In triangular co-ordinates, the ternary composition point falls __________ of the triangle. (A) In the corners(B) Inside(C) On the sides(D) None of these

In triangular co-ordinates, the ternary composition point falls

__________ of the triangle.

(A) In the corners

(B) Inside

(C) On the sides

(D) None of these

by

1 Answer

Answer :

(B) Inside

by

Related questions

For a ternary mixture, in which equilateral triangular co-ordinate is used in leaching and extraction, a __________ of the equilateral triangular co-ordinates. (A) Binary mixture is represented by the apex (B) Binary mixture is represented by any point inside (C) Ternary mixture is represented by the sides (D) Pure component is represented by the apex

Description : For a ternary mixture, in which equilateral triangular co-ordinate is used in leaching and extraction, a __________ of the equilateral triangular co-ordinates. (A) Binary mixture is ... Ternary mixture is represented by the sides (D) Pure component is represented by the apex

Last Answer : (D) Pure component is represented by the apex

Sides of equilateral-triangular co-ordinates (on which ternary liquid system is plotted) represent (A) A pure component (B) A binary mixture (C) A ternary mixture (D) Partially miscible ternary system

Description : Sides of equilateral-triangular co-ordinates (on which ternary liquid system is plotted) represent (A) A pure component (B) A binary mixture (C) A ternary mixture (D) Partially miscible ternary system

Last Answer : (B) A binary mixture

The co-ordinates of mid-points of sides of a triangle are (1, 2), (0, –1) and (2, –1). Find its centroid. -Maths 9th

Description : The co-ordinates of mid-points of sides of a triangle are (1, 2), (0, –1) and (2, –1). Find its centroid. -Maths 9th

Last Answer : ABCD is a parallelogram, if the mid-points of diagonals AC and BD have the same co-ordinates (∵ Diagonals of a parallelogram bisect each other)Co-ordinates of mid-point of AC are \(\bigg(rac{a+2}{2},rac{-11+15}{2}\bigg)\) = \(\bigg(rac ... \(rac{a+2}{2}\) = 3 and 2 = \(rac{b+1}{2}\) ⇒ a = 4, b = 3.

If the co-ordinates of the mid-points of the sides of a triangle are (1, 1), (2, –3), (3, 4), find its incentre. -Maths 9th

Description : If the co-ordinates of the mid-points of the sides of a triangle are (1, 1), (2, –3), (3, 4), find its incentre. -Maths 9th

Last Answer : (b) 3 : 2 ; m = \(-rac{2}{5}\)Let P(m, 6) divides AB in the ratio k : 1. Then co-ordinates of P are \(\bigg(\)\(rac{2k-4}{k+1}\), \(rac{8k+3}{k+1}\)\(\bigg)\)Given, co-ordinates of P are (m, 6) ⇒\(rac{2k-4}{k+1} ... 2}-4}{rac{3}{2}+1}\) = \(rac{3-4}{rac{5}{2}}\) = \(rac{-2}{5}\)∴ m = \(rac{-2}{5}\).

The apex of an equilateral-triangular coordinate (in ternary liquidsystem) represents a/an(A) Pure component(B) Binary mixture(C) Ternary mixture(D) Insoluble binary system

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Find the co-ordinates of the circumcentre of the triangle whose vertices are (3, 0), (–1, –6) and (4, –1). Also find its circum-radius. -Maths 9th

Description : Find the co-ordinates of the circumcentre of the triangle whose vertices are (3, 0), (–1, –6) and (4, –1). Also find its circum-radius. -Maths 9th

Last Answer : Let A ≡ (2, - 2), B ≡ (-2, 1), C ≡ (5, 2 ). Then,AB = \(\sqrt{(-2-2)^2+(1+2)^2}\) = \(\sqrt{16+9}\) = \(\sqrt{25}\) = 5BC = \(\sqrt{(5+2)^2+(2-1)^2}\) = \(\sqrt{49+1}\) = \(\sqrt{50}\) = \( ... of ΔABC = \(rac{1}{2}\) x base x height = \(rac{1}{2}\) x AB x AC = \(rac{1}{2}\)x 5 x 5 = 12.5 sq. units.

Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Description : Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Last Answer : Let A(1, 2), B(0, -1) and C(2, -1) be the mid-points of the sides PQ, QR and RP of the triangle PQR. Let the co-ordinates of P, Q and R be (x1, y1), (x2, y2) and (x3 , y3) respectively. Then, by the mid- ... ordinates of centroid of ΔPQR = \(\bigg(rac{3+(-1)+1}{3},rac{2+2+(-4)}{3}\bigg)\) = (1, 0).

A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

Description : A floral design on a floor is made up of 16 tiles which are triangular, the sides of the triangle being 9 cm, 28 cm and 35 cm (see figure). -Maths 9th

Last Answer : NCERT Solutions for Class 9 Maths Chapter 12 Heron's Formula NCERT Solutions for Class 9 Maths Chapter 12 Heron's Formula Ex 12.1 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths ... = 48 m Sides ∆ABC are a = AB = 30m, b = AD = 30m, c = BD = 48m S

An Azeotropic mixture is a __________ mixture. (A) Binary (B) Ternary (C) Constant boiling point (D) None of these

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Van Laar equation deals with the activity co-efficients in (A) Binary solutions (B) Ternary solutions (C) Azeotropic mixture only (D) None of these

Description : Van Laar equation deals with the activity co-efficients in (A) Binary solutions (B) Ternary solutions (C) Azeotropic mixture only (D) None of these

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Inside a triangular park, there is a flower bed forming a similar triangle. Around the flower bed runs a uniform path of such a width that the -Maths 9th

Description : Inside a triangular park, there is a flower bed forming a similar triangle. Around the flower bed runs a uniform path of such a width that the -Maths 9th

Last Answer : (d) 3 : 1Let ABC be the triangular flower bed of side lengths a, b and c respectively. Then Area of ΔABC = \(\sqrt{s(s-a)(s-b)(s-c)}\)where s = \(rac{a+b+c}{2}\)Now according to the given condition,ΔPQR ... of ΔABC - Area of ΔABC= 3 (Area of ΔABC)∴ Reqd. Ratio = Area of Path : Area of ΔABC = 3 : 1.

Find the co-ordinates of the points on the x-axis which are at a distance of 10 units from the point (– 4, 8)? -Maths 9th

Description : Find the co-ordinates of the points on the x-axis which are at a distance of 10 units from the point (– 4, 8)? -Maths 9th

Last Answer : (a) Internal division: If P(x, y) divides the line segment formed by the joining of the points A (x1, y1) and B (x2, y2) internally in the ratio m1 : m2. Then\(x=rac{m_1x_2+m_2x_1}{m_1+m_2}\) and \(y=rac ... : 1, the co-ordinates of the mid-point are \(\bigg(rac{x_1+x_2}{2},rac{y_1+y_2}{2}\bigg)\).

What is the equation of the straight line passing through the point (4, 3) and making intercepts on the co-ordinates axes whose sum is –1 ? -Maths 9th

Description : What is the equation of the straight line passing through the point (4, 3) and making intercepts on the co-ordinates axes whose sum is –1 ? -Maths 9th

Last Answer : Diagonals of a rhombus bisect each other at right angles ⇒ Co-ordinates of mid-points of AC and BD are equal∴ 0 = \(\bigg(rac{4+(-2)}{2},rac{-5+(-1)}{2}\bigg)\) = (1, -3)Slope of BD = \(rac{-5+1}{4+2}\) = \(rac{-4}{6}\) ... (rac{3}{2}\) isy + 3 = \(rac{3}{2}\) (x - 1)⇒ 2y + 6 = 3x - 3 ⇒ 2y = 3x - 9.

What are the co-ordinates of the foot of the perpendicular from the point (2, 3) on the line x + y – 11 = 0 ? -Maths 9th

Description : What are the co-ordinates of the foot of the perpendicular from the point (2, 3) on the line x + y – 11 = 0 ? -Maths 9th

Last Answer : (d) 2x + 9y + 7 = 0PS being the median of ΔPQR, S is the mid-point of QR, i.e., Coordinates of S ≡ \(\bigg(rac{6+7}{2},rac{-1+3}{2}\bigg)\) = \(\bigg(rac{13}{2},1\bigg)\)Slope of line parallel to PS = Slope of PS= \(rac{1 ... y + 1) = \(rac{-2}{9}\)(x - 1), i.e., 9y + 9 = - 2x + 2 ⇒ 2x + 9y + 7 = 0.

Find the co-ordinates of that point on the curve `x^(2)/a^(2)+y^(2)/b^(2) = 1` at which the tangent drawn is parallel to Y-axis.

Description : Find the co-ordinates of that point on the curve `x^(2)/a^(2)+y^(2)/b^(2) = 1` at which the tangent drawn is parallel to Y-axis.

Last Answer : Find the co-ordinates of that point on the curve `x^(2)/a^(2)+y^(2)/b^(2) = 1` at which the tangent drawn is parallel to Y-axis.

Find the co-ordinates of that point on the curve`y^(2)=x^(2)(1-x)` at which the tangent drawn is perpendicular to X-axis.

Description : Find the co-ordinates of that point on the curve`y^(2)=x^(2)(1-x)` at which the tangent drawn is perpendicular to X-axis.

Last Answer : Find the co-ordinates of that point on the curve`y^(2)=x^(2)(1-x)` at which the tangent drawn is perpendicular to X-axis.

Find the co-ordinates of that point on the curve `x^(3)+y^(3)= a^(3)` at which the tangent drawn is parallel to X-axis.

Description : Find the co-ordinates of that point on the curve `x^(3)+y^(3)= a^(3)` at which the tangent drawn is parallel to X-axis.

Last Answer : Find the co-ordinates of that point on the curve `x^(3)+y^(3)= a^(3)` at which the tangent drawn is parallel to X-axis.

Let R be the rectangular window against which the lines are to be clipped using 2D Sutherland-Cohen line clipping algorithm. The rectangular window has lower left-hand corner at (-5,1) and upper righthand corner at (3,7). Consider the following three lines for clipping with the given end point co-ordinates: Line AB: A(-6,2) and B(-1,8) Line CD: C(-1,5) and D(4,8) Line EF: E(-2,3) and F(1,2) Which of the following line(s) is/are candidate for clipping? (A) AB (B) CD (C) EF (D) AB and CD

Description : Let R be the rectangular window against which the lines are to be clipped using 2D Sutherland-Cohen line clipping algorithm. The rectangular window has lower left-hand corner at (-5,1) and upper righthand corner at (3,7). ... s) is/are candidate for clipping? (A) AB (B) CD (C) EF (D) AB and CD

Last Answer : (D) AB and CD

Compressibility factor-reduced pressure plot on reduced co-ordinates facilitates (A) Use of only one graph for all gases (B) Covering of wide range (C) Easier plotting (D) More accurate plotting

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The centroid of a triangle is at the inter-section of a.perpendicular bisectors b.107 dynes c.base and perpendicular from opposite vertex d.perpendiculars down from the corners e.medians

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A wire has a resistance of 12 ohm . It is bent in the form of equilateral triangle. The effective resistance between any two corners of the triangle i

Description : A wire has a resistance of 12 ohm . It is bent in the form of equilateral triangle. The effective resistance between any two corners of the triangle i

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A plait point is the point on the solubility curve, where the tie line reduces to a point. What is the number of plait point for a ternary system containing two pairs of partially miscible liquids? (A) 0 (B) 1 (C) 2 (D) 3

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Any convenient co-ordinate system or Cartesian co-ordinates which can be usedto define the picture is called a.spherical co-ordinates b.vector co-ordinates c.viewport co-ordinates d.world co-ordinates

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Co-ordinates are ranging according to the screen resolution. a.TRUE b.FALSE c. d.

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Which co-ordinates allow common vector operations such as translation, rotation,scaling and perspective projection to be represented as a matrix by which the vector is multiplied? a.vector co-ordinates b.3D co-ordinates c.affine co-ordinates d.homogenous co-ordinates

Description : Which co-ordinates allow common vector operations such as translation, rotation,scaling and perspective projection to be represented as a matrix by which the vector is multiplied? a.vector co-ordinates b.3D co-ordinates c.affine co-ordinates d.homogenous co-ordinates

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Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Description : Draw the graph of the equation 3x + 4y = 12 and find the co-ordinates of the points of intersection of the equation with the co-ordinate axes. -Maths 9th

Last Answer : Solution :-

What do you mean by Co-ordinates (Abscissa and Ordinate)? Explain with figure. -Maths 9th

Description : What do you mean by Co-ordinates (Abscissa and Ordinate)? Explain with figure. -Maths 9th

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Distance Formula for co-ordinates: -Maths 9th

Description : Distance Formula for co-ordinates: -Maths 9th

Last Answer : The position of each point of the plane is determined with reference to the rectangular axes by means of a pair of numbers called co-ordinates which are distances of the point from the respective axes. The distance of the ... are (x, 0) and the co-ordinates of any point of the y-axis are (0, y)

Section formula for co-ordinates: -Maths 9th

Description : Section formula for co-ordinates: -Maths 9th

Last Answer : The co-ordinate axes separate the plane into four regions called the quadrants. By custom the quadrants are numbered I, II, III, IV, in the counter clockwise direction as shown in the figure. (i) For distances along the x- ... +)X′OY′3rd quadrantx < 0, y < 0(-, -)XOY′4th quadrantx > 0, y < 0(+, -)

Let the opposite angular points of a square be (3, 4) and (1, – 1), Find the co-ordinates of the remaining angular points. -Maths 9th

Description : Let the opposite angular points of a square be (3, 4) and (1, – 1), Find the co-ordinates of the remaining angular points. -Maths 9th

Last Answer : P ≡ (-3, 2), Q ≡ (-5, -5), R ≡ (2, -3), S ≡ (4, 4)∴ PQ = \(\sqrt{(-5+3)^2+(-5-2)^2}\) = \(\sqrt{4+49}\) = \(\sqrt{53}\)QR = \(\sqrt{(2+5)^2+(-3+5)^2}\) = \(\sqrt{49+4}\) = \ ... of rhombus = \(rac{1}{2}\) x (Product of length of diagonals) = \(rac{1}{2}\) x \(5\sqrt2\) x \(9\sqrt2\) = 45 sq. units.

In the adjoining figure, P and Q have co-ordinates (4, 6)and (0, 3) respectively. Find (i) the co-ordinates of R (ii) Area of quadrilateral OAPQ. -Maths 9th

Description : In the adjoining figure, P and Q have co-ordinates (4, 6)and (0, 3) respectively. Find (i) the co-ordinates of R (ii) Area of quadrilateral OAPQ. -Maths 9th

Last Answer : Let the line 2x + 3y - 30 = 0 divide the join of A(3, 4) and B(7, 8) at point C(p, q) in the ratio k : 1. Then,p = \(rac{7k+3}{k+1}\), q = \(rac{8k+4}{k+1}\)As the point C lies on the line 2x + 3y - 30 ... {3}{2}+1},rac{8 imesrac{3}{2}+4}{rac{3}{2}+1}\bigg)\) = \(\big(rac{27}{5},rac{32}{5}\big)\).

(–2, –1) and (4, –5) are the co-ordinates of vertices B and D respectively of rhombus ABCD. Find the equation of the diagonal AC. -Maths 9th

Description : (–2, –1) and (4, –5) are the co-ordinates of vertices B and D respectively of rhombus ABCD. Find the equation of the diagonal AC. -Maths 9th

Last Answer : 3\(x\) - 2y + 5 = 0 ⇒ -2y = -3\(x\) - 5 ⇒ y = \(rac{3}{2}\)\(x\) + \(rac{5}{2}\)On comparing with y = m\(x\) + c, we see that slope of given line = \(rac{3}{2}\)As the required line is perpendicular to the given line, ... - 4)⇒ 3(y - 5) = - 2\(x\) + 8 ⇒ 3y - 15 = -2\(x\) + 8 ⇒ 3y + 2\(x\) - 23 = 0

The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Description : The line x – 4y = 6 is the perpendicular bisector of the segment AB and the co-ordinates of B are (1, 3). Find the co-ordinates of A. -Maths 9th

Last Answer : Co-ordinates of A are \(\bigg(rac{3 imes9+1 imes5}{3+1},rac{3 imes6+1 imes-2}{3+1}\bigg)\) = \(\bigg(rac{32}{4},rac{16}{4}\bigg)\), i.e. (8, 4)Now, \(x\) - 3y + 4 = 0 ⇒ -3y = -\(x\) - 4 ⇒ y = \(rac{x}{3}+rac{4} ... 8) [Using, y - y1 = m (x - x1)]⇒ 3y - 12 = \(x\) - 8 ⇒ 3y - \(x\) = 4.

If A(3, 5), B(– 5, – 4), C(7, 10) are the vertices of a parallelogram taken in order, then the co-ordinates of the fourth vertex are: -Maths 9th

Description : If A(3, 5), B(– 5, – 4), C(7, 10) are the vertices of a parallelogram taken in order, then the co-ordinates of the fourth vertex are: -Maths 9th

Last Answer : (c) RhombusCo-ordinates of P are \(\bigg(rac{-1-1}{2},rac{-1+4}{2}\bigg)\)i.e, \(\big(-1,rac{3}{2}\big)\)Co-ordinates of Q are \(\bigg(rac{-1+5}{2},rac{4+4}{2}\bigg)\)i.e, (2, 4)Co-ordinates of R ... \sqrt{(2-2)^2+(4+1)^2}\) = \(\sqrt{25}\) = 5⇒ PR ≠ SQ ⇒ Diagonals are not equal ⇒ PQRS is a rhombus.

If the points with the co-ordinates {a, ma}, {b, (m + 1)b}, {c, (m + 2)c} are collinear, then which of the following is correct ? -Maths 9th

Description : If the points with the co-ordinates {a, ma}, {b, (m + 1)b}, {c, (m + 2)c} are collinear, then which of the following is correct ? -Maths 9th

Last Answer : (d) (7, -2)Let the co-ordinates of R be (x, y). As can be easily seen, it is a point of external division Also, PR = 2QR⇒ R divides the join of P and Q externally in the ratio 2:1. ∴ x = \(rac{2 imes2-1 imes-3}{2-1}\), ... }{2-1}\)⇒ x = 4 + 3 = 7 and y = 2 - 4 = -2. ∴ Co-ordinates of R are (7, -2).

The co-ordinates of P and Q are (–3, 4) and (2, 1) respectively. -Maths 9th

Description : The co-ordinates of P and Q are (–3, 4) and (2, 1) respectively. -Maths 9th

Last Answer : (b) \(rac{\pi}{4}\)\(x\) cos θ + y sin θ = 2 ⇒ y sin θ = 2 - \(x\) cos θ ⇒ y = - \(x\) cot θ + 2 ⇒ Slope of this line = - cot θ Also, given \(x\) - y = 3 ⇒ y = \(x\) + 3 ⇒ Slope of this ... lines are perpendicular, - cot θ x 1 = -1⇒ cot θ = 1 ⇒ cot θ = cot \(rac{\pi}{4}\) ⇒ θ = \(rac{\pi}{4}\)

(i) Find the co-ordinates of the points on the curve xy = 16 at which the normal drawn meet at origin. (ii) Find the points on the curve`4x^(2)+9 y^(2

Description : (i) Find the co-ordinates of the points on the curve xy = 16 at which the normal drawn meet at origin. (ii) Find the points on the curve`4x^(2)+9 y^(2

Last Answer : (i) Find the co-ordinates of the points on the curve xy = 16 at which the normal drawn meet at ... ` at which the normal drawn is parallel to X-axis.

What co-ordinates the muscle function?

Description : What co-ordinates the muscle function?

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The most reliable method of plotting a theodolite traverse, is (A) By consecutive co-ordinates of each station (B) By independent co-ordinates of each station (C) By plotting included angles and scaling off each traverse leg (D) By the tangent method of plotting

Description : The most reliable method of plotting a theodolite traverse, is (A) By consecutive co-ordinates of each station (B) By independent co-ordinates of each station (C) By plotting included angles and scaling off each traverse leg (D) By the tangent method of plotting

Last Answer : (B) By independent co-ordinates of each station

......... is used to pointing / selecting the screen co-ordinates by detecting the light. A) Light Pen B) Bar Code Reader C) Digital Camera D) Smart Cards

Description : ......... is used to pointing / selecting the screen co-ordinates by detecting the light. A) Light Pen B) Bar Code Reader C) Digital Camera D) Smart Cards

Last Answer : A) Light Pen

Which of the following is NOT a purpose of a marketing plan? A)it specifies how resources are to be allocated B)it co -ordinates marketing and production activities C)it assigns responsibilities, tasks and timing D)it assists in management

Description : Which of the following is NOT a purpose of a marketing plan? A)it specifies how resources are to be allocated B)it co-ordinates marketing and production activities C)it assigns responsibilities, tasks and timing D)it assists in management

Last Answer : B)it co-ordinates marketing and production activities

Describe the procedure to determine co-ordinates of a station using GPS.

Description : Describe the procedure to determine co-ordinates of a station using GPS. 

Last Answer : The following are some general GPS field survey procedures that should be performed at each station, observation, and/or session on a GPS survey. A. Receiver setup : GPS receiver shall be set up ... is to identify any problem that may exist which can be corrected before returning from the field.  

Translate the polygon with co-ordinates A (3, 6), B (8, 11), & C (11, 3) by 2 units in X direction and 3 units in Y direction.

Description : Translate the polygon with co-ordinates A (3, 6), B (8, 11), & C (11, 3) by 2 units in X direction and 3 units in Y direction.

Last Answer : X’=x+tx Y’=y+ty tx=2 ty=3 for point A(3,6) x’=3+2=5 y’=6+3=9 for point B(8,11) x’=8+2=10 y’=11+3=14 for point C(11,3) x’=11+2=13 y’=3+3=6 A’=(x’,y’)=(5,9) B’=(x’,y’)=(10,14) C’=(x’,y’)=(13,6)

Explain the need of homogeneous co-ordinates matrix.

Description : Explain the need of homogeneous co-ordinates matrix.

Last Answer : Homogeneous coordinates are used extensively in computer vision and graphics because they allow common operations such as translation, rotation, scaling and perspective projection to be implemented as matrix operations.

Gibbs-Duhem equation relates composition in liquid phase and the __________ at constant temperature & pressure. (A) Fugacity (B) Partial pressure (C) Activity co-efficient (D) All (A), (B), and (C)

Description : Gibbs-Duhem equation relates composition in liquid phase and the __________ at constant temperature & pressure. (A) Fugacity (B) Partial pressure (C) Activity co-efficient (D) All (A), (B), and (C)

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The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of ₹5000 per m² per year. -Maths 9th

Description : The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122 m, 22 m and 120 m (see figure). The advertisements yield an earning of ₹5000 per m² per year. -Maths 9th

Last Answer : Let the sides of the triangular will be a = 122m, b = 12cm, c = 22m Semi-perimeter, s = a+b+c2 (122+120+224)m = 2642 m = 132m The area of the triangular side wall Rent for 1 year (i.e. 12 months) per m2 = ... = Rs. 5000 x 312 = Rent for 3 months for 1320 m2 = Rs. 5000 x 312 x 1320 = Rs. 16,50,000.

Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs. 7 per m2. -Maths 9th

Description : Find the cost of laying grass in a triangular field of sides 50 m, 65 m and 65 m at the rate of Rs. 7 per m2. -Maths 9th

Last Answer : Sides of the triangle are a=50m,b=65m,c=65m Area of triangle, by Heron's formula =s(s−a)(s−b)(s−c)​where, s=2a+b+c​s=250+65+65​s=90 Area of triangle = 90(40)(25)(25)​Area of triangle = 1500m2 Cost of laying grass = Area ×7 Cost of laying grass =1500×7 Cost of laying grass = Rs 10500

The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field. -Maths 9th

Description : The perimeter of a triangular field is 420 m and its sides are in the ratio 6:7:8. Find the area of the triangular field. -Maths 9th

Last Answer : Let sides of △ are=6x,7x and 8x Perimeter=6x+7x+8x=21x 21x=410 x=20 Sides are 120,140 and 160 m Area =S(S−A)(S−B)(S−C)​ [Heron's Formula] S=2120+140+160​=210 m A=210(210−120)(210−140)(210−160)​=210015​ sq. m