Suppose the round trip propagation delay for a 10 Mbps Ethernet having 48-bit jamming signal is 46.4 ms. The minimum frame size is a. 94 b. 416 c. 464

Suppose the round trip propagation delay for
a 10 Mbps Ethernet having 48-bit jamming
signal is 46.4 ms. The minimum frame size
is
a. 94
b. 416
c. 464
by

1 Answer

Answer :

c. 464
by

Related questions

Suppose that the one-way propagation delay for a 100 Mbps Ethernet having 48-bit jamming signal is 1.04 micro-seconds. The minimum frame size in bits is: a. 112 b. 160 c. 208 d. 256

Description : Suppose that the one-way propagation delay for a 100 Mbps Ethernet having 48-bit jamming signal is 1.04 micro-seconds. The minimum frame size in bits is: a. 112 b. 160 c. 208 d. 256

Last Answer : d. 256

In an Ethernet local area network, which one of the following statements is TRUE ? a. A station stops to sense the channel once it starts transmitting a frame. b. The purpose of the jamming signal is to pad the frames that are smaller than the minimum frame size. c. A station continues to transmit the packet even after the collision is detected. d. The exponential backoff mechanism reduces the probability of collision on retransmissions

Description : In an Ethernet local area network, which one of the following statements is TRUE ? a. A station stops to sense the channel once it starts transmitting a frame. b. The purpose ... collision is detected. d. The exponential backoff mechanism reduces the probability of collision on retransmissions

Last Answer : The exponential backoff mechanism reduces the probability of collision on retransmissions

The minimum frame length for 10-Mbps Ethernet is _______bytes. A) 32 B) 80 C) 128 D) none of the above

Description : The minimum frame length for 10-Mbps Ethernet is _______bytes. A) 32 B) 80 C) 128 D) none of the above

Last Answer : none of the above

Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Description : Consider a CSMA/CD network that transmits data at a rate of 100 Mbps (108 bits per second) over a 1 km (kilometre) cable with no repeaters. If the minimum frame size required for this network is 1250 bytes, what is the signal speed (km/sec) in the cable? a. 8000 b. 10000 c. 16000 d. 20000

Last Answer : d. 20000

Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s.b. 2 c. 2.5 d. 5

Description : Determine the maximum length of the cable (in km) for transmitting data at a rate of 500 Mbps in an Ethernet LAN with frames of size 10,000 bits. Assume the signal speed in the cable to be 2,00,000 km/s. b. 2 c. 2.5 d. 5

Last Answer : b. 2

The round-trip propagation delay between two earth stations through a geosynchronous satellite is A. 500 to 600 ms B. 300 to 400 ms C. 600 to 700 ms D. 400 to 500 ms

Description : The round-trip propagation delay between two earth stations through a geosynchronous satellite is A. 500 to 600 ms B. 300 to 400 ms C. 600 to 700 ms D. 400 to 500 ms

Last Answer : A. 500 to 600 ms

The maximum frame length for 10-Mbps Ethernet is ________ bytes. A) 1518 B) 1500 C) 1200 D) none of the abov

Description : The maximum frame length for 10-Mbps Ethernet is ________ bytes. A) 1518 B) 1500 C) 1200 D) none of the abov

Last Answer : 1518

The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channelcapacity. Assuming that processing delay is negligible, the minimum number of bits for the sequence number field in a frame for maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Description : The distance between two stations M and N is L kilometers. All frames are K bits long. The propagation delay per kilometer is t seconds. Let R bits/second be the channel capacity. Assuming that processing ... maximum utilization, when the sliding window protocol used is: a. A b. B c. C d. D

Last Answer : c. C

A sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of an acknowledgement is 100 bytes and the transmission rate at the receiver is 8 Kbps. The one-way propagation delay is 100 milliseconds. Assuming no frame is lost, the sender throughput is __________ bytes/second. a. 2500 b. 2000 c. 1500 d. 500

Description : A sender uses the Stop-and-Wait ARQ protocol for reliable transmission of frames. Frames are of size 1000 bytes and the transmission rate at the sender is 80 Kbps (1Kbps = 1000 bits/second). Size of ... is lost, the sender throughput is __________ bytes/second. a. 2500 b. 2000 c. 1500 d. 500

Last Answer : a. 2500

Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

Description : Which of the following couldnot be an Ethernet unicast destination? A) 43:7B:6C:DE:10:00 B) 44:AA:C1:23:45:32 C) 46:56:21:1A:DE:F4 D) 48:32:21:21:4D:34

Last Answer : 43:7B:6C:DE:10:0

Which of the following statements is TRUE about CSMA/CD a. IEEE 802.11 wireless LAN runs CSMA/CD protocol b. Ethernet is not based on CSMA/CD protocolc. CSMA/CD is not suitable for a high propagation delay network like satellite network d. There is no contention in a CSMA/CD network

Description : Which of the following statements is TRUE about CSMA/CD a. IEEE 802.11 wireless LAN runs CSMA/CD protocol b. Ethernet is not based on CSMA/CD protocol c. CSMA/CD is not suitable for a high propagation delay network like satellite network d. There is no contention in a CSMA/CD network

Last Answer : CSMA/CD is not suitable for a high propagation delay

A 8-Mbps tokenring has atoken holding timer value of 10 msec. What is the longest frame (assumeheader bits are negligible) that canbe sent on this ring? A. 8000 B frame B. 80,000 B frame C. 8 x 105 bit frame D. 10,000 B frame

Description : A 8-Mbps tokenring has atoken holding timer value of 10 msec. What is the longest frame (assumeheader bits are negligible) that canbe sent on this ring? A. 8000 B frame B. 80,000 B frame C. 8 x 105 bit frame D. 10,000 B frame

Last Answer : 10,000 B frame

Station A uses 32 byte packets to transmit messages to Station B using a sliding window protocol. The round trip delay between A and B is 80 milliseconds and the bottleneck bandwidth on the path between A and B is 128 kbps. What is the optimal window size that A should use? a. 20 b. 40 c. 160 d. 320

Description : Station A uses 32 byte packets to transmit messages to Station B using a sliding window protocol. The round trip delay between A and B is 80 milliseconds and the bottleneck bandwidth on the path between A and B ... What is the optimal window size that A should use? a. 20 b. 40 c. 160 d. 320

Last Answer : b. 40

In a token ring network the transmission speed is 10^7 bps and the propagation speed is 200 metres/micro second. The 1- bit delay in this network is equivalent to: a. 500 metres of cable. b. 200 metres of cable. c. 20 metres of cable. d. 50 metres of cable

Description : In a token ring network the transmission speed is 10^7 bps and the propagation speed is 200 metres/micro second. The 1- bit delay in this network is equivalent to: a. 500 metres of cable. b. 200 metres of cable. c. 20 metres of cable. d. 50 metres of cable

Last Answer : c. 20 metres of cable.

Standard Ethernet (10-Mbps) uses_______ encoding A) NRZ B) AMI C) Manchester D) differential Manchester

Description : Standard Ethernet (10-Mbps) uses_______ encoding A) NRZ B) AMI C) Manchester D) differential Manchester

Last Answer : Manchester

The IEEE 802.3 Standard defines _________ CSMA/CD as the access method for first-generation 10-Mbps Ethernet. A) 1-persistent B) p-persistent C) non-persistent D) none of the above

Description : The IEEE 802.3 Standard defines _________ CSMA/CD as the access method for first-generation 10-Mbps Ethernet. A) 1-persistent B) p-persistent C) non-persistent D) none of the above

Last Answer : 1-persistent

Each station on an Ethernet network has a unique _______ address imprinted onits network interface card (NIC). A) 5-byte B) 32-bit C) 48-bit D) none of the above

Description : Each station on an Ethernet network has a unique _______ address imprinted onits network interface card (NIC). A) 5-byte B) 32-bit C) 48-bit D) none of the above

Last Answer : 48-b

The least significant 23 bits in a 48-bit Ethernet address identify a ________. A) multicast router B) host C) multicast group D) noneof the above

Description : The least significant 23 bits in a 48-bit Ethernet address identify a ________. A) multicast router B) host C) multicast group D) noneof the above

Last Answer : multicast group

What is the difference between the Ethernet frame preamble field and the IEEE 802.3 preamble and start of frame Delimiter fields? a. 1 byte b. 1 bit c. 4 bit d. 16 bit

Description : What is the difference between the Ethernet frame preamble field and the IEEE 802.3 preamble and start of frame Delimiter fields? a. 1 byte b. 1 bit c. 4 bit d. 16 bit

Last Answer : a. 1 byte

The program used to determine the round trip delay between a workstation and a destination address is a. Tracert b. Traceroute c. Ping d. Pop

Description : The program used to determine the round trip delay between a workstation and a destination address is a. Tracert b. Traceroute c. Ping d. Pop

Last Answer : b. Traceroute

What is the minimum propagation delay of a geostationary satellite? A. 278 ms B. 239 ms C. 300 ms D. 600 ms

Description : What is the minimum propagation delay of a geostationary satellite? A. 278 ms B. 239 ms C. 300 ms D. 600 ms

Last Answer : B. 239 ms

A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? a. 1 Mbps b. 2 Mbps c. 10 Mbps d. 12 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 12,000 frames per minute with each frame carrying an average of 10,000 bits. What is the throughput of this network ? a. 1 Mbps b. 2 Mbps c. 10 Mbps d. 12 Mbps

Last Answer : b. 2 Mbps

A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Description : A network with bandwidth of 10 Mbps can pass only an average of 15,000 frames per minute with each frame carrying an average of 8,000 bits. What is the throughput of this network? a. 2 Mbps b. 60 Mbps c. 120 Mbps

Last Answer : a. 2 Mbps

Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Description : Station A uses 32 byte packets to transmit messages to station B using sliding window protocol. The round trip delay between A and B is 40 milli seconds and the bottleneck bandwidth on the path between A and B is 64 kbps. The optimal window size of A is (1) 20 (2) 10 (3) 30 (4) 40

Last Answer : (2) 10

When propagationspeed is multiplied by propagation time, we get the ________. A) throughput B) wavelength of thesignal C) distortionfactor D) distancea signal or bit has traveled

Description : When propagationspeed is multiplied by propagation time, we get the ________. A) throughput B) wavelength of thesignal C) distortionfactor D) distancea signal or bit has traveled

Last Answer : distancea signal or bit has traveled

______ eliminates the varying delay times associated withdifferent-size packets. A) X.25 B) Frame Relay C) ATM D) all of theabove

Description : ______ eliminates the varying delay times associated withdifferent-size packets. A) X.25 B) Frame Relay C) ATM D) all of theabove

Last Answer : ATM

The total propagation delay time from transmission to reception of signals from a ground transmitter to ground receiver with angle of elevation at 10 degrees respectively is A. 273 ms B. 239 ms C. 275 ms D. 260 ms

Description : The total propagation delay time from transmission to reception of signals from a ground transmitter to ground receiver with angle of elevation at 10 degrees respectively is A. 273 ms B. 239 ms C. 275 ms D. 260 ms

Last Answer : A. 273 ms

The phase constant of a wave propagation with frequency of 35 radian/sec and time delay of 7.5 sec is a) 4.66 b) 262.5 c) 46.6 d) 26.25

Description : The phase constant of a wave propagation with frequency of 35 radian/sec and time delay of 7.5 sec is a) 4.66 b) 262.5 c) 46.6 d) 26.25

Last Answer : b) 262.5

The maximum propagation delay of a geostationary satellite is A. 278 ms B. 239 ms C. 300 ms D. 250 ms

Description : The maximum propagation delay of a geostationary satellite is A. 278 ms B. 239 ms C. 300 ms D. 250 ms

Last Answer : A. 278 ms

Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____. a. 2 sec b. 3 sec c. 4 sec d. 1 sec

Description : Suppose transmission rate of a channel is 32 kbps. If there are ‘8’ routes from source to destination and each packet p contains 8000 bits. Total end to end delay in sending packet P is _____. a. 2 sec b. 3 sec c. 4 sec d. 1 sec

Last Answer : a. 2 sec

- MAC is to Ethernet what ________ is to Frame Relay. A. DLCI B. LCI C. PVC D. None of the above

Description : - MAC is to Ethernet what ________ is to Frame Relay. A. DLCI B. LCI C. PVC D. None of the above

Last Answer : DLCI

In the Ethernet frame, the_______field contains error detection information. A) CRC B) preamble C) address D) none of the above

Description : In the Ethernet frame, the_______field contains error detection information. A) CRC B) preamble C) address D) none of the above

Last Answer : CRC

In the Ethernet, the _______field is actually added at the physical layer and isnot (formally)part of the frame. A) CRC B) preamble C) address D) none of the above

Description : In the Ethernet, the _______field is actually added at the physical layer and isnot (formally)part of the frame. A) CRC B) preamble C) address D) none of the above

Last Answer : preamble

An IGMP packet is carried in an __________ packet. A) UDP B) IP C) Ethernet frame D) noneof the above

Description : An IGMP packet is carried in an __________ packet. A) UDP B) IP C) Ethernet frame D) noneof the above

Last Answer : IP

Which of the following statements is TRUE? a. Both Ethernet frame and IP packet include checksum fields b. Ethernet frame includes a checksum field and IP packet includes a CRC field c. Ethernet frame includes a CRC field and IP packet includes a checksum field d. Both Ethernet frame and IP packet include CRC fields

Description : Which of the following statements is TRUE? a. Both Ethernet frame and IP packet include checksum fields b. Ethernet frame includes a checksum field and IP packet includes a CRC field c. Ethernet ... and IP packet includes a checksum field d. Both Ethernet frame and IP packet include CRC fields

Last Answer : Ethernet frame includes a CRC field and IP packet includes a checksum field

If delaysare recorded as 10 bit numbers in a 50 router network, and delay vectorsare exchanged twicea second,how muchbandwidth per fill duplex line is occupied by the distributedrouting algorithm? A. 500 bps B. 1500 bps C. 5 bps D. 1000 bps

Description : If delaysare recorded as 10 bit numbers in a 50 router network, and delay vectorsare exchanged twicea second,how muchbandwidth per fill duplex line is occupied by the distributedrouting algorithm? A. 500 bps B. 1500 bps C. 5 bps D. 1000 bps

Last Answer : 1000 bps

Which consequences are more likely to occur during the frame transmission in StopandWait ARQ mechanism? a. Loss of frame or an acknowledgementb. Delay in an acknowledgement c. Normal operation d. All of the above

Description : Which consequences are more likely to occur during the frame transmission in StopandWait ARQ mechanism? a. Loss of frame or an acknowledgement b. Delay in an acknowledgement c. Normal operation d. All of the above

Last Answer : d. All of the above

the maximum window size for data transmission using the selective reject protocol with n-bit frame sequence numbers is: a. 2^n b. 2^(n-1) c. 2^n – 1 d. 2^(n-2)

Description : the maximum window size for data transmission using the selective reject protocol with n-bit frame sequence numbers is: a. 2^n b. 2^(n-1) c. 2^n – 1 d. 2^(n-2)

Last Answer : b. 2^(n-1)

A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for change of state will be (A) 15 ns. (B) 30 ns. (C) 45 ns. (D) 60 ns.

Description : A 4-bit synchronous counter uses flip-flops with propagation delay times of 15 ns each. The maximum possible time required for change of state will be (A) 15 ns. (B) 30 ns. (C) 45 ns. (D) 60 ns.

Last Answer : Ans: A 15 ns because in synchronous counter all the flip-flops change state at the same time.

Ethernet is baseband system using CSMA/CD operating at A. 20 Mbps B. 10 Mbps C. 30 Mbps D. 40 Mbps

Description : Ethernet is baseband system using CSMA/CD operating at A. 20 Mbps B. 10 Mbps C. 30 Mbps D. 40 Mbps

Last Answer : B. 10 Mbps

What is the baud rate of the standard 10 Mbps Ethernet ? (A) 10 megabaud (B) 20 megabaud (C) 30 megabaud (D) 40 megabaud

Description : What is the baud rate of the standard 10 Mbps Ethernet ? (A) 10 megabaud (B) 20 megabaud (C) 30 megabaud (D) 40 megabaud

Last Answer : (B) 20 megabaud

An image is 1024∗800 pixels with 3 bytes/pixel. Assume the image is uncompressed. How long does it take to transmit it over a 10-Mbps Ethernet ? (A) 196.6 seconds (B) 19.66 seconds (C) 1.966 seconds (D) 0.1966 seconds

Description : An image is 1024∗800 pixels with 3 bytes/pixel. Assume the image is uncompressed. How long does it take to transmit it over a 10-Mbps Ethernet ? (A) 196.6 seconds (B) 19.66 seconds (C) 1.966 seconds (D) 0.1966 seconds

Last Answer : (C) 1.966 seconds

In Ethernet addressing, if the least significant bit of the firstbyte is 1, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

Description : In Ethernet addressing, if the least significant bit of the firstbyte is 1, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

Last Answer : multicast

In Ethernet addressing, if the least significant bit of the firstbyte is 0, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

Description : In Ethernet addressing, if the least significant bit of the firstbyte is 0, the address is _________. A) unicast B) multicast C) broadcast D) none of the above

Last Answer : unicast

In Ethernet CSMA/CD, the special bit sequence transmitted by media access management to handle collision is called a. Preamble b. Postamble c. Jam d. None of the above

Description : In Ethernet CSMA/CD, the special bit sequence transmitted by media access management to handle collision is called a. Preamble b. Postamble c. Jam d. None of the above

Last Answer : c. Jam

In Ethernet when Manchester encoding is used, the bit rate is: a. Half the baud rate. b. Twice the baud rate. c. Same as the baud rate. d. None of the above

Description : In Ethernet when Manchester encoding is used, the bit rate is: a. Half the baud rate. b. Twice the baud rate. c. Same as the baud rate. d. None of the above

Last Answer : a. Half the baud rate.

What is the propagation delay when a signal is transmitter by an earth station to a geosynchronous satellite about 38,500 km above earth’s equator and then received by the same earth station? A. 256 msec B. 128 msec C. 300 msec D. 400 msec

Description : What is the propagation delay when a signal is transmitter by an earth station to a geosynchronous satellite about 38,500 km above earth’s equator and then received by the same earth station? A. 256 msec B. 128 msec C. 300 msec D. 400 msec

Last Answer : A. 256 msec

What do you call the phenomenon in digital circuits that describe the duration of time a digital signal passes a circuit? A. Transmission time B. Elapsed time C. Propagation delay D. Travel delay

Description : What do you call the phenomenon in digital circuits that describe the duration of time a digital signal passes a circuit? A. Transmission time B. Elapsed time C. Propagation delay D. Travel delay

Last Answer : C. Propagation delay