A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?

A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?
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A is twice as fast as B and together they can complete a work in 20 days. In how many days can A alone complete the work?
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Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between the number of days taken by Ram and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Description : Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between ... and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5

Last Answer : Let the time taken by Ram, Suresh and Shilpa to finish the work alone be A, B and C respectively Therefore, 1/A + 1/B + 1/C = 1 Also it is given that, A = B/3 and C =B/2 3/B + 1/B + ... between the number of days taken by Ram and Shilpa, each working alone, to complete the work = 3-2 = 1 Answer: a)

Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Description : Sai and Ram working together completed a job in 10 days. If sai worked twice as efficiently as he actually did and ram worked 2/3 as efficiently as he actually did, the work would have been completed in 6 days. Sai alone could complete the work in. a) 40/3 days b) 42/4 days c) 44/6 days d) 43/3 days

Last Answer : A Let sai's 1 day work = x Ram's 1 day work = y Then x+y = 1/10 ===>1 and 2x +2y /3 = 1/6 (6x+2y )/3 = 1/6 6x + 2y =1/2 ====>2 Multiply 1 by 6 =>6x+6y = 6/10 2 = ... /10 - 1/40 = 4-1/10 =3/40 Sai's 1 day work = 3/40 So sai alone could complete the work in 40/3 days.

P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Description : P,Q, & R can complete a piece of job together in 20 days. All the 3 started working at it together and after 8 days P left. Then Q & R together completed a job in 20 more days. P alone could complete the work in. a) 60 b) 50 c) 40 d) 30

Last Answer : B Work done by P,Q & R in 8 days = 1/20 * 8 =2/5 Remaining work = (1 - 2/5) = 3/5 Now 3/5 work is done by Q & R in 20 days Whole work will be done by Q & R in(20*5/3) =100/3 days (P+Q+R ... (Q+R)'s 1 day work =1/20 - 3/100 =5-3/100 =2/100 =1/50 P alone could complete the work in 50 days..

6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Description :  6 male , 8 female and 12 children can complete a work in 14 days .a female does twice the work of a male does and a child does half the work a male does . how many female alone can complete this work in 14 days? a) 15 b) 10 c) 12 d) 14

Last Answer :  D Let 1 female ‘s 1 day work= x Then 1 male’s 1 day work =x/2 And 1 child’s 1 day work =x/4 So 6x/2 + 8x +12x/4 =1/14 3x+8x+3x = 1/14 14x = 1/14 X=196 1 female alone can complete the work in 196 days So, to complete the work in 14 days number of female required = 14.

Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Description : Karthik is 2 times as good workman as Raghu and together they complete a piece of work in 42 days. The number of days taken by Karthik alone to finish the work is. a) 55 days b) 60 days c) 63 days d) 67 days

Last Answer : C Karthik’s 1 day work : Raghu’s 1 day work = 2:1 (Karthik + Raghu)’s 1 day work = 1/42 Divide 1/42 in the ratio 2:1 Therefore karthick’s 1 day work = 1/42 * 2/3 =1/63 Hence karthik alone can finish the work in 63 days.

A and B together can complete a work in 24 days. A alone can complete it in 40 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work? a) 24 days b) 15 days c) 21 days d) 19 days

Description : A and B together can complete a work in 24 days. A alone can complete it in 40 days. If B does the work only for half a day daily, then in how many days A and B together will complete the work? a) 24 days b) 15 days c) 21 days d) 19 days

Last Answer : A B’s 1 day’s work = (1/24 -1/40) =(5-3)/120 =2/120=>1/60 Now, (A + B)’s 1 day’s work = (1/40 +1/60) =(3+2)/120 =5/120 So, A and B together will complete the work in 120/5 = 24 days.

Prabu and balaji are two workers. Working together they can complete the whole work in 20 hours. If the Prabu worked for 5 hours and balaji worked for 17 hours, still there was half of the work to be done. In how many hours Prabu working alone, can complete the whole work? a) 17 hours b) 23 hours c) 34 hours d) 37 hours

Description : Prabu and balaji are two workers. Working together they can complete the whole work in 20 hours. If the Prabu worked for 5 hours and balaji worked for 17 hours, still there was half of the work to be done ... working alone, can complete the whole work? a) 17 hours b) 23 hours c) 34 hours d) 37 hours

Last Answer : C Efficiency of Prabu and balaji = 5% Prabu worked for 5 hours and balaji worked separately 17 hours. Which means it can be considered that Prabu and balaji worked together for 5 hours and balaji worked alone for ... (5-2.08) = 2.92% Thus, prabu require . = 34 hours to complete the work alone.

A task was assigned to P, Q and R to be completed by not more than seven days. P alone can complete the task in ten days. Q alone can complete the task in twelve days and R alone can complete the task in fifteen days. All three of them worked for two days and P and Q together worked for another two days. What portion of the task will remain after four days? a) 3/10 b) 1/15 c) 1/9 d) 5/16 e) None of these

Description : A task was assigned to P, Q and R to be completed by not more than seven days. P alone can complete the task in ten days. Q alone can complete the task in twelve days and R alone can complete the task in fifteen days. ... will remain after four days? a) 3/10 b) 1/15 c) 1/9 d) 5/16 e) None of these

Last Answer : 1day's work of (P + Q+ R) = 1/10 + 1/12 +1/15 = 15/60 2 day's work of (P + Q+ R) = 15/60 × 2 = 1/2 1 day's work of (P+Q) = 1/10 +1/12 = 11/60 2 day's work of (P+Q) = 11/60 × 2 = 11/30 Rem. work of 4 days = 1- 1/2 + 11/30 = 2/15 Answer: e)

P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P when completing the same job alone to the number of days taken by R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Description : P and Q together can complete a job in 30 days. Q and R together can complete the same job in 40 days. P and R together can complete the same job in 40 days. What is the respective ratio of the number of days taken by P ... R when completing the same job alone? a) A.2:5 b) B.1:2 c) C.3:4 d) D.2:3

Last Answer : B Efficiency of P and Q= 1/30 per day ___________1 ⇒ Efficiency of Q and R = 1/40 per day_________2 ⇒ Efficiency of R and P = 1/40 per day _________3 Taking equation 2 and 3 together ⇒ Q + R = ... 120 days he they work alone. ⇒ Ratio of number of days in which P and R can complete the job 1:2.

X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Description : X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Last Answer : X, Y and Z can complete a piece of work in 10 days. X and Y can do it in 20 days. Then Z alone can complete the work in ……………… days.

Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Description : Pranesh can do a piece of job in 60 days. He works at it for 4 days and then sarvesh alone finishes the remaining work in28 days. In how much time will pranesh and sarvesh working together, finish the work? a) 35 days b) 30 days c) 25 days d) 20 days

Last Answer : D Work done by pranesh in 4 days = 1/60 *4 =1/15 Remaining work = 1-1/15 =(15 - 1)/15 =14/15 Now 14/15 work done by sarvesh in 28 days Whole work will be done by sarvesh in(28*15 /14) = 2* 15 =30 ... 's work = 1/60 + 1/30 = (1+2) /60 = 3/60 =1/20 Hence both will finish the work in 20 days

X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Description : X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

Last Answer : X and Y can do a piece of work in 20 days and 30 days respectively. The time they take to complete the work by working together is ……………

P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each one of them finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60

Description : P and Q can do a piece of job in 24 days; Q and R can do it in 30 days while R and P can finish it in 40 days. If P, Q, Rworks together, in how many days will they finish the job? In how many days will each ... finish it, working alone? A) 15,25,35,45 B) 20,30,40,120 C) 20,30,40,50 D) 20,25,30,60 

Last Answer : B Time taken by (P + Q) to finish the job = 24days. (P + Q)'s 1 day's job = 1/24 Time taken by (Q +R) to finish the job = 30days. (Q + R)'s 1 day's job = 1/30 Time taken by (R + P) to finish the ... - {(P + Q)'s 1 day's job } = (1/20 -1/24)=1/120 Hence, R alone can finish the job in 120 days.

Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Description : Rubika can do the 12 times the actual work in 72 days while sathya can do the one-half of the original work in 6 days. In how many days will both working together complete the 6 times of the original work? a) 20 days b) 25 days c) 30 days d) 35 days

Last Answer :  C Efficiency of Rubika = 16.666% Efficiency of sathya = 4.166% Total efficiency of rubika and sathya =(16+4) =20% Actual work 100/20=5 So, they can do actual work in 5 days So, 6 times work requires 30 days.

Among 4 persons A, B, C and D. A takes twice as much time as B to complete a piece of work. B takes twice as much time as C and C takes twice as much time as D to complete the same work. One group of three of the four men can complete the work in 11 days while another group of three can do so in 7 days. Which is the group that takes 11 days? a) A.B.C b) A,B,D c) B,C,D d) None of the above

Description : Among 4 persons A, B, C and D. A takes twice as much time as B to complete a piece of work. B takes twice as much time as C and C takes twice as much time as D to complete the same work. One group of three of the ... is the group that takes 11 days? a) A.B.C b) A,B,D c) B,C,D d) None of the above

Last Answer : B From the given information B is twice as efficient as A. C is twice as efficient as B. D is twice efficient as C. If work done by A in a day is 'n' units, the work done in a day by B, ... of times taken to complete the work by the former and later groups is 11:7 A, B and D take 11 days.

Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Description :  Arfath is thrice as good workman as deekshith and together they finish a piece of work in 27 days. In how many days will arfath alone finish the work? a) 9 days b) 10 days c) 11 days d)12 days

Last Answer : A Arfath’s 1 days work = 3 Deekshith 1 day’s work = 1 Arfath 1 day’s work : Deekshith 1 days work = 3:1 (Arfath + deekshith )’s 1 day’s work = 1/27 Divide 1/27 in the ratio 3:1 Arfath’s 1 days work = 1/27 *3/1 = 3/27 =1/9 Hence Arfath’s alone can finish the work in 9 days

One tube can fill a tank five times as fast as another tube. If together the two tubes can fill tank in 42 min, then the slower tube alone will be able to fill the tank in? A) 252 min B) 208 min C) 244 min D) 192 min

Description : One tube can fill a tank five times as fast as another tube. If together the two tubes can fill tank in 42 min, then the slower tube alone will be able to fill the tank in? A) 252 min B) 208 min C) 244 min D) 192 min

Last Answer : A Let the slower tube alone fill the tank in x min. Then, faster tube will fill it in x/5 min. 1/x + 5/x = 1/42 6/x = 1/42 => x = 252min.

One tap can fill a cistern four times as fast as another tap. If together the two taps can fill the cistern in 48 mins then the slower tap alone will be able to fill the cisterns. A) 1hr B) 2hr C) 3hr D) 4hr

Description : One tap can fill a cistern four times as fast as another tap. If together the two taps can fill the cistern in 48 mins then the slower tap alone will be able to fill the cisterns. A) 1hr B) 2hr C) 3hr D) 4hr

Last Answer : D Let the slower tap alone fill the cistern in x mins Then faster tap will fill it in x/4 mins Therefore 1/x +4/x = 1/48 5/x = 1/48 X = 48*5 x = 240 mins x = 4 hrs.

One tap can fill a tank thrice as fast as another tap. If together the two taps can fill the tank in 12 minutes, then the slower tap alone will be able to fill the tank in A) 30min B) 33min C) 32min D) 35min

Description : One tap can fill a tank thrice as fast as another tap. If together the two taps can fill the tank in 12 minutes, then the slower tap alone will be able to fill the tank in A) 30min B) 33min C) 32min D) 35min

Last Answer : C (1/x)+(1/3x)=(1/12) 3+1/3x = 4/3x = 1/12 3x = 48 x=32mins

Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Description : Praneetha and Pooja together can do a piece of work in 24 days ,which pooja and priya can do in 32 days. After praneetha has been working at it for 10 days and pooja for 14 days, Priya finishes it in 26 days. In how many days Priya alone will do the work? a) 12 days b) 24 days. c) 48 days d) 50 days

Last Answer : C Praneetha's 10 day's work + Pooja 14 day's work + Priya's 26 days work = 1 (Praneetha's +pooja's) 10 day's work + (pooja + priya)'s 4 day's work +priya's 22 days work = 1 =>10/24 + 4/32 + priya' ... 13/24 =11/24 Priya's 1 day's work = 11/24 * 1/22 =1/48 Priya can finish the work in 48 days.

M & N can do a work together in 12 days. M is 2 ½ time as efficient as N. the same work can be done by M alone in. a) 84/5 b) 6/84 c) 82/5 d) 6/82

Description : M & N can do a work together in 12 days. M is 2 ½ time as efficient as N. the same work can be done by M alone in. a) 84/5 b) 6/84 c) 82/5 d) 6/82

Last Answer : A M’s 1 day work = 2 ½ = 5/2 N’s 1 day work = 1 Ratio of M and N = 5/2 : 1= 5:2 Let M’s and N’s 1 day work be 5x and 2x respectively. Then 5x+2x = 1/12 7x=1/12 X= 1/(12*7) X=1/84 M’s 1 day work = 1/84 * 5 = 5/84 Hence M alone can finish the work in 84/5 days.

X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Description : X does half as much work as Yand Z does half as much work as X and Y together. If Z alone can finish the work in 120 days, then together ,all will finish the work in ? a) 14 1/2 b) 40 c) 24 1/2 d)17 1/3

Last Answer : B Z alone can finish the work in 120 days. As given Z does half as much work as X and Y together => (X + Y) can do it in 60 days (X+ Y)s 1 days wok = 1/60. X's 1 days work : Y's 1 days Work = 1 ... (1/90) + (1/120) =(2+4+3)/360 =9/360 = 1/40 All the three together will finish it in 40 days

A is thrice as fast as B. If B can do a piece of work in 60 days, the number of days they take to complete the work is ……..

Description : A is thrice as fast as B. If B can do a piece of work in 60 days, the number of days they take to complete the work is ……..

Last Answer : A is thrice as fast as B. If B can do a piece of work in 60 days, the number of days they take to complete the work is ……..

Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6

Description : Rakchita can do a piece of work in 28 days, while Shreya can do the same work in 42 days.They started the work together but 6 days before the completion of the work, Rakchita left the work. The total number of days to complete the work is a) 3 b) 4 c) 5 d) 6 

Last Answer : D 6 days before the completion of the work Rakchita left the work means in last 6 days only Shreya has worked alone So, in last 6 days worked done by Shreya = 6*1/42=6/42=1/7 So, the rest = 1-1/7 =6/7 So 6/7work was done by Rakchita and Shreya worked together=6/7*70/10 =420/70=6 days

Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Description : Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both rishwi and dhiviksha work together, working 4 hrs a day, in how many days can they finished the work? a) 30/11 b) 11/120 c) 11/30 d) 30/13

Last Answer : A Rishwi can complete the work in (6*4) = 24 hrs Dhiviksha can complete the work in (4*5) = 20 hrs Rishwi's 1 hr work = 1/24 Dhiviksh's 1 hr work = 1/20(Rishwi and dhivikasha)'s 1 hr work = (1/24 ... fininsh the work in (120/11)hrs Number of days of 4 hrs each = 120/11*1/4 =120/44 =30/11 days

A task is done by 46 persons not all of them have the same capacity to task. Every day exactly 2 persons, do the task with no pair of persons working together twice. Even after all possible pairs have worked once, all the persons together works for two more days to finish the task. Find the number of days in which all the persons together will finish the whole task? a) 44 b) 45 c) 46 d) 47

Description : A task is done by 46 persons not all of them have the same capacity to task. Every day exactly 2 persons, do the task with no pair of persons working together twice. Even after all possible pairs have worked ... in which all the persons together will finish the whole task? a) 44 b) 45 c) 46 d) 47

Last Answer : D 46 persons task in pairs, with no same pair of persons working together. Each person will be working with other 45 which means each persons will work for 45 days in pair. Let the time taken by each ... +1/T46)= 1/47 If all the persons work together they will finish the whole task in 47 days.

The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the thre of them can complete the work in 24 days. In how man

Description : The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the thre of them can complete the work in 24 days. In how man

Last Answer : The capacities of A,B and C to complete a piece of work is `1:2:3`. By working together, the ... days. In how many days can C alone complete it ?

A boy and his mother together can do a piece of work in 24 days while the day, working with his father, can complete it in 18 days. If the mother and

Description : A boy and his mother together can do a piece of work in 24 days while the day, working with his father, can complete it in 18 days. If the mother and

Last Answer : A boy and his mother together can do a piece of work in 24 days while the day, working with ... take to complete the job, if they work individually.

8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days

Description : 8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men ... more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days 

Last Answer : 1 man = 2 women 8 men + 4 women = 20 women 2 day's work of 20 women = 20 × 6/1 = 20 × 2/x x =1/3 Remaining work = 1 – 1/3 = 2/3 Total number of females = 16 20 × 6/1 = 16 × x ÷2/ 3 x = 5 days Short Cut M1D1=M2D2+M3D3 10x6 =10x2 + 8 x 60-20= 8x x= 5 days Answer: c)

Arul can do a certain work in 9 days while Ravi can do the same work in 7 days. Both of them complete the work together and get Rs.288. what is the share of Arul? a) Rs.124 b) RS.126 c) Rs.128 d) Rs.130

Description : Arul can do a certain work in 9 days while Ravi can do the same work in 7 days. Both of them complete the work together and get Rs.288. what is the share of Arul? a) Rs.124 b) RS.126 c) Rs.128 d) Rs.130

Last Answer : B Arul’s 1 day work = 1/9 Ravi’s 1 day work = 1/7 Arul’s salary : Ravi’s salary = Arul’s 1 day work : Ravi’s 1 day work = 1/9 : 1/7 = 7 :9 Arul’s share = Rs.(7/16 *288) =Rs.126

On a T.V. channel, four serials A, B, C and D were screened, one on eacn day, on four consecutive days but not necessarily in that order. On which day was the serial C screened ? Statements: I. I. The first serial was screened on 23rd, Tuesday and was followed by serial D. II. Serial A was not screened on 25th and one serial was screened between serials A and B. (a) statement (I) alone is sufficient (b) statement (II) alone is sufficient (c) Both statements (I) and (II) together are not sufficient (d) Both statements (I) and (II) together are necessary

Description : On a T.V. channel, four serials A, B, C and D were screened, one on eacn day, on four consecutive days but not necessarily in that order. On which day was the serial C screened ? Statements: I ... (I) and (II) together are not sufficient (d) Both statements (I) and (II) together are necessary

Last Answer : (c) Both statements (I) and (II) together are not sufficient

Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Description : Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23

Last Answer : Answer- 3( 19,20,21) Explanation:- let number be x,x+1,x+2 2x + 3(x+1)+4(x+2)=180 x=19 so numbers are 19,20,21

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10

Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c

M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Description : M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Last Answer : C Work done by M in 8 days = 1/40*8 =1/5 Remaining work = 1-1/5 = 4/5 (M+N)’s 1 day work = 1/40 + 1/24 =(3+5)/120 =8/120 =1/15 Now 1/15 work is done by M & N in 1 day. So 4/5 work will be done by X and Y is, =15 / 1 * 4/5 =12 days Hence total time taken = 12+8 = 20 days

A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take both the punctures together to make it flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Description : A motor bike tyre has two punctures. The 1st puncture alone would have made the tyre flat in 27 minutes and the 2nd alone would have done it in 18 minutes. If air leaks out at a constant rate, how long does it take ... flat? a) 20 4/3 minutes b) 15 4/7 minutes c) 10 4/5 minutes d) 25 4/3 minutes

Last Answer : C 1st puncture made the tyre flat in 27 mins 2nd puncture made the tyre flat in 18 mins 1 minute’s work of both the punctures = (1/27 + 1/18) =(2+3)/54 =5/54 So, both the punctures will make the tyre flat in 54/5 mins =>10 4/5 minutes

3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Description :  3 faucet P,Q & R can fill a cistern in 12 hrs. After working together for 4hrs, R is closed P and Q can fill the remaining part in 14 hrs. The number of hrs taken by R alone to fill the cistern is. A) 18 hrs B) 20 hrs C) 28hrs D) 30hrs

Last Answer : C  Part filled in 4 hrs = 4/12 = 1/3 Remaining part = 2/3 (P+Q)’s 14 hrs work = 2/3 (P+Q)’s 1 hr work = 2/ 3 *14 = 1/21 R’s 1 hr work = (P+Q+R)’s 1 hr work – (P+Q)’s 1 hr work = 1/12 – 1/21 = 7-4/84 = 3/84 = 1/28 R alone can fill the tank in 28 hrs.

A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there are 20 days holidays. How many male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Description : A officer undertakes to complete a job in 250 days. He employs 300 male for 50 days and they complete 1/2 of the work . He then reduces the number of male to 100, who work for 120 days, after which there ... male must be employed for the remaining period to finish the work? a) 25 b) 50 c) 45 d) 35

Last Answer : B 300 male in 50 days do = 1/2work 1 male in 1 day does = ½*1/50*1/300 work 100 male in 120 days do = ½ *1/50*1/300 *100*120 =2/5 work Total work done = ½ + 2/5 =(5+4)/10=9/10 ... is done in 50 days by 300 male 1/10 work is done in 60 days by =300*50*1*2/10*60 =50 male

A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can they do it, all working together?

Description : A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can they do it, all working together?

Last Answer : A and B can do a piece of work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can they do it, all working together?

A can do a work in 15 days and B in 20 days. If they work together for 4 days, then the fraction of work that is left is a) 7/15 b) 8/10 c) 8/15 d) 7/20

Description : A can do a work in 15 days and B in 20 days. If they work together for 4 days, then the fraction of work that is left is a) 7/15 b) 8/10 c) 8/15 d) 7/20

Last Answer : c) 8/15

A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C

Description : A can complete a piece of work working along with B in 20 days. If he can complete the same work working along with C in 10 days, then between B and C

Last Answer : A can complete a piece of work working along with B in 20 days. If he can complete the same work ... , then between B and C who is more efficient ?

6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Description : 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days

Last Answer : Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b Work done by 6 men and 8 women in 1 day = 1/10 => 6m + 8b = 1/10 => 60m + 80b = 1 --- (1) Work done by 26 men and 48 ... 1 day = 15/100 + 20/200 =1/4 => Time taken by 15 men and 20 women in doing the work = 4 days Answer: a)

20 workers working 5hours a day can finish the work in 20 days.If the workers went to work for 4hours a day.How many more workers are required to complete the work in same 20days? 1)7 2)4 3)5 4)6

Description : 20 workers working 5hours a day can finish the work in 20 days.If the workers went to work for 4hours a day.How many more workers are required to complete the work in same 20days? 1)7 2)4 3)5 4)6

Last Answer : 3)5 Exp: workers required for 4h=>(5/4)×20=25. 25-20=5.

Twenty workers can complete a piece of work in 30 days. After how many days should 5 workers leave the job so that the work is completed in 35 days? a) 5 days b) 10 days c) 15 days d) 20 days

Description : Twenty workers can complete a piece of work in 30 days. After how many days should 5 workers leave the job so that the work is completed in 35 days? a) 5 days b) 10 days c) 15 days d) 20 days

Last Answer : c) 15 days

Thirty men take 20 days to complete a job working 9 hours a day. How many hour a day should 40 men work to complete the job? (a) 8 hrs (b) 7 1/2 hrs (c) 7 hrs (d) 9 hrs

Description : Thirty men take 20 days to complete a job working 9 hours a day. How many hour a day should 40 men work to complete the job? (a) 8 hrs (b) 7 1/2 hrs (c) 7 hrs (d) 9 hrs

Last Answer : (b) 7 1/2 hrs

A and B together can do a piece of work in 20 days, while B and C together can do the same work in 15 days. If A ,B and C together can finish this wor

Description : A and B together can do a piece of work in 20 days, while B and C together can do the same work in 15 days. If A ,B and C together can finish this wor

Last Answer : A and B together can do a piece of work in 20 days, while B and C together can do the same ... number of days in which B alone can finish the work.

A can do a piece of work in 20 days while B can do it in 30 days. Both of them start the work together and work for some time, then B leaves. If A com

Description : A can do a piece of work in 20 days while B can do it in 30 days. Both of them start the work together and work for some time, then B leaves. If A com

Last Answer : A can do a piece of work in 20 days while B can do it in 30 days. Both of them start ... then find the number of days for which they worked together.

Working together, X and Y can do a piece of work in 12 days, Y and Z can do it in 15 days where as X and Z can do it in 20 days. Who is the most effci

Description : Working together, X and Y can do a piece of work in 12 days, Y and Z can do it in 15 days where as X and Z can do it in 20 days. Who is the most effci

Last Answer : Working together, X and Y can do a piece of work in 12 days, Y and Z can do it in 15 days where ... Z can do it in 20 days. Who is the most effcient?

A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these

Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)

For complete stabilisation of organic matter in polluted water, it takes (A) 5 days (B) 10 days (C) 20 days (D) 30 days

Description : For complete stabilisation of organic matter in polluted water, it takes  (A) 5 days  (B) 10 days  (C) 20 days  (D) 30 days 

Last Answer : (D) 30 days