What shapes has 0 vertices and 2 flat surfaces?

Description : What is he required surface finish for raised or flat faced gasket surfaces? a) 63 µ in. b) 125 µ in-250 µ in. c) 250 µ in-400 µ in. d) 400-500 µ in.

Last Answer : b) 125 µ in-250 µ in.

Two perspective views of the same solid object are shown below. How many surfaces does the object contain? Assume hidden surfaces to be flat.

Description : Two perspective views of the same solid object are shown below. How many surfaces does the object contain? Assume hidden surfaces to be flat.

Last Answer : 18

Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Description : Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Last Answer : The graph obtained by plotting the points A, B and C and D is given below. Take a point C on the graph such that ABCD is a square i.e., all sides AB, BC, CD, and AD are equal. So, abscissa of C should be ... of C should be equal to ordinate of D i.e., -4. Hence, the coordinates of C are (-2, - 4).

Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Description : Points A(5, 3), B(-2, 3) and 0(5, – 4) are three vertices of a square ABCD. -Maths 9th

Last Answer : The graph obtained by plotting the points A, B and C and D is given below. Take a point C on the graph such that ABCD is a square i.e., all sides AB, BC, CD, and AD are equal. So, abscissa of C should be ... of C should be equal to ordinate of D i.e., -4. Hence, the coordinates of C are (-2, - 4).

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : NEED ANSWER

A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Description : A(5,0) and B(0,8) are two vertices of triangle OAB. a). What is the equation of the bisector of angle OAB. b). If E is the point of intersection of this bisector and the line through A and B,find the coordinates of E. Hence show that OA:OB = AE:EB -Maths 9th

Last Answer : This answer was deleted by our moderators...

Find the co-ordinates of the circumcentre of the triangle whose vertices are (3, 0), (–1, –6) and (4, –1). Also find its circum-radius. -Maths 9th

Description : Find the co-ordinates of the circumcentre of the triangle whose vertices are (3, 0), (–1, –6) and (4, –1). Also find its circum-radius. -Maths 9th

Last Answer : Let A ≡ (2, - 2), B ≡ (-2, 1), C ≡ (5, 2 ). Then,AB = \(\sqrt{(-2-2)^2+(1+2)^2}\) = \(\sqrt{16+9}\) = \(\sqrt{25}\) = 5BC = \(\sqrt{(5+2)^2+(2-1)^2}\) = \(\sqrt{49+1}\) = \(\sqrt{50}\) = \( ... of ΔABC = \(rac{1}{2}\) x base x height = \(rac{1}{2}\) x AB x AC = \(rac{1}{2}\)x 5 x 5 = 12.5 sq. units.

Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Description : Find the co-ordinates of the in-centre of the triangle whose vertices are (–36, 7), (20, 7) and (0, –8). -Maths 9th

Last Answer : Let A(1, 2), B(0, -1) and C(2, -1) be the mid-points of the sides PQ, QR and RP of the triangle PQR. Let the co-ordinates of P, Q and R be (x1, y1), (x2, y2) and (x3 , y3) respectively. Then, by the mid- ... ordinates of centroid of ΔPQR = \(\bigg(rac{3+(-1)+1}{3},rac{2+2+(-4)}{3}\bigg)\) = (1, 0).

Find the area of the quadrilateral whose vertices are (3, 4), (0, 5), (2, –1) and (3, –2). -Maths 9th

Description : Find the area of the quadrilateral whose vertices are (3, 4), (0, 5), (2, –1) and (3, –2). -Maths 9th

Last Answer : Let A(-36, 7), B(20, 7) and C(0, -8) be the vertices of the given triangle.Then, a = BC = \(\sqrt{(0-20)^2+(-8-7)^2}\) = \(\sqrt{400+225}\) = \(\sqrt{625}\) = 25b = AC =\(\sqrt{(0-36)^2+(-8-7 ... (rac{-900+780}{120},rac{175+273-448}{120}\bigg)\) = \(\bigg(rac{-120}{120},rac{0}{120}\bigg)\) = (-1, 0)

Without using Pythagoras’ theorem, show that the points A (0, 4), B(1, 2) and C(3, 3) are the vertices of a right angle triangle. -Maths 9th

Description : Without using Pythagoras’ theorem, show that the points A (0, 4), B(1, 2) and C(3, 3) are the vertices of a right angle triangle. -Maths 9th

Last Answer : Slope (m) = \(rac{(y_2-y_1)}{(x_2-x_1)}\) = \(rac{6-2}{5-1}\) = \(rac{4}{4}\) = 1Also slope (m) = tan θ, where θ is the inclination of the line to the positive direction of the x-axis in the anticlockwise direction. tan θ = 1 ⇒ θ = tan –11 = 45º.

What is the perimeter of the triangle with the vertices A(–4, 2), B(0, –1) and C(3, 3) ? -Maths 9th

Description : What is the perimeter of the triangle with the vertices A(–4, 2), B(0, –1) and C(3, 3) ? -Maths 9th

Last Answer : The two given lines are ax + by + c1 = 0 and ax + by + c2 = 0. Any line parallel to these two lines and midway between them is ax + by + c = 0 ...(i) Putting x = 0, y = \(-rac{c}{b}\) is ... c1 = c - c2 ⇒ c = \(rac{c_1+c_2}{2}\)∴ Required equation is ax + by + \(rac{c_1+c_2}{2}\) = 0.

(0, –1) and (0, 3) are the two opposite vertices of a square. The other two vertices are: -Maths 9th

Description : (0, –1) and (0, 3) are the two opposite vertices of a square. The other two vertices are: -Maths 9th

Last Answer : (c) (15, 19)Let Δ(a, b) be the fourth vertex of the parallelogram ABCD. The diagonals of a parallelogram bisect each other at point O (say), so the diagonals AC and BD have the same mid-point.

If (0, 0) and (2, 0) are the two vertices of a triangle whose centroid is (1, 1), then the area of the triangle is: -Maths 9th

Description : If (0, 0) and (2, 0) are the two vertices of a triangle whose centroid is (1, 1), then the area of the triangle is: -Maths 9th

Last Answer : (b) \(\bigg(rac{2\sqrt{13}+20\sqrt2}{\sqrt{13}+\sqrt{17}+5\sqrt2},rac{8\sqrt{13}-6\sqrt{17}}{\sqrt{13}+\sqrt{17}+5\sqrt2}\bigg)\)Let A(x1, y1), B(x2, y2), C(x3, y3) be the vertices of ΔABC the ... +6)^2}\) = \(\sqrt{4+196}\) = \(\sqrt{200}=10\sqrt{2}\)∴ Co-ordinates of incentre of Δ ABC are

The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C(a, 0) are mutually perpendicular if -Maths 9th

Description : The medians AD and BE of the triangle with vertices A(0, b), B(0, 0) and C(a, 0) are mutually perpendicular if -Maths 9th

Last Answer : (c) \(rac{b+k}{f+h}\)Let the slope of the lin passing through the points (-k, h) and (b, - f) be m1. Then m1 = \(rac{-f-h}{b+k}\) = \(-\bigg(rac{f+h}{b+k}\bigg)\)\(\bigg[Slope = rac{y_2-y_1}{x_2-x_1}\bigg]\) ... \(-rac{1}{m_1}\)= \(rac{-1}{-\big(rac{f+h}{b+k}\big)}\) = \(\bigg(rac{b+k}{f+h}\bigg)\)

The point A(0, 0), B(1, 7) and C(5, 1) are the vertices of a triangle. Find the length of the perpendicular from -Maths 9th

Description : The point A(0, 0), B(1, 7) and C(5, 1) are the vertices of a triangle. Find the length of the perpendicular from -Maths 9th

Last Answer : (b) 3x - y = 0 Given lines are 3x - y - 3 = 0 and 3x - y + 5 = 0. Line parallel to the given lines can be written as 3x - y + c = 0 ...(i) Let us taken a point, say ... 5c + 15 = - 3c + 15 ⇒ 8c = 0 ⇒ c = 0. Substituting c = 0 in (i), the required equation is 3x - y = 0.

The orthocentre of a triangle whose vertices are (0, 0), (3, 0) and (0, 4) is -Maths 9th

Description : The orthocentre of a triangle whose vertices are (0, 0), (3, 0) and (0, 4) is -Maths 9th

Last Answer : (c) 60ºSince p is the length of perpendicular from origin on the straight line ax + by - p = 0.p = \(rac{|a.0+b.0-p|}{\sqrt{a^2+b^2}}\)⇒ 1 = \(\sqrt{a^2+b^2}\) ⇒ 1 ... 60° + y sin 60° = p Hence required angle is 60°, which is the angle between the perpendicular and the positive direction of x-axis.

If A (-2, 4), B (0, 0) and C (4, 2) are the vertices of triangle ABC, then find the length of the median through the vertex A. -Maths 9th

Description : If A (-2, 4), B (0, 0) and C (4, 2) are the vertices of triangle ABC, then find the length of the median through the vertex A. -Maths 9th

Last Answer : D=slid ht of BC D≅(20+4,20+2) =(2,1) ∴ Length of median = Light of AD =root(−2−2)2+(4−1)2=root42+32=5 hope it helps thank u

Find the area of quadrilateral ABCD whose vertices are A (1, 0), B (5, 3), C (2, 7), D ( -2, 4) -Maths 9th

Description : Find the area of quadrilateral ABCD whose vertices are A (1, 0), B (5, 3), C (2, 7), D ( -2, 4) -Maths 9th

Last Answer : answer:

what- A triangle is formed by the intersection of the lines y = 0, y = -3x + 3, and y = 3x + 3.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

Description : what- A triangle is formed by the intersection of the lines y = 0, y = -3x + 3, and y = 3x + 3.Is the triangle equilateral, isosceles, or scalene Graph the lines on grid paper to find the vertices of the triangle?

Last Answer : isosceles

what- Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5), I at(-2, 2), and X at (4, -1), where x > 0.What is the value of x?

Description : what- Isosceles triangle SIX has congruent sides SI and IX and vertices S at (x, 5), I at(-2, 2), and X at (4, -1), where x > 0.What is the value of x?

Last Answer : 4

What shape has 0 vertices 2 edges 2 faces and 1 curved surface?

Description : What shape has 0 vertices 2 edges 2 faces and 1 curved surface?

Last Answer : Feel Free to Answer

The points (-2,-1),(a,0),(4,b),(1,2) are the vertices of a parallelogram taken in order , then the values of a and b are: (a) a = 1,b = 3 (b) a = 3 , b = 1 (c) a = 1 , b = 1 (d) a = 0 , b = 4

Description : The points (-2,-1),(a,0),(4,b),(1,2) are the vertices of a parallelogram taken in order , then the values of a and b are: (a) a = 1,b = 3 (b) a = 3 , b = 1 (c) a = 1 , b = 1 (d) a = 0 , b = 4

Last Answer : (a) a = 1,b = 3

The points A (9, 0), B (9, 6), C (–9, 6) and D (–9, 0) are the vertices of a: A(-3,-5) and(a)Square (b) Rhombus (c) Rectangle (d) Trapezium

Description : The points A (9, 0), B (9, 6), C (–9, 6) and D (–9, 0) are the vertices of a: A(-3,-5) and(a)Square (b) Rhombus (c) Rectangle (d) Trapezium

Last Answer : (c) Rectangle

The points (-4, 0), (4, 0), (0, 3) are the vertices of a: (а) Right triangle (b) Isosceles triangle (c) Equilateral triangle (d) Scalene triangle

Description : The points (-4, 0), (4, 0), (0, 3) are the vertices of a: (а) Right triangle (b) Isosceles triangle (c) Equilateral triangle (d) Scalene triangle

Last Answer : (b) Isosceles triangle

The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is: (a) 12 units (b) 11 units (c) 5units (d) (7 + √5)units

Description : The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is: (a) 12 units (b) 11 units (c) 5units (d) (7 + √5)units

Last Answer : (a) 12 units

The coordinates of the vertices of region bounded by lines 3x - y = 5; x+ 2y = 4 and Y-axis are: (a) A(2,0); B(5,0) and C(1,2) (b) A(2,0); B(-5,0) and C(1,2) (c) A(0,2); B(0,-5) and C(2,1) (d) A(0,2); B(0,5) and C(2,1)

Description : The coordinates of the vertices of region bounded by lines 3x - y = 5; x+ 2y = 4 and Y-axis are: (a) A(2,0); B(5,0) and C(1,2) (b) A(2,0); B(-5,0) and C(1,2) (c) A(0,2); B(0,-5) and C(2,1) (d) A(0,2); B(0,5) and C(2,1)

Last Answer : (c) A(0,2); B(0,-5) and C(2,1)

A structure is erected on an impervious clay whose thickness is 12 m. Drainage is possible both at upper and lower surfaces. Coefficient of consolidation is 0.015 cm2 per minute. For attaining 50% consolidation with a time factor 0.20, the number of days required (A) 3233 (B) 3123 (C) 33331 (D) 3313

Description : A structure is erected on an impervious clay whose thickness is 12 m. Drainage is possible both at upper and lower surfaces. Coefficient of consolidation is 0.015 cm2 per minute. For attaining 50% consolidation with a ... 20, the number of days required (A) 3233 (B) 3123 (C) 33331 (D) 3313

Last Answer : Answer: Option C

Different perspectives on how language shapes identity?

Description : Different perspectives on how language shapes identity?

Last Answer : answer:I haven't read the article, and I don't intend to. But just off the top of my head, I have the following thoughts: - from the point of the majority population - for example: in ... Boston English' and Chicago English' as specific subcultures. I can see lots of directions where this would go.

Are there any inkjet printers that can simultaneously perforate shapes into the paper?

Description : Are there any inkjet printers that can simultaneously perforate shapes into the paper?

Last Answer : This is a paper cutter for PC’s or Mac’s but it doesn’t print at the same time. Silhouette electronic cutting machines.

Life, is it being charmed, being cursed, or is it force of will, that shapes destiny?

Description : Life, is it being charmed, being cursed, or is it force of will, that shapes destiny?

Last Answer : I don’t believe in charms or curses, but I do believe in conjuncture and my own limited will, so I’ll take that.

What do you call the shapes our thoughts take?

Description : What do you call the shapes our thoughts take?

Last Answer : Don’t know the word for it ( not “senesthesia” ), but experience it quite often. I also discern “thoughts” at different levels, the lowest level being non-verbal. : )

Can you compute the ratio of shapes on a soccer ball?

Description : Can you compute the ratio of shapes on a soccer ball?

Last Answer : answer:I think the answer to your question is “no”. Just visualising a ball like that is making my visual cortex short-circuit. And then go on strike demanding better working conditions. Interesting question though.

What is it about arbitrary (shiny) geometric shapes that seem so appealing?

Description : What is it about arbitrary (shiny) geometric shapes that seem so appealing?

Last Answer : I don’t think they are arbitrary shapes. Apple designers execute everything with intention. The proportions of the original iPod, for example, are based on the golden ratio. That is probably one of the reasons why most people find the iPod aesthetically pleasing.

are used to express the geometry or shape of theelement a.Mode shapes b.Shape functions c.Natural curves d.None of the above

Description : are used to express the geometry or shape of theelement a.Mode shapes b.Shape functions c.Natural curves d.None of the above

Last Answer : b.Shape functions

In which type of projection, actual dimensions and angles of objects andtherefore shapes cannot be preserved? a.Orthographic b.Isometric c.Perspective d.None of the above

Description : In which type of projection, actual dimensions and angles of objects andtherefore shapes cannot be preserved? a.Orthographic b.Isometric c.Perspective d.None of the above

Last Answer : c.Perspective

I'm used for a lot of things, I'm used for flowers, plants, food and sometimes for decoration, I come in different colors and shapes and I break if you don't take care of me. What am I? -Riddles

Description : I'm used for a lot of things, I'm used for flowers, plants, food and sometimes for decoration, I come in different colors and shapes and I break if you don't take care of me. What am I? -Riddles

Last Answer : I’m glass.

I can hold you prisoner Or set you free I can swing with ease (Though not from a tree) I have many shapes I have many sizes Yet, ‘til we shake hands I’ll hide my surprises. What am I? -Riddles

Description : I can hold you prisoner Or set you free I can swing with ease (Though not from a tree) I have many shapes I have many sizes Yet, ‘til we shake hands I’ll hide my surprises. What am I? -Riddles

Last Answer : A door.

I am a piece of equipment that has hundreds of uses; I can even be used to save a life! I am not a medicine and I am non-electric. I come in all shapes and sizes. It doesn't require much specialist training to be used. What am I? -Riddles

Description : I am a piece of equipment that has hundreds of uses; I can even be used to save a life! I am not a medicine and I am non-electric. I come in all shapes and sizes. It doesn't require much specialist training to be used. What am I? -Riddles

Last Answer : A rope.

I have 2 hands for only one use. I come In many different shapes. What am I? -Riddles

Description : I have 2 hands for only one use. I come In many different shapes. What am I? -Riddles

Last Answer : A clock.

I always follow you around, everywhere you go at night. I look very bright to people, but I can make the sun dark. I can be in many different forms and shapes. What am I? -Riddles

Description : I always follow you around, everywhere you go at night. I look very bright to people, but I can make the sun dark. I can be in many different forms and shapes. What am I? -Riddles

Last Answer : The moon!

You need me to see me,I can be quite pretty;I come in different shades,But no shapes or sizes;What am I? -Riddles

Description : You need me to see me,I can be quite pretty;I come in different shades,But no shapes or sizes;What am I? -Riddles

Last Answer : An eye.

I come in different shapes and sizes. Part of me are curves, others are straight. You can put me anywhere you like, but there is only one right place for me. What am I? -Riddles

Description : I come in different shapes and sizes. Part of me are curves, others are straight. You can put me anywhere you like, but there is only one right place for me. What am I? -Riddles

Last Answer : A Jigsaw Puzzle Piece.

How can this be true? Have a look at the picture. All the lines are straight, the shapes that make up the top picture are the same as the ones in the bottom picture so where does the gap come from? -Riddles

Description : How can this be true? Have a look at the picture. All the lines are straight, the shapes that make up the top picture are the same as the ones in the bottom picture so where does the gap come from? -Riddles

Last Answer : The green triangle has dimensions 2 x 5 and gradient 2 / 5 = 0.4 The red triangle has dimensions 3 x 8 and gradient 3 / 8 = 0.375 Hence the gradient of the green triangle is greater than that of the red triangle.

What shapes has 0 vertices and 2 flat surfaces?

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