If the three points (k, 2k), (2k, 3k) and (3, 1) are collinear then k is equal to -Maths 9th

1 Answer

Answer :

(d) 3Let (x, y) be the co-ordinates of the third vertex of the triangle. Then\(rac{0+2+x}{3}\) = 1 and \(rac{0+0+y}{3}\) = 1⇒ 2 + \(x\) = 3 and y = 3 ⇒ \(x\) = 1, y = 3. ∴ Co-ordinates of vertices of the triangle are (0, 0), (2, 0) and (1, 3). ∴ Area of triangle = \(rac{1}{2}\) [0(0 – 3) + 2(3 – 0) + 1(0 – 0)][∵Area of Δ = \(rac{1}{2}\) (x1(y2 – y3) + x2 (y2 – y3) + x3(y1 – y2)]= \(rac{1}{2}\) [0+6+0] = \(rac{6}{2}\) = 3.

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