The efficiency of power transmission through pipe is (where H = Total supply head, and hf = Head lost due to friction in the pipe) (A) (H - hf )/H (B) H/(H - hf ) (C) (H + hf )/H (D) H/(H + hf )

The efficiency of power transmission through pipe is (where H = Total supply head, and hf
 = Head
lost due to friction in the pipe)
(A) (H - hf )/H
(B) H/(H - hf )
(C) (H + hf )/H
(D) H/(H + hf )
by

1 Answer

Answer :

Answer: Option A
by

Related questions

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The power transmitted through the pipe is maximum when the head lost due to friction is equal to (A) One-fourth of the total supply head (B) One-third of the total supply head (C) One-half of the total supply head (D) Two-third of the total supply head

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In case of a pipe exit fitted with a nozzle, the (A) Conversion of kinetic head to pressure head is facilitated (B) Conversion of pressure head to kinetic head is facilitated (C) Power transmitted through the nozzle is maximum, when the head lost due to friction in the pipe is equal to one third of the total supply head (D) Both (B) and (C)

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149 The power transmitted through a pipe is (where w = Specific weight in N/m3 , and Q = Discharge in m 3 /s) (A) w × Q × H (B) w × Q × hf (C) w × Q (H - hf ) (D) w × Q (H + hf )

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Power transmitted through a pipe is maximum when the loss of head due to friction is :

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According to Darcy's formula, the loss of head due to friction in the pipe is (where f = Darcy's coefficient, l = Length of pipe, v = Velocity of liquid in pipe, and d = Diameter of pipe) (A) flv²/2gd (B) flv²/gd (C) 3flv²/2gd (D) 4flv²/2gd

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If Nf , Nd and H are total number flow channels, total number of potential drops and total hydraulic head differences respectively, the discharge q through the complete flow is given by (where K is a constant) (A) q = (Nf/Nd) (B) q = KH (Nd/(Nf ) (C) q = KH (Nf/Nd) (D) q = KH Nf/Nd)

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