When supposing that it takes 0.6 seconds for a mass on a spring to move from its highest position to its lowest position. What is the period of the spring?

When supposing that it takes 0.6 seconds for a mass on a spring to move from its highest position to its lowest position. What is the period of the spring?
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A spring with a force constant of 100 Newtons per meter is loaded with a mass of 1.0 kilogram. The period of vibration of this system is: w) .03 seconds x) .06 seconds y) .31 seconds z) .63 seconds

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Last Answer : ANSWER: Z -- .63 SECONDS 

As a 10 kilogram mass on the end of a spring passes through its equilibrium position, the kinetic energy of the mass is 20 joules. The speed of the mass is: w) 2.0 meters per second x) 4.0 meters per second y) 5.0 meters per second z) 6.3 meters per second

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Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr

A spring with a force constant of 20 newtons per meter is known to obey Hooke's Law. The spring is attached to a mass of 5 kilograms and placed on a horizontal, frictionless surface. The mass is displaced 3 meters from its equilibrium position and released. What is the kinetic energy of the mass as it passes through its equilibrium position?

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Description :  A person runs opposite to that of chandigarh train at a speed of 10km/hr. If the relative speed between train and the boy running in opposite direction is 25km/hr. What is the length of the train, if it takes 10 seconds to cross a boy, when is at rest? A) 36.6 m B) 40.6 m C) 43.6m D) 41.6m

Last Answer : ANSWER : D  Explanation: Speed of person = 10km/hr  As the train and the running person are moving in opposite direction,therir speed values are added to find the relative speed.  Relative speed = speed of train + speed of ... s  Distance = speed * time = 25 / 6 * 10 = 250/6 m/s = 41.6 m

A blender has a power of 0.3 kW. It is used to make a fruit smoothie, which takes 50 seconds. How much energy is used Give your answer in kilojoules.kJ?

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When the speed of a turbine is 6000 rpm, it takes _____ seconds for the turbine to complete one revolution. a)0.1 sec b)0.0001sec c)10sec d)0.001sec

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Which of the following statements dealing with simple harmonic motion of a mass-spring system is TRUE? w) The acceleration is largest when the oscillating mass is instantaneously at rest. x) The larger the spring force constant the larger the period. y) The period of the motion depends linearly on the amplitude of the motion. z) The acceleration is larger when the oscillating mass has its greatest velocity.

Description : Which of the following statements dealing with simple harmonic motion of a mass-spring system is TRUE? w) The acceleration is largest when the oscillating mass is instantaneously at rest. x) The ... of the motion. z) The acceleration is larger when the oscillating mass has its greatest velocity.

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The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Description : The acceleration due to gravity on the moon is 1.6 meters per second squared. If a pendulum is whose length is 6.4 meters is placed on the moon, its period will be: w) 1.57 seconds x) 3.14 seconds y) 12.56 seconds z) 25.12 seconds

Last Answer : not real

The time period of a second’s pendulum is – (1) 1 second (2) 2 seconds (3) 0.5 second (4) 1.5 seconds

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Last Answer : (2) 2 seconds Explanation: A seconds pendulum is a pendulum whose period is precisely two seconds; one second for a swing in one direction and one second for the return swing, a frequency of 1/2 Hz. At standard gravity its length is 0.994 m.

Period of oscillation of 3 cm microwaves in seconds is (1) 1 x 10¹⁰ (2) 1 x 10⁻¹⁰ (3) 0.01 (4) 0.001

Description : Period of oscillation of 3 cm microwaves in seconds is (1) 1 x 10¹⁰ (2) 1 x 10⁻¹⁰ (3) 0.01 (4) 0.001

Last Answer : (2) 1 x 10⁻¹⁰ Explanation: The period of oscillation of 3 cm microwaves is 1 x 10^-10 (Physics, Volume 1, by Halliday). The period of oscillation is the smallest interval of time in which a system undergoing oscillation returns to the state it was in at the beginning of the oscillation.

A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Description : A boy sitting in a train which is travelling at 25 km/hr observes that a goods train travelling in opposite direction, takes 4.5 seconds to pass him. If the train is 140 m long, find its speed. A) 77km/hr B) 79km/hr C) 87km/hr D) 89km/hr

Last Answer : ANSWER : C Explanation: Relative speed = distance / time = (140 / 4.5) m/s = 31.11 m/s Convert m/s into km/hr  31.11 m/s = (31.11 * 18 / 50 km/hr  = (560 / 5) km/hr  = ... train (by sitting) = (112 - 25) km/hr = 87 km/hr  Therefore the speed of goods train is 87 km/hr.

The natural frequency of a spring-mass system on earth is ωn. The natural frequency of this system on the moon (g of moon = g of earth /6) is * 1 point (A) ωn (B) 0.408ωn (C) 0.204ωn (D) 0.167ωn

Description : The natural frequency of a spring-mass system on earth is ωn. The natural frequency of this system on the moon (g of moon = g of earth /6) is * 1 point (A) ωn (B) 0.408ωn (C) 0.204ωn (D) 0.167ωn

Last Answer : (A) ωn

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... , are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz

Last Answer : a) 0.471 and 1.19 Hz

The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

Description : The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

Last Answer : a) ω n

A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (f n ), respectively, are a) 0.471 and 1.19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Description : A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural ... .19 Hz b) 0.471 and 7.48 Hz c) 0.666 and 1.35 Hz d) 0.666 and 8.50 Hz

Last Answer : a) 0.471 and 1.19 Hz

The natural frequency of a spring-mass system on earth is ω n . The natural frequency of this system on the moon (g moon = g earth /6) is a) ω n b) 0.408ω n c) 0.204ω n d) 0.167ω n

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Last Answer : a) ω n

The time needed for a net force of 10 newtons to change the velocity of a 5 kilograms mass by 3 meters/second is: w) 1.5 seconds x) 6 seconds y) 16.7 seconds z) 150 seconds

Description : The time needed for a net force of 10 newtons to change the velocity of a 5 kilograms mass by 3 meters/second is: w) 1.5 seconds x) 6 seconds y) 16.7 seconds z) 150 seconds

Last Answer : ANSWER: W -- 1.5 SECONDS

If an animal breaths 7 times a minute. How many seconds it takes to breath one million times?

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Last Answer : 420 millions

If a drinking driver is traveling 70 miles per hour and it takes three seconds for her or his pupils to return to normal after being temporarily blinded by bright headlights the person has driven over?

Description : If a drinking driver is traveling 70 miles per hour and it takes three seconds for her or his pupils to return to normal after being temporarily blinded by bright headlights the person has driven over?

Last Answer : 50

How many seconds does it takes the ball to fall to the ground with height of meters?

Description : How many seconds does it takes the ball to fall to the ground with height of meters?

Last Answer : It would depend on the size of the ball and height you weredropping it from.

In a thunderstorm the formula M t 5.1 Mt5.1 gives the approximate distance M M in miles from a lightning strike if it takes t t seconds to hear the thunder after seeing the lightning. If you are 8.9 m?

Description : In a thunderstorm the formula M t 5.1 Mt5.1 gives the approximate distance M M in miles from a lightning strike if it takes t t seconds to hear the thunder after seeing the lightning. If you are 8.9 m?

Last Answer : Need answer

How many seconds does it takes the ball to fall to the ground with height of meters?

Description : How many seconds does it takes the ball to fall to the ground with height of meters?

Last Answer : It would depend on the size of the ball and height you weredropping it from.

If a drinking driver is traveling 70 miles per hour and it takes three seconds for her or his pupils to return to normal after being temporarily blinded by bright headlights, the person has drivenE Over _ yards without being able to see?

Description : If a drinking driver is traveling 70 miles per hour and it takes three seconds for her or his pupils to return to normal after being temporarily blinded by bright headlights, the person has drivenE Over _ yards without being able to see?

Last Answer : 50 yards

Suppose that the number of instructions executed between page faults is directly proportional to the number of page frames allocated to a program. If the available memory is doubled, the mean interval between page faults is also doubled. Further, consider that a normal instruction takes one micro second, but if a page fault occurs, it takes 2001 micro seconds. If a program takes 60 sec to run, during which time it gets 15000 page faults, how long would it take to run if twice as much memory were available? (A) 60 sec (B) 30 sec (C) 45 sec (D) 10 sec

Description : Suppose that the number of instructions executed between page faults is directly proportional to the number of page frames allocated to a program. If the available memory is doubled, the mean interval between page faults is also ... memory were available? (A) 60 sec (B) 30 sec (C) 45 sec (D) 10 sec

Last Answer : Answer: C Explanation: T = Ninstr x 1µs + 15,000 x 2,000 µs = 60s Ninstr x 1µs = 60,000,000 µs - 30,000,000 µs = 30,000,000 µs Ninstr = 30,000,000 The number of instruction ... doesn't mean that the program runs twice as fast as on the first system. Here, the performance increase is of 25%.

A metro train 200 metres long takes 12 seconds to cross a man walking at 10 km/hr in a opposite to that of the train. Find the speed of the train? A) 50 km/hr B) 60km/hr C) 130km/hr D) 140km/hr

Description : A metro train 200 metres long takes 12 seconds to cross a man walking at 10 km/hr in a opposite to that of the train. Find the speed of the train? A) 50 km/hr B) 60km/hr C) 130km/hr D) 140km/hr

Last Answer : ANSWER: A Explanation:  Length of the train = 200 m  Man walking speed = 10 km/hr  Let the speed of the train be x' km/hr  Speed of the train relative to man = (x +10) km/hr  Convert km/hr into m/s   ... = 60(x +10)  3600 = 60x +600  60x = 3000 X = 50  So speed of the train is 110km/hr.

A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec

Description : A shatabadi express takes 240 seconds to cover a distance of length 700 meters at a speed of 270 km/hr. What will be the time taken by the train to cross a standing pole? A) 160sec B) 465sec C) 310sec D) 231sec

Last Answer : ANSWER:D Explanation:  Speed of the train = 270 km/hr. Converting the speed into m/sec  Speed = 270 km/hr = 270 x 5/18 m/sec = 75 m/sec  First, we have to find the length of the train  Let ... a standing Pole at 75 m/s =( 17300/75)seconds = 231 seconds. Hence the answer is 231 sec(approx.)

An object travels from a fixed position 5 seconds to start the journey. After 20 m / s. Velocity is. Next 10 sec. How far will it cover ?

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Last Answer : The distance covered by the object in the next 10 seconds s = vt s = 20 × 10 = 200m

The position of a particle with respect to time is given by the equation: x = t3 + 2 where x is in feet and t is in seconds. What is the acceleration of the particle at a time of 2 seconds?

Description : The position of a particle with respect to time is given by the equation: x = t3 + 2 where x is in feet and t is in seconds. What is the acceleration of the particle at a time of 2 seconds?

Last Answer : ANSWER: 12 FEET PER SECOND SQUARED