# What is the sag for a span of 400m, if the ultimate tensile strength...

What is the sag for a span of 400m, if the ultimate tensile strength of conductor is 6000 kgf, and the weight of conductor is 550 kgf/km? Factor of safety is 2.

3.6 m is the sag for a span of 400m, if the ultimate tensile strength of conductor is 6000 kgf, and the weight of conductor is 550 kgf/km? Factor of safety is 2.

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Last Answer : B Relative speed of the tiger = (5-4)km/hr =1 km/hr Time taken by tiger to cover 50 m, =(50/1000)hr =1/20hr In 1/20 hrs, the tiger cover a distance of (4*1/20)km =1/5km =>(1/5*1000)m =200m

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Last Answer :  ANSWER : D Explanation:  Let the speed of 2 trains be a1 and a2  Total distance covered to cross each other = (500 + 400)m  = 900m  When they run in the same direction,  Relative speed = a1 - a2  = 900 /60 ... hr  a 2= (15 * 18 / 5)m/s  = 54km/hr  Speed of two trains are 108 and 54 km/hr

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Description : The Mohr's straight theory is based on the following fact: (A) Material fails essentially by shear (B) Ultimate strength of the material is determined by the stress in the plane of slip (C) Failure criterion is independent of the intermediate principal stress (D) All the above

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