15.5 GHz D. 11 to 11.5 GHz

Description : Which of the following are uplinks in the Ku band? A. 14 to 14.5 GHz B. 11.7 to 12.2 GHz C. 14 to 15.5 GHz D. 11 to 11.5 GHz

Last Answer : A. 14 to 14.5 GHz

‘Order’ is defined in………………..of Code of civil Procedure 1908. (a) 2(11) (b) 2(14) (c) 2(15) (d) 2(12)

Description : ‘Order’ is defined in………………..of Code of civil Procedure 1908. (a) 2(11) (b) 2(14) (c) 2(15) (d) 2(12)

Last Answer : (b) 2(14)

All active prostaglandins have at least one double bond between positions (A) 7 and 8 (B) 10 and 11 (C) 13 and 14 (D) 16 and 17

Description : All active prostaglandins have at least one double bond between positions (A) 7 and 8 (B) 10 and 11 (C) 13 and 14 (D) 16 and 17

Last Answer : Answer : A

During the fiscal year 2010-11 gross fixed capital formation or domestic investment was _____ A. 10.3% B. 11.11% C. 13.4% D. 14.7%

Description : During the fiscal year 2010-11 gross fixed capital formation or domestic investment was _____ A. 10.3% B. 11.11% C. 13.4% D. 14.7%

Last Answer : ANSWER: C

During the fiscal year 2010-11 gross fixed capital formation or domestic investment was _____ A. 10.3% B. 11.11% C. 13.4% D. 14.7%

Description : During the fiscal year 2010-11 gross fixed capital formation or domestic investment was _____ A. 10.3% B. 11.11% C. 13.4% D. 14.7%

Last Answer : ANSWER: C

A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Description : A pair of linear equations which has a unique solution x = 2, y = -3 is (a) x + y = -1 ; 2x – 3y = -5 (b) 2x + 5y = -11 ; 4x + 10y = -22(c) 2x – y = 1 ; 3x + 2y = 0 (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

Last Answer : (d) x – 4y – 14 = 0 ;5x – y – 13 = 0

A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Description : A bed consists of particles of density 2000 kg/m3 . If the height of the bed is 1.5 metres and its porosity 0.6, the pressure drop required to fluidise the bed by air is (A) 25.61 kPa (B) 11.77 kPa (C) 14.86 kPa (D) 21.13 kPa

Last Answer : (B) 11.77 kPa

If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

A young patient has all incisors, some premolars and some canines erupted but no 2nd molars are showing: What is his age? A. 8 years B. 11 years C. 13 years D. 14 years

Description : A young patient has all incisors, some premolars and some canines erupted but no 2nd molars are showing: What is his age? A. 8 years B. 11 years C. 13 years D. 14 years

Last Answer : B. 11 years

Amalgamation of companies is governed by - (A) AS -14 (B) AS-11 (C) AS- 13 (D) AS-9

Description : Amalgamation of companies is governed by - (A) AS -14 (B) AS-11 (C) AS- 13 (D) AS-9

Last Answer : (A) AS -14

Menarche usually occurs at age of: a) 8 and 10 years. b) 11 and 13 years. c) 14 and 16 years. d) 17 and 18 years. e) 18 and above.

Description : Menarche usually occurs at age of: a) 8 and 10 years. b) 11 and 13 years. c) 14 and 16 years. d) 17 and 18 years. e) 18 and above.

Last Answer : b) 11 and 13 years.

The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen.Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Description : The ratio between the present age of Maha and Deepa is 5:X. Maha is 9yrs younger than Parveen. Parveen’s age after 9yrs will be 33yrs. The difference between the Deepa and Maha age is same as the present age of Parveen.Find X. a) 13 b) 10 c) 11 d) 14 e) None of these

Last Answer : Answer: A P present age = 33-9 = 24 M = 24 – 9 =15 D – M = 24 D – 15 = 24 D = 24+15 = 39 15:39 = 5:13 X = 13