The equivalent resistance between P and Q in the figure is approximately

The equivalent resistance between P and Q in the figure is approximately
by

1 Answer

Answer :

The equivalent resistance between P and Q in the figure is approximately A. 6`Omega` B. 5.333`Omega` C. `7.5Omega` D. 20`Omega`
by
selected by

Related questions

A bakery P can sold 500 breads in 4 hours, bakery Q can sold the same number of bread in 5 hrs while bakery R can sold them in 6 hrs. All the bakeries are opened at 8 a.m while bakery P is closed at 9 p.m and the remaining 2 bakeries complete their target. Approximately at what time will the work be finished? a) 10 b) 8 c) 12 d) 6

Description : A bakery P can sold 500 breads in 4 hours, bakery Q can sold the same number of bread in 5 hrs while bakery R can sold them in 6 hrs. All the bakeries are opened at 8 a.m while bakery P is closed ... complete their target. Approximately at what time will the work be finished? a) 10 b) 8 c) 12 d) 6

Last Answer : A (P+Q+R)'s 1 hour work = (1/4 +1/5+ 1/6) =(15+12+10)/60 =37/60 Remaining work = 1- 37/60 = 23/60 (Q+R)'s 1 hour work = (1/5 +1/6) =11/30 Now 11/30 work is done by Q and R ... R in(30/11*23/60) =23/22 hrs = 1hr So the work will be finished approximately 1 hr after 9.am i.e., around 10 a.m

Which of the following is NOT equivalent to `(P^^ ~ q) rarr r`

Description : Which of the following is NOT equivalent to `(P^^ ~ q) rarr r`

Last Answer : Which of the following is NOT equivalent to `(P^^ ~ q) rarr r` A. `~ (qv ~p) rarr r` B. `~ r rarr (~ p v q)` ... (~ p ^^ q)` D. `~((p^^(~q))^^(~r))`

Find the equivalent resistance of the network showed in figure between the terminal A and B? -Technology

Description : Find the equivalent resistance of the network showed in figure between the terminal A and B? -Technology

Last Answer : This answer was deleted by our moderators...

The equivalent resistance resistance between A and B of network shown in figure is

Description : The equivalent resistance resistance between A and B of network shown in figure is

Last Answer : The equivalent resistance resistance between A and B of network shown in figure is A. `(3R)/(4)` B. `(4R)/(3)` C. 6 R D. 2 R

For the circuit shown in figure given below, the equivalent resistance points A and B is

Description : For the circuit shown in figure given below, the equivalent resistance points A and B is

Last Answer : For the circuit shown in figure given below, the equivalent resistance points A and B is A. `10Omega` B. `5 Omega` C. `(10)/(3)Omega` D. `2Omega`

If each of the resistance in the network in figure `R`, the equivalent resistance between terminals `A` and `B` is

Description : If each of the resistance in the network in figure `R`, the equivalent resistance between terminals `A` and `B` is

Last Answer : If each of the resistance in the network in figure `R`, the equivalent resistance between terminals `A` and `B` is A. R B. 5R C. 3R D. 6R

In the network of resistors shown in the adjoining figure, the equivalent resistance between A and B is

Description : In the network of resistors shown in the adjoining figure, the equivalent resistance between A and B is

Last Answer : In the network of resistors shown in the adjoining figure, the equivalent resistance between A and B is A. 54 ... `Omega` C. 36 `Omega` D. 9 `Omega`

A receiver connected to an antenna whose resistance is 50 Ω has an equivalent noise resistance of 30Ω. Calculate its equivalent noise temperature if the noise figure is equal to 1.6. A. 17.4 K B. 174K C. 1.74K D. 17K

Description : A receiver connected to an antenna whose resistance is 50 Ω has an equivalent noise resistance of 30Ω. Calculate its equivalent noise temperature if the noise figure is equal to 1.6. A. 17.4 K B. 174K C. 1.74K D. 17K

Last Answer : B. 174K

Calculate the noise figure of the receiver whose RF amplifier has an input resistance of 1000Ω and an equivalent shot-noise resistance of 2000Ω, a gain of 25 and load resistance of 125 kΩ. Given that the bandwidth is 1.0MHz and the temperature is 20˚C, and that the receiver is connected to an antenna with an impedance of 75Ω. A. 30.3 B. 3.03 C. 303 D. .303

Description : Calculate the noise figure of the receiver whose RF amplifier has an input resistance of 1000Ω and an equivalent shot-noise resistance of 2000Ω, a gain of 25 and load resistance of 125 kΩ. Given that the bandwidth is 1. ... to an antenna with an impedance of 75Ω. A. 30.3 B. 3.03 C. 303 D. .303

Last Answer : A. 30.3

One of the following is not a useful quantity for comparing the noise performance receivers. A. Input noise voltage B. Equivalent noise resistance C. Noise temperature D. Noise figure.

Description : One of the following is not a useful quantity for comparing the noise performance receivers. A. Input noise voltage B. Equivalent noise resistance C. Noise temperature D. Noise figure.

Last Answer : A. Input noise voltage

What is the total resistance of the circuit shown in figure 3- 59? (Hint: Redraw the circuit to simplify and then use equivalent resistances to compute for RT.)

Description : What is the total resistance of the circuit shown in figure 3- 59? (Hint: Redraw the circuit to simplify and then use equivalent resistances to compute for RT.)

Last Answer : 4Ω

l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Description : l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Last Answer : Though E, draw a line parallel to p intersecting L at G and n at H respectively. Since l | | m ⇒ AG | | BE and AB | | GE [by construction] ∴ Opposite sides of quadrilateral AGEB are ... ∠DGE = ∠FHE [alternate interior angles] By ASA congruence axiom, we have △DEG ≅ △FEH Hence, DE = EF

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Description : In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Last Answer : In △PAD, ∠A = 90° and DA = PA = PB ⇒ ∠ADP = ∠APD = 90° / 2 = 45° Similarly, in △QBC, ∠B = 90° and BQ = BC = AB ⇒∠BCQ = ∠BQC = 90° / 2 = 45° In △PAD and △QBC , we have PA = QB [given] ∠A = ... [each = 90° + 45° = 135°] ⇒ △PDC = △QCD [by SAS congruence rule] ⇒ PC = QD or DQ = CP

Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

In figure, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. -Maths 9th

Description : In figure, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. -Maths 9th

Last Answer : Given ABCDE is a pentagon. BP || AC and EQ|| AD. To prove ar (ABCDE) = ar (APQ) Proof We know that, triangles on the same base and between the same parallels are equal in area. Here, ΔADQ and ΔADE lie on the ... ar (ΔACD) = ar (ΔADE) + ar (ΔACB) + ar (ΔACD) ⇒ ar (ΔAPQ) = ar (ABCDE) Hence proved.

l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Description : l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th

Last Answer : Though E, draw a line parallel to p intersecting L at G and n at H respectively. Since l | | m ⇒ AG | | BE and AB | | GE [by construction] ∴ Opposite sides of quadrilateral AGEB are ... ∠DGE = ∠FHE [alternate interior angles] By ASA congruence axiom, we have △DEG ≅ △FEH Hence, DE = EF

P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Description : P is the mid - point of side AB of a parallelogram ABCD. A line through B parallel to PD meets DC at Q and AD produced at R (see figure). -Maths 9th

Last Answer : (i) In △ARB,P is the mid point of AB and PD || BR. ∴ D is a mid - point of AR [converse of mid - point theorem] ∴ AR = 2AD But BC = AD [opp sides of ||gm ABCD] Thus, AR = 2BC (ii) ∴ ABCD is a ... a mid - point of AR and DQ || AB ∴ Q is a mid point of BR [converse of mid - point theorem] ⇒ BR = 2BQ

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Description : The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q, then parallelogram PBQR is completed (see figure). -Maths 9th

Last Answer : Join AC and QP, also it is given that AQ || CP ∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP. ∴ ar(△ACQ) = ar(△APQ) or ar(△ABC) + ar(△ABQ) = ar(△BPQ) + ar(△ABQ) or ar(△ABC) = ar( △BPQ) or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR) or ar(||gm ABCD) = ar(||gm PBQR)

In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Description : In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th

Last Answer : In △PAD, ∠A = 90° and DA = PA = PB ⇒ ∠ADP = ∠APD = 90° / 2 = 45° Similarly, in △QBC, ∠B = 90° and BQ = BC = AB ⇒∠BCQ = ∠BQC = 90° / 2 = 45° In △PAD and △QBC , we have PA = QB [given] ∠A = ... [each = 90° + 45° = 135°] ⇒ △PDC = △QCD [by SAS congruence rule] ⇒ PC = QD or DQ = CP

Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Description : Write the coordinates of each of the points P, Q, R, S, T and 0 from the figure . -Maths 9th

Last Answer : Here, points P and S lie in I quadrant so their both coordinates will be positive. Now, perpendicular distance of P from both axes is 1, so coordinates of P are (1, 1). Also, perpendicular distance of S ... 0 is the intersection of both axes, so it is the origin and its coordinates are O (0,0).

In figure, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. -Maths 9th

Description : In figure, ABCDE is any pentagon. BP drawn parallel to AC meets DC produced at P and EQ drawn parallel to AD meets CD produced at Q. -Maths 9th

Last Answer : Given ABCDE is a pentagon. BP || AC and EQ|| AD. To prove ar (ABCDE) = ar (APQ) Proof We know that, triangles on the same base and between the same parallels are equal in area. Here, ΔADQ and ΔADE lie on the ... ar (ΔACD) = ar (ΔADE) + ar (ΔACB) + ar (ΔACD) ⇒ ar (ΔAPQ) = ar (ABCDE) Hence proved.

In the adjoining figure, P and Q have co-ordinates (4, 6)and (0, 3) respectively. Find (i) the co-ordinates of R (ii) Area of quadrilateral OAPQ. -Maths 9th

Description : In the adjoining figure, P and Q have co-ordinates (4, 6)and (0, 3) respectively. Find (i) the co-ordinates of R (ii) Area of quadrilateral OAPQ. -Maths 9th

Last Answer : Let the line 2x + 3y - 30 = 0 divide the join of A(3, 4) and B(7, 8) at point C(p, q) in the ratio k : 1. Then,p = \(rac{7k+3}{k+1}\), q = \(rac{8k+4}{k+1}\)As the point C lies on the line 2x + 3y - 30 ... {3}{2}+1},rac{8 imesrac{3}{2}+4}{rac{3}{2}+1}\bigg)\) = \(\big(rac{27}{5},rac{32}{5}\big)\).

In the above figure, AB is parallel to CD. P and R are the points on AB and CD respectively. Q is in between AB and CD. Find the value of x in degrees

Description : In the above figure, AB is parallel to CD. P and R are the points on AB and CD respectively. Q is in between AB and CD. Find the value of x in degrees

Last Answer : In the above figure, AB is parallel to CD. P and R are the points on AB and CD respectively. Q is in between AB and CD. Find the value of x in degrees

The figure shows the front view of a convex lens, which originally had only one edge. Five holes of different shapes, namely triangle, square, pentagon, hexagon and circle, were drilled through it at points P, Q, R, S and T in such a way that the holes were parallel to each other, perpendicular to the edge and all the holes were still within the lens edge. What is the total number of edges in the lens after the holes were drilled?

Description : The figure shows the front view of a convex lens, which originally had only one edge. Five holes of different shapes, namely triangle, square, pentagon, hexagon and circle, were drilled through it at points P ... . What is the total number of edges in the lens after the holes were drilled? 

Last Answer : 57

Figure P shows how a point on a circle traces a path when it is rolled on the ground. The point in which of the polygons shown in the options creates the path in Figure Q?

Description : Figure P shows how a point on a circle traces a path when it is rolled on the ground. The point in which of the polygons shown in the options creates the path in Figure Q?  

Last Answer : D 

Figure P shows an isometric view of an object made with a single sheet of cardboard. Figure Q shows the front view of the same object after colouring. Which option shows the object after it is cut open?

Description : Figure P shows an isometric view of an object made with a single sheet of cardboard. Figure Q shows the front view of the same object after colouring. Which option shows the object after it is cut open?

Last Answer : C

Top and side views of a photographer’s setup for a product shoot are shown in the figure. P is the primary light source, S is the secondary light source, R is the reflector and Q is the camera position. If the Primary Light Source is at 100% intensity, and the secondary light is at 25% intensity, which one of the given options is the photograph taken using this setup?

Description : Top and side views of a photographer's setup for a product shoot are shown in the figure. P is the primary light source, S is the secondary light source, R is the reflector and Q is the camera ... 25% intensity, which one of the given options is the photograph taken using this setup?

Last Answer : D

Triangle P and pentagon Q have markings on them as shown in the figure. If they are placed over each other, which of the following arrangements is/are possible?

Description : Triangle P and pentagon Q have markings on them as shown in the figure. If they are placed over each other, which of the following arrangements is/are possible? 

Last Answer : A, B, D

For the circuit shown in figure, the Boolean expression for the output y in terms of inputs P, Q, R and S is

Description : For the circuit shown in figure, the Boolean expression for the output y in terms of inputs P, Q, R and S is

Last Answer : For the circuit shown in figure, the Boolean expression for the output y in terms of inputs P, Q, R and S is P+Q+R+S

Find the equivealent resistance of the circuit shown in Fig. 4.61 between the points P and Q. Each resistor has a resistance r.

Description : Find the equivealent resistance of the circuit shown in Fig. 4.61 between the points P and Q. Each resistor has a resistance r.

Last Answer : Find the equivealent resistance of the circuit shown in Fig. 4.61 between the points P and Q. Each resistor has a resistance r.

In the circuit shown here, what is the value of the unknown resistor R so that the total resistance of the circuit between points P and Q is also equa

Description : In the circuit shown here, what is the value of the unknown resistor R so that the total resistance of the circuit between points P and Q is also equa

Last Answer : In the circuit shown here, what is the value of the unknown resistor R so that the total resistance of the ... ` C. `sqrt(69)Omega` D. `10 Omega`

One Horsepower (1 HP) is equivalent to approximately?

Description : One Horsepower (1 HP) is equivalent to approximately?

Last Answer : 746 Watts

he crossed the breadth of the Eastern Hemisphere, visited territories equivalent to about 44 modern countries, and put behind him a total distance of approximately 73000 miles: he was world's greatest traveler of Pre-modern times A. Megasthenes B. Fahien C. Marco Polo D. Ibn-e-Batuta

Description : he crossed the breadth of the Eastern Hemisphere, visited territories equivalent to about 44 modern countries, and put behind him a total distance of approximately 73000 miles: he was world's greatest traveler of Pre-modern times A. Megasthenes B. Fahien C. Marco Polo D. Ibn-e-Batuta

Last Answer : ANSWER: C

he crossed the breadth of the Eastern Hemisphere, visited territories equivalent to about 44 modern countries, and put behind him a total distance of approximately 73000 miles: he was world's greatest traveler of Pre-modern times A. Megasthenes B. Fahien C. Marco Polo D. Ibn-e-Batuta

Description : he crossed the breadth of the Eastern Hemisphere, visited territories equivalent to about 44 modern countries, and put behind him a total distance of approximately 73000 miles: he was world's greatest traveler of Pre-modern times A. Megasthenes B. Fahien C. Marco Polo D. Ibn-e-Batuta

Last Answer : ANSWER: C

he crossed the breadth of the Eastern Hemisphere, visited territories equivalent to about 44 modern countries, and put behind him a total distance of approximately 73000 miles: he was world's greatest traveler of Pre-modern times A. Megasthenes B. Fahien C. Marco Polo D. Ibn-e-Batuta

Description : he crossed the breadth of the Eastern Hemisphere, visited territories equivalent to about 44 modern countries, and put behind him a total distance of approximately 73000 miles: he was world's greatest traveler of Pre-modern times A. Megasthenes B. Fahien C. Marco Polo D. Ibn-e-Batuta

Last Answer : ANSWER: C

A temperature of 295 K is equivalent to approximately: w) 0 degrees Fahrenheit x) 32 degrees Fahrenheit y) 72 degrees Fahrenheit z) 97 degrees Fahrenheit

Description : A temperature of 295 K is equivalent to approximately: w) 0 degrees Fahrenheit x) 32 degrees Fahrenheit y) 72 degrees Fahrenheit z) 97 degrees Fahrenheit

Last Answer : ANSWER: Y -- 72 DEGREES FAHRENHEIT

Q: What makes up approximately 70% of the human body? -General Knowledge

Description : Q: What makes up approximately 70% of the human body? -General Knowledge

Last Answer : Water is the answer

We've always known that smoking is terrible for our health, yet until quite recently at least 35% of American adults smoked. What turned that figure to approximately 15% (CDC figures for 2015) and in some communities, down to 10%?

Description : We've always known that smoking is terrible for our health, yet until quite recently at least 35% of American adults smoked. What turned that figure to approximately 15% (CDC figures for 2015) and in some communities, down to 10%?

Last Answer : Ten bucks a pack along with relegation of smokers to the status of lepers.

When a resistor is used as a shunt and is connected in parallel with a meter movement coil, it will provide _____________. A. a measurement of circuit resistance B. an increased accuracy of approximately 1.5 percent C. an extended meter range D. none of the above

Description : When a resistor is used as a shunt and is connected in parallel with a meter movement coil, it will provide _____________. A. a measurement of circuit resistance B. an increased accuracy of approximately 1.5 percent C. an extended meter range D. none of the above

Last Answer : Answer: C

You are testing the insulation in an AC generator with a megohmeter. The resistance value of a dry, clean winding will ____________. A. continue to rise as the test potential is maintained, becoming fairly steady as the leakage current stabilizes B. remain constant as the temperature of the windings increases C. continue to drop as the potential is maintained, becoming fairly steady after 5 to 7 minutes D. stabilize after approximately 2 to 4 minutes of fluctuation

Description : You are testing the insulation in an AC generator with a megohmeter. The resistance value of a dry, clean winding will ____________. A. continue to rise as the test potential is maintained, ... fairly steady after 5 to 7 minutes D. stabilize after approximately 2 to 4 minutes of fluctuation

Last Answer : Answer: A

The factional resistance of a pipe varies approximately with __________ of the liquid. (A) Pressure (B) Velocity (C) Square of velocity (D) Cube of velocit

Description : The factional resistance of a pipe varies approximately with __________ of the liquid. (A) Pressure (B) Velocity (C) Square of velocity (D) Cube of velocit

Last Answer : Answer: Option C

The grade resistance factor for an earth moving machine can be obtained by multiplying grade percentage by a factor approximately equal to (A) 2 kg/tonne (B) 6 kg/tonne (C) 9 kg/tonne (D) 20 kg/tonne

Description : The grade resistance factor for an earth moving machine can be obtained by multiplying grade percentage by a factor approximately equal to (A) 2 kg/tonne (B) 6 kg/tonne (C) 9 kg/tonne (D) 20 kg/tonne

Last Answer : (C) 9 kg/tonne

A resistance of 3.3 M ohms is connected across a 500 V source. The resulting current is approximately?

Description : A resistance of 3.3 M ohms is connected across a 500 V source. The resulting current is approximately? A.15.1 μA B.151 μA C.66 mA D.660 mA

Last Answer : A

An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately...

Description : An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately equal to: A. 385Ω B. 38.5Ω C. 3.1Ω D. 31Ω

Last Answer : An electric heater draws 3.5 A from a 110 V source. The resistance of the heating element is approximately equal to: 31Ω

How many minimum tractor hours per year of 40 H.P. power should be used approximately for purely agricultural use and not for custom service unit to become viable unit ? (A) 500 hrs. (B) 600 hrs. (C) 1000 hrs. (D) 1500 hrs. (E) 2000 hrs.

Description : How many minimum tractor hours per year of 40 H.P. power should be used approximately for purely agricultural use and not for custom service unit to become viable unit ? (A) 500 hrs. (B) 600 hrs. (C) 1000 hrs. (D) 1500 hrs. (E) 2000 hrs.

Last Answer : (C) 1000 hrs.

How many minimum tractor hours per year of 40 H.P. power should be used approximately for purely agricultural use and not for custom service unit to become viable unit ? (A) 500 hrs. (B) 600 hrs. (C) 1000 hrs. (D) 1500 hrs. (E) 2000 hrs.

Description : How many minimum tractor hours per year of 40 H.P. power should be used approximately for purely agricultural use and not for custom service unit to become viable unit ? (A) 500 hrs. (B) 600 hrs. (C) 1000 hrs. (D) 1500 hrs. (E) 2000 hrs.

Last Answer : (E) 2000 hrs.