Is 0.05 mg more than 0.025 mg?

Is 0.05 mg more than 0.025 mg?
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1 Answer

Answer :

Yes it is twice as much
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How strong is a 0.05 mg Xanax?

Description : How strong is a 0.05 mg Xanax?

Last Answer : Need answer

Safe and adequate daily dietary intake of chromium in adults in mg is (A) 0.01–0.02 (B) 0.02–0.03 (C) 0.03–0.04 (D) 0.05–0.2

Description : Safe and adequate daily dietary intake of chromium in adults in mg is (A) 0.01–0.02 (B) 0.02–0.03 (C) 0.03–0.04 (D) 0.05–0.2

Last Answer : Answer : D

Maximum permissible concentration of copper in drinking water in mg/L, is – (1) 0.01 (2) 0.05 (3) 1.0 (4) 2.0

Description : Maximum permissible concentration of copper in drinking water in mg/L, is – (1) 0.01 (2) 0.05 (3) 1.0 (4) 2.0

Last Answer : (3) 1.0 Explanation: The 1959 WHO International Standards for Drinking Water suggested that concentrations of copper greater than 1.5 mg/litre would markedly impair the potability of the water. However, ... 1.0 mg/litre was established for copper, based on its laundry and other staining properties.

Maximum permissible concentration of copper in drinking water in mg/L is - (1) 0.01 (2) 0.05 (3) 1.0 (4) 2.0

Description : Maximum permissible concentration of copper in drinking water in mg/L is - (1) 0.01 (2) 0.05 (3) 1.0 (4) 2.0

Last Answer : (3) 1.0 Explanation: In the first edition of the Guidelines for Drinking Water Quality, published in 1984, a guideline value of 1.0 mg/litre was established for copper, based on its laundry and other staining properties.

Maximum permissible concentration of copper in drinking water in mg/L is (1) 0.01 (2) 0.05 (3) 1.0 (4) 2.0

Description : Maximum permissible concentration of copper in drinking water in mg/L is (1) 0.01 (2) 0.05 (3) 1.0 (4) 2.0

Last Answer : 1.0

What is 0.025 million in number form?

Description : What is 0.025 million in number form?

Last Answer : 25000

How much cents does 0.025 represent?

Description : How much cents does 0.025 represent?

Last Answer : $0.025 = 2.5 cents $0.25 = 25 cents

An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol?

Description : An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol?

Last Answer : An adult human lung has a volume of 2.9 liters. If its volume decreases to 1.2 liters and it contains 0.049 mole of air after it exhales, how many moles of air does it contain when full? A. 0.025 mol B. 0.041 mol C. 0.083 mol D. 0.12 mol E. 0.14 mol

One international unit (I.U) of vitamin D is defined as the biological activity of (A) 0.025 µg of cholecalciferol (B) 0.025 µg of 7-dehydrocholecalciferol (C) 0.025 µg of ergosterol (D) 0.025 µg of ergocalciferol VITAMINS 113

Description : One international unit (I.U) of vitamin D is defined as the biological activity of (A) 0.025 µg of cholecalciferol (B) 0.025 µg of 7-dehydrocholecalciferol (C) 0.025 µg of ergosterol (D) 0.025 µg of ergocalciferol VITAMINS 113

Last Answer : Answer : A

For the open drain (N = 0.025) shown in the below figure, the discharge is A. 26.88 cumecs B. 27.88 cumecs C. 28.88 cumecs D. 29.88 cumecs

Description : For the open drain (N = 0.025) shown in the below figure, the discharge is A. 26.88 cumecs B. 27.88 cumecs C. 28.88 cumecs D. 29.88 cumecs

Last Answer : ANS: C

Determine the lower half-power frequency of a class-C amplifier having upper half-power frequency of 10.025 MHz, a resonant frequency 5 MHz and a circuit Q of 10. A. 1.0025 MHz B. 10.525 MHz C. 0.5 MHz D. 10 MHz

Description : Determine the lower half-power frequency of a class-C amplifier having upper half-power frequency of 10.025 MHz, a resonant frequency 5 MHz and a circuit Q of 10. A. 1.0025 MHz B. 10.525 MHz C. 0.5 MHz D. 10 MHz

Last Answer : A. 1.0025 MHz

The velocity of thermal (slow) neutrons triggering nuclear fissionreaction (having energy equal to 0.025 eV) is about __________metres/second.(A) 1100(B) 2200(C) 3300(D) 4400

Description : The velocity of thermal (slow) neutrons triggering nuclear fissionreaction (having energy equal to 0.025 eV) is about __________ metres/second. (A) 1100 (B) 2200 (C) 3300 (D) 4400

Last Answer : (B) 2200

Velocity of the thermal neutron (< 0.025 eV) used for fission of U-235 is around __________ m/sec. (A) 1 (B) 2200 (C) 3 × 10 11 (D) 9 × 10 21

Description : Velocity of the thermal neutron (< 0.025 eV) used for fission of U-235 is around __________ m/sec. (A) 1 (B) 2200 (C) 3 × 10 11 (D) 9 × 10 21

Last Answer : (B) 2200

Thermal neutrons which are used to cause the fission of U-235 haveenergy __________ eV.(A) < 0.025(B) > 1(C) 1-25(D) > 200

Description : Thermal neutrons which are used to cause the fission of U-235 haveenergy __________ eV. (A) < 0.025 (B) > 1 (C) 1-25 (D) > 200

Last Answer : (A) < 0.025

A metal wire of 0.01 m dia and thermal conductivity 200 W/m.K is exposed to a fluid stream with a convective heat transfer coefficient of 100 W/m2 .K. The Biot number is (A) 5.6 (B) 0.025 (C) 3.5 (D) 0.0035

Description : A metal wire of 0.01 m dia and thermal conductivity 200 W/m.K is exposed to a fluid stream with a convective heat transfer coefficient of 100 W/m2 .K. The Biot number is (A) 5.6 (B) 0.025 (C) 3.5 (D) 0.0035

Last Answer : (B) 0.025

The density of Air is-------? A. 0.225 kg/m3 B. 1.025 kg/m3 C. 1.225 kg/m3 (Answer) D. 1.425 kg/m3

Description : The density of Air is-------? A. 0.225 kg/m3 B. 1.025 kg/m3 C. 1.225 kg/m3 (Answer) D. 1.425 kg/m3

Last Answer : C. 1.225 kg/m3 (Answer)

Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Description : Evaluate: (0.625 × 0.0729 × 28.9)/(0.0081 × 0.025 × 1.7) a) 382.5 b) 3725 c) 3625 d) 3825 e) None of these

Last Answer : (0.625×0.0729×28.9) / (0.0081×0.025×1.7) = (625/25) × (729/81) × (289/17) = 25×9× 17 = 3825. Answer: d)

The electric force between two charges placed in air is 2 Newton. When placed in a medium of ∈r = 80, the force reduced to: (a) 0.029 N (b) 0.025 N (c) 0.03 N (d) 0.04 N

Description : The electric force between two charges placed in air is 2 Newton. When placed in a medium of ∈r = 80, the force reduced to: (a) 0.029 N (b) 0.025 N (c) 0.03 N (d) 0.04 N

Last Answer : (b) 0.025 N

In 0.025 W, there are?

Description : In 0.025 W, there are? A.25 kW B.0.00025 mW C.2,500 μW D.25 mW

Last Answer : In 0.025 W, there are? A.25 kW B.0.00025 mW C.2,500 μW D.25 mW

When the nurse notes that the post cardiac surgery patient demonstrates low urine output (< 25 ml/hr) with high specific gravity (> 1.025), the nurse suspects: a) Inadequate fluid volume Urine output of less than 25 ml/hr may indicate a decrease in cardiac output. A high specific gravity indicates increased concentration of solutes in the urine which occurs with inadequate fluid volume. b) Normal glomerular filtration Indices of normal glomerular filtration are output of 25 ml or greater per hour and specific gravity between 1.010 and 1.025. c) Overhydration Overhydration is manifested by high urine output with low specific gravity. d) Anuria The anuric patient does not produce urine.

Description : When the nurse notes that the post cardiac surgery patient demonstrates low urine output (< 25 ml/hr) with high specific gravity (> 1.025), the nurse suspects: a) Inadequate fluid volume Urine ... by high urine output with low specific gravity. d) Anuria The anuric patient does not produce urine.

Last Answer : a) Inadequate fluid volume Urine output of less than 25 ml/hr may indicate a decrease in cardiac output. A high specific gravity indicates increased concentration of solutes in the urine which occurs with inadequate fluid volume.

what is 3.025 in expanded form?

Description : what is 3.025 in expanded form?

Last Answer : 3000+20+5

How do you write 37.025 in words forms?

Description : How do you write 37.025 in words forms?

Last Answer : Thirty Seven and Twenty-Five Thousandths.

How do you do 8.025 as a mixed number in simplest form?

Description : How do you do 8.025 as a mixed number in simplest form?

Last Answer : Need answer

Normal specific gravity of urine is (A) 1.000–1.010 (B) 1.012–1.024 (C) 1.025–1.034 (D) 1.035–1.045

Description : Normal specific gravity of urine is (A) 1.000–1.010 (B) 1.012–1.024 (C) 1.025–1.034 (D) 1.035–1.045

Last Answer : B

Assume a frequency range of 405.0125 MHz to 405.0875 MHz and 25 kHz channeling plan, determine the center frequency of the second channel from the lower limit. A. 405.030 MHz B. 405.025 MHz C. 405.050 MHz D. 405.075 MHz

Description : Assume a frequency range of 405.0125 MHz to 405.0875 MHz and 25 kHz channeling plan, determine the center frequency of the second channel from the lower limit. A. 405.030 MHz B. 405.025 MHz C. 405.050 MHz D. 405.075 MHz

Last Answer : C. 405.050 MHz

Assume a frequency range of 401.000 MHz to 401.050 MHz, if you apply 25 kHz channeling plan, determine the center frequency of the first channel from the lower limit. A. 401.010 MHz B. 401.0125 MHz C. 401.025 MHz D. 401.00625 MHz

Description : Assume a frequency range of 401.000 MHz to 401.050 MHz, if you apply 25 kHz channeling plan, determine the center frequency of the first channel from the lower limit. A. 401.010 MHz B. 401.0125 MHz C. 401.025 MHz D. 401.00625 MHz

Last Answer : B. 401.0125 MHz

When fluid intake is normal, the specific gravity of urine should be a) 1.010-1.025. Urine specific gravity is a measurement of the kidney’s ability to concentrate urine.

Description : When fluid intake is normal, the specific gravity of urine should be a) 1.010-1.025. Urine specific gravity is a measurement of the kidney's ability to concentrate urine. b) 1.000. The ... intake. d) greater than 1.025. A urine specific gravity greater than 1.025 may indicate overhydration.

Last Answer : a) 1.010-1.025. Urine specific gravity is a measurement of the kidney’s ability to concentrate urine.

Torque and bending moment of 100 kN.m and 200 kN.m acts on a shaft which has external diameter twice of internal diameter. What is the external diameter of the shaft which is subjected to a maximum shear stress of 90 N/mm2? a. 116.5 mm b. 233.025 mm c. 587.1 mm d. 900 mm

Description : Torque and bending moment of 100 kN.m and 200 kN.m acts on a shaft which has external diameter twice of internal diameter. What is the external diameter of the shaft which is subjected to a maximum shear stress of 90 N/mm2? a. 116.5 mm b. 233.025 mm c. 587.1 mm d. 900 mm

Last Answer : c. 587.1 mm

A patient of iron deficiency anaemia has been put on iron therapy. What should be the rate of rise in haemoglobin level of blood so that response is considered adequate: A. 0.05 – 0.1 g% per week B. 0.1 – 0.2 g% per week C. 0.5 – 1.0 g% per week D. More than 1.0 g% per week

Description : A patient of iron deficiency anaemia has been put on iron therapy. What should be the rate of rise in haemoglobin level of blood so that response is considered adequate: A. 0.05 – 0.1 g% per week B. 0.1 – 0.2 g% per week C. 0.5 – 1.0 g% per week D. More than 1.0 g% per week

Last Answer : C. 0.5 – 1.0 g% per week

Is 0.05 greater than 0.82?

Description : Is 0.05 greater than 0.82?

Last Answer : No because 0.82 is greater than 0.05

Is 0.05 greater than 0.083?

Description : Is 0.05 greater than 0.083?

Last Answer : No, it is not.

Is 0.05 greater than 0.5?

Description : Is 0.05 greater than 0.5?

Last Answer : No because its only 5 and 0.5 is 50

Hazen’s formula VS = 418 (GS – Gw)d [(3T + 70)/100] is used for the settlement velocity of the particles of diameter A. Less than 0.01 mm B. Less than 0.05 mm C. Less than 0.1 mm D. Greater than 0.1 mm

Description : Hazen’s formula VS = 418 (GS – Gw)d [(3T + 70)/100] is used for the settlement velocity of the particles of diameter A. Less than 0.01 mm B. Less than 0.05 mm C. Less than 0.1 mm D. Greater than 0.1 mm

Last Answer : ANS: D

Always perform A/B Testing if there is probability to beat the original variation by? A. 0.05 B. less than 5% C. greater than 5% D. greater than equal to 5%

Description : Always perform A/B Testing if there is probability to beat the original variation by? A. 0.05 B. less than 5% C. greater than 5% D. greater than equal to 5%

Last Answer : C. greater than 5%

The area of side face reinforcement shall not be less than [ A ] 0.10 percent of the web area on each vertical face [ B ] 0.05 percent of the web area on each vertical face [ C ] 0.15 percent of the web area on each vertical face [ D ] 0.20 percent of the web area

Description : The area of side face reinforcement shall not be less than [ A ] 0.10 percent of the web area on each vertical face [ B ] 0.05 percent of the web area on each vertical face [ C ] 0.15 percent of the web area on each vertical face [ D ] 0.20 percent of the web area

Last Answer : [ B ] 0.05 percent of the web area on each vertical face

A hammer gains 50 Ns momentum in 0.05 sec. The average force on the hammer will be a.500 N b.2000 N c.1500 N d.107 dynes e.1000 N

Description : A hammer gains 50 Ns momentum in 0.05 sec. The average force on the hammer will be a.500 N b.2000 N c.1500 N d.107 dynes e.1000 N

Last Answer : e. 1000 N

The maximum efficiency of a scres jack having square threads and friction angle of 30 degree will be a.0.2 b.0.11 c.0.05 d.0.33 e.0.09

Description : The maximum efficiency of a scres jack having square threads and friction angle of 30 degree will be a.0.2 b.0.11 c.0.05 d.0.33 e.0.09

Last Answer : d. 0.33

The moment of inertia of a semi-circle of radius r with respect to a centroidal axis parallel to the diameter is a.0.33 r2 b.0.11 r2 c.0.055 r2 d.0.05 r2 e.0.22 r2

Description : The moment of inertia of a semi-circle of radius r with respect to a centroidal axis parallel to the diameter is a.0.33 r2 b.0.11 r2 c.0.055 r2 d.0.05 r2 e.0.22 r2

Last Answer : b. 0.11 r2

Antazol 0.05 (Antazol 0.05) What are the functions of nasal drops ?

Description : Antazol 0.05 (Antazol 0.05) What are the functions of nasal drops ?

Last Answer : Used to relieve nasal congestion , nasal congestion , year-round allergic rhinitis , sinusitis.

India plays two matches each with West Indies and Australia. In any match the probabilities of India getting points `0, 1 and 2` are `0.45, 0.05 and 0

Description : India plays two matches each with West Indies and Australia. In any match the probabilities of India getting points `0, 1 and 2` are `0.45, 0.05 and 0

Last Answer : India plays two matches each with West Indies and Australia. In any match the probabilities of India getting points ` ... B. 0.0875 C. 0.0625 D. 0.025

In the reaction `N_(2(g))+O_(2(g))rArr2NO_((g))`at equilibrium the concentrations of `N_(2),O_(2)andNO` are 0.25 , 0.05 and 1 M respectively . Calcula

Description : In the reaction `N_(2(g))+O_(2(g))rArr2NO_((g))`at equilibrium the concentrations of `N_(2),O_(2)andNO` are 0.25 , 0.05 and 1 M respectively . Calcula

Last Answer : In the reaction `N_(2(g))+O_(2(g))rArr2NO_((g))`at equilibrium the concentrations of `N_(2),O_(2)andNO` are 0.25 ... .75 M , 0.55 M D. 0.75 M , 0.45 M

The quantity of electricity requried to reduce 0.05 mol of `MnO_(4)^(-)` to `Mn^(2+)` in acidic medium would be

Description : The quantity of electricity requried to reduce 0.05 mol of `MnO_(4)^(-)` to `Mn^(2+)` in acidic medium would be

Last Answer : The quantity of electricity requried to reduce 0.05 mol of `MnO_(4)^(-)` to `Mn^(2+)` in acidic medium would be A. ... F B. 0.05 F C. 0.15 F D. 0.25 F

What volume of 0.05 M `Ca(OH)_(2)` solution is needed for complete conversion of 10mL of 0.1 M `H_(3)PO_(4)` into `Ca(H_(2)PO_(4))_(2)` ?

Description : What volume of 0.05 M `Ca(OH)_(2)` solution is needed for complete conversion of 10mL of 0.1 M `H_(3)PO_(4)` into `Ca(H_(2)PO_(4))_(2)` ?

Last Answer : What volume of 0.05 M `Ca(OH)_(2)` solution is needed for complete conversion of 10mL of 0.1 M `H_(3)PO_(4)` into `Ca(H_(2)PO_(4))_(2)` ?

A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified

Description : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for titration. The resulting solution is then acidified

Last Answer : A mixture containing `As_(2)O_(3)` and `As_(2)O_(5)` required 20 mL of 0.05 N iodine solution for ... +2H_(2)O " " `(Atomic weight : As = 75)

An alectron in a circular orbit of radius 0.05 mn performs `10^(16) "rev"//s.` the magnetic moment due to this ratation of electron is `(in A-m^(2)).`

Description : An alectron in a circular orbit of radius 0.05 mn performs `10^(16) "rev"//s.` the magnetic moment due to this ratation of electron is `(in A-m^(2)).`

Last Answer : An alectron in a circular orbit of radius 0.05 mn performs `10^(16) "rev"//s.` the magnetic moment due to ... `3.21xx10^(-24)` D. `1.26xx10^(-23)`

A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it ent

Description : A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it ent

Last Answer : A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. ... `0.209 m` C. `2.82 m` D. `2.41 m`

What decimal is largest 0.5 0.15 0.05?

Description : What decimal is largest 0.5 0.15 0.05?

Last Answer : 0.5 is the largest decimal

What is the value for G at 5000 k if H-220 KJmol and S-0.05 KJ (molK)?

Description : What is the value for G at 5000 k if H-220 KJmol and S-0.05 KJ (molK)?

Last Answer : 30 kj

What is 0.05 times 0.05?

Description : What is 0.05 times 0.05?

Last Answer : Need answer

What is 400 billion times 0.05?

Description : What is 400 billion times 0.05?

Last Answer : 20 billion.