The relation between EER in BTU/hr/W EER in W/W is given as_________. A. EER in BTU/hr/W = 3.245 EER in W/W. B. EER in BTU/hr/W = 3.44 EER in W/W. C. EER in BTU/hr/W = 3.413 EER in W/W. D. EER in BTU/hr/W = 1.234 EER in W/W.

The relation between EER in BTU/hr/W EER in W/W is given as_________.
A. EER in BTU/hr/W = 3.245 EER in W/W.
B. EER in BTU/hr/W = 3.44 EER in W/W.
C. EER in BTU/hr/W = 3.413 EER in W/W.
D. EER in BTU/hr/W = 1.234 EER in W/W.
by

1 Answer

Answer :

EER in BTU/hr/W = 3.413 EER in W/W.
by

Related questions

EER in BTU/hr/W = a) 3.222 * EER in W/W c) 3.413 * EER in W/W b) 3.234 * EER in W/W d) 3.400 * EER in W/W

Description : EER in BTU/hr/W = a) 3.222 * EER in W/W c) 3.413 * EER in W/W b) 3.234 * EER in W/W d) 3.400 * EER in W/W

Last Answer : 3.413 * EER in W/W

EER in BTU/HR/W = ______ X EER in W/W A. 3.410 C. 3.411 B. 3.412 D. 3.413

Description : EER in BTU/HR/W = ______ X EER in W/W A. 3.410 C. 3.411 B. 3.412 D. 3.413

Last Answer : 3.413

nergy Efficiency rating in BTU/hr/W is equal to a) 4.413 W/W b) 2.413 W/W c) 3.413 W/W

Description : Energy Efficiency rating in BTU/hr/W is equal to a) 4.413 W/W b) 2.413 W/W c) 3.413 W/W

Last Answer : 3.413w/w

We have defined EER by a) BTU/hr/W c) BTU/min/W b) BTU/sec/W d) BTU/hr/V

Description : We have defined EER by a) BTU/hr/W c) BTU/min/W b) BTU/sec/W d) BTU/hr/V

Last Answer : BTU/hr/W

Which one is the correct relation between energy efficiency ratio (EER) and coefficient of performance (COP)?  A. EER = 2.34 COP  B. EER = 3.24 COP  C. EER = 3.42 COP  D. EER = 4.23 COP

Description : Which one is the correct relation between energy efficiency ratio (EER) and coefficient of performance (COP)?  A. EER = 2.34 COP  B. EER = 3.24 COP  C. EER = 3.42 COP  D. EER = 4.23 COP

Last Answer : EER = 3.42 COP

Overall heat transfer co-efficient for cooling of hydrocarbons by water is about (A) 50 -100 Kcal/hr.m2 .°C (B) 50 -100 W/m2 .°K (C) 50 -100 BTU/hr. ft. 2°F (D) 1000 - 1500 BTU/hr. ft. 2°F

Description : Overall heat transfer co-efficient for cooling of hydrocarbons by water is about (A) 50 -100 Kcal/hr.m2 .°C (B) 50 -100 W/m2 .°K (C) 50 -100 BTU/hr. ft. 2°F (D) 1000 - 1500 BTU/hr. ft. 2°F

Last Answer : (C) 50 -100 BTU/hr. ft. 2°F

Minimum EER of 5-star rating is a. 3.50 c) 3.99 b. 4.00 d) 4.50

Description : Minimum EER of 5-star rating is a. 3.50 c) 3.99 b. 4.00 d) 4.50

Last Answer : 4.50

Higher the number of stars, ________ will be the efficiency or EER a) Lesser c) Greater b) Likewise e) average

Description : Higher the number of stars, ________ will be the efficiency or EER a) Lesser c) Greater b) Likewise e) average

Last Answer : Greater

Full form of EER is _____ A. Energy Electric Ratio C. Energy Efficiency Ratio B. Energy Effective Ratio D. Energy Electron Ratio

Description : Full form of EER is _____ A. Energy Electric Ratio C. Energy Efficiency Ratio B. Energy Effective Ratio D. Energy Electron Ratio

Last Answer : Energy Efficiency Ratio

Higher the number stars, EER or efficiency will be. A. Greater C. Lesser B. Moderate D. None of the above

Description : Higher the number stars, EER or efficiency will be. A. Greater C. Lesser B. Moderate D. None of the above

Last Answer : Greater

___________ is the minimum EER for 5-star in India in 2019. A) 4.50 C) 4.00 B) 7.10 D) 4.49

Description : ___________ is the minimum EER for 5-star in India in 2019. A) 4.50 C) 4.00 B) 7.10 D) 4.49

Last Answer : 4.50

The ratio of the total amount of heat that equipment can remove from the indoors to travel and amount of energy consumed by the equipment is known as A) Energy performance ratio (EPR). C) Energy efficiency RATIO (EER). B) Energy consumption ratio (ECR). D) None of the above

Description : . The ratio of the total amount of heat that equipment can remove from the indoors to travel and amount of energy consumed by the equipment is known as A) Energy performance ratio (EPR). C) Energy efficiency RATIO (EER). B) Energy consumption ratio (ECR). D) None of the above

Last Answer : Energy efficiency RATIO (EER).

Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Description : Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Last Answer : -364 BTU/lbm

1 BTU/hr.ft.°F is equal to __________ kcal/hr. m.°C. (A) 1.49 (B) 1 (C) 4.88 (D) None of these

Description : 1 BTU/hr.ft.°F is equal to __________ kcal/hr. m.°C. (A) 1.49 (B) 1 (C) 4.88 (D) None of these

Last Answer : (A) 1.49

The unit of heat transfer co-efficient is (A) BTU/hr. ft 2°F (B) BTU/hr. °F. ft (C) BTU/hr. °F (D) BTU/hr. ft

Description : The unit of heat transfer co-efficient is (A) BTU/hr. ft 2°F (B) BTU/hr. °F. ft (C) BTU/hr. °F (D) BTU/hr. ft

Last Answer : (A) BTU/hr. ft 2°F

A BTU/hr.ft. 2 °F is equal to (A) 1 kcal/hr. m2°C (B) 4.88 kcal/hr. m. 2°C (C) 1 kcal/hr. m2 .°K (D) None of these

Description : A BTU/hr.ft. 2 °F is equal to (A) 1 kcal/hr. m2°C (B) 4.88 kcal/hr. m. 2°C (C) 1 kcal/hr. m2 .°K (D) None of these

Last Answer : (B) 4.88 kcal/hr. m. 2°C

Pick out the correct statement. (A) 1 kcal/hr.m.°C is equal to 1 BTU/hr. ft.°F (B) In steady state heat conduction, the only property of the substance which determines the temperature distribution, is the thermal conductivity (C) In unsteady state heat conduction, heat flows in the direction of temperature rise (D) In heat transfer by forced convection, Grashoff number is very important

Description : Pick out the correct statement. (A) 1 kcal/hr.m.°C is equal to 1 BTU/hr. ft.°F (B) In steady state heat conduction, the only property of the substance which determines the ... in the direction of temperature rise (D) In heat transfer by forced convection, Grashoff number is very important

Last Answer : (B) In steady state heat conduction, the only property of the substance which determines the temperature distribution, is the thermal conductivity

One ton of refrigeration capacity is equivalent to the heat removal rate of (A) 50 kcal/hr (B) 200 BTU/hr (C) 200 BTU/minute

Description : One ton of refrigeration capacity is equivalent to the heat removal rate of (A) 50 kcal/hr (B) 200 BTU/hr (C) 200 BTU/minute

Last Answer : (C) 200 BTU/minute

The load instruction is mostly used to designate a transfer from memory to a processor register known as_________ A. Accumulator B. Instruction Register C. Program counter D. Memory address Register

Description : The load instruction is mostly used to designate a transfer from memory to a processor register known as_________ A. Accumulator B. Instruction Register C. Program counter D. Memory address Register

Last Answer : A. Accumulator

What Is The Meaning Of Btu In Air Conditioners?

Description : What Is The Meaning Of Btu In Air Conditioners?

Last Answer : Btu - British Thermal Unit (Btu) is the international measure of energy. A Btu is the amount of heat needed to raise 1 (one) pound of water by 1(one) degree Fahrenheit. In HVAC industry, Btu's ... heat a conditioning unit can remove from a room per hours. One BTU per hour is equal to 0293 watts.

What Is Btu?

Description : What Is Btu?

Last Answer : The British thermal unit (Btu or BTU) is a traditional unit of heat; it is defined as the amount of heat required to raise the temperature of one pound of water by one degree Fahrenheit. ... Heat is ... to be equivalent to energy, for which the metric unit is the joule; one BTU is about 1055 joules.

78 India‘s total primary energy consumption is a) 24.3 BTU b) 19.01 BTU c) 120 BTU d) 30.1 BTU

Description : 78 India‘s total primary energy consumption is a) 24.3 BTU b) 19.01 BTU c) 120 BTU d) 30.1 BTU

Last Answer : 30.1 BTU

The mechanical equivalent of heat is  a. joule  b. calorie  c. Btu  d. Specific heat

Description : The mechanical equivalent of heat is  a. joule  b. calorie  c. Btu  d. Specific heat

Last Answer : joule

What is defined as the quantity of heat needed to raise the temperature of one kilogram of water by one degrees Celsius?  a. Kilojoule  b. Btu  c. Kilocalorie  d. Latent heat

Description : What is defined as the quantity of heat needed to raise the temperature of one kilogram of water by one degrees Celsius?  a. Kilojoule  b. Btu  c. Kilocalorie  d. Latent heat

Last Answer : Kilocalorie

Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216  a. 1214 Btu / lb  b. 1234 Btu /lb  c. 1342 Btu / lb  d. 1324 Btu /lb formula: ∫ = h– pv/ J

Description : Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216  a. 1214 Btu / lb  b. 1234 Btu /lb  c. 1342 Btu / lb  d. 1324 Btu /lb formula: ∫ = h– pv/ J

Last Answer : 1214Btu / lb

A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. T2 = 2.620ºR, ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Description : A certain gas with cp = 0.529Btu/lb°R and R = 96.2ft/lbºR expands from 5 ft and 80ºF to 15 ft while the pressure remains constant at 15.5 psia.  a. T2=1.620ºR, ∫H = 122.83 Btu  b. T2 = 2°R, ∫H = 122.83 Btu  c. ... , ∫H = 122.83 Btu  d. T2 = 1°R, ∫H = 122.83 Btu T2= V2(t2)/V1 and ∫H = mcp (T2-T1)

Last Answer : T2=1.620ºR, ∫H = 122.83 Btu

Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Description : Find the change in internal energy of 5 lb. of oxygen gas when the temperature changes from 100 ˚F to 120 ˚F. CV = 0.157 BTU/lbm-˚R  A.14.7 BTU  B.15.7 BTU  C. 16.8 BTU  D. 15.9 BTU Formula: U= mcv T

Last Answer : 15.7 BTU

Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Description : Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Last Answer : 1.1577 BTU/lbm-˚R

_________ is the quantity of heat required to raise the temperature of one pound of water 1 F˚ from 63 ˚F to 64 ˚F.  a. one Joule  b. one calorie  c. one watt  d. one BTU

Description : _________ is the quantity of heat required to raise the temperature of one pound of water 1 F˚ from 63 ˚F to 64 ˚F.  a. one Joule  b. one calorie  c. one watt  d. one BTU

Last Answer : one BTU

1 British thermal unit (BTU) is equivalent to how many joules?  A. 1016  B. 1043  C. 1023  D. 1054

Description : 1 British thermal unit (BTU) is equivalent to how many joules?  A. 1016  B. 1043  C. 1023  D. 1054

Last Answer : 1054

The amount of heat required to raise the temperature of 1 pound of water by 1°F is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Description : The amount of heat required to raise the temperature of 1 pound of water by 1°F is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Last Answer : BTU

The amount of heat required to raise the temperature of 1kg of water through 1 °C is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Description : The amount of heat required to raise the temperature of 1kg of water through 1 °C is called ______.  A. Calorie  B. Joule  C. BTU  D. Kilocalorie

Last Answer : Kilocalorie

What is the SI unit of energy?  A. Newton  B. Btu  C. Calorie  D. Joule

Description : What is the SI unit of energy?  A. Newton  B. Btu  C. Calorie  D. Joule

Last Answer : Joule

A vertical column of water will be supported to what height by standard atmospheric pressure. If the Y w = 62.4lb/ft3 po = 14.7 psi.  a. 44.9 ft  b. 33.9 ft  c. 22.9 ft  d. 55.9 ft formula: ho= po/Yw

Description : A vertical column of water will be supported to what height by standard atmospheric pressure. If the Y w = 62.4lb/ft3 po = 14.7 psi.  a. 44.9 ft  b. 33.9 ft  c. 22.9 ft  d. 55.9 ft formula: ho= po/Yw

Last Answer : 33.9 ft

A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Last Answer : (a) 3km/hr

A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Description : A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours it can go 40 km upstream and 55 km downstream. Then what is the speed of the stream? (a) 3km/hr (b) 5km/hr (c) 6km/hr (d) 7km/hr

Last Answer : (a) 3km/hr

A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train (in kmph) if sound travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr

Description : A certain thing is thrown twice from a place with the gap of 45 minutes between the two shots. A girl approaching this point in a train heard the second shot 44 minutes after she heard the first shot. What is the speed of train ... travels at 660 m/s? a) 62 km/hr b) 54 km/hr c) 48 km/hr d) 27 km/hr

Last Answer : B Actual time between the two shots being fired = 45 minutes. If a girl was stationary she would have heard the shots after 44 minutes. But since the train was moving towards the source, she heard the second shot after ... = (15 *18/5) km/hr =54 km/hr Hence the speed of the train is 54 km/hr

A mototboat can row to a place 112 km away and come back in 44 hours. The time to row 42 km with the stream is same as the time to row 24 km against the stream. Find the speed of boat in still water. A) 5.5 km/hr B) 7.5km/hr C) 10.5 km/hr D) 3.5 km/hr

Description : A mototboat can row to a place 112 km away and come back in 44 hours. The time to row 42 km with the stream is same as the time to row 24 km against the stream. Find the speed of boat in still water. A) 5.5 km/hr B) 7.5km/hr C) 10.5 km/hr D) 3.5 km/hr 

Last Answer : ANSWER: A Explanation: Downstream speed = 42/x km/hr Upstream speed = 24/x km/hr 112 / (42 / x) + 112 / (24 / x) = 44 112[x /42 + x / 24] = 44 112 / 3 [x / 14 + x / 8] = 44 11x / 56 = 44 * ... = 4 km/hr Speed of boat = 1/2 * (7 + 4) km/hr = 11 /2 speed of boat in still water = 5.5 km/hr

Write the simple form of a rational number 177/413. -Maths 9th

Description : Write the simple form of a rational number 177/413. -Maths 9th

Last Answer : This answer was deleted by our moderators...

my phone isnt working is the network down 254-413-0193?

Description : my phone isnt working is the network down 254-413-0193?

Last Answer : At times the networks conduct maintenance but not that long..Usually there is weather problems

Hello I'm interested in becoming a Loan broker. Please contact with requirements. Henry Howard 205-413-2741?

Description : Hello I'm interested in becoming a Loan broker. Please contact with requirements. Henry Howard 205-413-2741?

Last Answer : To become a loan broker you would need a license and first you need to be a loan agent in order to get your loan broker's license. All you need to be is start working with a licensed loan broker, get suitable training and the apply for a brokerage license.

The settlement velocity of a solid (diameter 0.5 mm, specific gravity 1.75) in water having temperature 10°C, is A. 213.5 cm/sec B. 313.5 cm/sec C. 413.5 cm/sec D. 500 cm/sec

Description : The settlement velocity of a solid (diameter 0.5 mm, specific gravity 1.75) in water having temperature 10°C, is A. 213.5 cm/sec B. 313.5 cm/sec C. 413.5 cm/sec D. 500 cm/sec

Last Answer : ANS: B

Perform following number system conversion : (i) (589)10 = ( )2 (ii) (101101)2 = ( )16 (iii) (413)8 = ( )2 (iv) (5AF)16 = ( )10 (v) (AC8)16 = ( )2 (vi) (106)8 = ( )10

Description : Perform following number system conversion : (i) (589)10 = ( )2 (ii) (101101)2 = ( )16 (iii) (413)8 = ( )2 (iv) (5AF)16 = ( )10 (v) (AC8)16 = ( )2 (vi) (106)8 = ( )10

Last Answer : (i) (589)10 = (1001001101)2 (ii) (101101)2 = ( 2D )16 (iii) (413)8 = (100001011 )2 (iv) (5AF)16 = (1455 )10 (v) (AC8)16 = (101011001000)2 (vi) (106)8 = (70)10

Capacity of flight conveyor in tons/hr is given by (where, W & D = width and depth of flight respectively in metre V = speed of the conveyor, metre/second ρ = bulk density of material, kg/m3 ) (A) 3.6 W.D.V.ρ (B) 3.6 W.D.V (C) 3.6 W.V.ρ (D) 3.6 D.V.ρ

Description : Capacity of flight conveyor in tons/hr is given by (where, W & D = width and depth of flight respectively in metre V = speed of the conveyor, metre/second ρ = bulk density of material, kg/m3 ) (A) 3.6 W.D.V.ρ (B) 3.6 W.D.V (C) 3.6 W.V.ρ (D) 3.6 D.V.ρ

Last Answer : (A) 3.6 W.D.V.ρ

Theoretical capacity of crushing rolls in tons/hr is given by (where, V = peripheral velocity, m/sec. W = width of rolls, m Dr = distance between rolls ρ = density of material to be crushed, kg/m3 here, V =πND where, N = speed of the rolls in rotation per second (rps) D = diameter of rolls, m). (A) 3.6 V.W.Dr.ρ (B) 3.6 V.W. ρ (C) 3.6 W.Dr.ρ (D) 3.6 V.W.Dr/ρ

Description : Theoretical capacity of crushing rolls in tons/hr is given by (where, V = peripheral velocity, m/sec. W = width of rolls, m Dr = distance between rolls ρ = density of material to be crushed, kg/m3 here, V =πND where, N = speed of the rolls ... V.W.Dr.ρ (B) 3.6 V.W. ρ (C) 3.6 W.Dr.ρ (D) 3.6 V.W.Dr/ρ

Last Answer : (A) 3.6 V.W.Dr.ρ

A ball is dropped from a height of 2.25 m on a smooth floor and it rises to a height of 1 m after the first bounce. The coefficient of restitutions between the ball and the floor is a.107 dynes b.0.33 c.0.44 d.0.57 e.0.67

Description : A ball is dropped from a height of 2.25 m on a smooth floor and it rises to a height of 1 m after the first bounce. The coefficient of restitutions between the ball and the floor is a.107 dynes b.0.33 c.0.44 d.0.57 e.0.67

Last Answer : e. 0.67

The x coordinate of the centroid of the area enclosed by the parabolas y = x2 and x = y2 will be a.107 dynes b.0.44 c.0.43 d.0.45 e.0.46

Description : The x coordinate of the centroid of the area enclosed by the parabolas y = x2 and x = y2 will be a.107 dynes b.0.44 c.0.43 d.0.45 e.0.46

Last Answer : d. 0.45

A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in 10 sec. The distance between the locomotive and the wagons at this instant assuming that the forces acting on the train are unaltered would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Description : A locomotive of weight 100 tonnes is attached to train of wagons weighing 1000 tonnes. The locomotive pulls the wagons with a constant velocity of 36 km/hour. When the coupling between the train and wagons breaks, the wagons roll on 95 m in ... would be a.0.36 m b.0.44 m c.0.77 m. d.0.5 m e.0.66 m

Last Answer : d. 0.5 m

A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Description : A problem Drum ( 3 ft. diameter ; 6 ft. height ) is field with a fluid whose density is 50 lb/ft^3. Determine the total volume of the fluid.  A. 42.41 ft^3  B.44.35 ft^3  C.45.63 ft^3  D.41.23 ft^3 Formula: Vf = (pi d^2 h) / 4

Last Answer : 42.41 ft^3