A person takes `1//2` kg of cheese sandwitches of energy equivalent to `813 kJ`. Suppose that all the energy is lost only through perspiration, what m

A person takes `1//2` kg of cheese sandwitches of energy equivalent to `813 kJ`. Suppose that all the energy is lost only through perspiration, what m
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A person takes `1//2` kg of cheese sandwitches of energy equivalent to `813 kJ`. Suppose that all the energy is ... A. 360g B. 3.6 g C. 180g D. 190g
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A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 x10^6 kJ  D. 2 x10^6 kJ Formula: fromthe steamtable vƒ = 0.001043 m^3 / kg vg = 1.6940 m^3 / kg u ƒ= 417.3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Description : A 10m^3 vessel initially contains 5 m^3 of liquid water and 5 m^3 of saturated water vapor at 100 kPa. Calculate the internal energy of the system using the steam table.  A. 5 x10^5 kJ  B. 8x10^5 kJ  C. 1 ... 3 kJ/kg ug= 2506kJ/kg formula: Mvap = V vap/vg M liq = Vliq/ vƒ u =uƒM liq + ug M vap

Last Answer : 2 x10^6 kJ

what is 813 rounded to the nearest 100?

Description : what is 813 rounded to the nearest 100?

Last Answer : mu address is 79 cardnail village

The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Description : The combined mass of car and passengers travelling at 72 km/hr is 1500 kg. Find the kinetic energy of this combined mass. (Formula: K =mv2 / 2k )  a. 300 kJ  b. 200 kJ  c. 500 kJ  d. None of the above

Last Answer : 300 kJ

What is the unit of the total energy of the system?  A. Kj  B. Kj/Kg  C. Kg  D. g

Description : What is the unit of the total energy of the system?  A. Kj  B. Kj/Kg  C. Kg  D. g

Last Answer : Kj

A blender has a power of 0.3 kW. It is used to make a fruit smoothie, which takes 50 seconds. How much energy is used Give your answer in kilojoules.kJ?

Description : A blender has a power of 0.3 kW. It is used to make a fruit smoothie, which takes 50 seconds. How much energy is used Give your answer in kilojoules.kJ?

Last Answer : 15 KJ

One ton of refrigeration is not equivalent to the heat removal rate of (A) 200 BTU/minute (B) 50 kcal/minute (C) 50 kJ/sec (D) 3.5 KW

Description : One ton of refrigeration is not equivalent to the heat removal rate of (A) 200 BTU/minute (B) 50 kcal/minute (C) 50 kJ/sec (D) 3.5 KW

Last Answer : (C) 50 kJ/sec

An engine produces 10 kW brake power while working with a brake thermal efficiency of 30%. If the calorific value of the fuel used is 40000 kJ/kg, then what is the fuel consumption? (a) 1.5 kg/hour (b) 3 kg/hour (c) 0.3 kg/hour (d) 1 kg/hour

Description : An engine produces 10 kW brake power while working with a brake thermal efficiency of 30%. If the calorific value of the fuel used is 40000 kJ/kg, then what is the fuel consumption? (a) 1.5 kg/hour (b) 3 kg/hour (c) 0.3 kg/hour (d) 1 kg/hour

Last Answer : Ans :b

An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per cycle is 1800 kJ/kg, then work output per cycle per kg of air is a. 879.1 kJ/ b. 890.2 kJ c. 895.3 kJ d. 973.5 kJ

Description : An engine working on air standard Otto cycle has a cylinder diameter of 10 cm and stroke length of 15 cm. The ratio of specific heats for air is 1.4. If the clearance volume is 196.3 cc and the heat supplied per kg of air per ... kg of air is a. 879.1 kJ/ b. 890.2 kJ c. 895.3 kJ d. 973.5 kJ

Last Answer : ANSWER d. 973.5 kJ

The heat value of combustion of Gasoline is - (1) 12600 kJ/kg (2) 14600 kJ/kg (3) 39400 kJ/kg (4) 47000 kJ/kg

Description : The heat value of combustion of Gasoline is - (1) 12600 kJ/kg (2) 14600 kJ/kg (3) 39400 kJ/kg (4) 47000 kJ/kg

Last Answer : (4) 47000 kJ/kg Explanation: The calorific value of Gasoline is 47,300 kJ/kg. The calorific value of a fuel is the quantity of heat produced by its combustion - at constant pressure and under "normal" conditions (i.e. to 0°C and under a pressure of 1,013 mbar).

If the specific heats of a gas and a vapor are 0.2KJ/Kg.°K and 1.5 KJ/Kg.°K respectively, and the humidity is 0.01; the humid heat in KJ/°Kg. is (A) 0.31 (B) 0.107 (C) 0.017 (D) 0.215

Description : If the specific heats of a gas and a vapor are 0.2KJ/Kg.°K and 1.5 KJ/Kg.°K respectively, and the humidity is 0.01; the humid heat in KJ/°Kg. is (A) 0.31 (B) 0.107 (C) 0.017 (D) 0.215

Last Answer : (D) 0.215

Hot water (0.01 m3 /min) enters the tube side of a counter current shell and tube heat exchanger at 80°C and leaves at 50°C. Cold oil (0.05 m3 /min) of density 800 kg/m3 and specific heat of 2 kJ/kg.K enters at 20°C. The log mean temperature difference in °C is approximately (A) 32 (B) 37 (C) 45 (D) 50

Description : Hot water (0.01 m3 /min) enters the tube side of a counter current shell and tube heat exchanger at 80°C and leaves at 50°C. Cold oil (0.05 m3 /min) of density 800 kg/m3 and specific heat of ... mean temperature difference in °C is approximately (A) 32 (B) 37 (C) 45 (D) 50

Last Answer : (A) 32

It is desired to concentrate a 20% salt solution (20 kg of salt in 100 kg of solution) to a 30% salt solution in an evaporator. Consider a feed of 300 kg/min at 30°C. The boiling point of the solution is 110°C, the latent heat of vaporisation is 2100 kJ/kg and the specific heat of the solution is 4 kJ/kg.K. The rate at which the heat has to be supplied in (kJ/min) to the evaporator is (A) 3.06 × 10 5 (B) 6.12 × 10 5 (C) 7.24 × 10 5 (D) 9.08 × 10

Description : It is desired to concentrate a 20% salt solution (20 kg of salt in 100 kg of solution) to a 30% salt solution in an evaporator. Consider a feed of 300 kg/min at 30°C. The boiling point of the solution is 110°C, the latent heat of ... 3.06 10 5 (B) 6.12 10 5 (C) 7.24 10 5 (D) 9.08 10

Last Answer : (A) 3.06 × 10

A solid metallic block weighing 5 kg has an initial temperature of 500°C. 40 kg of water initially at 25°C is contained in a perfectly insulated tank. The metallic block is brought into contact with water. Both of them come to equilibrium. Specific heat of block material is 0.4 kJ.kg-1. K-1. Ignoring the effect of expansion and contraction and also the heat capacity to tank, the total entropy change in kJ.kg-1, K-1is (A) -1.87 (B) 0 (C) 1.26 (D) 3.91

Description : A solid metallic block weighing 5 kg has an initial temperature of 500°C. 40 kg of water initially at 25°C is contained in a perfectly insulated tank. The metallic block is brought into contact with water. Both of them come to equilibrium. ... .kg-1, K-1is (A) -1.87 (B) 0 (C) 1.26 (D) 3.91

Last Answer : (B) 0

Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg. K, entropy of saturated vapour = 7.2234 kJ/kg. K) The exit condition of steam is (A) Superheated vapour (B) Partially condensed vapour with quality of 0.9 (C) Saturated vapour (D) Partially condensed vapour with quality of 0.1

Description : Steam undergoes isentropic expansion in a turbine from 5000 kPa and 400°C (entropy = 6.65 kJ/kg K) to 150 kPa) (entropy of saturated liquid = 1.4336 kJ/kg. K, entropy of saturated vapour = 7.2234 ... vapour with quality of 0.9 (C) Saturated vapour (D) Partially condensed vapour with quality of 0.1

Last Answer : (A) Superheated vapour

Specific heat capacity in SI unit.  a. kJ / kg.k  b. kJ / kg  c. kN / kg  d. None of the above

Description : Specific heat capacity in SI unit.  a. kJ / kg.k  b. kJ / kg  c. kN / kg  d. None of the above

Last Answer : kJ / kg.k

Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Description : Steam is throttled to 0.1 MPa with 20 degrees of superheat. (a) What is the quality of throttled steam if its pressure is 0.75 MPa (b) What is the enthalpy of the process?  a) 97.6%,2713 kJ/kg  b) -97.6%, 2713 kJ/kg  c) 87.6%,3713 kJ/kg  d) -87.6%, 3713 kJ/kg

Last Answer : 97.6%,2713 kJ/kg

A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Description : A 1-kg steam-water mixture at 1.0 MPa is contained in an inflexible tank. Heat is added until the pressure rises to 3.5 MPa and the temperature to 400°. Determine the heat added.  a) 1378.7 kJ  b) 1348.5 kJ  c) 1278,7 kJ  d) 1246,5 kJ Formula: Q = (h2 – p2v2) –(h1 –p1v1)

Last Answer : 1378.7 kJ

There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and there are also added 105.5 kJ of heat. Determine t2. (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Description : There are 1.36 kg of gas, for which R = 377 J/kg.k and k = 1.25, that undergo a nonflow constant volume process from p1 = 551.6 kPa and t1 = 60°C to p2 = 1655 kPa. During the process the gas is internally stirred and ... (Formula: T2= T1p2/ p1)  a. 999 K  b. 888 K  c. 456 K  d. One of the above

Last Answer : 999 K

Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water?  A. 0.043 K/s  B. 0.179 K/s  C. 0.357 K/s  D. 1.50 K/s Formula: Q = mcv ( T)

Description : Water (specific heat cv= 4.2 kJ/ kg ∙ K ) is being heated by a 1500 W h eater. What is the rate of change in temperature of 1kg of the water?  A. 0.043 K/s  B. 0.179 K/s  C. 0.357 K/s  D. 1.50 K/s Formula: Q = mcv ( T)

Last Answer : 0.179 K/s

From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Description : From the steam table, determine the average constant pressure specific heat (c) of steam at 10 kPa and45.8 ˚C  A.1.79 kJ/ kg-˚C  B.10.28 kJ/ kg-˚C  C.30.57 kJ/ kg-˚C  D. 100.1 kJ/ kg-˚C Formula: h = c T ∆ ∆ From the steam table At 47.7 ˚C h= 2588.1 kJ/ kg At 43.8 ˚C h= 2581.1 kJ/ kg

Last Answer : 1.79 kJ/ kg-˚C

What is the latent heat of vaporization of water at 1 atm?  A. 2314.8 kJ/kg  B. 2257.1 kJ/kg  C. 2511.7 kJ/kg  D. 2429.8 kJ/kg

Description : What is the latent heat of vaporization of water at 1 atm?  A. 2314.8 kJ/kg  B. 2257.1 kJ/kg  C. 2511.7 kJ/kg  D. 2429.8 kJ/kg

Last Answer : 2257.1 kJ/kg

What is the latent heat of fusion of water at 1 atm?  A. 331.1 kJ/kg  B. 332.6 kJ/kg  C. 333.7 kJ/kg  D. 330.7 kJ/kg

Description : What is the latent heat of fusion of water at 1 atm?  A. 331.1 kJ/kg  B. 332.6 kJ/kg  C. 333.7 kJ/kg  D. 330.7 kJ/kg

Last Answer : 333.7 kJ/kg

2000 kJ of heat is supplied to 500 kg of ice at 0oC. If the latent heat of fusion of ice is 335 kJ/kg then the amount of ice in kg melted will be a) 1.49 b) 83.75 c) 5.97 d) None of the above

Description : 2000 kJ of heat is supplied to 500 kg of ice at 0oC. If the latent heat of fusion of ice is 335 kJ/kg then the amount of ice in kg melted will be a) 1.49 b) 83.75 c) 5.97 d) None of the above

Last Answer : c) 5.97

The unit of calorific value of fuel is __________ . a) Kj /Kg b) J/Kg c)Kj /g d)J/g

Description : The unit of calorific value of fuel is __________ . a) Kj /Kg b) J/Kg c)Kj /g d)J/g

Last Answer : a) Kj /Kg

In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg

Description : In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg 

Last Answer : Constant pressure process Final condition of steam is dry saturated Enthalpy of dry steam = hg= hf + hfg =2776.2 KJ/Kg .Given Latent heat of vaporization = hfg = hg - hf =2776.2-762.6 =2013.6 KJ/Kg Initial condition ... hfg = 762.6+0.8 X 2013.6 =2373.48 KJ/Kg Heat added = hg-hw = 402.72 KJ/kg

In a boiler enthalpy of water supplied was 2000 kJ/kg. Enthalpy being added by fuel combustion is 3200 kJ/kg. Using first law of thermodynamics, find amount of heat supplied if steam generation rate is 10 tons per hour.

Description : In a boiler enthalpy of water supplied was 2000 kJ/kg. Enthalpy being added by fuel combustion is 3200 kJ/kg. Using first law of thermodynamics, find amount of heat supplied if steam generation rate is 10 tons per hour.

Last Answer : Heat supplied Q = m (h2-h1) …….(Steady flow energy equation for boiler) ; h2=3200 KJ/kg h1=2000 KJ/kg m = 10 Tons /hour = (10 x 1000)/3600 kg/sec = 2.77 Kg/sec Q = 2.77(3200-2000) = 3324 KJ/sec heat supplied for 10 Tons/hr steam generation

The heat value of combustion of Gasoline is (1) 12600 kJ/kg (2) 14600 kJ/kg (3) 39400 kJ/kg (4) 47000 kJ/kg

Description : The heat value of combustion of Gasoline is (1) 12600 kJ/kg (2) 14600 kJ/kg (3) 39400 kJ/kg (4) 47000 kJ/kg

Last Answer : 47000 kJ/kg

The mass and energy equivalent to 1 a.m.u. respectively are - (1) 1.67 x 10−27 g, 9.30 MeV (2) 1.67 x 10−27kg, 930 MeV (3) 1.67 x 10−27kg, 1 MeV (4) 1.67 x 10−34 kg, 1 MeV

Description : The mass and energy equivalent to 1 a.m.u. respectively are - (1) 1.67 x 10−27 g, 9.30 MeV (2) 1.67 x 10−27kg, 930 MeV (3) 1.67 x 10−27kg, 1 MeV (4) 1.67 x 10−34 kg, 1 MeV

Last Answer : (2) 1.67 x 10−27kg, 930 MeV Explanation: The mass and energy equivalent to 1 a.m.u. respectively are 1.67 x 10−27kg, 930 MeV.

In summer, man with excess perspiration feels weak, because of the (a) Loss of more water through evaporation (b) Loss of salts through evaporation (c) Loss of carbohydrates through evaporation (d) All factors mentioned above

Description : In summer, man with excess perspiration feels weak, because of the (a) Loss of more water through evaporation (b) Loss of salts through evaporation (c) Loss of carbohydrates through evaporation (d) All factors mentioned above

Last Answer : Ans:(d)

Perspiration is maximum when 1. temperature is high 2. humidity is high 3. humidity is low Which of the above is/are correct? (a) 1 only (b) 1 and 2 (c) 1 and 3 (d) 2 only

Description : Perspiration is maximum when 1. temperature is high 2. humidity is high 3. humidity is low Which of the above is/are correct? (a) 1 only (b) 1 and 2 (c) 1 and 3 (d) 2 only

Last Answer : Ans:(b)

A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Description : A man pulls a cart with 100 N force from rest with an acceleration of 10 m/sec2 for 10 seconds. The work done by him is a.500 KJ b.50.96 KJ c.101.92 KJ d.None of the above e.Tapered bearing

Last Answer : a. 500 KJ

Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Description : Gas is enclosed in a cylinder with a weighted piston as the stop boundary. The gas is heated and expands from a volume of 0.04 m^3 to 0.10 m^3 at a constant pressure of 200kPa.Calculate the work done by the system.  A. 8 kJ  B. 10 kJ  C.12 kJ  D.14 kJ Formula: W = p(V2-V1)

Last Answer : 12 kJ

N kg-1 is equivalent to A. m s-2 B. m s-1 C. m s D. m s-3

Description : N kg-1 is equivalent to A. m s-2 B. m s-1 C. m s D. m s-3

Last Answer : m s-2

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A 12.32 Hz B 4.10 Hz C 6.16 HzD None of the above

Last Answer : C 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 43200 N/m and mass of 12 kg. A 40.22 rad/sec B 40 Hz C 60 Hz D 60 rad/sec

Last Answer : D 60 rad/sec

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A. 12.32 Hz B. 4.10 Hz C. 6.16 Hz D. None of the above

Last Answer : C. 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? A) 12.32 Hz B) 4.10 Hz C) 6.16 Hz D) None of the above

Last Answer : C) 6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m and mass of 20 kg? C ( A )12.32 Hz (B) 4.10 Hz ( C )6.16 Hz (D)None of the above

Last Answer : ( C )6.16 Hz

Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

Description : Determine natural frequency of a system, which has equivalent spring stiffness of 30000 N/m mass of 20 kg? a. 12.32 Hz b. 4.10 Hz c. 6.16 Hz d. None of the above

Last Answer : c. 6.16 Hz

. One stoke (unit of kinematic viscosity) is equivalent to (A) 1 cm2 /second (B) 1 m2 /second (C) 1 gm/cm. second (D) 1 kg. m/second

Description : . One stoke (unit of kinematic viscosity) is equivalent to (A) 1 cm2 /second (B) 1 m2 /second (C) 1 gm/cm. second (D) 1 kg. m/second

Last Answer : (A) 1 cm2 /second

One joule is equivalent to one _____.  A. Kg m/ s^2 ∙  B. Kg m^2/s^2 ∙  C. Kg m^2/s ∙  D. Kg m/s

Description : One joule is equivalent to one _____.  A. Kg m/ s^2 ∙  B. Kg m^2/s^2 ∙  C. Kg m^2/s ∙  D. Kg m/s

Last Answer : Kg m^2/s^2

Suppose the inventory manager at Hotpoint intends to lower stockout costs. Which of the following is considered a stockout cost that the manager at Hotpoint might address? A)Price of washing machines B)Sales lost due to short supply of dishwashers C)Order -processing expenses D)Expenses of backordering small appliances

Description : Suppose the inventory manager at Hotpoint intends to lower stockout costs. Which of the following is considered a stockout cost that the manager at Hotpoint might address? A)Price of washing ... to short supply of dishwashers C)Order -processing expenses D)Expenses of backordering small appliances

Last Answer : B)Sales lost due to short supply of dishwashers

Suppose you are in a helicopter when an earthquake takes place. Is there any danger to you?

Description : Suppose you are in a helicopter when an earthquake takes place. Is there any danger to you?

Last Answer : If it moves the air that much you’re going to have bigger problems then a little turbulence.

There is a circular path around a sports field. Priya takes 18 minutes to drive one round of the field. Harish takes 12 minutes. Suppose they both start at the same point and at the same time and go in the same direction. After how many minutes will they meet ? (a) 36 minutes (b) 18 minutes (c) 6 minutes (d) They will not meet

Description : There is a circular path around a sports field. Priya takes 18 minutes to drive one round of the field. Harish takes 12 minutes. Suppose they both start at the same point and at the same time and go in the same ... will they meet ? (a) 36 minutes (b) 18 minutes (c) 6 minutes (d) They will not meet

Last Answer : (a) 36 minutes

Suppose that the number of instructions executed between page faults is directly proportional to the number of page frames allocated to a program. If the available memory is doubled, the mean interval between page faults is also doubled. Further, consider that a normal instruction takes one micro second, but if a page fault occurs, it takes 2001 micro seconds. If a program takes 60 sec to run, during which time it gets 15000 page faults, how long would it take to run if twice as much memory were available? (A) 60 sec (B) 30 sec (C) 45 sec (D) 10 sec

Description : Suppose that the number of instructions executed between page faults is directly proportional to the number of page frames allocated to a program. If the available memory is doubled, the mean interval between page faults is also ... memory were available? (A) 60 sec (B) 30 sec (C) 45 sec (D) 10 sec

Last Answer : Answer: C Explanation: T = Ninstr x 1µs + 15,000 x 2,000 µs = 60s Ninstr x 1µs = 60,000,000 µs - 30,000,000 µs = 30,000,000 µs Ninstr = 30,000,000 The number of instruction ... doesn't mean that the program runs twice as fast as on the first system. Here, the performance increase is of 25%.

The order of a leaf node in a B+ tree is the maximum number of children it can have. Suppose that block size is 1 kilobytes, the child pointer takes 7 bytes long and search field value takes 14 bytes long. The order of the leaf node is ............ (1) 16 (2) 63 (3) 64 (4) 65

Description : The order of a leaf node in a B+ tree is the maximum number of children it can have. Suppose that block size is 1 kilobytes, the child pointer takes 7 bytes long and search field value takes 14 bytes long. The order of the leaf node is ............ (1) 16 (2) 63 (3) 64 (4) 65

Last Answer : Answer: All

Anand takes 9 hours more than Babu to cover 150 km. Suppose the time taken by Anand is 30 minutes less than Babu he must double his speed. Then the speed of Anand will be: a) 7.64 km/hr. b) 7.43km/hr. c) 7.89 km/hr. d) 7.25 km/hr.

Description : Anand takes 9 hours more than Babu to cover 150 km. Suppose the time taken by Anand is 30 minutes less than Babu he must double his speed. Then the speed of Anand will be: a) 7.64 km/hr. b) 7.43km/hr. c) 7.89 km/hr. d) 7.25 km/hr.

Last Answer : C Let Anand 's speed be X km/hr. And let the time taken by Babu be Y. Since Anand takes 9+Y hours to cross 150km at X km/hr. i.e., 150 / X = 9+Y ---eqn1 And he takes Y - 1/2 hours to cross 150km at 2X km ... )/ 2x = 19/2 150/2X =19/2 150/X = 19 X = 7.89 Hence Anand 's speed is 7.89 km/hr.

What is the most important function of perspiration? -Do You Know?

Description : What is the most important function of perspiration? -Do You Know?

Last Answer : answer: