Description : 10 ml 0.2 Molar Na2CO3 How many grams of 0.1 Molar HCl is needed to soothe ?
Last Answer : Na₂CO₃ + 2HCl = NaCl + CO₂ + H₂O of Na₂CO₃ , density S₁ = 0.2 M; Volume , V₁ = 10 mL HCl density S₂ = 0.1 M; Volume = V₂ 2S₁V₁ = S₂V₂ ∴ V₂ = 2S₁V₁ / S₂ = 2 0.2 10 / 0.1 = 40 mL The molecular mass of HCl , M = ... / MV₂ ∴ w = S₂MV₂ / 1000 = 0.1 36.5 40/1000 = 0.146 g (Ans.)