A number when increased by `40%` becomes 42. What is the number ?

A number when increased by `40%` becomes 42. What is the number ?
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A number when increased by `40%` becomes 42. What is the number ?
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What is the share of population under 15 in the total population? A. 42.3% B. 41% C. 43.40% D. 45%

Description : What is the share of population under 15 in the total population? A. 42.3% B. 41% C. 43.40% D. 45%

Last Answer : ANSWER: C

What is the share of population under 15 in the total population? A. 42.3% B. 41% C. 43.40% D. 45%

Description : What is the share of population under 15 in the total population? A. 42.3% B. 41% C. 43.40% D. 45%

Last Answer : ANSWER: C

A person sold an item for Rs. 14280 after giving 15% discount on the labelled price and earned 19% profit on the cost price. What would have been the percentage profit, had he not given the discount? a) 30% b) 34% c) 40% d) 42.5% e) None of these

Description : A person sold an item for Rs. 14280 after giving 15% discount on the labelled price and earned 19% profit on the cost price. What would have been the percentage profit, had he not given the discount? a) 30% b) 34% c) 40% d) 42.5% e) None of these

Last Answer : Labelled price = [(14280×100)/85] = Rs. 16800 Or, 23X/120 = 69/5 Or, X= [(69×120)/(23×5)] = 72km. Answer is: c)

If in 2000 nominal GDP is = `70000 Crore and the prices in 2000 were 40% more than the real GDP in 2000 using 1996 as a base year is (a) `45,000 Crore ; (b) `50,000 Crore ; (c) `42,000 Crore ; (d) `98000 Crore

Description : If in 2000 nominal GDP is = `70000 Crore and the prices in 2000 were 40% more than the real GDP in 2000 using 1996 as a base year is (a) `45,000 Crore ; (b) `50,000 Crore ; (c) `42,000 Crore ; (d) `98000 Crore

Last Answer : (b) `50,000 Crore ;

In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg

Description :  In 1 kg mixture of iron and carbon, 40% is carbon. How much iron should be added so that the proportion of carbon becomes 20% a)1.5kg b)2kg c)3kg d)5kg e)1kg

Last Answer : E Quantity of the mixture : Quantity of iron = 20 : 20 = 1 : 1 Given that quantity of the mixture = 1 kg Hence quantity of iron to be added = 1 kg

The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Description : The number of candidates writing three different entrance exams is in the ratio 4:5:6. There is a proposal to increase these numbers of candidates by 40%, 60% and 85% respectively. What will be the ratio of increased numbers? a) 14:15:16 b) 12:15:19 c)13:19:21 d) 14:16:19 E) None of these

Last Answer : Answer : E Given ratio of number of candidates is 4:5:6 Let the number of candidates for 3 exams be 4k, 5k and 6k respectively. After increasing, number of candidates become (140% of 4k), (160% of 5k) & (185% ... 111k/10 Now, the required new ratio is: 56k/100 : 80k/10 : 111k/10 = 56 : 80 : 111

The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher? A.50 B.44 C.45 D.42 E.None of these

Description : The average age of 30 boys of a class is equal to 14 years. When the age of the class teacher is included the average becomes 15 years. Find the age of the class teacher? A.50 B.44 C.45 D.42 E.None of these

Last Answer : Answer – C (45) Explanation – Total ages of 30 boys = 14 x 30 = 420 years Total age when class teacher is included = 15 x 31 = 465 years Age of class teacher = 465 – 420 = 45 years

Two numbers are in the ration 3:5. If 9 is subtracted from the numbers, the ratio becomes 12:23. The numbers are (A) 30, 50 (B) 36, 60 (C) 33, 55 (D) 42, 70

Description : Two numbers are in the ration 3:5. If 9 is subtracted from the numbers, the ratio becomes 12:23. The numbers are (A) 30, 50 (B) 36, 60 (C) 33, 55 (D) 42, 70

Last Answer : Answer: C

In 2000-2001 the use of mechanical & electrical increased from a)20% to 45%. c) 45% to 75% b) 45 to below 83% d)40% to over 83 %

Description : In 2000-2001 the use of mechanical & electrical increased from a)20% to 45%. c) 45% to 75% b) 45 to below 83% d)40% to over 83 %

Last Answer : 40% to over 83 %

If the radius of a circle is increased by 50%, the perimeter of the circle will increase by (A) 20% (B) 30% (C) 40% (D) 50%

Description : If the radius of a circle is increased by 50%, the perimeter of the circle will increase by (A) 20% (B) 30% (C) 40% (D) 50%

Last Answer : Answer: D

Murugan sold a book at a loss of 40%. If the selling price had been increased by Rs.200, there would have been a gain of 10%. What was the cost price of the book?

Description : Murugan sold a book at a loss of 40%. If the selling price had been increased by Rs.200, there would have been a gain of 10%. What was the cost price of the book?

Last Answer : Let cost price be Rs ‘x’  Then (110% of x) – (60 % of x) = 200  (110x/100) - (60x/10) = 200  110x – 60x = 20000  X = 400  So cost price of the book = Rs.400

Reenu sold an article at a loss of 40%. If the selling price had been increased by Rs.200, there would have been a gain of 10%. The cost price of the article was

Description : Reenu sold an article at a loss of 40%. If the selling price had been increased by Rs.200, there would have been a gain of 10%. The cost price of the article was 

Last Answer : Let the C.P. of article be Rs. x. 110% of x - 60% of x = Rx. 200 50% of x = Rx. 200 x = Rs. (200×100)/50 = Rs. 400

If 20% discount is allowed on the marked price then the profit is 40%. If the discount is increased to 40% then what will be the profit percentage?

Description : If 20% discount is allowed on the marked price then the profit is 40%. If the discount is increased to 40% then what will be the profit percentage?

Last Answer :  cp=100% profit=40% selling price= 140% marked price = 140% mp=140*100/80= 175 40%discount in mp= 175 *60/100 New sp=105 new profit%= new sp-cp/cp *100 =105-100/100*100 =5

The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Description : The population of a town was 200000 three years ago. If increased by 4%, 6% and 10% respectively in the last three years, then the present population of town is a) 1,10,313 b) 1,10,314 c) 2,42,528 d) 2,93,313 e) 2,10,313

Last Answer : Answer: C The present population = (1+4/100)×(1+6/100)×(1+10/100)×200000  = (104/100) × (106/100) × (110/100) × 200000  = 1.04×1.06×1.1×200000  = 2,42,528

The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Description : The ratio between two number is 3:4 ,if each number be increased by 9, the ratio becomes 18:23 find the sum of the number a) 135 b) 105 c) 155 d) 165 e) None of these

Last Answer : Let the two numbers be 3x and 4x. When they are increased by 9 they become 3x + 9 and 4x + 9. It is given that the ratio is 18:23 Thus, 3x + 9/4x + 9 = 18:23 23(3x + 9) = 18(4x + 9) 69x + 207 = 72x ... = -45 X = 15 Thus two numbers are 3x15 = 45 and 4 x 15 = 60 And the sum is 60+45 = 105 Answer: b)

When a society becomes more complex and organized why is there an increased need for codes of law?

Description : When a society becomes more complex and organized why is there an increased need for codes of law?

Last Answer : to ensure some degree of order and justice.

When a society becomes more complex and organized why is there an increased need for codes of law?

Description : When a society becomes more complex and organized why is there an increased need for codes of law?

Last Answer : to ensure some degree of order and justice.

Which of the following statements about Menke’s disease are true. (A) It is an inherited disorder of copper metabolism (B) It occurs only in males (C) Plasma copper is increased in it (D) Hair becomes steely and kinky in it

Description : Which of the following statements about Menke’s disease are true. (A) It is an inherited disorder of copper metabolism (B) It occurs only in males (C) Plasma copper is increased in it (D) Hair becomes steely and kinky in it

Last Answer : Answer : C

What happens to the bandwidth of an antenna as it is shortened through the use of loading coils? A. It is increased B. It is decreased C. No change occurs D. It becomes flat

Description : What happens to the bandwidth of an antenna as it is shortened through the use of loading coils? A. It is increased B. It is decreased C. No change occurs D. It becomes flat

Last Answer : A. It is increased

As particle size is reduced (A) Screening becomes progressively more difficult (B) Screening becomes progressively easier (C) Capacity and effectiveness of the screen is increased (D) None of these

Description : As particle size is reduced (A) Screening becomes progressively more difficult (B) Screening becomes progressively easier (C) Capacity and effectiveness of the screen is increased (D) None of these

Last Answer : (A) Screening becomes progressively more difficult

In multistage equilibrium conversion of SO2 to SO3 (2SO2 + O2 ⇌ 2SO3 ), the reverse reaction becomes appreciable at a temperature of 550° C. The percentage equilibrium conversion of SO2 to SO3 can be increased by (A) Increasing the oxygen concentration (B) Putting more quantity of V2O5 catalyst in the converter (C) Removing some quantity of SO3 during intermediate stage (D) Maintaining low temperature & pressure in the converter

Description : In multistage equilibrium conversion of SO2 to SO3 (2SO2 + O2 ⇌ 2SO3 ), the reverse reaction becomes appreciable at a temperature of 550° C. The percentage equilibrium conversion of SO2 to ... some quantity of SO3 during intermediate stage (D) Maintaining low temperature & pressure in the converter

Last Answer : (C) Removing some quantity of SO3 during intermediate stage

For a symmetrical two hinged parabolic arch, if one of the supports settles horizontally, then the horizontal thrust (A) Is increased (B) Is decreased (C) Remains unchanged (D) Becomes zero

Description : For a symmetrical two hinged parabolic arch, if one of the supports settles horizontally, then the horizontal thrust (A) Is increased (B) Is decreased (C) Remains unchanged (D) Becomes zero

Last Answer : (B) Is decreased

For a two-hinged arch, if one of the supports settles down vertically, then the horizontal thrust (A) Is increased (B) Is decreased (C) Remains unchanged (D) Becomes zero

Description : For a two-hinged arch, if one of the supports settles down vertically, then the horizontal thrust (A) Is increased (B) Is decreased (C) Remains unchanged (D) Becomes zero

Last Answer : (C) Remains unchanged

Cavitation will begin when (A) The pressure at any location reaches an absolute pressure equal to the saturated vapour pressure of the liquid (B) Pressure becomes more than critical pressure (C) Flow is increased (D) Pressure is increased

Description : Cavitation will begin when (A) The pressure at any location reaches an absolute pressure equal to the saturated vapour pressure of the liquid (B) Pressure becomes more than critical pressure (C) Flow is increased (D) Pressure is increased

Last Answer : Answer: Option A

When purchasing increased Capacity and Automation, the new capacity becomes available a. immediately. b. in 1 year. c. in 6 months. d. in 2 years. e. none of these.

Description : When purchasing increased Capacity and Automation, the new capacity becomes available a. immediately. b. in 1 year. c. in 6 months. d. in 2 years. e. none of these.

Last Answer : b. in 1 year.

What is one drawback of increasing automation? a. The product requires increased time/expense for subsequent short-move repositioning. b. Operating second shift becomes more expensive. c. Automation causes large leaps in repositioning. d. Automation slows production capability. e. It requires more employees for the production line.

Description : What is one drawback of increasing automation? a. The product requires increased time/expense for subsequent short-move repositioning. b. Operating second shift becomes more expensive. c. ... d. Automation slows production capability. e. It requires more employees for the production line.

Last Answer : a. The product requires increased time/expense for subsequent short-move repositioning.

In a ferromagnetic material the state of flux density is as follows when external magnetic field is applied to it. (A) Increased (B) Decreased (C) Remains unchanged (D) Becomes zero

Description : In a ferromagnetic material the state of flux density is as follows when external magnetic field is applied to it. (A) Increased (B) Decreased (C) Remains unchanged (D) Becomes zero

Last Answer : (C) Remains unchanged

Decreases in price of a product results in increased consumption of the product as the product becomes cheaper compared to other products. This effect is known as (a) Substitution effect ; (b) Income effect ; (c) Diminishing marginal utility concept; (b) Law of diminishing returns

Description : Decreases in price of a product results in increased consumption of the product as the product becomes cheaper compared to other products. This effect is known as (a) Substitution effect ; (b) Income effect ; (c) Diminishing marginal utility concept; (b) Law of diminishing returns 

Last Answer : (a) Substitution effect ;

A fuel of cetane number 40 has the same ignition quality as a mixture of a) 40% cetane and 60% alpha methyl naphthalene b) 40% alpha methyl naphthalene and 60% cetane c) 40% petrol and 60% diesel d) 40% diesel and 60% petrol

Description : A fuel of cetane number 40 has the same ignition quality as a mixture of a) 40% cetane and 60% alpha methyl naphthalene b) 40% alpha methyl naphthalene and 60% cetane c) 40% petrol and 60% diesel d) 40% diesel and 60% petrol

Last Answer : Answer: a Explanation: A fuel of cetane number 40 has the same ignition quality as a mixture of 40% cetane and 60% alpha methyl naphthalene as cetane number is counted on cetane percentage.

In 2001, 6400 candidates appeared at the exam and 40% of them qualified. In 2005 the ratio between qualified males and females was 3:5. What is the total number of female candidates who qualified in these two years? A. 1120 B. 1220 C. 1330 D. 1150

Description : In 2001, 6400 candidates appeared at the exam and 40% of them qualified. In 2005 the ratio between qualified males and females was 3:5. What is the total number of female candidates who qualified in these two years? A. 1120 B. 1220 C. 1330 D. 1150

Last Answer : B. 1220

Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Description : Number of students in 4th and 5th class is in the ratio 6 : 11. 40% in class 4 are girls and 48% in class 5 are girls. What percentage of students in both the classes are boys? A) 62.5% B) 54.8% C) 52.6% D) 55.8% E) 53.5%

Last Answer : Answer: B Total students in both = 6x+11x = 17x Boys in class 4 = (60/100)*6x = 360x/100 Boys in class 5 = (52/100)*11x = 572x/100 So total boys = 360x/100 + 572x/100 = 932x/100 = 9.32x % of boys = [9.32x/17x] * 100=54.8%

Two numbers are respectively 40% and 60% more than than the third number. The ratio of the two number is A) 6:7 B) 7:8 C) 8:7 D) 7:5 E) None of these

Description : Two numbers are respectively 40% and 60% more than than the third number. The ratio of the two number is A) 6:7 B) 7:8 C) 8:7 D) 7:5 E) None of these

Last Answer : Answer: B Let third number = x (140/100)x = (7/5)x (160/100)x = (8/5)x (7/5) : (8/5) = 35 : 40 = 7 : 8

The average age of 150 students in a class is 40% of the number of students in the class and the average age of a group of 50 students present in the class is 32yrs and the average age of another 50 students in the class is 36yrs. What is the average age of the remaining students in the class? A) 102 B) 118 C) 112 D) 108

Description : The average age of 150 students in a class is 40% of the number of students in the class and the average age of a group of 50 students present in the class is 32yrs and the average age of another 50 students ... is the average age of the remaining students in the class? A) 102 B) 118 C) 112 D) 108

Last Answer : C) 150 students average 150×40/100=60 years According to the question, 150×60=50×32+50×36+50×X 50×X=9000-1600-1800 50x=5600 X=112

In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800

Description : In an election, candidate A got 40% of the total valid votes. If 55% of the total votes were declared invalid and the total numbers of votes is 280000, find the number of valid vote polled in favour of candidate. a) 32500 b) 56000 c) 35700 d) 50400 e) 29800

Last Answer : Answer: D Total number of invalid votes = 55 % of 280000  = 55/100 280000  = 15400000/100  = 154000 Total number of valid votes 280000 - 154000 = 126000 Percentage of votes polled in favour of candidate ... favour of candidate A = 40 % of 126000  = 40/100 126000  = 5040000/100  = 50400

In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800

Description : In an election between two candidates, one got 45% of the total valid votes, 40% of the votes were invalid. If the total number of votes was 15000, the number of valid votes that the other candidate got, was a) 2500 b) 3600 c) 4500 d) 4950 e) 9800 

Last Answer : Answer: D Total number of votes = 15000 Given that 40% of Percentage votes were invalid => Valid votes = 60% Total valid votes = 15000* 60/100 1st candidate got 45% of the total valid votes. Hence ... votes that 2nd candidate got = total valid votes x 55/100  =15000*60/100*55/100  =4950