32.23-3.47?

32.23-3.47?
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Last Answer : 22

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Description : The average molecular weight of a flue gas having the composition by volume as CO2 = 25%, O2 = 25%, N2 = 50% will be (A) 27.6 (B) 23 (C) 47.3 (D) 42.9

Last Answer : (B) 23

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Last Answer : e) None of these

A rod, 120cm long and of diameter 3.0 cm is subjected to an axial pull of 18 kN. The stress in N/mm2 is. a. 22.57 b. 23.47 c. 24.57 d. 25.47

Description : A rod, 120cm long and of diameter 3.0 cm is subjected to an axial pull of 18 kN. The stress in N/mm2 is. a. 22.57 b. 23.47 c. 24.57 d. 25.47

Last Answer : d. 25.47

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Last Answer : 24 years 

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Description : When a voltage of 95 VDC is applied to the illustrated circuit with a resistance of 10.23 kohms the current will be _______ . EL-0018 A. 9.29 milliamps B. 107.68 amps C. 10.32 amps D. 11.02 amps

Last Answer : Answer: A

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Last Answer : D. 32

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Last Answer : D. 14 dB

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Description : A mass of 1 kg is attached to two identical springs each with stiffness k = 20 kN/m as shown in the figure. Under frictionless condition, the natural frequency of the system in Hz is close to * 1 point (A) 32 (B) 23 (C) 16 (D) 11

Last Answer : (A) 32

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Description : A flag pole 18 m high casts a shadow 9.6 m long. Then the distance of the top of the pole from the far end of the shadow is (a) 25.6 (b) 20.4 (c) 23.7 (d) 32.5

Last Answer : (b) 20.4

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Last Answer : 7C:56:21:1A:DE:F4

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Last Answer : 43:7B:6C:DE:10:0

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Last Answer : a) 23.4

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Last Answer : (D) 1.27

A two digit number is such that the sum of the digits is 11.When the number with the same digits is reversed is subtracted from this number, the difference is 9.What is the number? 1. 23 2. 24 3. 65 4. 14 5. 32

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Last Answer : Answer- 3(65) Explanation:- let the number be written as xy x-ten’s place y units place x+y=11…………………1 (10x+y)-(10y+x)=9 10x+y-10y-x=9 9x-9y=9 x-y=1………………….2 Add (1) & (2) 2x=12 x=6 y=5 the number is 65

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Description : Two concentric circles have radii of 23 cm and 9 cm. A rectangle has an area equal to the annular space between the above two circles. If the breadth of the rectangle is 22 cm then find its length. 1 : 32 cm 2 : 48 cm 3 : 76 cm 4 : 64 cm 5 : None of these

Last Answer : 4 : 64 cm

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In a 2700 m race around a round track of length 300m, abi and kabi meet at the end of the 3rd minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. If abi runs at twice the speed of the kabi. Find the time taken by abi to finish the race. a) 27 mints b) 32 mints c) 5 mints d) 23 mints

Description : In a 2700 m race around a round track of length 300m, abi and kabi meet at the end of the 3rd minute, for the first time after the start of the race. All the runners maintain uniform speed throughout the race. ... time taken by abi to finish the race. a) 27 mints b) 32 mints c) 5 mints d) 23 mints

Last Answer : A As, abi is twice as fast as the kabi, abi would have completed two rounds by the time kabi completes one round. And that is their second meeting. Their first meeting takes place after the abi ... 300m ⇒He takes 2700/300 *3 =27 mints Hence he takes 27 minutes to finish the race.

Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41

Description : Nesha scored 120 out of 150 in English, 120 out of 180 in mathematics and 160 out of 200 in Science. Find Nesha’s score as percentage: (i) in Mathematics (ii) in all the three subjects (on the whole). a) 66 2/3, 78 22/51 b) 71 23/5, 45 7/31 c) 54 13/33, 82 3/4 d) 60 3/4, 76 32/41 

Last Answer :  Answer: A (i) Percentage scored in Mathematics = 120/180 100  = 12000/180  =1200/18  = 66 2 /3 % (ii) Total maximum of all the three subjects = 150 + 160 + 200 = 510 and Total score in the ... percentage on the whole = (400/510 100)  = (40000/510)  = 4000/51  = 78 22/51 %

My mother is three times as old as I am. Together, we are 47 years old. How old is my mother?

Description : My mother is three times as old as I am. Together, we are 47 years old. How old is my mother?

Last Answer : A: To solve this problem, you can use the following equation: Mother's age + My age = 47 years Mother's age = 3 * My age Substituting the second equation into the first equation, we get: 3 * My age + My ... 47 years / 4 = 11.75 years Therefore, my mother is 3 * 11.75 years = 35.25 years old.

How do I get into a good college with a 3.47 gpa?

Description : How do I get into a good college with a 3.47 gpa?

Last Answer : airecka99 Please think about it in a different light. Remember you don't actually need college. You will survive and even prosper without it. You kind of need to let go of it then you can actually ... . Completely. What has meaning is what you actually learn and are able to apply in the real world.

The Jelly Below Me - Part 47!

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Last Answer : What does “TJBM” stand for?

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AK-47, Dragunov- which to pick?

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Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Description : Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Last Answer : Mean of 36 observations = 12 Total of 36 observations = 36 x 12 = 432 Correct sum of 36 observations = 432 – 74 + 47 = 405 Correct mean of 36 observations = 405/ 36 =11.25

If P (event E) = 0.47, then find P(not E). -Maths 9th

Description : If P (event E) = 0.47, then find P(not E). -Maths 9th

Last Answer : P(not E) = 1 - P(E) ⇒ 1 - 0.47 = 0.53

Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Description : Mean of 36 observations is 12. One observation 47 was misread as 74. Find the correct mean. -Maths 9th

Last Answer : Mean of 36 observations = 12 Total of 36 observations = 36 x 12 = 432 Correct sum of 36 observations = 432 – 74 + 47 = 405 Correct mean of 36 observations = 405/ 36 =11.25

If P (event E) = 0.47, then find P(not E). -Maths 9th

Description : If P (event E) = 0.47, then find P(not E). -Maths 9th

Last Answer : P(not E) = 1 - P(E) ⇒ 1 - 0.47 = 0.53

Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Description : Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Last Answer : Let x = 0.7Bar ⇒ x = 0.777.......... .........(1) Multiplying (1) by 10 ⇒ 10x = 7.7...... = 7.777 ...........(2) Subtracting (1) from (2) ⇒ 10x - x = 9x ⇒ 7.777 - 0.777 = 7 ... and then solving it, we get. ⇒ (594 + 770 + 470)/990 ⇒ 1834/990 ⇒ 917/495 Hence, 0.6 + 0.7Bar + 0.47Bar = 917/495

Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Description : Express 0.6bar +0.7bar+0.47 bar in the form p/q where p and q are integers and q is not equal to 0 -Maths 9th

Last Answer : Let x=0.666....... (1) Multiply equation (1 by 10 10x = 6.666....... (2) Subtract equation (1) from (2) x=6/9 Similarly 0.7bar =7/9 and 0.47bar = 47/99. 6/9+7/9+47/99=190/99

Teacher asked the students 'Can we write 0.47(recurring) -Maths 9th

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Convert each of the following fraction into a percentage: (i) 47 100 (ii) 9 20 (iii) 3 8 (iv) 8 125 (v) 19 500 (vi) 4 15 (vii) 2 3 (viii) 1 3 5 -Maths

Description : Convert each of the following fraction into a percentage: (i) 47 100 (ii) 9 20 (iii) 3 8 (iv) 8 125 (v) 19 500 (vi) 4 15 (vii) 2 3 (viii) 1 3 5 -Maths

Last Answer : We have the following: (i) 47100=47100×100% = 47% (ii) 920=920×100% =9×5%= 45% (iii) 38=38×100% =3×252%=752%=3712% (iv) 8125=8125×100%=8×45%=325%=6.4% (v) ... ;203%=803%=2623% (vii) 23=23×100%=2003%=6623% (viii) 135=85=85×100%=(8×20)%=160%

IfP (event E) = 0.47, then find P(not E). -Maths 9th

Description : IfP (event E) = 0.47, then find P(not E). -Maths 9th

Last Answer : P(not E) = 1 - P(E) ⇒ 1 - 0.47 = 0.53

If a person on one side of earth drops an ak 47, and another person drops a bomb. Is that called war?

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Is there Zakat on the money of the association ? I owe Rs 50,000 / - to one and Rs 47,000 / - to another. We have an association where I have deposited Rs. 150,000 / -. The money of the association is deposited in the bank , no work is done. Do I have to pay zakat ? How much more do you have to pay ?

Description : Is there Zakat on the money of the association ? I owe Rs 50,000 / - to one and Rs 47,000 / - to another. We have an association where I have deposited Rs. 150,000 / -. The money of the association is ... in the bank , no work is done. Do I have to pay zakat ? How much more do you have to pay ?

Last Answer : : If a person has zakatable assets worth the equivalent of 52.5 tolas (612.36 grams) of silver, then zakat is obligatory on him at the end of the year. So zakat has become obligatory in the case ... total amount of Zakat has to be collected by calculation. (Hedaya: 1/196 , Addurrul Mukhtar: 2/30)

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Description : XI. Answer any TWO of the following questions.47) On the basis of data you have collected regarding participation of women in your locality in below mentioned catagories construct a pie chart.a) Self employed.b) Regular salaried employees.c) Causel wage labours.

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Description : The mode of the data 48, 45, 49, 51, 46, 48, 47, 49, 48, and 51 is ______.

Last Answer : The mode of the data 48, 45, 49, 51, 46, 48, 47, 49, 48, and 51 is ______. A. 47 B. 49 C. 51 D. 48