Draw and explain: bridge rectifier with shunt capacitor filter.

Draw and explain: bridge rectifier with shunt capacitor filter.
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1 Answer

Answer :

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Operation of bridge rectifier with capacitor filter is explained in different intervals with the help of the following wave form.

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Operation in interval at 0 to A:

The initial voltage on capacitor C is assumed to be 0.In first positive half cycle of the supply, diode D1 and D2 will forward biased and starts conducting.

Diodes D3 and D4 are reversed biased and act as open switch. Forward biased diodes will provide charging current for capacitor and the load current.

Capacitor starts charging through D1 and D2, and at the end of this interval , it charges to the peak value of secondary voltage Vm.

Voltage at capacitor C is now Vm.

After point A capacitor voltage starts reducing.

Operation in interval A to B:

After point A, voltage on capacitor is higher than rectified output. Diodes D1 and D2 are reversed biased. So capacitor discharges exponentially through the load resistance RL.

As value of RL is much higher than RF, the capacitor discharges slowly.

Value of C is large enough to make discharging time constant as large as possible. This will reduce ripple content in the output voltage.

Operation in interval B to C:

After point B , rectified output again increases.So again capacitor C will start charging towards Vm in interval B to C abd the process repeats.

The load voltage waveform with capacitor filter is very close to theideal dc voltage waveform as most of the ripple is removed from rectified output.

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