What Consists Of Cooling Water Circuit And Coal & Ash Circuit In Steam Power Plant?

What Consists Of Cooling Water Circuit And Coal & Ash Circuit In Steam Power Plant?
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The cooling water circuit consists of a pump, condenser and cooling tower. The coal and ash circuit consists of coal delivery, preparation of coal, handling of coal to the boiler furnace, ash handling and ash storage.
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What consists of cooling water circuit and coal & ash circuit in steam power plant?

Description : What consists of cooling water circuit and coal & ash circuit in steam power plant?

Last Answer : The cooling water circuit consists of a pump, condenser and cooling tower. The coal and ash circuit consists of coal delivery, preparation of coal, handling of coal to the boiler furnace, ash handling and ash storage.

What consists of cooling water circuit and coal & ash circuit in steam power plant?

Description : What consists of cooling water circuit and coal & ash circuit in steam power plant?

Last Answer : The cooling water circuit consists of a pump, condenser and cooling tower. The coal and ash circuit consists of coal delivery, preparation of coal, handling of coal to the boiler furnace, ash handling and ash storage.

What Consists Of Feed Water And Steam Flow Circuit In Steam Power?

Description : What Consists Of Feed Water And Steam Flow Circuit In Steam Power?

Last Answer : The feed water and steam flow circuit consists of feed pump, economizer boiler drum super heater, turbine and condenser.

Water gas is obtained by passing air and a large amount of steam over waste coal at about 650°C.  A.Correct  B.Incorrect

Description : Water gas is obtained by passing air and a large amount of steam over waste coal at about 650°C.  A.Correct  B.Incorrect

Last Answer : Answer: B

Carbonisation of coal consists of  A. drying and crushing the coal to a fine powder  B. moulding the finely ground coal under pressure with or without a binding material  C. heating the wood with a limited supply of air to temperature not less than 280°C  D. none of the above

Description : Carbonisation of coal consists of  A. drying and crushing the coal to a fine powder  B. moulding the finely ground coal under pressure with or without a binding material  C. heating the wood with a limited supply of air to temperature not less than 280°C  D. none of the above

Last Answer : Answer: D

In producer gas making furnace, steam is added along with air to mainly control the (A) Fusion of coal ash & clinker formation (B) C. V. of producer gas (C) Temperature of producer gas (D) Tar content in producer gas

Description : In producer gas making furnace, steam is added along with air to mainly control the (A) Fusion of coal ash & clinker formation (B) C. V. of producer gas (C) Temperature of producer gas (D) Tar content in producer gas

Last Answer : (A) Fusion of coal ash & clinker formation

Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Description : Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Last Answer : Answer: A

Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Description : Producer gas is obtained by  A. partial combustion of coal, coke, anthracite coal or charcoal in a mixed air steam blast  B. carbonisation of bituminous coal  C. passing steam over incandescent coke  D. passing air and a large amount of steam over waste coal at about 650°C

Last Answer : Answer: A

The fuel mostly used in steam boilers is  A. brown coal  B. peat  C. coking bituminous coal  D. non-coking bituminous coal

Description : The fuel mostly used in steam boilers is  A. brown coal  B. peat  C. coking bituminous coal  D. non-coking bituminous coal

Last Answer : Answer: D

What Consists Of Air And Flue Gas Circuit?

Description : What Consists Of Air And Flue Gas Circuit?

Last Answer : Air and flue gas circuit consists of forced draught fan, air preheater, boiler, furnace, superheater, economizer, dust collector, induced draught fan and chimney.

Name The Four Major Circuits In Steam Power Plant?

Description : Name The Four Major Circuits In Steam Power Plant?

Last Answer :  Coal and ash circuit  Air and flue gas circuit  Feed water and steam circuit  Cooling water circuit

What is sometimes known as the “Fourth-power law”?  A. Kirchhoff’s radiation law  B. Newton’s law of cooling  C. Stefan-Boltzmann law  D. Hess’s law

Description : What is sometimes known as the “Fourth-power law”?  A. Kirchhoff’s radiation law  B. Newton’s law of cooling  C. Stefan-Boltzmann law  D. Hess’s law

Last Answer : Stefan-Boltzmann law

What consists of feed water and steam flow circuit in steam power?

Description : What consists of feed water and steam flow circuit in steam power?

Last Answer : The feed water and steam flow circuit consists of feed pump, economizer boiler drum super heater, turbine and condenser.

What consists of feed water and steam flow circuit in steam power?

Description : What consists of feed water and steam flow circuit in steam power?

Last Answer : The feed water and steam flow circuit consists of feed pump, economiser boiler drum super heater, turbine and condenser.

For a body cooling in a draft, the rate of heat loss is proportional to the difference in temperature between the body and its surroundings.  a. Nemst Effect  b. Caloric Theory  c. Joule’s Law  d. Newton’s Law of Cooling

Description : For a body cooling in a draft, the rate of heat loss is proportional to the difference in temperature between the body and its surroundings.  a. Nemst Effect  b. Caloric Theory  c. Joule’s Law  d. Newton’s Law of Cooling

Last Answer : Newton’s Law of Cooling

The theory that heat consisted of a fluid, which could be transferred from one body to another, but not “created” or “destroyed”.  a. Clausius Theorem  b. Caloric Theory  c. Joules Law  d. Newton’s Law of cooling

Description : The theory that heat consisted of a fluid, which could be transferred from one body to another, but not “created” or “destroyed”.  a. Clausius Theorem  b. Caloric Theory  c. Joules Law  d. Newton’s Law of cooling

Last Answer : Caloric Theory

Adiabatic heating and Adiabatic cooling really means _________ and _________ respectively.  a. raising the temp and lowering the temp  b. maintaining the pressure and changing the temperature  c. decreasing the volume and increasing the pressure  d. lowering the temp and raising the temp

Description : Adiabatic heating and Adiabatic cooling really means _________ and _________ respectively.  a. raising the temp and lowering the temp  b. maintaining the pressure and changing the temperature  c. decreasing the volume and increasing the pressure  d. lowering the temp and raising the temp

Last Answer : raising the temp and lowering the temp

What is the temperature when water and vapor are in equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Description : What is the temperature when water and vapor are in equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Last Answer : Steam point

At steam point, the temperature of water and its vapor at standard pressure are:  a. Extremes or maximum  b. unity  c. in equilibrium  d. undefined

Description : At steam point, the temperature of water and its vapor at standard pressure are:  a. Extremes or maximum  b. unity  c. in equilibrium  d. undefined

Last Answer : in equilibrium

What is the temperature when water and vapor are in the equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Description : What is the temperature when water and vapor are in the equilibrium with the atmospheric pressure?  a. Ice point  b. Steam point  c. Critical point  d. Freezing point

Last Answer : Steam point

Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Description : Water vapor at 100 KPa and 150°C is compressed isothermally until half the vapor has condensed. How much work must be performed on the steam in this compression process per kilogram?  a) -1384.7 kJ  b) 1384.7 kJ  c) -2384.7 kJ  d) 2384.7 kJ

Last Answer : -1384.7 kJ

A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C. 2.54 kg  D. 3.16 kg Formula: from the steam table at 600kPa vƒ = 0.001101 m^3 / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Description : A vessel with a volume of cubic meter contains liquid water and water vapor ion equilibrium at 600 kPa. The liquid water has mass of1kg. Using the steam table, calculate the mass of the water vapor.  A. 0.99kg  B. 1.57 kg  C ... / kg vg = 0.3157 m^3 / kg Vtot = mƒ vƒ + mg vg mg = (tot-mƒ vƒ) / vg

Last Answer : 3.16 kg

A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Last Answer : 2 x10^6 kJ

When liquid water is converted to steam at 100˚C, the entropy of water  a. increases  b. decreases  c. remains the same  d. none of the above

Description : When liquid water is converted to steam at 100˚C, the entropy of water  a. increases  b. decreases  c. remains the same  d. none of the above

Last Answer : increases

The boiling of water into steam in an open container is an example of a/an _________ process.  a. adiabatic  b. isochoric  c. isobaric  d. zero work

Description : The boiling of water into steam in an open container is an example of a/an _________ process.  a. adiabatic  b. isochoric  c. isobaric  d. zero work

Last Answer : isobaric

The thermodynamic difference between a Rankine cycle working with saturated steam and the Carnot cycle is that  (a) carnot cycle can’t work with saturated steam  (b) heat is supplied to water at temperature below the maximum temperature of the cycle  (c) a rankine cycle receives heat at two places  (d) rankine cycle is hypothetical  (e) none of the above.

Description : The thermodynamic difference between a Rankine cycle working with saturated steam and the Carnot cycle is that  (a) carnot cycle can't work with saturated steam  (b) heat is supplied to water at temperature ... heat at two places  (d) rankine cycle is hypothetical  (e) none of the above.

Last Answer : Answer : b

Water contained in a beaker can be made to boil by passing steam through it  (a) at atmospheric pressure  (b) at a pressure below the firuosphejric pressure  (c) at a pressure greater than atmospheric pressure  (d) any pressure  (e) not possible.

Description : Water contained in a beaker can be made to boil by passing steam through it  (a) at atmospheric pressure  (b) at a pressure below the firuosphejric pressure  (c) at a pressure greater than atmospheric pressure  (d) any pressure  (e) not possible.

Last Answer : Answer : c

For which of the following substances, the internal energy and enthalpy are the functions of temperature only  (a) any gas  (b) saturated steam  (c) water  (d) perfect gas  (e) superheated steam.

Description : For which of the following substances, the internal energy and enthalpy are the functions of temperature only  (a) any gas  (b) saturated steam  (c) water  (d) perfect gas  (e) superheated steam.

Last Answer : Answer : d

Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits.  (a) 02, N2, steam, C02  (b) Oz, N2, water vapour  (c) S02, NH3, C02, moisture  (d) 02, N2, H2, air  (e) steam vapours, H2, C02.

Description : Which of the following can be regarded as gas so that gas laws could be applicable, within the commonly encountered temperature limits.  (a) 02, N2, steam, C02  (b) Oz, N2, water vapour  (c) S02, NH3, C02, moisture  (d) 02, N2, H2, air  (e) steam vapours, H2, C02.

Last Answer : Answer : d

What pressure measuring device consists of a coiled hollow tube that tends to straighten out when the tube is subjected to an internal pressure?  A. Aneroid  B. Manometer  C. Bourdon pressure gage  D. Barometer

Description : What pressure measuring device consists of a coiled hollow tube that tends to straighten out when the tube is subjected to an internal pressure?  A. Aneroid  B. Manometer  C. Bourdon pressure gage  D. Barometer

Last Answer : Bourdon pressure gage

A system which consists of fixed amount of mass and no mass can cross its boundary called _____.  A. Equilibrium system  B. Thermal equilibrium system  C. Open system  D. Closed system

Description : A system which consists of fixed amount of mass and no mass can cross its boundary called _____.  A. Equilibrium system  B. Thermal equilibrium system  C. Open system  D. Closed system

Last Answer : Closed system

The dual combustion cycle consists of one constant pressure, two constant volume and two isentropic processes.  A. Agree  B. Disagree

Description : The dual combustion cycle consists of one constant pressure, two constant volume and two isentropic processes.  A. Agree  B. Disagree

Last Answer : Answer: A

Ericsson cycle consists of two constant pressure and two isothermal processes.  A. Agree  B. Disagree

Description : Ericsson cycle consists of two constant pressure and two isothermal processes.  A. Agree  B. Disagree

Last Answer : Answer: A

Gas turbine cycle consists of  (a) two isothermals and two isentropics  (b) two isentropics and two constant volumes  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pressures  (e) none of the above.

Description : Gas turbine cycle consists of  (a) two isothermals and two isentropics  (b) two isentropics and two constant volumes  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pressures  (e) none of the above.

Last Answer : Answer : d

Brayton cycle consists’ of following four processes  (a) two isothermals and two isentropics  (b) two isentropics and two constant volumes  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pres-sures  (e) none of the above.

Description : Brayton cycle consists’ of following four processes  (a) two isothermals and two isentropics  (b) two isentropics and two constant volumes  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pres-sures  (e) none of the above.

Last Answer : Answer : d

Diesel cycle consists of following four processes  (a) two isothermals and two isentropics  (b) two isentropics, and two constant volumes.  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pressures  (e) none of the above.

Description : Diesel cycle consists of following four processes  (a) two isothermals and two isentropics  (b) two isentropics, and two constant volumes.  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pressures  (e) none of the above.

Last Answer : Answer : c

Otto cycle consists of following four processes  (a) two isothermals and two isentropics  (b) two isentropics and two constant volumes  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pres-sures  (e) none of the above.

Description : Otto cycle consists of following four processes  (a) two isothermals and two isentropics  (b) two isentropics and two constant volumes  (c) two isentropics, one constant volume and one constant pressure  (d) two isentropics and two constant pres-sures  (e) none of the above.

Last Answer : Answer : b

Which of the following is the other term used for enthalpy-entropy diagram?  a. Enthalpy diagram  b. Mollier diagram  c. Steam diagram  d. Entropy chart

Description : Which of the following is the other term used for enthalpy-entropy diagram?  a. Enthalpy diagram  b. Mollier diagram  c. Steam diagram  d. Entropy chart

Last Answer : Mollier diagram

Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Description : Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Last Answer : 97.6%,2713 kJ/kg

Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Description : Wet steam at 1 MPa flowing through a pipe is throttled to a pressure of 0.1 MPa. If the throttling temperature is110°C, What is the quality of the steam in the pipe?  a) 96%  b) 86%  c) 76%  d) 66%

Last Answer : 96%

A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Description : A steam calorimeter receives steam from a pipe at 0.1 MPa and 20°SH. For a pipe steam pressure of 2 MPa, what is the quality of the steam?  a) 95.56%  b) 70.10%  c) 95.20%  d) 85.10% Formula: h1 = hf1 + x1hfg1

Last Answer : 265.4°C, 430.7kJ/kg, 71.4kJ/kg, 1.0327kJ/(kg)(K),502.1 kJ/kg

Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216  a. 1214 Btu / lb  b. 1234 Btu /lb  c. 1342 Btu / lb  d. 1324 Btu /lb formula: ∫ = h– pv/ J

Description : Find ∫ for steam at 100 psia and 600°F.If h = 1329.6 and v = 6.216  a. 1214 Btu / lb  b. 1234 Btu /lb  c. 1342 Btu / lb  d. 1324 Btu /lb formula: ∫ = h– pv/ J

Last Answer : 1214Btu / lb

Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Description : Calculate the entropy of steam at 60psiawith a quality of 0.8  A. 0.4274 BTU/lbm-˚R  B. 0.7303 BTU/lbm-˚R  C. 1.1577 BTU/lbm-˚R  D. 1.2172 BTU/lbm-˚R Formula: fromthe steamtable at 60 psia: sƒ = 0.4274 BTU/lbm-˚R sƒg = 1.2172 BTU/lbm-˚R) s = sƒ + x sƒg where x = is the quality

Last Answer : 1.1577 BTU/lbm-˚R

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

Description : Steam at 1000 lbf/ft^2 pressure and 300˚R has specific volume of 6.5 ft^3/lbm and a specific enthalpy of 9800 lbf-ft/lbm. Find the internal energy per pound mass of steam.  A.2500 lbf-ft/lbm  B.3300 lbf-ft/lbm  C.5400 lbf-ft/lbm  D.6900 lbf-ft/lbm Formula: h= u+ pV u= h– pV

Last Answer : 3300 lbf-ft/lbm

A simple steam engine receives steam from the boiler at 180˚C and exhausts directly into the air at 100˚C. What is the upper limit of its efficiency?  a. 11.28 %  b. 36.77 %  c. 20.36 %  d. 17.66 %

Description : A simple steam engine receives steam from the boiler at 180˚C and exhausts directly into the air at 100˚C. What is the upper limit of its efficiency?  a. 11.28 %  b. 36.77 %  c. 20.36 %  d. 17.66 %

Last Answer : 17.66 %

Defined as the ratio of weight of dry steam to the weight of stuff.  a. dryness fraction  b. Vaporization  c. fusion  d. super heated steam

Description : Defined as the ratio of weight of dry steam to the weight of stuff.  a. dryness fraction  b. Vaporization  c. fusion  d. super heated steam

Last Answer : dryness fraction

The term _________ is traditionally used to describe steam issuing from condensate receiver vents and openended condensate discharge lines from steam traps.  a. dry steam  b. wet steam  c. phase steam  d. flash steam

Description : The term _________ is traditionally used to describe steam issuing from condensate receiver vents and openended condensate discharge lines from steam traps.  a. dry steam  b. wet steam  c. phase steam  d. flash steam

Last Answer : flash steam

Mixture of liquid and steam of the same substance in which both are at saturation temperature.  a. dry steam  b. current steam  c. wet steam  d. aerosol

Description : Mixture of liquid and steam of the same substance in which both are at saturation temperature.  a. dry steam  b. current steam  c. wet steam  d. aerosol

Last Answer : wet steam