Which is not constant for an ideal gas? (A) (∂P/∂V)T (B) (∂V/∂T)P (C) (∂P/∂V)V (D) All (A), (B) & (C)

Which is not constant for an ideal gas?
(A) (∂P/∂V)T
(B) (∂V/∂T)P
(C) (∂P/∂V)V
(D) All (A), (B) & (C)
by

1 Answer

Answer :

(A) (∂P/∂V)T
by

Related questions

Maxwell's relation corresponding to the identity, dH = dS = Vdp + ∑μi dni is (A) (∂T/∂V)S, ni = -(∂P/∂S)V, ni (B) (∂S/∂P)T, ni = (∂V/∂T)P, ni (C) (∂S/∂V)T, ni = (∂P/∂T)V, ni (D) (∂T/∂P)S, ni = (∂V/∂S)P, ni

Description : Maxwell's relation corresponding to the identity, dH = dS = Vdp + ∑μi dni is (A) (∂T/∂V)S, ni = -(∂P/∂S)V, ni (B) (∂S/∂P)T, ni = (∂V/∂T)P, ni (C) (∂S/∂V)T, ni = (∂P/∂T)V, ni (D) (∂T/∂P)S, ni = (∂V/∂S)P, ni

Last Answer : (D) (∂T/∂P)S, ni = (∂V/∂S)P, ni

The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is (A) (∂T/∂V)S = - (∂P/∂S)V (B) (∂S/∂P)T = - (∂V/∂T)P (C) (∂V/∂S)P = (∂T/∂P)S (D) (∂S/∂V)T = (∂P/∂T)V

Description : The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is (A) (∂T/∂V)S = - (∂P/∂S)V (B) (∂S/∂P)T = - (∂V/∂T)P (C) (∂V/∂S)P = (∂T/∂P)S (D) (∂S/∂V)T = (∂P/∂T)V

Last Answer : (D) (∂S/∂V)T = (∂P/∂T)V

Which of the following identities can be most easily used to verify steam table data for superheated steam? (A) (∂T/∂V)S = (∂p/∂S)V (B) (∂T/∂P)S = (∂V/∂S)P (C) (∂P/∂T)V = (∂S/∂V)T (D) (∂V/∂T)P = -(∂S/∂P)T

Description : Which of the following identities can be most easily used to verify steam table data for superheated steam? (A) (∂T/∂V)S = (∂p/∂S)V (B) (∂T/∂P)S = (∂V/∂S)P (C) (∂P/∂T)V = (∂S/∂V)T (D) (∂V/∂T)P = -(∂S/∂P)T

Last Answer : D) (∂V/∂T)P = -(∂S/∂P)T

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Description : For a reversible process involving only pressure-volume work (A) (dF)T, p < 0 (B) (dF)T, p > 0 (C) (dF)T, p = 0 (D) (dA)T, v < 0

Last Answer : (C) (dF)T, p = 0

In case of isentropic flow, the speed of sound in an ideal gas is proportional to (where, T = absolute temperature). (A) 1/√T (B) 1/T (C) √T (D) T

Description : In case of isentropic flow, the speed of sound in an ideal gas is proportional to (where, T = absolute temperature). (A) 1/√T (B) 1/T (C) √T (D) T

Last Answer : (C) √T

Translational kinetic energy of molecules of an ideal gas is proportional to (where, T = absolute temperature of the gas) (A) T (B) √T (C) T2 (D) 1/√T

Description : Translational kinetic energy of molecules of an ideal gas is proportional to (where, T = absolute temperature of the gas) (A) T (B) √T (C) T2 (D) 1/√T

Last Answer : (A) T