Find the value of `(i) (log_(10)5)(log_(10)20)+(log_(10)2)^(2)` `(ii) root3(5^((1)/(log_(7)5))+(1)/((-log_(10)0.1)))` `(iii) log_(0.75)log_(2)sqrtsqrt

Find the value of `(i) (log_(10)5)(log_(10)20)+(log_(10)2)^(2)` `(ii) root3(5^((1)/(log_(7)5))+(1)/((-log_(10)0.1)))` `(iii) log_(0.75)log_(2)sqrtsqrt
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Answer :

Find the value of `(i) (log_(10)5)(log_(10)20)+(log_(10)2)^(2)` `(ii) root3(5^((1)/(log_(7)5))+(1)/(( ... 3)5)+3^(log_(5)7)-5^(log_(3)7)-7^(log_(5)3)`
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Solve the following inequalities `(i) log_(5)(3x-1) lt 1` `(ii) (log_(.5)x)^(2)+log_(.5)x-2 le 0` `(iii) log_(3)(x+1)+log_(3)(x+7) ge 3` `(iv)log_(1//

Description : Solve the following inequalities `(i) log_(5)(3x-1) lt 1` `(ii) (log_(.5)x)^(2)+log_(.5)x-2 le 0` `(iii) log_(3)(x+1)+log_(3)(x+7) ge 3` `(iv)log_(1//

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Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1)` `(iii) (log_(10)(100x))^(2)+(log_(10)(10

Description : Solve the following equations `(i) (log_(2)(9-2^(x)))/(3-x)=1` `(ii) x^((log_(10)x+7)/(4))=10^((log_(10)x+1)` `(iii) (log_(10)(100x))^(2)+(log_(10)(10

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Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

Description : Solve the following equations : `(i) log_(x)(4x-3)=2` `(ii) log_2)(x-1)+log_(2)(x-3)=3` `(iii) log_(2)(log_(8)(x^(2)-1))=0` `(iv) 4^(log_(2)x)-2x-3=0`

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Let `alpha,beta`, are two real solution of equation `(log_(10)x)^2 + log_(10)x^2 = (log_(10))^2 -1,` then ` sqrt1/(alpha beta)`equal to `(i) 20 (ii) 3

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Description : The value of `((log_(2)9)^(2))^((1)/(log_(2)(log_(2)9)))xx(sqrt(7))^((1)/(log_(4)7))` is .......... .

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Description : Let `log_(10)2=a` and `log_(10)3=b` determine the following in term of `a` and `b` `(i) log_(4)100+2log_(27)100` `(ii) log_(144)sqrt(45)`

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Root5 +root3 by root5-root3 -Maths 9th

Description : Root5 +root3 by root5-root3 -Maths 9th

Last Answer : 8+2√15 by 2 :by rationalisation

Root5 +root3 by root5-root3 -Maths 9th

Description : Root5 +root3 by root5-root3 -Maths 9th

Last Answer : 8+2√15 by 2 :by rationalisation

Let L denotes the value of a satisfying the equation `log_(sqrt(3))(a) =(10)/(3)` and M denotes the value of b satisfying the equation `4^(log_(9)^(3)

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A 75-year-old man had been receiving gentamicin (an aminoglycoside antibiotic) to treat an urinary tract infection. After three months of therapy patient's serum creatinine levels were 10 mg/dL ( normal 0.5-1.2) and serum gentamicin concentrations obtained just before the last dose were 9 mg/dL (normal < 2). Which of the following is the most likely adverse drug reaction the patient was suffering from? a) Type II allergic reaction b)Type III allergic reaction c) Pseudo allergic reaction d) Overdose toxicity

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Last Answer : d) Overdose toxicity 

Complete set of solution of equation `(log_(0.3)(x-2))/(|x|) >= 0`

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If 20 kg of coarse aggregate is sieved through 80 mm, 40 mm, 20 mm, 10 mm, 4.75 mm, 2.36 mm, 1.18 mm, 600 micron, 300 micron and 150 micron standard sieves and the weights retained are 0 kg, 2 kg, 8 kg, 6 kg, 4 kg respectively, the fineness modulus of the aggregate, is (A) 7.30 (B) 7.35 (C) 7.40 (D) 7.45

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`int_(1)^(2) (log_(e) x)/(x^(2)) dx`

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`int (dx)/(x(1+log_(e)x)(3+log_(e)x))`

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If `log_(1/2) ((x^2+6x+9)/(2(x+1)) )< - log_2(x+1)` then complete set of values of x is

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Minimum traffic block required for execution of AT Weld ? (i) 70 minutes (ii) 70-75 minute.* (iii) 60 mints (iv) 1 hrs and 30 mints

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X Limited forfeited Ram’s 20 shares of Rs. 10 each on which Rs. 7 is called up. Ram had paid application and allotment money of Rs. 5 per share. Of these forfeited shares 15 shares were reissued to Hari as fully paid up for Rs. 6 per share. What amount should be transferred to Capital Reserve account ? (A) Rs. 15 (B) Rs. 20 (C) Rs. 75 (D) Rs. 100

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Last Answer : Answer: Rs. 15

A company has to choose between two projects whose cash flows are as indicated below; Project 1: i. Investment – Rs. 15 Lakhs ii. Annual cost savings – Rs. 4 lakhs. iii. Bi-annual maintenance cost – Rs. 50,000/- iv. Reconditioning and overhaul during 5th year: 6 lakhs v. Life of the project – 8 years vi. Salvage value – Rs. 5 lakhs Project 2: vii. Investment – Rs. 14 Lakhs viii. Annual cost savings – Rs. 3.5 lakhs. ix. Annual Maintenance cost – Rs. 20,000/- x. Reconditioning and overhaul during 4th year: 5 lakhs xi. Life of the project – 8 years xii. Salvage Value- 2 lakhs Which project should the company choose? The annual discount rate is 12

Description :  A company has to choose between two projects whose cash flows are as indicated  below; Project 1:  i. Investment - Rs. 15 Lakhs ii. Annual cost savings - Rs. 4 lakhs. iii. Bi-annual ... years xii. Salvage Value- 2 lakhs Which project should the company choose? The annual discount rate is 12

Last Answer : Year Project 1 Project 2 Outgo Saving NPV Outgo Saving NPV 0 15.0 0 =-15.0 14.0 0 = -14 1 0 4.0 = (4 / (1+.12)1 = 3.571 0.2 3.5 = (3.3 / (1+.12)1 = 2.95 2 0.5 4.0 = (3.5 / (1+.12)2 = 2.79 0.2 3.5 ... (1+.12)8 = 3.43 0.2 5.5  (3.5+2) = (5.3 / (1+.12)8 = 2.14 NPV = + 2.301 @12% = + 0.15

In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 days and 8 kg to 10 kg (C) 105 days to 120 days and 18 kg to 21 kg (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Description : In India, which one of the following should be considered the right combination of the age in days and live body weight in kg for a lamb for its weaning ? (A) 20 days to 30 days and 6 kg to 7 kg (B) 45 days to 60 ... (D) 75 days to 90 days and 12 kg to 15 kg (E) 55 days to 70 days and 9 kg to 11 kg

Last Answer : (C) 105 days to 120 days and 18 kg to 21 kg

An excavator costs Rs. 20,00,000 and has an estimated life of 8 years. It has no salvage value at the end of 8 years. The book value of the excavator at the end of 3 years using general double declining balance method is (A) Rs. 8,43,750 (B) Rs. 8,75,000 (C) Rs. 10,50,000 (D) Rs. 11,56,250

Description : An excavator costs Rs. 20,00,000 and has an estimated life of 8 years. It has no salvage value at the end of 8 years. The book value of the excavator at the end of 3 years using general double declining balance method is (A) Rs. 8,43,750 (B) Rs. 8,75,000 (C) Rs. 10,50,000 (D) Rs. 11,56,250

Last Answer : (A) Rs. 8,43,750

Minm. deflection during transverse breaking load test is? (i) 5 mm (ii) 10 mm (iii) 15 mm* (iv) 20 mm

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What is the value of x in the equation 0.25 open brackets 3x - 4 close brackets - 0.5x equals 2.75 A. 27 B. 15 C. 7 D. 3?

Description : What is the value of x in the equation 0.25 open brackets 3x - 4 close brackets - 0.5x equals 2.75 A. 27 B. 15 C. 7 D. 3?

Last Answer : Work it through, doing the same thing to both sides:0.25(3x - 4) - 0.5x = 2.75[Multiply both sides by 4]→ 4 (0.25(3x - 4) - 0.5x) = 4 (2.75)→ 4 0.25(3x - 4) - 4 0.5x = 4 2.75→ 3x - 4 - 2x = ... 11[Add 4 to both sides]→ (x - 4) + 4 = (11) + 4→ x - 4 + 4 = 11 + 4→ x = 15→ Solution is B. 15

A patient being treated with 20 mg prednisolone daily has to be shifted on to dexamethasone. What should be his daily dose of dexamethasone: A. 0.75 mg B. 3 mg C. 10 mg D. 40 mg

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Last Answer : (ii) 10 Mt.*

Painting of weld is done up to (i) 10 CM minimum both side of weld & on welded surface .* (ii) 15 CM minimum both side of weld & on welded surface (iii) 20 CM minimum both side of weld & on welded surface (iv) None of the above

Description : Painting of weld is done up to (i) 10 CM minimum both side of weld & on welded surface .* (ii) 15 CM minimum both side of weld & on welded surface (iii) 20 CM minimum both side of weld & on welded surface (iv) None of the above

Last Answer : (i) 10 CM minimum both side of weld & on welded surface .*

The frequency of a wave travelling at a speed of 500 ms-1 is 25 Hz. Its time period will be ______. (i) 20 s (ii) 0.05 s (iii) 25 s (iv) 0.04 s

Description : The frequency of a wave travelling at a speed of 500 ms-1 is 25 Hz. Its time period will be ______. (i) 20 s (ii) 0.05 s (iii) 25 s (iv) 0.04 s

Last Answer : (iv) 0.04 s

How many grams of chromium (III) chloride are required to produce 75.0 g of silver chloride?

Description : How many grams of chromium (III) chloride are required to produce 75.0 g of silver chloride?

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The group index for a soil, whose liquid limit is 40 percent, plasticity index is 10 percent and percentage passing 75 micron IS sieve (A) 0 (B) 3 (C) 5 (D) 7

Description : The group index for a soil, whose liquid limit is 40 percent, plasticity index is 10 percent and percentage passing 75 micron IS sieve (A) 0 (B) 3 (C) 5 (D) 7

Last Answer : Answer: Option A

The regimens recommended for treatment of chloroquine resistant P.falciparum malaria in an adult include the following except: A. Quinine 10 mg/kg/8 hourly+ doxycycline 100 mg/day for 7 days B. Quinine 10 mg/kg 3 times a day × 7 days with pyrimethamine 75 mg + sulfadoxine 1500 mg on first day C. Mefloquine 0.5 g daily for 7 days D. Artemether 80 mg i.m./twice on first day followed by once daily for 4 days

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Last Answer : C. Mefloquine 0.5 g daily for 7 days

Approximate value of the modulus of elasticity for steel is about __________ × 10 6kg/cm2 . (A) 0.5 (B) 2 (C) 40 (D) 75

Description : Approximate value of the modulus of elasticity for steel is about __________ × 10 6kg/cm2 . (A) 0.5 (B) 2 (C) 40 (D) 75

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I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 XII=12 XIII=13 XIV=14 XV=15...... Of course, I + XI = X is wrong. You are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Description : I have some matchsticks set up like this: I + XI = X. If you do not know Roman numerals, here is a quick starter: I=1 II=2 III=3 IV=4 V=5 VI=6 VII=7 VIII=8 IX=9 X=10 XI=11 ... are told to move the minimum number of matchsticks to make the question correct. So, how many do you have to move? -Riddles

Last Answer : Most people would get to one move at the least, but the real answer is zero moves. If you rotate the whole question around 180 degrees, it will display this: X = IX + I

Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

Description : Solve the following in equalities `(i) |x+7| gt 5` `(ii) |x+3| lt 10` `(iii) (x+2) lt |x^(2)+3x+5|``(iv) |(2x-1)/(x-1)| gt 2` `(v) |x-6| le x^(2)-5x+9

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Write the molecular formulae of: 1. Copper oxide 2. Iron (III) chloride 3. Sodium hydroxide 4. Iron (II) sulphide 5. Lead (II) oxide 6. Hydrogen nitrate (nitric acid) 7. Hydrogen sulphate (sulphuric acid) 8. Calcium hydroxide 9. Magnesium carbonate 10.Ammonium carbonate

Description : Write the molecular formulae of: 1. Copper oxide 2. Iron (III) chloride 3. Sodium hydroxide 4. Iron (II) sulphide 5. Lead (II) oxide 6. Hydrogen nitrate (nitric ... Hydrogen sulphate (sulphuric acid) 8. Calcium hydroxide 9. Magnesium carbonate 10.Ammonium carbonate

Last Answer : 1. Copper oxide - CuO 2. Iron (III) chloride - FeCl3 3. Sodium hydroxide - NaOH 4. Iron (II) sulphide - FeS 5. Lead (II) oxide - PbO 6. Hydrogen nitrate (nitric acid) - HNO3 7. ... ) - H2SO4 8. Calcium hydroxide - Ca(OH)2 9. Magnesium carbonate - MgCO3 10.Ammonium carbonate - (NH4)2CO3

Express the following as pth power of qth root of x. (i) `(156)^(5/3)` (ii) `(-23)^(3/7)` (iii) `(2/3)^(3/2)` (iv) `(0.61)^(5/9)`

Description : Express the following as pth power of qth root of x. (i) `(156)^(5/3)` (ii) `(-23)^(3/7)` (iii) `(2/3)^(3/2)` (iv) `(0.61)^(5/9)`

Last Answer : Express the following as pth power of qth root of x. (i) `(156)^(5/3)` (ii) `(-23)^(3/7)` (iii) `(2/3)^(3/2)` (iv) `(0.61)^(5/9)`

Pressure of Oxygen during pre-heating shall be? (i) 4.0 – 5.0 kg/ sq cm (ii) 5.0 – 6.0 kg/ sq cm (iii) 6.0 – 7.0 kg/ sq cm (iv) 7.0 – 8.0 kg/ sq cm *

Description : Pressure of Oxygen during pre-heating shall be? (i) 4.0 – 5.0 kg/ sq cm (ii) 5.0 – 6.0 kg/ sq cm (iii) 6.0 – 7.0 kg/ sq cm (iv) 7.0 – 8.0 kg/ sq cm *

Last Answer : (iv) 7.0 – 8.0 kg/ sq cm *

PROBLEM EA Sample of moist soil has a water content of 20.0% and the moist unit weight of 21.09 KN/cu.meter. The specific gravity of the soil is 2.75. Compute the degree of saturation and the value of porosity?

Description : PROBLEM EA Sample of moist soil has a water content of 20.0% and the moist unit weight of 21.09 KN/cu.meter. The specific gravity of the soil is 2.75. Compute the degree of saturation and the value of porosity?

Last Answer : two seconds

How many % of mobile web users abandon pages if they don't load within 10 seconds? A. 0.6 B. 0.65 C. 0.7 D. 0.75

Description : How many % of mobile web users abandon pages if they don't load within 10 seconds? A. 0.6 B. 0.65 C. 0.7 D. 0.75

Last Answer : B. 0.65

Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, 49, 50, 74, 75, 99,100 B. 10, 50, 75,100, 250, 1000 C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Description : Assume postal rates for 'light letters' are: $0.25 up to 10 grams; $0.35 up to 50 grams; $0.45 up to 75 grams; $0.55 up to 100 grams. Which test inputs (in grams) would be selected using boundary value analysis? A. 0, 9,19, ... C. 0, 1,10,11, 50, 51, 75, 76,100,101 D. 25, 26, 35, 36, 45, 46, 55, 56

Last Answer : C. 0, 1,10,11, 50, 51, 75, 76,100,101

2. In Activity 13.7, how do we think the displacement of rod AB will be affected if (i) current in rod AB is increased; (ii) a stronger horse-shoe magnet is used; and (iii) length of the rod AB is increased? -Physics-10

Description : 2. In Activity 13.7, how do we think the displacement of rod AB will be affected if (i) current in rod AB is increased; (ii) a stronger horse-shoe magnet is used; and (iii) length of the rod AB is increased? -Physics-10

Last Answer : A current carrying conductor when placed in a magnetic field experiences force. The magnitude of this force will increase with the increase in the amount of current, length of conductor and the strength ... AB is increased Stronger horse shoe magnet is used When the length of the rod AB increases

After how much time lining of crucible should be changed ? (i) After every weld (ii) After 7 welds (iii) After every 10 welds* (iv) None of the above

Description : After how much time lining of crucible should be changed ? (i) After every weld (ii) After 7 welds (iii) After every 10 welds* (iv) None of the above

Last Answer : (iii) After every 10 welds*

NULL value means : (i) 0 value (ii) 1 value (iii) None value (iv) None of the above -Technology

Description : NULL value means : (i) 0 value (ii) 1 value (iii) None value (iv) None of the above -Technology

Last Answer : Correct option (d) None value

Calculate the labour turnover rate according to Separation method from the following: No. of workers on the payroll: - At the beginning of the month: 500 - At the end of the month: 600 During the month, 5 workers left, 20 workers were discharged and 75 workers were recruited. Of these, 10 workers were recruited in the vacancies of those leaving and while the rest were engaged for an expansion scheme. (a) 4.55% (b) 1.82% (c) 6% (d) 3%

Description : Calculate the labour turnover rate according to Separation method from the following: No. of workers on the payroll: - At the beginning of the month: 500 - At the end of the month: 600 During the month, 5 workers left ... engaged for an  expansion scheme. (a) 4.55% (b) 1.82% (c) 6% (d) 3%

Last Answer : (a) 4.55%