How many lengths to swim in a 15 meter pool?

How many lengths to swim in a 15 meter pool?
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40 lengths of a 15m pool at the gym today can you tell me how many calories in ...
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Why will my dogs go in the lake and swim with no hesitation, but won't go into the baby pool in the back yard when it has water in it?

Description : Why will my dogs go in the lake and swim with no hesitation, but won't go into the baby pool in the back yard when it has water in it?

Last Answer : Ask them.

How much or how little of a bikini/swimsuit have you ever been in at the gym, beach, swim park, public pool, etc?

Description : How much or how little of a bikini/swimsuit have you ever been in at the gym, beach, swim park, public pool, etc?

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How do you get the "pool water" smell out of a swim suit?

Description : How do you get the "pool water" smell out of a swim suit?

Last Answer : Wash in the washer and add a cup of vinegar to the rinse. Or wash in the sink with natural castille soap (Dr. Bronner’s or Kirk’s). This will also get the chlorine out of your hair.

In a 50-meter pool, how many laps is a mile?

Description : In a 50-meter pool, how many laps is a mile?

Last Answer : 32.2 laps (from start to other end is one, and back to start is two) 32.2 laps (from start to other end is one, and back to start is two)

What is the hydrostatic pressure at the bottom of a pool 6 meters deep? w) 60,000 Newtons per meter squared x) 6,000 Newtons per meter squared y) 600 Newtons per meter squared z) 60 Newtons per meter squared

Description : What is the hydrostatic pressure at the bottom of a pool 6 meters deep? w) 60,000 Newtons per meter squared x) 6,000 Newtons per meter squared y) 600 Newtons per meter squared z) 60 Newtons per meter squared

Last Answer : ANSWER: W -- 60,000 NEWTONS PER METER SQUARED

If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Description : If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Last Answer : LET EACH SIDE BE X 6X+11X+15X=96 32X=96 X=3 SIDES=6 3=18 11 3=33 15 3=45 AREA OF TRIANGLE BY HERONS FORMULA=S=96/2=48 WHOLE UNDERROOT 48 48-18 48-33 48-45 UNDERROOT=12 4 30 15 3 4 3 15ROOT2 180 ... bh/2 180root2=18 h/2 360root2=18h h=20 root2 But root 2=1.4(approx) h=20 1.4(approx) h=28cm(approx).

If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Description : If the lengths of the sides of a triangle are in the ratio 6:11:15 and it's perimeter is 96cm , then the height corresponding to the longest side is -Maths 9th

Last Answer : LET EACH SIDE BE X 6X+11X+15X=96 32X=96 X=3 SIDES=6 3=18 11 3=33 15 3=45 AREA OF TRIANGLE BY HERONS FORMULA=S=96/2=48 WHOLE UNDERROOT 48 48-18 48-33 48-45 UNDERROOT=12 4 30 15 3 4 3 15ROOT2 180 ... bh/2 180root2=18 h/2 360root2=18h h=20 root2 But root 2=1.4(approx) h=20 1.4(approx) h=28cm(approx).

The lengths of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of this triangle is -Maths 9th

Description : The lengths of three medians of a triangle are 9 cm, 12 cm and 15 cm. The area (in sq. cm) of this triangle is -Maths 9th

Last Answer : (b) 72 cm2Here sm = \(rac{9+12+15}{2}\) = 18 cm, where lengths of medians are m1 = 9 cm, m2 = 12 cm, m3 = 15 cm.∴ Area of triangle = \(rac{4}{3}\sqrt{18(18-9)(18-12)(18-15)}\) cm2= \(rac{4}{3}\sqrt{18 imes9 imes6 imes3}\) cm2 = \(rac{4}{3}\) x 9 x 6 cm2 = 72 cm2.

what- hakeem measures four ropes to find their lengths. The ropes each have the same length. First, he measures one rope in inches with a ruler.The rope is longer than the ruler, so he uses the ruler twice: 12 + 3 = 15?

Description : what- hakeem measures four ropes to find their lengths. The ropes each have the same length. First, he measures one rope in inches with a ruler.The rope is longer than the ruler, so he uses the ruler twice: 12 + 3 = 15?

Last Answer : He multiplies the length of one rope by 4 to find the total length of the ropes in inches: 4(15) = 60Then he thinks to himself: I used the whole ruler two times and got the measurements 12 inches and 3 inches. ... multiplied each of those measurements by 4 and then added: 4(12) + 4(3) = 48 + 12 = 60

Two thin lenses of focal lengths 15 cm and 30 cm resepectively are kept in contact with each other. What is the power of the combined system?

Description : Two thin lenses of focal lengths 15 cm and 30 cm resepectively are kept in contact with each other. What is the power of the combined system?

Last Answer : Two thin lenses of focal lengths 15 cm and 30 cm resepectively are kept in contact with each other. What is the power of the combined system?

ails are available in various lengths ranging from a ) 1.00 to 15 cm b) 1.25 to 15 cm c) 1.5 to 15 cm d) 2.5 to 15 cm

Description : ails are available in various lengths ranging from a ) 1.00 to 15 cm b) 1.25 to 15 cm c) 1.5 to 15 cm d) 2.5 to 15 cm

Last Answer : b) 1.25 to 15 cm

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Description : Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction? A.12 sec B.18 sec C.14 sec D.25 sec E.None of these

Last Answer : Answer – A (12 sec) Explanation – Speed of the first train = [120 / 10] m/sec = 12 m/sec. Speed of the second train = [120 / 15] m/sec = 8 m/sec. Relative speed = (12 + 8) = m/sec = 20 m/sec. ∴ Required time = (120 + 120) / 20 secc = 12 sec

A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N? A) 15 km/hr B) 61km/hr C) 51km/hr D) 50k/hr

Description : A train M speeding with 60km/hr crooses another train N, running in the same direction in 1 min. If the lengths of the trains M and N be 50m and 100m respectively. What is the speed of train N? A) 15 km/hr B) 61km/hr C) 51km/hr D) 50k/hr

Last Answer : ANSWER: C Explanation:  Let the speed of be train N be ‘x’km/hr  Speed of M relative to N = (60 – x)km/hr  = (60-x) * 5/18]m/s = (300 – 5x / 18)m/s  150 / (300 – 5x / 18) =60  2700/300-5x=60  2700=18000-300x 300x=15300  x= 153/3  x=51km/hr  Therefore the speed of the train is 51 km/hr

Dhanvanth can swim at 15 km/hr in stagnant water. In a river with 3 km/hr current, he swims to a certain distance and comes back within 100 min. What is the distance between the two points? A) 11km B) 13km C) 19km D) 12km

Description : Dhanvanth can swim at 15 km/hr in stagnant water. In a river with 3 km/hr current, he swims to a certain distance and comes back within 100 min. What is the distance between the two points? A) 11km B) 13km C) 19km D) 12km

Last Answer : ANSWER: D Explanation: Speed in still water (a) = 15 km/hr Speed in current( b) = 3 km/hr Upstream speed = a - b = 15 - 3 = 12 km/hr Downstream speed = a + b = 15 + 3 = 18 km/hr Let the ... 36 = 5 / 3 15x = 36 * 5 x = 36 * 5 / 15 = 12 km Distance between the two points is 12km

The length and width of a swimming pool are 50 metres and 15 metres respectively. If the depth of the swimming pool at one end is 10 -Maths 9th

Description : The length and width of a swimming pool are 50 metres and 15 metres respectively. If the depth of the swimming pool at one end is 10 -Maths 9th

Last Answer : 11250 m3 If we take the vertical crossection of the face of the swimming pool, then it is a trapezium ABCD, with parallel sides AD and BC respectively of lengths 10 m and 20 m and distance between parallel sides as 50 m ... 50]×15[12(10+20)×50]×15 m3 = (15 x 50 x 15) m3 = 11250 m3.

What Rectangular pool has an area of 192 square feet. The length of the pool is 15 feet. What is the pool and width rounded to the nearest foot?

Description : What Rectangular pool has an area of 192 square feet. The length of the pool is 15 feet. What is the pool and width rounded to the nearest foot?

Last Answer : 13 feet

Hi, I have a fiberglass that was install 15 years ago. I notice that there a bubbles in the pool recently. i'm going to get cracks , what can I do to prevent that.?

Description : Hi, I have a fiberglass that was install 15 years ago. I notice that there a bubbles in the pool recently. i'm going to get cracks , what can I do to prevent that.?

Last Answer : If the cracks are in the surface layer of the fiberglass, the problem can be rectified. These "spider" cracks form in the gel coating of the fiberglass, due to pressures that can occur from a pool ... types of cracks aren't structural. If the bubbles are raised, I would call a pool repair service.

Adam's Pool Service charges £50 for swimming pool cleaning performed prior to May 15 and £75 for jobs performed after that date. This pricing structure provides the benefits to Adam's of: A)price leaders. B)smoothing demand fluctuations. C)increasing service tangibility. D)tying prices to service costs.

Description : Adam's Pool Service charges £50 for swimming pool cleaning performed prior to May 15 and £75 for jobs performed after that date. This pricing structure provides the benefits to Adam's of: ... leaders. B)smoothing demand fluctuations. C)increasing service tangibility. D)tying prices to service costs.

Last Answer : B)smoothing demand fluctuations.

15) Adam's Pool Service charges £50 for swimming pool cleaning performed prior to May 15 and £75 for jobs performed after that date. This pricing structure provides the benefits to Adam's of: A)price leaders. B)smoothing demand fluctuations. C)increasing service tangibility. D)tying prices to service costs.

Description : 15) Adam's Pool Service charges £50 for swimming pool cleaning performed prior to May 15 and £75 for jobs performed after that date. This pricing structure provides the benefits to Adam's ... leaders. B)smoothing demand fluctuations. C)increasing service tangibility. D)tying prices to service costs.

Last Answer : B)smoothing demand fluctuations.

Why would an atheist, or group of atheists, go to such lengths to try and convince believers that God doesn't exist?

Description : Why would an atheist, or group of atheists, go to such lengths to try and convince believers that God doesn't exist?

Last Answer : Why do you not ask the same question of theists?

Why is it so hard for some people to imagine what incredible lengths they would go to to get something to eat, if they were literally starving to death?

Description : Why is it so hard for some people to imagine what incredible lengths they would go to to get something to eat, if they were literally starving to death?

Last Answer : Living in a country where obesity is rampant might have something to do with it.

Why is it that when you fold your fingers down, they are all the same length, but when you put them straight up they are all different lengths?

Description : Why is it that when you fold your fingers down, they are all the same length, but when you put them straight up they are all different lengths?

Last Answer : Mine don’t. But can you touch your elbows behind your back?

What's the nastiest or strangest thing you've ever pawed through; what are the greatest lengths you've ever gone to try to find or retrieve something of monetary or sentimental value that you've lost?

Description : What's the nastiest or strangest thing you've ever pawed through; what are the greatest lengths you've ever gone to try to find or retrieve something of monetary or sentimental value that you've lost?

Last Answer : I’ve walked for miles to heal a wounded relationship.

What lengths would you do to assure someone does not get on the roadway drunk?

Description : What lengths would you do to assure someone does not get on the roadway drunk?

Last Answer : I would be prepared to steal the distributor cap, or take the keys to drive the car and the person home myself. There is no excuse for drink driving, and it is irresponsible to let a friend do ... when a friend drink drives, you are putting their life at risk, as well as innocent road users.

Non morning people: What’s the most extreme lengths you’ve gone to wake up early in the morning?

Description : Non morning people: What’s the most extreme lengths you’ve gone to wake up early in the morning?

Last Answer : My go-to is always just staying up

I have three colors, each with a different meaning. When I'm old they become dull, but when I'm new they are gleaming. I help keep people safe, but sometimes they hate me. You won't see me in a forest, but you will in a big city. Some of me have short lengths, and some of me have long. And in the time that the longest of me take, you could sing a very long song. When my colors change, people get happy or sad, and when you guess what I am, you will be very glad. What am I? -Riddles

Description : I have three colors, each with a different meaning. When I'm old they become dull, but when I'm new they are gleaming. I help keep people safe, but sometimes they hate me. You won't see me in a forest, ... get happy or sad, and when you guess what I am, you will be very glad. What am I? -Riddles

Last Answer : A Stoplight.

If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Description : If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Last Answer : (d) Given, the length of two sides of a triangle are 5 cm and 1.5 cm, respectively. Let sides AB = 5 cm and CA = 1.5 cm We know that, a closed figure formed by three intersecting lines ( ... options (a), (b) and (c) satisfy the above inequality but option (d) does not satisfy the above inequality.

Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Last Answer : No, it is not possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm because here we see that sum of the lengths of two sides is equal to third side i.e., 4+3 ... , the sum of any two sides of a triangle is greater than its third side, so given statement is not correct.

If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Description : If two sides of a triangle are of lengths 5 cm and 1.5 cm, then the length of third side of the triangle cannot be -Maths 9th

Last Answer : (d) Given, the length of two sides of a triangle are 5 cm and 1.5 cm, respectively. Let sides AB = 5 cm and CA = 1.5 cm We know that, a closed figure formed by three intersecting lines ( ... options (a), (b) and (c) satisfy the above inequality but option (d) does not satisfy the above inequality.

Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm ? -Maths 9th

Last Answer : No, it is not possible to construct a triangle with lengths of its sides as 4 cm, 3 cm and 7 cm because here we see that sum of the lengths of two sides is equal to third side i.e., 4+3 ... , the sum of any two sides of a triangle is greater than its third side, so given statement is not correct.

Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Description : Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Last Answer : We know that, each angle of a rectangle is right angle (i.e., 90°) and its opposite sides are equal and parallel. To construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm, use the ... AD and CD. Thus, ABCD is the required rectangle with adjacent sides of length 5 cm and 3.5 cm.

A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Description : A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Last Answer : we know that , all sides of a rhombus are equal and the diagonals of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4cm and 6cm ... ) From Eqs. (i) and (ii), AB = BC = CD = DA Hence , ABCD is a rhombus.

Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Description : Construct a rectangle whose adjacent sides are of lengths 5 cm and 3.5 cm. -Maths 9th

Last Answer : To construct a triangle ABC in which AB = 3.6 cm, AC = 3.0 cm and BC = 4. 8 cm, use the following steps. 1.Draw a line segment BC of length 4.8 cm. 2.From B, point A is at a distance of 3.6 ... 3.Joining BP, we obtain angle bisector of ∠B. 4.Flere, ∠ABC=39° Thus, ∠ABD = ∠DBC = 1/2 x 139° = 19.5°

A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Description : A rhombus whose diagonals are 4 cm and 6 cm in lengths. -Maths 9th

Last Answer : We know that, all sides of a rhombus are equal and the diagonals of a rhombus are perpendicular bisectors of one another. So, to construct a rhombus whose diagonals are 4 cm and 6 cm use the following steps. 1.Draw ... B and D. 6.Now, join AB, BC, CD, and DA . Thus, ABCD is the required rhombus.

Is it possible to construct a triangle with lengths of its sides 5cm, 3cm and 8cm? Give reason for your answer. -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides 5cm, 3cm and 8cm? Give reason for your answer. -Maths 9th

Last Answer : Solution :- No, since sum of two sides is equal to third side. (5 cm + 3 cm = 8 cm)

Is it possible to construct a triangle with lengths of its sides as 7 cm, 8 cm and 5 cm? Give reason for your answer. -Maths 9th

Description : Is it possible to construct a triangle with lengths of its sides as 7 cm, 8 cm and 5 cm? Give reason for your answer. -Maths 9th

Last Answer : Solution :- Yes, because in each case sum of two sides is greater than the third side.

Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm

The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of other chord from the centre? -Maths 9th

Description : The lengths of two parallel chords of a circle are 6 cm and 8 cm. If the smaller chord is at a distance of 4 cm from the centre, what is the distance of other chord from the centre? -Maths 9th

Last Answer : There are two parallel chords of length 8 cm and 6 cm. The distance between center and shortest chord (6cm chord) is 4cm. So, the perpendicular distance from the center to the shortest chord is 4cm. The ... 32+42 =5. Since the radius is 5. The distance from center to largest chord is 52−42 =3.

The lengths of the sides of a triangle are 7 cm, 13 cm and 12 cm. -Maths 9th

Description : The lengths of the sides of a triangle are 7 cm, 13 cm and 12 cm. -Maths 9th

Last Answer : Let, a = 7 cm, b = 13 cm, c = 12 cm ∴ s = (a + b + c)/2 = (7 +13 +12)/2 = 32/2 = 16 cm Area of △ ABC = under root( √s(s -a) (s - b)(s -c)) = under root( √16(16 - 7)(16 - 13)(16 - 12) = ... 24 √3 cm2 Also, Area of △ ABC = 1/2AC.BD 24 √3 = 1/2 x 12 x BD ⇒ BD = (24 √3 x 2)/12 = 4 √3 cm

The lengths of two adjacent sides of a parallelogram are 17 cm and 12 cm. -Maths 9th

Description : The lengths of two adjacent sides of a parallelogram are 17 cm and 12 cm. -Maths 9th

Last Answer : For △BCD: Let a = 17 cm, b = 12 cm, c = 25 cm So its semi-perimeter, s = (a + b + c)/2 = (17 + 12 + 25)/2 = 27 cm ∴ Area of △BCD = root under(√(s -a)(s - b)(s - c)) = ... △BCD = 2 x 90 = 180 cm2 Also, area of parallelogram ABCD = DC x AE ∴ 180 = 12 x AE ⇒ AE = 180/12 = 15 cm

If the length of hypotenuse of a right angled triangle is 5 cm and its area is 6 sq cm, then what are the lengths of the remaining sides? -Maths 9th

Description : If the length of hypotenuse of a right angled triangle is 5 cm and its area is 6 sq cm, then what are the lengths of the remaining sides? -Maths 9th

Last Answer : Let one of the remaining sides be x cm.Then, other side = \(\sqrt{5^2-x^2}\) cm∴ Area = \(rac{1}{2} imes{x} imes\sqrt{25-x^2}\) = 6⇒ \(x\sqrt{25-x^2}\) = 12 ⇒ x2(25 - x2) = 144⇒ 25x2 - x4 = 144 ⇒ x4 - 25x2 ... (x2 - 16) (x2 - 9) = 0 ⇒ x2 = 16 or x2 = 9 ⇒ x = 4 or 3∴ The two sides are 4 cm and 3 cm.

The lengths of the perpendiculars drawn from any point in the interior of an equilateral -Maths 9th

Description : The lengths of the perpendiculars drawn from any point in the interior of an equilateral -Maths 9th

Last Answer : (a) \(rac{2}{\sqrt3}\) (p1 + p2 + p3) Let each side of equilateral ΔPQR = a units. O is any point in the interior of DΔPQR ⇒ OD = p1, OE = p2 and OF = p3 are perpendiculars on sides PQ, PR and QR respectively. ∴ Area of ... }{4}a^2\) = \(rac{a}{2}(p_1+p_2+p_3)\) ⇒ \(rac{2}{\sqrt3}\) (p1 + p2 + p3)

What is the radius of a circle inscribed in a triangle having side lengths 35 cm, 44 cm and 75 cm? -Maths 9th

Description : What is the radius of a circle inscribed in a triangle having side lengths 35 cm, 44 cm and 75 cm? -Maths 9th

Last Answer : (d) 6 cmLet a = 35 cm, b = 44 cm, c = 75 cm. Thens = \(rac{a+b+c}{2}\) = \(rac{34+44+75}{2}\) cm = 77 cm∴ Area if triangle = \(\sqrt{77(77-35)(77-44)(77-75)}\) cm2= \(\sqrt{77 imes42 ... ) cm2 = 462 cm2∴ Radius of incircle = \(rac{ ext{Area}}{ ext{semi-perimeter}}\) = \(rac{462}{77}\) cm = 6 cm.

If the lengths of a sides of a triangle are in the ratio 4 : 5 : 6 and the in-radius of the triangle is 3 cm, -Maths 9th

Description : If the lengths of a sides of a triangle are in the ratio 4 : 5 : 6 and the in-radius of the triangle is 3 cm, -Maths 9th

Last Answer : (b) 7.5 cm.Area of a triangle = \(rac{1}{2}\)x base x height= In-radius x semi-perimeter of the Δ \(\big[ ext{Using r =}rac{\Delta}{s}\big]\)Let the sides of triangle be 4x, 5x and 6x respectively. Given: In-radius = 3 ... x \(rac{15x}{2}\) = \(rac{6x}{2}\) x h ⇒ h = \(rac{45}{6}\) = 7.5 cm.

The base of a right prism is a trapezium. The lengths of the parallel sides are 8 cm and 14 cm and the distance between the parallel -Maths 9th

Description : The base of a right prism is a trapezium. The lengths of the parallel sides are 8 cm and 14 cm and the distance between the parallel -Maths 9th

Last Answer : Area of trapezium =12×h(AB+CD) =12×8×(8+14)=12×8×(8+14) =4×22=88cm2=4×22=88cm2 = Volume of prism = Height of prism ×× area of base ⇒height×88=1056 (given)⇒height×88=1056 (given) ⇒height×88=105688⇒height×88=105688 ⇒12cm =12×h(AB+CD)

Let a, b, c be the lengths of the sides of a right angled triangle, the hypotenuse having the length c, then a + b is -Maths 9th

Description : Let a, b, c be the lengths of the sides of a right angled triangle, the hypotenuse having the length c, then a + b is -Maths 9th

Last Answer : answer:

If a, b, c are the lengths of the sides of a non-equilateral triangle, then -Maths 9th

Description : If a, b, c are the lengths of the sides of a non-equilateral triangle, then -Maths 9th

Last Answer : https://discuss.aiforkids.in/36748/if-are-the-lengths-of-the-sides-non-equilateral-triangle-then

In an equilateral triangle if a, b and c denote the lengths of the perpendicular from A, B and C respectively on the opposite sides, then -Maths 9th

Description : In an equilateral triangle if a, b and c denote the lengths of the perpendicular from A, B and C respectively on the opposite sides, then -Maths 9th

Last Answer : b=2c=3​⇒⇒b=3​c=23​​cosA=2bcb2+c2−a2​⇒23​​=33+43​−a2​⇒233​​=415​−a2 ⇒a2=415​−43​​⇒a=1.673278 We know sinaa​=2R1​⇒R=2asina​=221​​=41​

The lengths of the sides a, b, c of a ΔABC are connected by the relation a^2 + b^2 = 5c^2. The angle between medians drawn to the sides 'a' and 'b' is -Maths 9th

Description : The lengths of the sides a, b, c of a ΔABC are connected by the relation a^2 + b^2 = 5c^2. The angle between medians drawn to the sides 'a' and 'b' is -Maths 9th

Last Answer : Let median through C be CF. AF=FB=c2 CF=122(a2+b2)−c2−−−−−−−−−−−−√=3c2 CG=c where G is the centroid and GF=c2 34( ... +M2b+9c24 c2=(23M2a)+(23M2b) BC2=AG2+BG2 So medians through A and B are perpendicular.