An ideal gas is taken around the cycle ABCA as shown in P-V diagram below: The work done by the gas during the cycle is equal to
(A) 12 P1V1
(B) 6 P1 V1
(C) 3 P1V1
(D) P1 V1

1 Answer

Answer :

(C) 3 P1V1

Related questions

Description : Which of the following is the Ideal gas law (equation)?  A. V/T = K  B. V= k*(1/P)  C. P1/T1 = P2/T2  D. PV = nRT

Last Answer : PV = nRT

Description : An ideal gas at 45psig and 80ºF is heated in the close container to 130ºF. What is the final pressure?  a. 65.10 psi  b. 65.11 psi  c. 65.23 psi  d. 61.16 psi P1V1/T1= P2V2/T2;V = Constant

Last Answer : 65.23 psi

Description : What horse power is required to isothermally compress 800 ft^3 of Air per minute from 14.7 psia to 120 psia?  A. 28 hp  B.108 hp  C.256 hp  D.13900 hp Formula: W= p1V1 ln (p1/p2) Power = dW / dt

Last Answer : 108 hp

Description : The expression, nRT ln(P1/P2), is for the __________of an ideal gas. (A) Compressibility (B) Work done under adiabatic condition (C) Work done under isothermal condition (D) Co-efficient of thermal expansion

Last Answer : C) Work done under isothermal condition

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

Description : A two stage compressor is used to compress an ideal gas. The gas is cooled to the initial temperature after each stage. The intermediate pressure for the minimum total work requirement should be equal to ... final pressures respectively) (A) Logarithmic (B) Arithmetic (C) Geometric (D) Harmonic

Last Answer : (C) Geometric

Description : Q No: 251 In a sludge digestion tank if the moisture content of sludge V1 litres is reduced from p1 % to p2 % the volume V2 is A. [(100 + P1)/(100 – P2)] V1 B. [(100 – P1)/(100 + P2)] V1 C. [(100 – P1)/(100 – P2)] V1 D. [(100 + P2)/(100 – P1)] V1

Last Answer : ANS: C

Description : Which of the following is the mathematical representation of the Charles’s law?  A. V1/V2= P2/P1  B. V1/T1=V2/T2  C. V1/T2=V2/T1  D. V1/V2=√P2/√P1

Last Answer : V1/T1=V2/T2

Description : p1V1= p2V2  a. Charle's Law  b. Boyle's Law  c. Ideal Gas Law  d. Joule's Law

Last Answer : Boyle's Law

Description : The expression, ∆G = nRT. ln(P2/P1), gives the free energy change (A) With pressure changes at constant temperature (B) Under reversible isothermal volume change (C) During heating of an ideal gas (D) During cooling of an ideal gas

Last Answer : (A) With pressure changes at constant temperature

Description : In a P-V diagram (for an ideal gas), an isothermal curve will coincide within adiabatic curve (through a point), when (A) Cp < Cv (B) Cp = Cv (C) Cp > Cv (D) C ≥ Cv

Last Answer : (B) Cp = Cv

Description : On a P-V diagram of an ideal gas, suppose a reversible adiabatic line intersects a reversible isothermal line at point A. Then at a point A, the slope of the reversible adiabatic line (∂P/∂V)s and the slope of the reversible isothermal line ... Y (C) (∂P/∂V)S = y(∂P/∂V)T (D) (∂P/∂V)S = 1/y(∂P/∂V)T

Last Answer : (C) (∂P/∂V)S = y(∂P/∂V)T

Description : The compressibility factor of a gas is given by (where, V1 = actual volume of the gas V2 = gas volume predicted by ideal gas law) (A) V1/V2 (B) V2/V1 (C) V1- V2 (D) V1.V2

Last Answer : (A) V1/V2

Description : The expression for entropy change given by, ΔS = nR ln (V2/V1) + nCvln (T2/T1) is valid for (A) Reversible isothermal volume change (B) Heating of a substance (C) Cooling of a substance (D) Simultaneous heating and expansion of an ideal gas

Last Answer : (D) Simultaneous heating and expansion of an ideal gas

Description : The expression for entropy change given by, ΔS = - nR ln (P2/P1), holds good for (A) Expansion of a real gas (B) Reversible isothermal volume change (C) Heating of an ideal gas (D) Cooling of a real gas

Last Answer : (B) Reversible isothermal volume change

Description : To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to ... gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Last Answer : (D) All (A), (B) & (C)

Description : What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Last Answer : W = mRTln (V2/V1)

Description : Consider the fractional knapsack instance n = 4, (p1, p2, p3, p4) = (10, 10, 12, 18), (w1, w2, w3, w4) = (2, 4, 6, 9) and M = 15. The maximum profit is given by (Assume p and w denotes profit and weight of objects respectively) (A) 40 (B) 38 (C) 32 (D) 30

Last Answer : (B) 38

Description : Suppose there are four processes in execution with 12 instances of a Resource R in a system. The maximum need of each process and current allocation are given below: With reference to current allocation, is system safe? If so, ... B) Yes, P1 P2 P3 P4 (C) Yes, P4 P3 P1 P2 (D) Yes, P2 P1 P3 P4

Last Answer : (C) Yes, P4 P3 P1 P2

Description : Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Last Answer : -364 BTU/lbm

Description : Twenty grams of oxygen gas are compressed at a constant temperature of 30 ˚C to 5%of their original volume. What work is done on the system.  A.824 cal  B.924 cal  C.944 cal  D.1124 cal Formula: W = -mRTln (V2/V1) Where R = (1.98 cal/gmole·K) (32 g/gmole)

Last Answer : 1124 cal

Description : A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle ... fluidisation velocity, VOM is (A) 12 mm/s (B) 16 mm/s (C) 24 mm/s (D) 28 mm/s

Last Answer : (B) 16 mm/s

Description : In a dry packed bed, the pressure drop will be changed by increasing the flow rate as (A) V1.8 (B) V-0.8 (C) V (D) V-1

Last Answer : (A) V1.8

Description : essure drop (Δp) for a fluid flowing in turbulent flow through a pipe is a function of velocity (V) as (A) V1.8 (B) V-0.2 (C) V2.7 (D) V

Last Answer : (D) V

Description : Draw dual cycle on P V and T S diagram and write the processes involved in it. 

Last Answer : 1-2 Isentropic compression of air  2-3 the combustion of fuel at constant volume.  3-4 the combustion of fuel at constant pressure  4-5 Isentropic expansion during which work is done by the system.  5-1 Heat rejection at constant volume. 

Description : Draw P-V diagram of Otto cycle.

Last Answer : P-V diagram of Otto cycle :

Description : Draw P-V and T-S diagram of dual combustion cycle.

Last Answer : Dual combustion cycle: 1-2 Isentropic compression of air 2-3 the combustion of fuel at constant volume. 3-4 the combustion of fuel at constant pressure 4-5 Isentropic expansion during which work is done by the system. 5-1 Heat rejection at constant volume.

Description : Draw P-V and T-S diagram for brayton cycle.

Last Answer : P-V and T-S diagram for brayton cycle.

Description : Explain Otto cycle with P-V and T-S diagram.

Last Answer : This cycle is so named as it was conceived by Otto'. On this cycle, petrol, gas and many types of oil engines work. It is the standard of comparison for internal combustion engines. Figs. ... 4-1 shows the rejection of heat by air at constant volume till original state (point 1) reaches.

Description : Describe with a neat diagram the working of a simple vapour compression refrigeration system. Represent the cycle on P–V and T–S diagram. 

Last Answer : Vapour compression refrigeration cycle: The vapor-compression uses a circulating liquid refrigerant as the medium which absorbs and removes heat from the space to be cooled and subsequently rejects that heat elsewhere. Figure shows ... the compressor. P-V Diagram T-S diagram: 

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Description : Which is not constant for an ideal gas? (A) (∂P/∂V)T (B) (∂V/∂T)P (C) (∂P/∂V)V (D) All (A), (B) & (C)

Last Answer : (A) (∂P/∂V)T

Description : The volume of a gas under standard atmospheric pressure & 76 cmHg is 200m³. What is the volume when pressure is 80 cmHg if the temperature is unchanged?  a) 180 in³  b) 170 in³  c) 160 in³  d) 190 in³ Formula: P2V2 = P1V1

Last Answer : 190 in³

Description : Assuming compression is according to the Law PV = C, Calculate the initial volume of the gas at a pressure of 2 bars w/c will occupy a volume of 6m³ when it is compressed to a pressure of 42 Bars.  a) 130m³  b) 136m³  c) 120m³  d) 126m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 126m³

Description : The pressure gauge on a 2000 m³ tank of oxygen gas reads 600 kPa. How much volumes will the oxygen occupied at pressure of the outside air 100 kPa?  a) 14026.5 m³  b) 15026.5 m³  c) 13026.5 m³  d) 16026.5 m³ Formula: P1V1/T1 =P2V2/T2

Last Answer : 14026.5 m³

Description : What steps shall be required to rotate an object about the point P1 (as shown in fig.1) and its placement such that what was at P1 is now reduced and is at P2 (as shown in fig.2). I. Translate P1 to origin II. ... (A) I,II and III (B) II,III and IV (C) I,III and IV (D) All of the above

Last Answer : Answer: Marks given to all

Description : A vertex cover of an undirected graph G(V, E) is a subset V1 ⊆ V vertices such that (A) Each pair of vertices in V1 is connected by an edge (B) If (u, v) ∈ E then u ∈ V1 and v ∈ V1 (C) If (u, v) ∈ E then u ∈ V1 or v ∈ V1 (D) All pairs of vertices in V1 are not connected by an edge

Last Answer : (C) If (u, v) ∈ E then u ∈ V1 or v ∈ V1

Description : 3.0 lbm of air are contained at 25 psia and 100 ˚F. Given that Rair = 53.35 ft-lbf/lbm- ˚F, what is the volume of the container?  A.10.7 ft^3  B.14.7 ft^3  C.15 ft^3  D.24.9 ft^3 Formula: use the ideal gas law pV = mRT T = (100 +460) ˚R V = mRT/p

Last Answer : 24.9 ft^3

Description : If air is at pressure, p, of 3200 lbf/ft2 , and at a temperature, T, of 800 ˚R, what is the specific volume, v? (R=5303 ft-lbf/lbm-˚R, and air can be modeled as an ideal gas.)  A.9.8 ft^3/lbm  B.11.2 ft^3/lbm  C.13.33 ft^3/lbm  D.14.2 ft^3/lbm Formula: pv = RT v = RT / p

Last Answer : 13.33 ft^3/lbm

Description : An ideal gas is heated at constant volume and then expanded isothermally. Show processes on P-V & T-S diagrams.

Last Answer : Process 1-2 : Constant volume process Process 2-3 : Constant temperature process (Isothermal process)

Description : The diagram below shows a simple machine in use. Study it, then answerquestion 6.The simple machine shown above is an example of a/an(B)(A) inclined plane.(D) wedge.(C)?

Last Answer : auscultation (listen

Description : A fluid flows in a steady manner between two section in a flow line at section 1: A 1 = 1ft², V1 = 100fpm, volume1 of 4ft³/lb. at sec2: A2 = 2 ft², p= 0.20 lb/ft³ calculate the velocity at section 2.  a. 625 fpm  b. 567 fpm  c. 356 fpm  d. None of the above

Last Answer : 625 fpm

Description : A definite amount of an ideal gas `(gamma = 1.5)` undergoes change of state in which heat exchange is equal to work done `(q=w)`. Molar heat capacity

Last Answer : A definite amount of an ideal gas `(gamma = 1.5)` undergoes change of state in which heat exchange is equal to work ... : A. 2R B. 3R C. R D. `3/2R`

Description : In the circuit shown in figure ammeter and voltmeter are ideal. If `E=4 V,R=9Omega` and `r=1Omega` then readings of ammeter and voltmeter are

Last Answer : In the circuit shown in figure ammeter and voltmeter are ideal. If `E=4 V,R=9Omega` and `r=1Omega` then readings of ... V C. 3 A, 4 V D. 4 A, 4 V

Description : Assume that the n-channel MOSFET shown in figure is ideal and that its threshold voltage is +1 .0 V. The voltage Vab between nodes a and b is A)5V B)2V C)1V D)0V

Last Answer : Assume that the n-channel MOSFET shown in figure is ideal and that its threshold voltage is +1 .0 V. The voltage Vab between nodes a and b is 0V

Description : A bed of spherical particles (specific gravity 2.5) of uniform size 1500 μm is 0.5 m in diameter and 0.5 m high. In packed bed state, the porosity may be taken as 0.4. Ergun's equation for the above fluid-particle system ... What is the porosity of the fluidised bed? (A) 0.2 (B) 0.5 (C) 0.7 (D) 0.8

Last Answer : (C) 0.7

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

Description : Oxygen at 15ºC and 10.3 Mpa gauge pressure occupies 600L. What is the occupied by the oxygen at 8.28 Mpa gauge pressure and 35ºC?  a. 789.32 L  b. 796.32 L  c. 699 L  d. 588 L V2= P1V1/T1P2

Last Answer : 796.32 L

Description : In the above problem, compute for the mass. (Formula: m = p1V1 / RT1)  a. 0.2148 lb  b. 0.2134 lb  c. 0.1248 lb  d. None of the above

Last Answer : 0.2148 lb