Bobby is 2 year older than Samsung if the sum of their ages is 36 how old is Bobby?

1 Answer

Answer :

25

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Description : Suresh and Ramesh are twins. In a form by mistake, Suresh reverses the last 2 digits of his year of birth, and this makes him 9 years older than Ramesh. With this mistake, the sum of their ages in 2015 becomes 43. How old will Ramesh be 2021? a) 17 b) 19 c) 21 d) 23 e) 25

Last Answer : Let the correct ages of Ramesh and Suresh be X in 2015 (since they are twins, they will have the same age) Given: 2x + 9 = 43 Or x = 17 years in 2015. Age in 2021 = 17 + 6 = 23 Note: year of birth = 2015 – 17 = 1998. Reversing, Suresh = 1989 or 9 year older. Answer: d)

Description : John is talking to Mary while working on a deal book at 2AM. Mary learns that John's sister has three children. 'How old are the children?' asks Mark.'Well,' replies John, 'the product of their ... after thinking for a minute. 'The eldest is dyslexic' says John. How old are the children? -Riddles

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Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these

Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)

Description : A is 2 years older than B who is twice as old as C. If sum of ages of A, B and C is 37 years, find the age of A. a) 7 years b) 9 years c) 14 years d) 16 years e) None of these

Last Answer : Let the age of C be x years. Then age of B = 2x and age of A = 2x + 2 sum of ages of A, B and C = (2x + 2) + (2x) + x = 37 (5x + 2) = 37  x = 7 Age of A = 2x + 2 = 16 years Answer: d)

Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these

Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years

Description : At present, a mother is 3 times older than her son. After 5 years, the sum of their ages will be 70 years. The age of the mother after 10 years will be (A) 40 (B) 55 (C) 45 (D) 60

Last Answer : 45

Description : The sum of present ages of a father and his son is 36 years. When the son reaches father’s present age, the sum of their ages will be 80 years. What is the present age of the son? a) 4 years b) 7 years c) 9 years d) 12 years e) None of these

Last Answer : Difference in two sums = 80- 36 = 44 Age of both are increased by 44/2 = 22 years Difference in ages of father and son = 22 years sum of present ages of father and son = 36 years Son’s present age = 1/2 × (36 - 22) = 7 years Answer: b)

Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20

Description : The mean of the ages of father and his son is 27 years. After 18 years, father will be twice as old as his son. Their present ages are (A) 42, 12 (B) 40, 14 (C) 30, 24 (D) 36, 18

Last Answer : Answer: A

Description : P is 6 years older than Q who is twice as old as R. If the total of the ages of P, Q and R be 81, the how old is Q? a) 27 b) 28 c) 29 d) 30

Last Answer : D Let R's age be x years. Then, Q's age = 2x years. P's age = (2x + 6) years. (2x + 6) + 2x + x = 81 5x = 75=> x =15. Hence, Q's age = 2x = 30 years

Description : The Smiths have 2 children. The sum of their ages is 21, and the product of their ages is 110. How old are the children?

Last Answer : 10 and 11

Description : After replacing an old person by a new person, it was found that the average age of five persons of a assembly is the same as it was 6 years ago. What is the difference between the ages of the replaced and the new persons? A) 24 B) 36 C) 30 D) 15 

Last Answer : C) Let the ages of the five persons at present be a, b, c, d & e years. And the age of the new persons be f years. So the new average of five members' age = (a + b + c + d + f)/5 - ... - e + f) = 5x Solving e - f = 30 years. Thus the difference of ages between replaced and new person = 30years.

Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these

Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.

Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years

Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28

Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32

Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Description : Ram is 3 times as old as his brother. Ram’s father is 3 times older than Ram. In 9 years , Ram will be 1.5 times the age of his brother. What will be the age of Ram’s father when Ram is 1.5 times the age of his brother? a) 27 b) 36 c) 45 d) 54 e) 63

Last Answer : Let the age of Ram be R, brother be B R=3B And (R + 9 ) =1.5(B + 9) 3B + 9 =1.5B + 13.5 1.5B =4.5 or B = 3 years R= 9 years. Father current age = 4R(Since father is 3 times older than Ram, his ... R + 3 R, and not 3R) Father age when Ram is 1.5 times the age of his brother = 4R + 9 = 45. Answer : c

Description : Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years from now. What was ratio of ages of keerthi and her grandfather 16 years ago. a) 1:10 b) 11:10 c) 10:11 d) 10:1 

Last Answer : A Let, keerthi’s age 32 years ago = x, Grandfather's age 32 years ago = 16x. 16 years from now, 6(x+32+16) = (16x+32+16) => x = 24 16 years ago ratio was: (x+16)/ (16x+16) = (24+16) / (16*24+16) 40 /400 = >1 / 10

Description : A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.What are the ages of the children? -Riddles

Last Answer : 2 - 5 - 8 - 11 - 14 - 17 - 20 - 23 - 26

Description : if the ratio of the ages (in years) of x and y, 6 years ago was 9:8 then which of the following can be the sum of their ages 6 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 6 years ago was 9:8 then which of the following can ... 89 years B. 85 years C. 91 years D. 92 years

Description : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be the sum of their ages 8 years from now?

Last Answer : if the ratio of the ages (in years) of x and y, 8 years ago is 7:6, then which of the following can be ... years from now? A. 82 B. 97 C. 75 D. 94

Description : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be the sum of their ages 5 years from now?

Last Answer : if the ratio of the ages (in years) of A and B, 5 years ago was 5:7, then which of the following can be ... years from now? A. 90 B. 98 C. 92 D. 87

Description : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Last Answer : The present age of A is twice that of B. The sum of their present ages is 33 years. Find the present age of A (in years)

Description : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after five years is 58. Find the ratio of their ages 3 years

Last Answer : The ratio of the present ages of a father and his son is ` 3 : 1` . The sum of their ages after ... is 58. Find the ratio of their ages 3 years ago.

Description : What is the product of Gary and his brother's ages if the sum of Gary's age and his brother's age is 34 and the difference between their ages is 4?

Last Answer : 34 (the sum) divided by 2 (people) = 17Now, account for the "4" difference, while maintaining the sumof 34.In other words, add "1" to one age, while subtracting "1" fromthe other until the difference is " ... 3419 - 15 = 4However, the question is asking for the product of the ages.19 x 15 = 285.285

Description : The ages of A and B are in the ratio 8 : 5. If the sum of their ages is 39 years, what will be the ratio of their ages after 9 years? a) 3 : 2 b) 8 : 7 c) 10: 7 d) 11 : 8 e) None of these

Last Answer : Sum of ratios = 8 +5 = 13. Sum of ages = 39 years 13 ratio = 39 years  1 ratio = 3 years 9 years = 3 ratio new ratio = (8+3) : (5+3) = 11 : 8 Answer: d)

Description : The sum of ages of Mohan and his father is 35 years. When Mohan’s age will be equal to present age of his father, then sum of their ages will be 85 years. Find present age of the father. a) 20 years b) 25 years c) 30 years d) 32 years e) None of these

Last Answer : Sum of present ages = 35 years sum of their ages will be 85 years after (85-35) / 2 = 25 years from now. the father is 25 years older than his son. Present age of father = (35 + 25)/2 = 30 years. Answer: c)

Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these

Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)

Description : Sum of present ages of A and B is 60 years. 5 years hence, their ages will be in the ratio 3:4. Find A’s present age. a) 25 years b) 30 years c) 35 years d) 40 years e) None of these

Last Answer : Sum of their present ages = 60 years sum of their ages, 5 years hence = 60 + (5 × 2) = 70 years. after 5 years, ratio of ages of A and B will be 3 : 4. A’s age after 5 years = (3/7) × 70 = 30 years A’s present age = 30 – 5 = 25 years Answer: a)

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10

Last Answer : Answer: A

Description : The sum of the current ages of two persons M and N is 129. If the age of M is twice that of N, find the sum of their ages 8 years hence. a)125 b)145 c)137 d)149

Last Answer : B M+N=129 Given M=2N From Which N =43,M=86 8 years their age will be 51 and 94 ,so the sum of their ages is 145

Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17 

Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.

Description :  The average age of K and L is 48 years. If M replaced K, the average age would be 40 and if M replaced L, the average would be 44. What are the ages of K,L,M repectively? A) 58, 46, 22 B) 32, 44, 36 C) 52,44,36 D) 56, 22,38

Last Answer : Answer: C)  Total age of K& L = 48*2 = 96 yrs----->1 Total age of L& M = 40*2 = 80yrs----->2 Total age of K& M = 44*2 = 88 yrs----->3 from 1, 2, 3 K+L+M =132---->4 from 1 & 4, M= 36 from 2 & 4, K=52 from 3 & 4, L=44 Hence the required answer is 52,44,36 

Description : The sum of two children is ‘a’. The age of the father is twice the ‘a’. After twenty years, his age will be equal to the addition of the ages of his children. Find the age of father. -Maths 10th

Last Answer : Let the sum of the ages of two children will be x and age of father will be y. A.T.Q. , y = 2x ----------(i) and , After 20 years, x+40=y+20 ==> ... i), x-2x = -20 ==> x = 20 Now, put x= 20 in (i), y = 2 x 20 = 40 Hence age of father will be 40 years.

Description : The sum of ages of Sunil and his father is 46 years. 3 years back, father’s age was 4 times sunil’s age. find present age of Sunil. a) 7 years b) 8 years c) 11 years d) 12 years e) None of these

Last Answer : Sum of their ages, 3 years ago = 46 – (2 × 3) = 40 years sunil’s age, 3 years ago = 1/5 × 40 = 8 years sunil’s present age = 8 + 3 = 11 years Answer: c)

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

Description : The sum of ages of family members (both children and parents) is 360 years.The total ages of children and parents are in the ratio 2:1 and the ages of wife and husband are in the ratio 5:7.What will be the age of husband? A.65 B.75 C.72 D.70

Last Answer : Answer : D (70) ExplanationSum of ages is 360 years.The ratio of children and parents ages is 2:1. Total age of parents = 360 x 1 / 3 = 120 years Ratio of wife and husband age is 5:7. Therefore, the age of husband = 120 x 7 / 12 = 70 Hence the age of husband is 70 years.

Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years

Last Answer : C

Description : The sum of ages of 4 puppies born at the intervals of 2 years each is 48 years. What is the age of the youngest puppy? a) 9years b) 8 years c) 10 years d) None of these 

Last Answer : A Let the ages of puppies be x, (x + 2), (x + 4)and (x + 6) years. Then, x + (x + 2) + (x + 4) + (x + 6) = 48 4x = 36,x = 9 Age of the youngest puppy = x = 9 years

Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years

Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35 

Description : At the time of marriage, a man was 6 years older to his wife. 12 years after their marriage, his age is 6/5 times the age of his wife. What was wife’s age at the time of marriage? a) 18 years b) 24 years c) 30 years d) 36 years e) None of these

Last Answer : ratio of their ages, 12 years hence = 6 : 5  Difference in ages = 1 ratio = 6 years wife’s age (12 years hence) = 5 ratio = 5 × 6 years = 30 years wife’s age at the time of marriage = 30 – 12 = 18 years Answer: a)

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