The radius of circle tends to zero then it approaches a ________.

The radius of circle tends to zero then it approaches a ________.
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The radius of circle tends to zero then it approaches a ________.
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Gibbs free energy of a pure fluid approaches __________ as the pressure tends to zero at constant temperature. (A) Infinity (B) Minus infinity (C) Zero (D) None of these

Description : Gibbs free energy of a pure fluid approaches __________ as the pressure tends to zero at constant temperature. (A) Infinity (B) Minus infinity (C) Zero (D) None of these

Last Answer : (B) Minus infinity

When the number of sides of a polygon tends to infinity, it approaches _______.

Description : When the number of sides of a polygon tends to infinity, it approaches _______.

Last Answer : When the number of sides of a polygon tends to infinity, it approaches _______.

As the temperature is lowered towards the absolute zero, the value of ∂(∆F)/∂T, then approaches (A) Unity (B) Zero (C) That of the heat of reaction (D) Infinity

Description : As the temperature is lowered towards the absolute zero, the value of ∂(∆F)/∂T, then approaches (A) Unity (B) Zero (C) That of the heat of reaction (D) Infinity

Last Answer : B) Zero

A particle is moving in a uniform circular motion with constant speed v along a circle of radius r. The acceleration-of the particle is – (1) zero (2) V/r (3) V/r² (4) V²/r

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Last Answer : (4) V²/r Explanation: When a particle is moving in a uniform circular motion with constant speed and radius. the acceleration of the particle is given by v2/r. The particle will exhibit centripetal acceleration.

Pick out the wrong statement. (A) The net change in entropy in any reversible cycle is always zero (B) The entropy of the system as a whole in an irreversible process increases (C) The entropy of the universe tends to a maximum (D) The entropy of a substance does not remain constant during a reversible adiabatic change

Description : Pick out the wrong statement. (A) The net change in entropy in any reversible cycle is always zero (B) The entropy of the system as a whole in an irreversible process increases (C) The ... to a maximum (D) The entropy of a substance does not remain constant during a reversible adiabatic change

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As complete saturation of an adsorbent is approached, the differential heat of adsrop-tion approaches (A) That of normal condensation (B) Integral heat of adsorption (C) Zero (D) None of these

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Asymptote in a logistic growth curve is obtained when (a) K = N (b) K > N(c) K < N (d) the value of ‘r’ approaches zero

Description : Asymptote in a logistic growth curve is obtained when (a) K = N (b) K > N (c) K < N (d) the value of ‘r’ approaches zero

Last Answer : (a) K = N

In fluid flow, cavitation is caused, if the (A) Fluid velocity decreases to zero (B) Total energy decreases (C) Both (A) and (B) (D) Flow pressure approaches its vapor pressure at the prevailing temperature

Description : In fluid flow, cavitation is caused, if the (A) Fluid velocity decreases to zero (B) Total energy decreases (C) Both (A) and (B) (D) Flow pressure approaches its vapor pressure at the prevailing temperature

Last Answer : (D) Flow pressure approaches its vapor pressure at the prevailing temperature

Pick out the wrong statement. (A) The vessel dispersion number (D/UL) for plug flow and mixed flow approaches zero and infinity respectively (B) Space time in a flow reactor is a measure of its capacity and is equal to the residence time when the density of reaction mixture is constant (C) Mixed reactor is always smaller than the plug flow reactor for all positive reaction orders for a particular duty (D) In an ideal tubular flow reactor, mixing takes place in radial direction and there is no mixing in longitudinal direction

Description : Pick out the wrong statement. (A) The vessel dispersion number (D/UL) for plug flow and mixed flow approaches zero and infinity respectively (B) Space time in a flow reactor is a ... ideal tubular flow reactor, mixing takes place in radial direction and there is no mixing in longitudinal direction

Last Answer : (C) Mixed reactor is always smaller than the plug flow reactor for all positive reaction orders for a particular duty

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Description : Thermal efficiency of a Carnot engine can approach 100%, only when the temperature of the (A) Cold reservoir approaches zero (B) Hot reservoir approaches infinity (C) Either (A) or (B) (D) Neither (A) nor (B)

Last Answer : C) Either (A) or (B)

As the temperature is lowered towards the absolute zero, the value of the quantity (∂∆F/∂T) approaches (A) Zero (B) Unity (C) Infinity (D) None of these

Description : As the temperature is lowered towards the absolute zero, the value of the quantity (∂∆F/∂T) approaches (A) Zero (B) Unity (C) Infinity (D) None of these

Last Answer : (A) Zero

When cut-off ratio is __________ the efficiency of Diesel cycle approaches to Otto cycle efficiency.  A. zero  B. 1/5  C. 4/5  D. 1

Description : When cut-off ratio is __________ the efficiency of Diesel cycle approaches to Otto cycle efficiency.  A. zero  B. 1/5  C. 4/5  D. 1

Last Answer : Answer: A

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Description : The efficiency of Diesel cycle approaches to Otto cycle efficiency when  A. cut-off is increased  B. cut-off is decreased  C. cut-off is zero  D. cut-off is constant

Last Answer : Answer: C

Asymptote in a logistic growth curve is obtained when : (1) K = N (2) K > N (3) K < N (4) The value of 'r' approaches zero

Description : Asymptote in a logistic growth curve is obtained when : (1) K = N (2) K > N (3) K < N (4) The value of 'r' approaches zero

Last Answer : (1) K = N

If the pole flux of a d.c. motor approaches zero, its speed will?

Description : If the pole flux of a d.c. motor approaches zero, its speed will?

Last Answer : If the pole flux of a d.c. motor approaches zero, its speed will approach infinity.

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Description : The given figure shows a circle with centre O in which a diameter AB bisects the chord PQ at the point R. If PR = RQ = 8 cm and RB = 4 cm, then find the radius of the circle. -Maths 9th

Last Answer : Let r be the radius, then OQ = OB = r and OR = (r - 4) ∴ OQ2 = OR2 + RO2 ⇒ r2 = 64 + (r-4)2 ⇒ r2 = 64 + r2 + 16 - 8r ⇒ 8r = 80 ⇒ r = 10 cm

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Description : If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is -Maths 9th

Last Answer : According to question the radius of the circle passing through the points A, B and C .

If the sides of a triangle are 3 cm, 4 cm and 5 cm, then what is the radius of the circum-circle? -Maths 9th

Description : If the sides of a triangle are 3 cm, 4 cm and 5 cm, then what is the radius of the circum-circle? -Maths 9th

Last Answer : Semi-perimeter of triangle (s) = \(rac{3+4+5}{2}\)cm = 6 cm∴ Area of triangle A = \(\sqrt{s(s-a)(s-b)(s-c)}\) = \(\sqrt{6 imes3 imes2 imes1}\) cm2 = 6 cm2∴ Radius of circum-circle = \(rac{abc}{4( ext{Area of}\,\Delta)}\) = \(rac{3+4+5}{4 imes60}\) cm = 2.5 cm

If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the circle solve the following :

Description : If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the circle solve the following :

Last Answer : If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the ... D. `x^(2)+y^(2)+6x+1=0`

If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the circle solve the following :

Description : If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the circle solve the following :

Last Answer : If a given line is tangent to the circle then perpendicular distance from centre of the circle is equal to radius of the ... 0` D. `x^(2)+y^(2)-8y=0`

The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.

Description : The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.

Last Answer : The radius of a circle is 10cm. The length of a chord is 12 cm. Then the distance of the chord from the centre is `"__________________"`.

If the diameter of the circle is 30 mm then what is the radius of the circle?

Description : If the diameter of the circle is 30 mm then what is the radius of the circle?

Last Answer : The radius if the circle is half of its diameter and so 30/2 =15 mm

In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2

Description : In a circle of radius 14 cm, an arc subtends an angle of 45 O at the centre, then the area of the sector is (a) 71 cm 2(b) 76 cm 2 (c) 77 cm 2 (d) 154 cm 2

Last Answer : (c) 77 cm 2

If S, L and R are the arc length, long chord and radius of the sliding circle then the perpendicular distance of the line of the resultant cohesive force, is given by (A) a = S.R/L (B) a = L.S/R (C) a = L.R/S (D) None of these

Description : If S, L and R are the arc length, long chord and radius of the sliding circle then the perpendicular distance of the line of the resultant cohesive force, is given by (A) a = S.R/L (B) a = L.S/R (C) a = L.R/S (D) None of these

Last Answer : (A) a = S.R/L

A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Description : A wire can be bent to form a circle of radius 56 cm. if it is instead bent in the form of a square, then its area will be: a) 6400 sq.cm b) 2025 sq.cm c) 7744 sq.cm d) 6561 sq.cm e) none of these

Last Answer : Length of the wire = circumference of the circle 2 × (22/7) × 56 = 2 × 22 × 8 = 352 cm side of square = 352/4 = 88cm area of square = 88 × 88 = 7744 sq.cm Answer: c)

Below are the few steps given for scan-converting a circle using Bresenham's Algorithm. Which of the given steps is not correct? (1) Compute d = 3 – 2r (where r is radius) (2) Stop if x> y (3) If d<0, then d=4x+6 and x=x+1 (4) If d≥0,then d=4 *(x-y)+10, x=x+1 and y=y+1

Description : Below are the few steps given for scan-converting a circle using Bresenham's Algorithm. Which of the given steps is not correct? (1) Compute d = 3 – 2r (where r is radius) (2) Stop if x> y (3) If d

Last Answer : If d≥0,then d=4 *(x-y)+10, x=x+1 and y=y+1

The cost impact of a risk event occurring as a project proceeds through its life cycle tends to A. Slowly rise B. Slowly drop C. Drop sharply and then level out D. Rise sharply and then level out

Description : The cost impact of a risk event occurring as a project proceeds through its life cycle tends to A. Slowly rise B. Slowly drop C. Drop sharply and then level out D. Rise sharply and then level out

Last Answer : A. Slowly rise

Halloween approaches! What's your favorite candy then (as a kid) and now (as an adult)?

Description : Halloween approaches! What's your favorite candy then (as a kid) and now (as an adult)?

Last Answer : answer:There were definitely tiers when I was a kid. The top tier included Reeses Peanutbutter Cups, Twix, Kit Kit, and full-size bars, followed by Snickers, M&Ms, etc. The bottom tiers were the non- ... kids to donate. The rest is just way too sweet. Nobody is giving out 70%+ dark chocolate bars.

How would you describe the sound of a car whose horn is stuck as it approaches then passes you?

Description : How would you describe the sound of a car whose horn is stuck as it approaches then passes you?

Last Answer : Need answer

Pick out the wrong statement. (A) In a first order reaction, A → products; the reaction becomes slower as it proceeds, because the concentration of A decreases and the rate is proportional to the concentration of A (B) Transition state theory approaches the problem of calculating reaction rates by concentrating on the idea of activated complexes (C) According to the penetration theory, the mass transfer co-efficient decreases, if the exposure time of an eddy to the solute decreases (D) If the rate of an irreversible reaction, A + B → 2C is k.CA .CB , then the reaction is always elementary

Description : Pick out the wrong statement. (A) In a first order reaction, A → products; the reaction becomes slower as it proceeds, because the concentration of A decreases and the rate is proportional to the concentration ... irreversible reaction, A + B → 2C is k.CA .CB , then the reaction is always elementary

Last Answer : (C) According to the penetration theory, the mass transfer co-efficient decreases, if the exposure time of an eddy to the solute decreases

For Q 51, find radius of circle a.3 b.3.6 c.4 d.3.5

Description : For Q 51, find radius of circle a.3 b.3.6 c.4 d.3.5

Last Answer : b.3.6

A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Description : A circle is represented by center point [5,5] and radius 6 units. Find the parametricequation of circle and determine the various points on circle in first quadrant if increment in angle by 45o a.9.24,9.24 b.9.42,9.42 c.9,9 d.11,5

Last Answer : a.9.24,9.24

The moment of inertia of a semi-circle of radius r with respect to a centroidal axis parallel to the diameter is a.0.33 r2 b.0.11 r2 c.0.055 r2 d.0.05 r2 e.0.22 r2

Description : The moment of inertia of a semi-circle of radius r with respect to a centroidal axis parallel to the diameter is a.0.33 r2 b.0.11 r2 c.0.055 r2 d.0.05 r2 e.0.22 r2

Last Answer : b. 0.11 r2

The satellite moves in a circle around the earth. The radius of this circle is equal to one-half the radius of the moons orbit. The satellite will complete one revolution in a.1 lunar month b.2-3/4 lunar month c.2-2/3 lunar month d.None of the above e.

Description : The satellite moves in a circle around the earth. The radius of this circle is equal to one-half the radius of the moons orbit. The satellite will complete one revolution in a.1 lunar month b.2-3/4 lunar month c.2-2/3 lunar month d.None of the above e.

Last Answer : e. None of the above

A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th

Description : AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th

Last Answer : According to question 4q 2 = p 2+ 3r 2.

A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Description : A chord of a circle of radius 7.5 cm with centre 0 is of length 9 cm. Find its distance from the centre. -Maths 9th

Last Answer : ∵ PM = MQ = 1/2 = PQ = 45 cm and OP = 7.5 cm In right angled ΔOMP, using phthagoras theorem OM2 = OP2 - PM2 ⇒OM2 = 7.52 - 4.52 ⇒OM2 = 56.25 - 20.25 ⇒OM2 = 36 ∴ OM = √36 = 6 cm

A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Description : A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point in major segment. -Maths 9th

Last Answer : Given, AB is a chord of a circle, which is equal to the radius of the circle, i.e., AB = BO …(i) Join OA, AC and BC. Since, OA = OB= Radius of circle OA = AS = BO

AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th

Description : AB and AC are two chords of a circle of radius r such that AB = 2AC. -Maths 9th

Last Answer : According to question 4q 2 = p 2+ 3r 2.

Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : circle of radius a touches both axis in 1st quadrant so its centre will be (a,a). ∴ Required equation ⇒(x−a)2+(y−a)2=a2 ⇒x2+a2−2ax+y2+a2−2ay=a2 ⇒x2+y2−2ax−2ay+2a2−a2=0 ⇒x2−y2−2ax−2ay+a2=0.

Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Description : Find the equation of the circle which touches the both axes in first quadrant and whose radius is a. -Maths 9th

Last Answer : Given that the circle of radius ‘a’ touches both axis. So, its centre is (a, a) So, the equation of required circles is : (x-a)2 + (y-a)2 = a2 ⇒ x2 - 2ax + a2+y2 - 2ay + a2 = a2 ⇒ x2 + y2 - 2ax - 2ay + a2 = 0

Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th

Description : Find the length of a chord which is at a distance of 12 cm from the centre of a circle of radius 13 cm. -Maths 9th

Last Answer : Let AB be a chord of circle with centre O and radius 13cm. Draw OM perpendicular AB and join OA. In the right triangle OMA, we have OA2 = OM2 + AM2 ⇒ 132 = 122 + AM2 ⇒ AM2 = 169 - 144 ... . As the perpendicular from the centre of a chord bisects the chord.Therefore, AB = 2AM = 2 x 5 = 10cm.

The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th

Description : The radius of a circle is 13 cm and the length of one of its chords is 24 cm. Find the distance of the chord from the centre. -Maths 9th

Last Answer : Let PQ be a chord of a circle with centre O and radius 13cm such that PQ = 24cm. From O, draw OM perpendicular PQ and join OP. As, the perpendicular from the centre of a circle to a chord bisects the chord. ∴ PM ... Hence, the distance of the chord from the centre is 5cm.

A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Description : A circle has radius √2 cm. It is divided into two segments by a chord of length 2cm.Prove that the angle subtended by the chord at a point in major segment is 45 degree . -Maths 9th

Last Answer : Given radius =2 cm Therefore AO=2 cm Let OD be the perpendicular from O on AB And AB =2cm Therefore AD=1cm (perpendicular from the centre bisects the chord) Now in triangle AOD, AO=2 cm ... by a chord at the centre is double of the angle made by the chord at any poin on the circumference)

Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Description : Two chords AB and CD of lengths 5 cm and 11 cm respectively of a circle are parallel to each other and are on opposite sides of its centre. If the A distance between AB and CD is 6 cm, find the radius of the circle. -Maths 9th

Last Answer : Join OA and OC. Let the radius of the circle be r cm and O be the centre Draw OP⊥AB and OQ⊥CD. We know, OQ⊥CD, OP⊥AB and AB∥CD. Therefore, points P,O and Q are collinear. So, PQ=6 cm. Let OP=x. Then, ... r2=52+(2.5)2=25+6.25=31.25 ⇒r2=31.25⇒r=5.6 Hence, the radius of the circle is 5.6 cm

Three girls Reshma, Salma and Mandeep are playing a game by standing on a circle of radius 5 m drawn in a park. -Maths 9th

Description : Three girls Reshma, Salma and Mandeep are playing a game by standing on a circle of radius 5 m drawn in a park. -Maths 9th

Last Answer : Solution :- Let R, S and M represent the position of Reshma, Salma and Mandeep respectively. Clearly △RSM is an isosceles triangle as RS = SM = 6m Join OS which intersect RM at A. In △ROS and △MOS OR = OM ( ... . ∴ RM = 2RA RM = 2 x 4.8 = 9.6m Hence, distance between Reshma and Mandeep is 9.6m.

AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre. Prove that -Maths 9th

Description : AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre. Prove that -Maths 9th

Last Answer : Draw OM perpendicular AB and ON perpendicular AC Join OA. In right △OAM, OA2 = OM2 + AM2 ⇒ r2 = p2 + (1/2AB)2 (Since,OM perpendicular AB, ∴ OM bisects AB ) ⇒ 1/4AB2 = r2 - p2 or AB2 = 4r2 - 4p2 ... ) and (ii), we have 4r2 - 4p2 = 16r2 - 16q2 or r2 - p2 = 4r2 - 4q2 or 4q2 = 3r2 + p2