Description : If they dug up some person who was buried a couple of hundred years ago and could get a DNA sample, would it be possible to tell whether I am related to him or her?
Last Answer : answer:At most, they could tell you that you share a relation to the corps. DNA is pretty definitive. Whether or not the deceased is the same person as the headstone implicates is subject to more scrutiny than DNA results. but I’m no scientist.
Description : The extinct human who lived 100000 to 40000 years ago, in Europe, Aisa and parts of Africa, with short stature, heavy eye brows, retreating fore heads
Last Answer : The extinct human who lived 100000 to 40000 years ago, in Europe, Aisa and parts of Africa, ... B. Ramapithecus C. Homo habilis D. Neanderthal human
Description : If you lived 400 years ago where might you think the mouse in the cabinet came from?
Last Answer : What is the answer ?
Description : The extinct human who lived 1,00,000 to 40,000 years ago, in Europe, Asia and parts of Africa, with short stature, heavy eye brows, retreating for heads, large jaws with heavy teeth, stocky ... and stooped posture was (1) Ramapithecus (2) Homo habilis (3) Neanderthal human (4) Cro-magnan humans
Last Answer : (3) Neanderthal human
Description : Copyright questions concerning classical musicians from over a hundred years ago?
Last Answer : answer:This was an interesting article. Copyright law is a mess.. but you have to concern yourself with not only the song, but lyrics (if any), performer, etc as well.
Description : About hundred years ago there were few countries that had hardly any political party. Now there are few countries that do not have political parties.' -SST 10th
Last Answer : Now there are only a few countries that don't have political parties because: 1. Contesting elections: In most elections around the world, parties put up candidates who compete in the elections. ... the policies of the government. They represent different views and keep the ruling party in check.
Description : Thirty years ago, the age of a man was three-fifth of his present age. Find the present age (in years)
Last Answer : Thirty years ago, the age of a man was three-fifth of his present age. Find the present age (in years)
Description : In a reservoir the average volume of sediment deposition is 0.15 million cubic per year. If the dead storage and total capacity of the reservoir are 8 million cubic metres and 36 million cubic metres respectively, (A) The ... reducing after 60 years (C) Both (a) and (b) (D) Neither (a) nor (b)
Last Answer : (C) Both (a) and (b)
Description : If some schools allow GPA's over 100%, or 4.00 then theoretically could admission averages follow suit?
Last Answer : Sure! And at that point everybody would get a scholarship to Harvard and then graduate Cum Laude Then they would get an MD at John’s Hopkins. Then one day they would kill you in the operating room because they were faking it the whole time. How cool is that?!
Description : Theoretically, could some language be acquired before birth?
Last Answer : answer:Oh my! Dragon riders of Pern! Love it! I don't think language can be acquired before birth. To learn words you have to be able to hear them in a physical context and a cause and effect. ... say the baby can't hear and respond to emotions. But that has nothing to do with a specific language.
Description : Theoretically speaking, what kind of kickback could energy weapons have?
Last Answer : Energy doesn’t have mass so there wouldn’t be recoil.
Description : Theoretically could a mutant (X-Men) be one without realising?
Last Answer : It is possible, but unlikely. Even if he was only super smart, he would notice the difference from the rest of the world.
Description : Theoretically, what Nobel prize could you be up for?
Last Answer : Literature, I guess. One of my songs may be good enough to be considered a great piece of literature (Not really). If I have to go to Stockholm as a condition of winning, I’d pass and let the runner-up take it.
Description : What can I do to help my hand recover from an injury that happened 4 years ago?
Last Answer : Go to the doctor, get an x-ray, and request physical therapy. PT will help relieve the pain.
Description : Can I sue for malpractice for something that happened 10 years ago?
Last Answer : answer:Welcome to Fluther. I wouldn't say you can't do that , but I also wouldn't say you can certainly do that. I expect that you can find a lawyer who would take the case on a ... of the event since at that age you were not considered competent to have such knowledge. Talk to an attorney.
Description : If an alien race threatens to destroy Earth unless one hundred healthy humans below fifty years of age voluntarily kill themselves on a daily basis how long would humankind survive?
Last Answer : Indefinetly. The world population is growing at a rate of about 80 million people per year (births – deaths). That’s about 219k people per day. 100 is minuscule in comparison. Also one might assume that people would have more children under such conditions.
Description : Which of the following statements regarding literacy in India are correct ? 1. A person who can only read but cannot write is not defined literate 2. Children below 7 years of age are not taken into consideration even if they are able to read ... and 4 (b) 2, 3, and 4 (c) 1, 2 and 3 (d) 1, 2, and 4
Last Answer : Ans: (b)
Description : A man who lived on the top floor of a twenty story building had to go up and down daily for work, and of course, for food and the other necessities. On most days he could only ride the elevator to ... way. When it rained, however, he could ride all the way up to the twentieth story. Why? -Riddles
Last Answer : The man wasn't tall enough to reach the button for the 20th floor. He could only reach the 15th story button on the elevator. When it rained, he brought his umbrella, and used it to press the 20th story button on the elevator.
Description : My age today is three times what it will be three years from now minus three times what my age was three years ago. How old am I? -Riddles
Last Answer : Don't be too confused, the answer is 18 years old.
Description : Five years ago, the age of a person was half of his present age. How old is he now ?
Last Answer : Five years ago, the age of a person was half of his present age. How old is he now ?
Description : In 15 years Alma will be four times as old as she was nine years ago. What is Alma's present age?
Last Answer : x + 15 = 4(x - 9)x + 15 = 4x - 36x = 4x - 513x = 51x = 17
Description : "Ravi is 10 years older than Rehan. Five years ago, one-seventh of Ravi's age was equal to one-fifth of Rehan's age." If Rehan's age be 'x' years and Ravi's age be 'y' years, which of the following pair of linear equations is ... y = 10 and 7x + 5y - 10 = 0 (d) x - y = -10 and 7y - 5x + 10 = 0
Last Answer : (b) y -x = 10 and 5y -7x + 10 = 0
Description : X says to Y, I am 3 times as old as you were 3 years ago .How old is X? I. Y s age 17 years from now is same as X's present age. II. X's age nine years from now is ... with the help of both the statements. If the data in either statement I or statement II alone is sufficient to answer the question
Last Answer : Let the current ages of X and Y be a and b respectively From the question: A=3(a-b) From statement I: A=b + 17 B = a-17 Therefore, a = 3(a-17-3) a=3a-60 2a=60 A=30 Hence, X ... a+9)/3 Substituting this in first equation, A=a+9-9 Hence, no result Therefore, statement I alone is sufficient Answer :a
Description : 10 years ago the average age of all the 25 teachers of a college was 45 years. 4 years ago, a teacher retired from the post at the age of 60 years, and was replaced by a new teacher whose age was 54 years. ... 53 b) Between 53 and 54 c) Between 54 and 55 d) Between 55 and 56 e) None of the above
Last Answer : Let current year be 2015 In 2005, sum of all ages = 25 45 = 1125 In 2015, sum of all ages = 1125 + (25 10) = 1375 Now 60 year old teacher was replaced by a 54 year old teacher. So we need ... all ages in 2015 considering the replacement teacher = 1375 - 6 = 1369 Average = 1369/25 = 54.76 Answer: c)
Description : Five years ago, the age of Arun was 4 times the age of Sarmi after 10 years, Arun will be twice as old as Sarmi. Find the Present ages of Arun and sarmi? a) 30 years, 10.5 years b) 32 years, 11.5 years c) 34 years, 14.5 years d) 35 years, 12.5 years e) None of these
Last Answer : Five years ago, x – 5/y – 5 = 4/1 x – 4y = – 15 —-(i) After 10 years, x + 10/y + 10 = 2/1 x – 2y = 10 —–(ii) From eqn (i) and (ii) => x = 35, y = 12.5 Answer: d)
Description : Sum of present age of A, B and C is 72 years. If 4 years ago, their ages were in the ratio 1 : 2 : 3, find A’s present age. a) 7 years b) 10 years c) 12 years d) 14 years e) None of these
Last Answer : Sum of present ages of A, B and C is 72 years. sum of their ages (4 years ago) = 72 – (3 × 4) = 60 years 4 years ago, ratio of ages of A, B and C was 1 : 2 :3. A’s age, 4 years ago = (1/6) ×60 = 10 years A’s present age = 10 + 4 = 14 years Answer: d)
Description : Ages of DEEPA and Subha are presently in the ratio of 5 : 6 respectively. Six years hence this ratio will become 6 : 7 respectively. What was Subha’s age 5 years ago? a) 33 years b) 32 years c) 35 years d) 31 years e) None of these
Last Answer : Present ratio of Deepa&Subha = 5 : 6 Six year hence ratio of Deepa&Subha = 6 : 7 Difference between ratio = 1 Difference in ages between present & future = 6 year. 1 ratio=6 yrs & SUBHA's age = 6 6 =36 year 5 year ago ... = 7 6 = 42 year B's age 5 year ago = 42-6-5 = 42-11 = 31 year Answer: d)
Description : Madhan was 3 times as old as his daughter 10 years ago. After 10 years, Madhan will be twice as old as his daughter. Find out the present age of Madhan. a) 68 years b) 70 years c) 40 years d) 55 years e) 80 years
Last Answer : b Let age of the daughter before 10 years = x Then, age of Madhan before 10 years = 3x After 10 years, Madhan will be twice as old as his daughter. ⇒ 3x + 20 = 2( x+20) ⇒ x = 20 ⇒ Present age of Madhan = 3x + 10 = 3× 20+ 10 = 70 years.
Description : One year ago the ratio between Sam and Ash’s age was 4:3. One year hence the ratio of their ages will be 5:4. What is the sum of their present ages in years? A.14 B.16 C.18 D.12 E.None of these
Last Answer : Answer - B (16) Explanation - Let one year ago Sam's age be 4X years And, Ash's age be 3X years Present age of Sam = (4X + 1) years Present age of Ash= (3X + 1) years One year hence Sam's age = (4X + 2) ... = 2 Sum of their present ages = 4X + 1 + 3X + 1 = 7X + 2 = 7 x 2 + 2 = 16 years.
Description : Ten years ago, Khush was thrice as old as Sam was but 10 years hence, he will be only twice as old. Find Khush’s present age? A.30 B.35 C.40 D.36 E.None of these
Last Answer : Answer - A (30) Explanation - Let Khush's present age be x years and Sam's present age be y years Then, according to the first condition, x - 10 = 3(y - 10) or, x - 3y = -20 ..(1) Now. Khush's age ... (1) and (2), we get x = 70 and y = 30 Khush's age = 70 years and Sam's age = 30 years
Description : 3 years ago, the average of a family of 5 members was 17 years. A baby having been born, the average age of the family is the same today. The present age of the baby is: A.5 years B.2 years C.1 year D.4 years E.None of these
Last Answer : Answer – B (2 years) Explanation – Total age of 5 members, 3 years ago = (17 x 5) years = 85 years Total age of 5 members now = (85 + 3 x 5) years = 100 years Total age of 6 members now = (17 x 6) years = 102 years Age of the baby = (102 – 100) years = 2 years
Description : The average age of four boys, five years ago was 9 of all the five is 15 years. The present age of the new boy is 1. 22 years 2. 24 years 3. 21 years 4. 18 years 5. 19 years
Last Answer : 5; Five years ago the average age of 4 boys = 9 years The present average age of 4 boys = 9+5 = 14 So the present age of new boys = 15 + 4 x 1 = 19 years
Description : The average age of a board of 8 trustless remains the same as it was 3 years ago, when one of them is replaced by a new member. The new member is younger than the truetee in whose place he has been replaced by (a) 24 years (b) 26 years (C) 47 years (d) 32 years
Last Answer : 24 years
Description : The average age of 10 members of a committee is the same as it was 4 years ago, because an old member has been replaced by ayoung member. Find how much younger is the new member?
Last Answer : Answer: 40 years.
Description : Anil is twice as old as Sunita. Three years ago, he was three times as old as Sunita. The present age of Anil is (A) 6 years (B) 8 years (C) 12 years (D) 16 years
Last Answer : Answer: C
Description : The sum of the ages of two persons A and B is 50. 5 years ago, the ratio of their ages was 5/3. The present age of A and B are (A) 30, 20 (B) 35, 15 (C) 38, 12 (D) 40, 10
Last Answer : Answer: A
Description : 15 years ago, vaishali age was 15 times the age of her brother and the sum of present ages of vaishali and brother is 94years. What will be the age of her brother after 18 years? a) 32 years b) 33.5 years c) 37 years d) 30 years
Last Answer : C
Description : The ratio of the age of a rithick and his wife is 12:9. At the time of marriage the ratio was 10:6 and After 6 years this ratio will become 18:14. How many years ago were they married? a) 27 b) 12 c) 18 d) 14
Last Answer : C Let the present age of the rithick and his wife be 12x and 9x respectively. After 6 years this ratio will become 18:14 =>9:7 (12x+6): (9x+6) = 9:7 84x+42 =81x+54 x=4 Present age of the rithick = ... that they got married before t years. Then, (48-t):(36-t)=10:6 144-3t=180-5t 2t=36 t=18
Description : The ratio of kabil’s age 6 years ago and sahul’s age after 6 years is 3 : 3. If at present, the ratio of their ages is 7: 5, then find the ratio between kabil’s age 6 years hence and sahul’s age 6 years ago. a) 1 : 3 b) 2 : 1 c) 4 : 3 d) 3 : 4
Last Answer : B At present: Ratio of their ages = 7 : 5. Therefore, 7: 5 will be 7x and 5x. kabil's age 6 years ago = 7x - 6 sahul's age after 6years = 5x + 6 Ratio of kabil's age 6years ago and sahul's age after 6 ... Ratio of sahul's age and kabil's age (7x + 6) / (5x - 6) = 48/24 =2/1 =2:1
Description : Total of the ages of P, Q and R at present is 99 years. Eight years ago, the ratio of their ages was 4: 5: 6. What is the age of Q at present a) 44 b) 30 c) 45 d) 33
Last Answer : D Let their ages 8 years ago is4x, 5x and 6x years. 4x+8+5x + 8 + 6x + 8= 99 hence x= 5 Q’s present age = (5x + 8) =33 years
Description : Keerthi's grandfather was 16 times older to her 32 years ago. He would be 6times of her age 16 years from now. What was ratio of ages of keerthi and her grandfather 16 years ago. a) 1:10 b) 11:10 c) 10:11 d) 10:1
Last Answer : A Let, keerthi’s age 32 years ago = x, Grandfather's age 32 years ago = 16x. 16 years from now, 6(x+32+16) = (16x+32+16) => x = 24 16 years ago ratio was: (x+16)/ (16x+16) = (24+16) / (16*24+16) 40 /400 = >1 / 10
Description : Eight years ago, the ratio of the ages of micky and Donald was 6:5, 12years hence, the ratio of their ages will be 11:10. What is Donald age at present a) 30 years b) 28 years c) 34 years d) 36 years
Last Answer : B Let 8 years ago the age of Micky and Donald be 6x and 5x resp. then, ((6x+8)+12) / ((5x+8)+12) = 11/10 10(6x+20) = 11(5x+20) 5x = 20 => x = 4 So Donald age is (5x+8) = 28
Description : Age of father 30 years ago was 9 times the age of her son. After 30 years, father’s age will be thrice that of his son. Find the ratio of their present ages. a) 21 : 5 b) 29 : 5 c) 27 : 4 d) 21 : 3
Last Answer : A At age of son be x and as father's age is 9 times the age of her son, let it be 9x, nine years ago. At present: father's age will be (9x + 30) and son's age will be (x + 30) After 30 years: father's age ... x = 20 We are asked to find the present ratio. (9x + 30) : (x + 30) = 210 : 50 = 21:5
Description : The sum of the current ages of a father and his son is 84 years. 7 years ago, father's age was 3 times the age of the son. After 7 years, son's age will be a) 35 years b) 28 years c) 56years d) 53 years
Last Answer : A Son’s current age = x years. Then father’s age = (84 - x)years (84 - x) - 7 = 3(x - 7) 2x=56 x =28; after 7years it will be turn on 35
Description : The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son a) 34,17 b) 14,40 c) 40,14 d) 50,17
Last Answer : C Let sons age = x years. Then mothers age = (54 - x)years. (x-8)(54-x-8) = 6(54- x - 8) hence (x-8) = 6 so x = 14 Their ages are 40 years and 14 years.
Description : 12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages a) 30 b) 35 c) 36 d) 32
Last Answer : C Let M's age 12 years ago = x years. Then, N's age 12 years ago = 2x years. (x + 12) / (2x+ l2) = 4/5 => x = 4. So, the total of their present ages =(x + 12 + 2x + 12) = (3x + 24) = 36 years.
Description : Amit is 18 years elder than Rohit. If 8 years ago, Amit was 6 times as old as Rohit, then find Amit’s present age. a). 32.5 years b) 27.5 years c) 29.6 years d) 24.9 years
Last Answer : C Let age of Rohit be y Amit is 18 years elder than Rohit = (y + 18). SoAmit's age 8 years ago = (y + 18 - 8) Rohit's age before 8 years = (y - 8) 8 years ago, Amit is 6 times as old as Rohit (y + 18 ... = 58 y = 11.6 Rohit's age = 11.6years Amit's age = (y + 18) = (11.6 + 18) = 29.6years
Description : The sum of the ages of the 4 members of Sinha family is 172 years. 8 years ago the ages of the 4 members Nishu, Vicky, Mrs.Sinha and Sinha were in the ratio of 2:3:7:8. After how many years would Nishu be ... present age of his mother? a) 33 years b) 35 years c) 36 years d) 37 years e) None of these
Last Answer : Answer: B Let their ages 8 years ago be 2x, 3x, 7x, and 8x. Their ages now 2x+8, 3x+8, 7x+8, 8x+8. According to the question, =2x+8+3x+8+7x+8+8x+8=172 20x+32=172 =>x=140/20=7 Present age of Nishu=2×7+8=22 years Present age of mother=7×7+8=57 years Hence, required years (57-22)=35 years
Description : 20 years ago, the average age of a family of 4 member was 48 years. 2 children having been born (with the age difference of4 yrs) the present average age of the family is the same. The present age of the youngest child is. A) 2yrs B) 4 yrs C) 6yrs D) 8yrs
Last Answer : C) Total age of 4 members, 20 yrs ago = (48 * 4)=192 yrs Total age of 4 members now = 192 + 20 * 4 = 272 yrs Total age of 6 members now = (48*6)=288yrs Sum of the age of children = 288 - 272 = 16 ... the age of the elder child 4 +x So x + 4 +x = 16 2x=12 X=6 Age of younger child = 6years
Description : After replacing an old person by a new person, it was found that the average age of five persons of a assembly is the same as it was 6 years ago. What is the difference between the ages of the replaced and the new persons? A) 24 B) 36 C) 30 D) 15
Last Answer : C) Let the ages of the five persons at present be a, b, c, d & e years. And the age of the new persons be f years. So the new average of five members' age = (a + b + c + d + f)/5 - ... - e + f) = 5x Solving e - f = 30 years. Thus the difference of ages between replaced and new person = 30years.