What is a line segment of a polyhedron where two faces intersect?

Description : Two congruent circles intersect each other at point A and B.Through A any line segment PAQ is drawn so that P,Q lie on the two circles.Prove that BP = BQ. -Maths 9th

Last Answer : Solution :- Let, O and O' be the centres of two congruent circles. As, AB is the common chord of these circles. ∴ ACB = ADB As congruent arcs subtent equal angles at the centre. ∠AOB = ∠AO'B ⇒ 1/2∠AOB = 1/2∠AO'B ⇒ ∠BPA = ∠BQA ⇒ BP = BQ (Sides opposite to equal angles)

What is a market segment? a. Group of customers with differing purchasing concerns b. Area of perceptual map where all points intersect c. Group of customers with similar purchasing concerns d. Geographic area where customers are located e. Common area of buying patterns

Description : What is a market segment? a. Group of customers with differing purchasing concerns b. Area of perceptual map where all points intersect c. Group of customers with similar purchasing concerns d. Geographic area where customers are located e. Common area of buying patterns

Last Answer : c. Group of customers with similar purchasing concerns

What is the regular polyhedron?

Description : What is the regular polyhedron?

Last Answer : A regular polyhedron has equal size faces as in the case of atetrahedron which is a triangular base pyramid that has 4equilateral triangle faces.

What is a polyhedron having a polygon for a base and triangular sides with a common vertex?

Description : What is a polyhedron having a polygon for a base and triangular sides with a common vertex?

Last Answer : A pyramid fits the given description

The region of feasible solution of a linear programming problem has a ............... property in geometry, provided the feasible solution of the problem exists. (A) concavity (B) convexity (C) quadratic (D) polyhedron

Description : The region of feasible solution of a linear programming problem has a ............... property in geometry, provided the feasible solution of the problem exists. (A) concavity (B) convexity (C) quadratic (D) polyhedron

Last Answer : (B) convexity

In Fig. 10.25, a line intersect two concentric circles with centre O at A, B, C and D, Prove that AB = CD. -Maths 9th

Description : In Fig. 10.25, a line intersect two concentric circles with centre O at A, B, C and D, Prove that AB = CD. -Maths 9th

Last Answer : Solution :- Let OP be perpendicular from O on line l. Since the perpendicular from the centre of a circle to a chord,bisects the chord.Therefore, AP = DP ...(i) BP = CP ...(ii) Subtracting (ii) from (i), we get AP - BP = DP - CP ⇒ AB = CD

Two circles with centre O and O' intersect at two points A and B. A line PQ is drawn parallel to OO' through B intersecting the circles at P and Q. Prove that PQ = 2 OO'. -Maths 9th

Description : Two circles with centre O and O' intersect at two points A and B. A line PQ is drawn parallel to OO' through B intersecting the circles at P and Q. Prove that PQ = 2 OO'. -Maths 9th

Last Answer : Solution :- Construction: Draw two circles having centres O and O' intersecting at points A and B. Draw a parallel line PQ to OO' ... iii) Again, OO' = MN [As OO' NM is a rectangle] ...(iv) ⇒ 2OO' = PQ Hence proved.

Drop manholes at the junctions of sewer lines, are provided if A. Invert level of a branch sewer is more than 60 cm that of the main sewer B. Sewer line runs along a main road C. Ordinary manhole cannot be built D. Two sewer lines intersect

Description : Drop manholes at the junctions of sewer lines, are provided if A. Invert level of a branch sewer is more than 60 cm that of the main sewer B. Sewer line runs along a main road C. Ordinary manhole cannot be built D. Two sewer lines intersect

Last Answer : ANS: A

Pick out the wrong statement about a streamline. (A) It is always parallel to the main direction of the fluid flow (B) It is a line across which there is no flow and it is equivalent to a rigid boundary(C) Streamlines intersect at isolated point of zero velocity and infinitevelocity(D) The fluid lying between any two streamlines can be considered to be inisolation and the streamline spacing varies inversely as the velocity

Description : Pick out the wrong statement about a streamline. (A) It is always parallel to the main direction of the fluid flow (B) It is a line across which there is no flow and it is ... any two streamlines can be considered to be in isolation and the streamline spacing varies inversely as the velocity

Last Answer : (A) It is always parallel to the main direction of the fluid flow

Why parallel line can not intersect -Maths 9th

Description : Why parallel line can not intersect -Maths 9th

Last Answer : Its a simple question which have a simple answer.. The answer is that :- When you draw a straight line on a paper you will find that the line is straight and when you measure it by you protector or ... so that means 90°+90°=180° which means it will never interest each other at any condition...

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Description : If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.

Why parallel line can not intersect -Maths 9th

Description : Why parallel line can not intersect -Maths 9th

Last Answer : Its a simple question which have a simple answer.. The answer is that :- When you draw a straight line on a paper you will find that the line is straight and when you measure it by you protector or ... so that means 90°+90°=180° which means it will never interest each other at any condition...

If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Description : If a line is drawn parallel to the base of an isosceles triangle to intersect its equal sides, prove that the quadrilateral, so formed is cyclic. -Maths 9th

Last Answer : Given ΔABC is an isosceles triangle such that AB = AC and also DE || SC. To prove Quadrilateral BCDE is a cyclic quadrilateral. Construction Draw a circle passes through the points B, C, D and E.

For determining the support reactions at A and B of a three hinged arch, points B and Care joined and produced to intersect the load line at D and a line parallel to the load line through A at D'. Distances AD, DD' and AD' when measured were 4 cm, 3 cm and 5 cm respectively. The angle between the reactions at A and B is (A) 30° (B) 45° (C) 60° (D) 90

Description : For determining the support reactions at A and B of a three hinged arch, points B and Care joined and produced to intersect the load line at D and a line parallel to the load line through A at D'. Distances AD, DD ... reactions at A and B is (A) 30° (B) 45° (C) 60° (D) 90

Last Answer : (D) 90

If the demand line drawn from a ridge in a flow mass curve does not intersect the curve again, it indicates that (A) Demand cannot be met by inflow (B) Reservoir was not full at the beginning (C) Both (A) and (B) (D) None of the above

Description : If the demand line drawn from a ridge in a flow mass curve does not intersect the curve again, it indicates that (A) Demand cannot be met by inflow (B) Reservoir was not full at the beginning (C) Both (A) and (B) (D) None of the above

Last Answer : Answer: Option A

Consider the following situation in a flow mass curve study when demand line drawn from a ridge in the mass curve does not intersect the mass curve again. This means that : (a) The storage is not adequate (b) The demand cannot be met by the inflow as the reservoir will not refill (c) The reservoir was not full at the beginning (d) The reservoir is wasting water by spill

Description : Consider the following situation in a flow mass curve study when demand line drawn from a ridge in the mass curve does not intersect the mass curve again. This means that : (a) The storage is not ... (c) The reservoir was not full at the beginning (d) The reservoir is wasting water by spill

Last Answer : (b) The demand cannot be met by the inflow as the reservoir will not refill

A loud buzzing noise at the contacts of a magnetic controller could indicate _____________. A. weak contact spring pressure B. misalignment of the magnet faces C. excessive line current D. mechanical binding

Description : A loud buzzing noise at the contacts of a magnetic controller could indicate _____________. A. weak contact spring pressure B. misalignment of the magnet faces C. excessive line current D. mechanical binding

Last Answer : Answer: B

Which of the following statement is true (a) Monopolist are price takers ; (b) Monopoly firm earn abnormal profits; (c) A Monopoly firm faces straight demand line ; (d) Supply curve of a monopoly firm is positive sloped

Description : Which of the following statement is true (a) Monopolist are price takers ; (b) Monopoly firm earn abnormal profits; (c) A Monopoly firm faces straight demand line ; (d) Supply curve of a monopoly firm is positive sloped

Last Answer : (a) Monopolist are price takers ;

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Description : The line segment joining the mid-points of any two sides of a triangle is parallel to the third side and equal to half of it. -Maths 9th

Last Answer : Given = A △ABC in which D and E are the mid-points of side AB and AC respectively. DE is joined . To Prove : DE || BC and DE = 1 / 2 BC. Const. : Produce the line segment DE to F , such that DE = ... of ||gm are equal and parallel] Also, DE = EF [by construction] Hence, DE || BC and DE = 1 / 2 BC

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : According to question prove that the two chords are parallel.

If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Description : If a line segment joining mid-points of two chords of a circle passes through the centre of the circle, prove that the two chords are parallel. -Maths 9th

Last Answer : Given : E and F are mid points of 2 chords AB and CD respectively. Line EF passes through centre. To prove : AB||CD ∠ OFC = ∠ OEA = 90° as line drawn through the centre to bisect the ... EF as traversal for lines AB and CD as alternate interior angles on same side are equal. Therefore, AB || CD

In Fig. 10.20, two circles intersects at two points A and B.AD and AC are diameters to the circles. Prove that B lies on the line A segment DC. -Maths 9th

Description : In Fig. 10.20, two circles intersects at two points A and B.AD and AC are diameters to the circles. Prove that B lies on the line A segment DC. -Maths 9th

Last Answer : Solution :- Jion AB ∠ABD = 90° (Angle in a semicircle) Similarly, ∠ABC = 90° So, ∠ABD + ∠ABC = 90° + 90° = 180° Therefore,DBC is a line i.e.,B lies on the segment DC.

Points P (5, -3) is one of the two points of trisection of the line segment joining points A(7, -2) and B(1, -5) near to A. find the coordinates of the other point of trisection. -Maths 9th

Description : Points P (5, -3) is one of the two points of trisection of the line segment joining points A(7, -2) and B(1, -5) near to A. find the coordinates of the other point of trisection. -Maths 9th

Last Answer : answer:

A line segment that connects any two points on the circle?

Description : A line segment that connects any two points on the circle?

Last Answer : It's called a chord.

If you create two line segments one vertical and the other horizontal to connect with line segment GH to form a right triangle how long will the vertical and horizontal line segments be?

Description : If you create two line segments one vertical and the other horizontal to connect with line segment GH to form a right triangle how long will the vertical and horizontal line segments be?

Last Answer : Need answer

A straight line segment is translated by applying the transformation equation a.Pâ€™=P+T b.Dx and Dy c.Pâ€™=P+P d.Only c

Description : A straight line segment is translated by applying the transformation equation a.Pâ€™=P+T b.Dx and Dy c.Pâ€™=P+P d.Only c

Last Answer : a.Pâ€™=P+T

Draw a line segment QR = 5 cm. Construct perpendiculars at point Q and R to it. -Maths 9th

Description : Draw a line segment QR = 5 cm. Construct perpendiculars at point Q and R to it. -Maths 9th

Last Answer : 1.Draw a line segment QR = 5 cm. 2.With Q as centre, construct an angle of 90° and let this line through Q is QX. 3. With R as centre, construct an angle of 90° and let this line through R is RY. Yes, the perpendicular lines QX and- RY are parallel.

In given figure l || m and M is the mid-point of a line segment AB. -Maths 9th

Description : In given figure l || m and M is the mid-point of a line segment AB. -Maths 9th

Last Answer : Solution of this question

Draw a line segment QR = 5 cm. Construct perpendiculars at point Q and R to it. -Maths 9th

Description : Draw a line segment QR = 5 cm. Construct perpendiculars at point Q and R to it. -Maths 9th

Last Answer : 1.Draw a line segment QR = 5 cm. 2.With Q as centre, construct an angle of 90° and let this line through Q is QX. 3. With R as centre, construct an angle of 90° and let this line through R is RY. Yes, the perpendicular lines QX and- RY are parallel.

In given figure l || m and M is the mid-point of a line segment AB. -Maths 9th

Description : In given figure l || m and M is the mid-point of a line segment AB. -Maths 9th

Last Answer : Solution of this question

Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Description : Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Last Answer : The lines are perpendicular to a common line AB. Hence, the angle between these lines will be 90+90=180∘ Since, the angle between them is 180∘, the lines are parallel to each other.

Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Description : Draw a line segment AB of 4 cm in length. Draw a line perpendicular to AB through A and B, respectively. -Maths 9th

Last Answer : To draw a line perpendicular to AB through A and B, respectively. Use the following steps of construction. 1.Draw a line segment AB = 4 cm. 2.Taking 4 as centre and radius more than ½ AB (i.e ... [since, it sum of interior angle on same side of transversal is 180°, then the two lines are parallel]

Prove that every line segment has one and only one mid-point. -Maths 9th

Description : Prove that every line segment has one and only one mid-point. -Maths 9th

Last Answer : Solution :-

In Fig. 7.19, AD and BC are equal perpendicular to a line segment AB. Show that CD bisects AB. -Maths 9th

Description : In Fig. 7.19, AD and BC are equal perpendicular to a line segment AB. Show that CD bisects AB. -Maths 9th

Last Answer : Solution :-

Prove that the line segment joining the mid-points of the diagonals of a trapezium is parallel to the parallel sides and equal to half of their difference. -Maths 9th

Description : Prove that the line segment joining the mid-points of the diagonals of a trapezium is parallel to the parallel sides and equal to half of their difference. -Maths 9th

Last Answer : In a parallelogram ABCD, the bisector of ∠ A also bisects BC at X.Prove that AD = 2AB.

Find the point of trisection of the line segment joining the points (1, 2) and (11, 9) ? -Maths 9th

Description : Find the point of trisection of the line segment joining the points (1, 2) and (11, 9) ? -Maths 9th

Last Answer : Let P divide AB in the ratio k : 1. Then, co-ordinates of P are \(\bigg(rac{7k+4}{k+1},rac{7k+4}{k+1}\bigg)\)But P ≡ (-1, -1)∴ \(rac{7k+4}{k+1}\) = -1 ⇒ 7k + 4 = - k - 1 ⇒ 8k = - ... , it means that the division is external. ∴ AB is divided by P externally in the ratio \(rac{5}{8}\) : 1, i.e. 5 : 8.

The line segment joining P(5, –2) and Q(9, 6) is divided in the ratio 3 : 1 by a point A -Maths 9th

Description : The line segment joining P(5, –2) and Q(9, 6) is divided in the ratio 3 : 1 by a point A -Maths 9th

Last Answer : Comparing y = 5\(x\) –7 with y = m\(x\) + c, the slope of given line = m = 5 ∴ Equation of a line parallel to y = 5\(x\) – 7 having y-intercept = –1 is y = 5\(x\) – 1.

The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.

If (–5, 4) divides the line segment between the co-ordinate axes in the ratio 1 : 2, then what is its equation ? -Maths 9th

Description : If (–5, 4) divides the line segment between the co-ordinate axes in the ratio 1 : 2, then what is its equation ? -Maths 9th

Last Answer : (d) x = yThe equations of the given lines are: 4x + 3y = 12 ...(i) 3x + 4y = 12 ...(ii) Solving the simultaneous equations (i) and (ii), we get\(x\) = \(rac{12}{7}\), y = \(rac{12}{7}\)∴ Point of the ... )isy - 0 = \(\bigg(rac{rac{12}{7}-0}{rac{12}{7}-0}\bigg)\) (x - 0), i.e., y = x.

A straight line passes through the points (a, 0) and (0, b). The length of the line segment contained between the axes is 13 and the product of -Maths 9th

Description : A straight line passes through the points (a, 0) and (0, b). The length of the line segment contained between the axes is 13 and the product of -Maths 9th

Last Answer : (d) \(rac{23}{\sqrt{17}}\)The given lines are:L : \(rac{x}{5}+rac{y}{b}=1\) ....(i)K : \(rac{x}{c}+rac{y}{3}=1.\) ...(ii)Since line L passes through (13, 32),\(rac{13}{ ... between parallel lines ax + by + c1 = 0 and ax + by c2 = 0 is d = \(rac{|c_2-c_1|}{\sqrt{a^2+b^2}}\bigg)\)

Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Description : Draw a circle with centre at point O and radius 5 cm. Draw its chord AB, draw the perpendicular bisector of line segment AB. Does it pass through the centre of the circle? -Maths 9th

Last Answer : STEP1: Draw a circle with centre at point O and radius 5 cm. STEP2: Draw its cord AB. STEP3: With centre A as centre and radius more than half of AB, draw two arcs, one on each side ... is perpendicular bisector of AB which is chord of circle, Hence, it passes through the centre of the circle.

Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th

Description : Draw a line segment AB of length 5.8 cm. Draw the perpendicular bisector of this line segment. -Maths 9th

Last Answer : Steps of Construction (i) Draw a line segment AB = 5.8 cm. (ii) Taking A as centre and radius more than 1/2AB, draw two arcs, one on either side of AB. (iii) Taking B as centre and ... . (iv) Join CD, intersecting AB at point P. Then, line CPD is the required perpendicular bisector of AB.

Draw a line segment of length 8.6 cm. Bisect it and measure the length of each part. -Maths 9th

Description : Draw a line segment of length 8.6 cm. Bisect it and measure the length of each part. -Maths 9th

Last Answer : Draw a line segment AB of length 8.6 cm. With A as centre and radius more than half of AB, draw arcs on both sides of AB. With the same radius and B as centre, draw arcs on the both sides of AB, ... line segment from E to F intersecting AB at C. On measuring AC and BC, we get: AC=BC=4.3 cm.

What is a line segment of a polyhedron where two faces intersect?

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