Description : PQ and RS are two equal and parallel line segments.Any points M not lying on PQ or RS is joined to Q and S and lines through P parallel to SM meet at N.Prove that line segments MN and PQ are equal and parallel to each other. -Maths 9th
Last Answer : hope its clear
Description : There are 3 poles M, N and O in a straight line such that point N is equidistant from points M and O. A boat can travel from point M to O downstream in 6 hours and from N to M upstream in 4 hours. Find the ratio of boat in still water to speed of stream. A) 2:3 B) 7:1 C) 3:2 D) 1:7
Last Answer : ANSWER: B Explanation: Let speed in still water = x km/hr, of current = y km/hr Downstream speed = (x+y) km/hr Upstream speed = (x - y) km/hr Let MO = 2p km. So MN = NO = p km. So 2p/(x+y) = 6 --------1 p/ ... - 2y) = 6x + 6y 8x - 8y = 6x +6y 2x = 14y x/y = 14 / 2 = 7/1 x : y = 7 :1
Description : l, m and n are three parallel lines intersected by transversals p and q such that l, m and n cut off equal intercepts AB and BC on p (see figure). -Maths 9th
Last Answer : Though E, draw a line parallel to p intersecting L at G and n at H respectively. Since l | | m ⇒ AG | | BE and AB | | GE [by construction] ∴ Opposite sides of quadrilateral AGEB are ... ∠DGE = ∠FHE [alternate interior angles] By ASA congruence axiom, we have △DEG ≅ △FEH Hence, DE = EF
Description : l,m and n are three parallel lines intersected by transversal p and q such that l,m and n cut-off equal intersepts AB and BC on p (Fig.8.55). Show that l,m and n cut - off equal intercepts DE and EF on q also. -Maths 9th
Last Answer : Given:l∥m∥n l,m and n cut off equal intercepts AB and BC on p So,AB=BC To prove:l,m and n cut off equal intercepts DE and EF on q i.e.,DE=EF Proof:In △ACF, B is the mid-point of ... a triangle, parallel to another side, bisects the third side. Since E is the mid-point of DF DE=EF Hence proved.
Description : what- in the figure, line p is a transversal to lines m and n.Which statement must be true?
Last Answer : lines m and n are parallel if x= 12 and y= 54
Description : Three pumps, M, N and O are opened to fill a tank such that M and N can fill the tank alone in 18 min. and 23 min. respectively and O can empty it in 15 min. After 3 minutes the emptying pipe is closed. In how many minutes the tank will be full in this way? A) 20 B) 25 C) 18 D) 12
Last Answer : D Let the tank full in x minutes, then M and N opened for x minutes and O for 3 minutes. (1/18 + 1/23)*x – (1/15)*3 = 1 (23+18/414)X=1+1/5 Solve, x = 12
Description : Three isometic compounds M,N and P `(C_(5)H_(10)O)` give the following tests (i) M and P react with sodium bisulfite to form an adduct J (ii) N Comsum
Last Answer : Three isometic compounds M,N and P `(C_(5)H_(10)O)` give the following tests (i) M and P react with ... M,N and P, respectively are A. B. C. D.
Description : A close-coiled helical spring of stiffness 30 N/mm is arranged in series with another such spring of stiffness 60 N/mm. The stiffness of composite unit is (a) 20 N/mm (b) 30 N/mm (c) 45 N/mm (d) 90 N/mm
Last Answer : (a) 20 N/mm
Description : P and O are points on opposite sides AD and BC of a parallelogram ABCD such that PQ passes through the point of intersection O of its diagonals AC and BD. -Maths 9th
Last Answer : According to question PQ passes through the point of intersection O of its diagonals AC and BD.
Description : If a point O lies between two points P and R such that PO=OR then prove that PO= 1/2PR. -Maths 9th
Last Answer : THINGS WHICH ARE COINCIDE WITH EACH OTHER ARE EQUAL TO ONE ANOTHER PO+OR=PR 2PO=PR PO=OR PO=1/2PR HENCE PROVED
Description : Buckingham-π theorem states that in any physical problem includingn' quantities having 'm' dimensions, the quantities can be arranged into __________ independent dimensionless parameters. (A) m (B) n (C) n-m (D) n/m
Last Answer : (C) n-m
Description : For an annual flood series arranged in descending order of magnitude, the return for a magnitude in a total is (A) N/(m + l) (B) m/(N + l) (C) m/N (D) (N + l)/m
Last Answer : Answer: Option D
Description : In the given figure, equal chords AB and CD of a circle with centre O cut at right angles at E. If M and N are the mid-points of AB and CD respectively, prove that OMEN is a square. -Maths 9th
Last Answer : Join OE. In ΔOME and ΔONE, OM =ON [equal chords are equidistant from the centre] ∠OME = ∠ONE = 90° OE =OE [common sides] ∠OME ≅ ∠ONE [by SAS congruency] ⇒ ME = NE [by CPCT] In quadrilateral OMEN, ... =ON , ME = NE and ∠OME = ∠ONE = ∠MEN = ∠MON = 90° Hence, OMEN is a square. Hence proved.
Description : Let O be any point inside a triangle ABC. Let L, M and N be the points on AB, BC and CA respectively, -Maths 9th
Last Answer : answer:
Description : Two circles with centre O and O' intersect at two points A and B. A line PQ is drawn parallel to OO' through B intersecting the circles at P and Q. Prove that PQ = 2 OO'. -Maths 9th
Last Answer : Solution :- Construction: Draw two circles having centres O and O' intersecting at points A and B. Draw a parallel line PQ to OO' ... iii) Again, OO' = MN [As OO' NM is a rectangle] ...(iv) ⇒ 2OO' = PQ Hence proved.
Description : The major macro- elements are C; H; O; N; S; P; K; Ca; Mg and Fe ganic food. Such plants are called?
Last Answer : Heterotrophic plants
Description : The operation of resection involves the following steps 1. Rough orientation of the plane table 2. The three lines form a triangle of error 3. Drawing lines back through the three control points 4. Select a point in the triangle of error ... 2, 3, 4, 5 (C) 1, 4, 3, 2, 5 (D) 1, 3, 2, 4, 5
Last Answer : (A) 1, 3, 2, 4, 5
Description : In Fig. 8.40, points M and N are taken on opposite sides AB and CD, respectively of a parallelogram ABCD such that AM = CN. Show that AC and MN bisect each other. -Maths 9th
Last Answer : Solution :-
Description : The Indian penal code 1860 extends to m) Whole India n) Whole India except Nagaland , tribal area & Jammu and Kashmir o) Whole India except Nagaland , tribal area p) Whole India except Jammu and Kashmir
Last Answer : Whole India except Jammu and Kashmir
Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less than O's lockers ... could be a) 52 or 53 only b) 53 or 54 only c) 54 or 55 only d) 53 or 55 only
Last Answer : c) 54 or 55 only
Description : Five persons M, N, O, P and Q request a bank for safety lockers. There are only 6 lockers available which are numbered from 52 to 57. The conditions are as follows: I. M's locker number is 2 less ... , then which locker number is not allocated? a) locker 52 b) locker 53 c) locker 54 d)locker 56
Last Answer : a) locker 52
Description : Curved twisted blades are specially suited for m. Minimum tillage of trashy land at shallow depths n. Dried hard soils o. Cutting and pulverisation in wet sticky clay soil p. For operating on the sides of plant bed
Last Answer : p. For operating on the sides of plant bed
Description : Cylinder loss in a stationary power thresher can be reduced by increasing the : M. Cylinder peCylinder loss in a stationary power thresher can be reduced by increasing the : M. Cylinder peripheral speed N. Concave clearance O. Blower speed P. All of the above
Last Answer : M. Cylinder peripheral speed
Description : Permissible creep in track is m. 50 mm n. 100 mm o. 125 mm p. 150 mm.*
Last Answer : p. 150 mm.*
Description : If A is coded as C, M as I, N as P, S as O, I as A, P as N, E as M, O as E and C as S, then the code of COMPANIES will be (A) SPEINMOAC (B) NCPSEIOMA (C) SMOPIEACH (D) SEINCPAMO
Last Answer : Answer: D
Description : The average weight of M,N and O is 168 kg. If P joins the group, the average weight of the group becomes 160 kg. If another man Q who weighs 6kg more than P replaces M, then the average of N,O,P and Qbecomes158 kg. What is the weight of M? A) 175 B) 140 C) 145 D) 150
Last Answer : D) M+N+O =168 * 3 =504 M+N+O+P=160*4=640……(1) P=136 kg and Q =142 kg N+O+P+Q =158*4 =632 N+O+P =632-142 =490…..(2) from 1 & 2, M=640-490 =150kg
Description : There are 18 points in a plane such that no three of them are in the same line except five points which are collinear. -Maths 9th
Description : Two lines l and m are perpendicular to the same line n.Are l and m perpendicular to each other ? -Maths 9th
Last Answer : Solution :- No, they are parallel.
Description : For new lines, width of formation in bank for N.G single line is (a) 3.35 m (b) 3.70 m* (c ) 5.25 m (e) 5.85 m
Last Answer : b) 3.70 m*
Description : For new lines, width of formation in cutting for N.G. single line is (a) 3.35 m* (b) 3.70 m (c) 5.25 m (d) 5.85 m
Last Answer : a) 3.35 m*
Description : In RSA public key cryptosystem suppose n=p*q where p and q are primes. (e,n) and (d,n) are public and private keys respectively. Let M be an integer such that 0
Last Answer : (2) I and III
Description : Pixels are: a) Points of light used by a cordless, wireless, optical mouse b) Dots of ink from inkjet printer c) Dots on the screen arranged in rows d) None of These
Last Answer : c) Dots on the screen arranged in rows
Description : Who says that social and economic inequalities are to be arranged in such a way that they are to be greatest advantage of the least advantaged? (a) Robert Nozik (b) Karl Marx (c) John Locke (d) John Rawls
Last Answer : (d) John Rawls
Description : In how many different ways can the letters of the word "POMADE" be arranged in such a way that the vowels occupy only the odd positions? a) 72 b) 144 c) 532 d) 36
Last Answer : Answer: D) There are 6 different letters in the given word, out of which there are 3 vowels and 3 consonants. Let us mark these positions as under: [1] [2] [3] [4] [5] [6] Now, 3 vowels can be ... of these arrangements = 3P3 = 3! = 6 ways. Therefore, total number of ways = 6 x 6 = 36.
Description : In how many different ways can the letters of the word "XANTHOUS" be arranged in such a way that the vowels occupy only the odd positions? a) 2880 b) 4320 c) 2140 d) 5420
Last Answer : Answer: A) There are 8 different letters in the given word "XANTHOUS", out of which there are 3 vowels and 5 consonants. Let us mark these positions as under: [1] [2] [3] [4] [5] [6] [7] ... in 5P5 ways = 5! Ways = 120 ways. Therefore, required number of ways = 24 x 120 = 2880 ways.
Description : In how many different ways can the letters of the word "ZYMOGEN" be arranged in such a way that the vowels always come together? a) 1440 b) 1720 c) 2360 d) 2240
Last Answer : Answer: A) The arrangement is made in such a way that the vowels always come together. i.e., "ZYMGN(OE)". Considering vowels as one letter, 6 different letters can be arranged in 6! ways; i.e., 6! = 720 ... in 2! ways; i.e.,2! = 2 ways Therefore, required number of ways = 720 x 2 = 1440 ways.
Description : In how many different ways can the letters of the word 'RAPINE' be arranged in such a way that the vowels occupy only the odd positions? A) 32 B) 48 C) 36 D) 60 E) 120
Last Answer : Answer: C) There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants. Let us mark these positions as under: (1) (2) (3) (4) (5) (6) Now, 3 vowels can be placed at ... . Number of ways of these arrangements = 3P3 = 3! = 6. Total number of ways = (6 x 6) = 36
Description : In how many different ways can the letters of the word 'POTENCY' be arranged in such a way that the vowels always come together? A) 1360 B) 2480 C) 3720 D) 5040 E) 1440
Last Answer : Answer: E) The word 'POTENCY' has 7 different letters. When the vowels EO are always together, they can be supposed to form one letter. Then, we have to arrange the letters PTNCY (EO). Now, 6 (5 ... be arranged among themselves in 2! = 2 ways. Required number of ways = (720 x2) = 1440.
Description : Two long thin wires ABC and DEF are arranged as shown in Fig. They carry equal currents I as shown. The magnitude of the magnetic field at O is
Last Answer : Two long thin wires ABC and DEF are arranged as shown in Fig. They carry equal currents I as shown. The ... `(mu_(0)I)/(2sqrt(2)pir)` D. zero
Description : Which instruction are arranged as per the protocols of memory reference format of the input file in a simple ASCII sequence of integers between the range O to 99 separated by spaces without formatted text ... : a. Memory reference instruction b. Memory reference format c. Both d. None of these
Last Answer : a. Memory reference instruction
Description : In the given figure, ABCD is a square. Side AB is produced to points P and Q in such a way that PA = AB = BQ. Prove that DQ = CP. -Maths 9th
Last Answer : In △PAD, ∠A = 90° and DA = PA = PB ⇒ ∠ADP = ∠APD = 90° / 2 = 45° Similarly, in △QBC, ∠B = 90° and BQ = BC = AB ⇒∠BCQ = ∠BQC = 90° / 2 = 45° In △PAD and △QBC , we have PA = QB [given] ∠A = ... [each = 90° + 45° = 135°] ⇒ △PDC = △QCD [by SAS congruence rule] ⇒ PC = QD or DQ = CP
Description : The figure shows the front view of a convex lens, which originally had only one edge. Five holes of different shapes, namely triangle, square, pentagon, hexagon and circle, were drilled through it at points P ... . What is the total number of edges in the lens after the holes were drilled?
Last Answer : 57
Description : A circular loop which is in the form of a major arc of a constant magnetic field B is applied in the vertical direction such that the magnetic lines o
Last Answer : A circular loop which is in the form of a major arc of a constant magnetic field B is applied in the ... `2 BIR sin(alpha//2)` D. None of these
Description : The advantage of I/O mapped devices to memory mapped is ___________ a) The former offers faster transfer of datab) The devices connected using I/O mapping have a bigger buffer space c) The devices have to deal with fewer address lines d) No advantage as such
Last Answer : The devices have to deal with fewer address lines
Description : If P, Q and R are three points on a line and Q is between P and R,then prove that PR - QR= PQ. -Maths 9th
Description : If P (5,1), Q (8, 0), R(0, 4), S(0, 5) and O(0, 0) are plotted on the graph paper, then the points on the X-axis is/are -Maths 9th
Last Answer : (d) We know that, a point lies on X-axis, if its y-coordinate is zero. So, on plotting the given points on graph paper, we get Q and O lie on the X-axis.