What is the sum of the series 1,2,4,8,16,31.........till 1000 terms?

What is the sum of the series 1,2,4,8,16,31.........till 1000 terms?
by

1 Answer

Answer :

The question is somewhat wrong because it must be 1+2+4+8+16+32+....+1000th term However , now coming to the point        1+2+4+8+16+32+..+1000th term => 1+(21+22+23+24+....+2999 ) => 1+{2(2999 -1)}...This is the correct answer.  As we all know Sn= Summation of n number digits in a series is= 2(2n-1)
by

Related questions

What is the sum, of 'n' terms in the series : log m + log -Maths 9th

Description : What is the sum, of 'n' terms in the series : log m + log -Maths 9th

Last Answer : (d) log \(\bigg[rac{m^{(1+n)}}{n^{(n-1)}}\bigg]^{rac{n}{2}}\) S = log m + log \(rac{m^2}{n}\) + log \(rac{m^3}{n^2}\) + ...........n terms= log \(\bigg[\)m.\(rac{m^2}{n}\).\(rac{m^3}{n^2}\)........ ... 2}}}{n^{rac{n(n-1)}{2}}}\)\(\bigg]\) = log \(\bigg[rac{m^{(1+n)}}{n^{(n-1)}}\bigg]^{rac{n}{2}}\)

Find the sum of ‘n’ terms of the series : -Maths 9th

Description : Find the sum of ‘n’ terms of the series : -Maths 9th

Last Answer : (b) \(n\, ext{log}_2\big(rac{x}{y}\big)\)Given series= \( ext{log}_2\big(rac{x}{y}\big)\) + \( ext{log}_{2^2}\big(rac{x}{y}\big)^2\) + \( ext{log}_{2^3}\big(rac{x}{y}\big)^3\) + \( ext{log}_{2^4 ... \, ext{terms}\big)\)= \( ext{log}_2\big(rac{x}{y}\big)^n\) = \(n\, ext{log}_2\big(rac{x}{y}\big)\).

The sum of n terms of the series -Maths 9th

Description : The sum of n terms of the series -Maths 9th

Last Answer : (d) log \(\bigg(rac{2^{n+1}}{3^{n-1}}\bigg)^{rac{n}{2}}\) \(\displaystyle\sum_{x=1}^n\) log \(rac{2^x}{3^{x-1}}\) = log \(\big(rac{2^1}{3^0}\big)\) + log \(\big(rac{2^2}{3^1}\big)\) + log \(\big(rac{2^ ... }{2}}}{3^{rac{n(n-1)}{2}}}\bigg]\) = log \(\bigg[rac{2^{n+1}}{3^{n-1}}\bigg]^{rac{n}{2}}\)

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Description : 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50'. What number is missing? -Riddles

Last Answer : 22

Insert the missing number in the following: 2/3, 4/7, ? , 11/21, 16/31 (A) 10/8 (B) 6/10 (C) 5/10 (D) 7/13

Description : Insert the missing number in the following: 2/3, 4/7, ? , 11/21, 16/31 (A) 10/8 (B) 6/10 (C) 5/10 (D) 7/13

Last Answer : Answer: D 2/3 = 2/2*2-1, 4/7 = 4/4 *2-1, 11/21 = 11/11*2-1, and 16/31 = 16/16*2-1; Therefore 7/13= 7/7*2-1.

In the sequence of numbers 2/3, 4/7, X, 11/21, 16/31 The missing number X is: (A) 8/10 (B) 6/10 (C) 5/10 (D) 7/13

Description : In the sequence of numbers 2/3, 4/7, X, 11/21, 16/31 The missing number X is: (A) 8/10 (B) 6/10 (C) 5/10 (D) 7/13

Last Answer : Answer: D

lf the series 4,5,8,13,14,17,22,........ is continued in the same pattern, which one of the following is not a term of this series? (A) 31 (B) 32 (C) 33 (D) 35

Description : lf the series 4,5,8,13,14,17,22,........ is continued in the same pattern, which one of the following is not a term of this series? (A) 31 (B) 32 (C) 33 (D) 35

Last Answer : Answer: C

What two numbers have the sum of 31 and the product of 234?

Description : What two numbers have the sum of 31 and the product of 234?

Last Answer : The two numbers are 13 and 18

What are the numbers if the sum of two numbers is 31 and the product is 150?

Description : What are the numbers if the sum of two numbers is 31 and the product is 150?

Last Answer : 25 and 6.

What two numbers have the sum of 31 and the product of 234?

Description : What two numbers have the sum of 31 and the product of 234?

Last Answer : The two numbers are 13 and 18

What is the latest bonus rate from 31 Mar 2006? a) WLA continuing Rs 90/- per thousand rupees of sum assured b) EA continuing policies Rs 70/- per thousand rupees of sum assured c) AEA continuing Rs 65/- per thousand rupees of sum assured d) All the above

Description : What is the latest bonus rate from 31 Mar 2006? a) WLA continuing Rs 90/- per thousand rupees of sum assured b) EA continuing policies Rs 70/- per thousand rupees of sum assured c) AEA continuing Rs 65/- per thousand rupees of sum assured d) All the above

Last Answer : d) All the above

The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 years hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Description : The ages of Gaurav and Goutham will be in the ratio 5 : 7 after ten years from now and will be in the ratio 13 : 18 after twelve years from now. Find the ratio of the sum of their ages 10 years hence to the sum of their ages 12 ... hence. 1 : 25 : 27 2 : 13 : 15 3 : 14 : 17 4 : 18 : 23 5 : 30 : 31

Last Answer : 5 : 30 : 31

Mahela Jayawardene hit his sixth Test double century in the first Test of the series between India and Sri Lanka at Ahmedabad recently. Who holds the record of exceeding the score of 200 runs in an inning for the highest number of times in Test Cricket till date? a. Don Bradman b. Brian Lara c. Wally Hammond d. Marvan Atapattu e. Javed Miandad

Description : Mahela Jayawardene hit his sixth Test double century in the first Test of the series between India and Sri Lanka at Ahmedabad recently. Who holds the record of exceeding the score of 200 runs in an inning for ... a. Don Bradman b. Brian Lara c. Wally Hammond d. Marvan Atapattu e. Javed Miandad

Last Answer : a. Don Bradman

What is 31 percent as a fraction in lowest terms?

Description : What is 31 percent as a fraction in lowest terms?

Last Answer : It is 31/100.

What is the rule for the number pattern 1 6 16 31?

Description : What is the rule for the number pattern 1 6 16 31?

Last Answer : The rule is 5, 10, 15 and so the next number will be 20+31 =51

According to 1998 census the density of population in Balochistan Province is: A. 16 Persons per Sq. Km B. 18 Persons per Sq. Km C. 22 Persons per Sq. Km D. 31 Persons per Sq. Km

Description : According to 1998 census the density of population in Balochistan Province is: A. 16 Persons per Sq. Km B. 18 Persons per Sq. Km C. 22 Persons per Sq. Km D. 31 Persons per Sq. Km

Last Answer : ANSWER: B

According to 1998 census the density of population in Balochistan Province is: A. 16 Persons per Sq. Km B. 18 Persons per Sq. Km C. 22 Persons per Sq. Km D. 31 Persons per Sq. Km 15

Description : According to 1998 census the density of population in Balochistan Province is: A. 16 Persons per Sq. Km B. 18 Persons per Sq. Km C. 22 Persons per Sq. Km D. 31 Persons per Sq. Km 15

Last Answer : ANSWER: B

What is the gain, in dB of a helical antenna with diameter of λ/3, 10 turns at pitch of λ/4, used at 100 MHz? A. 16 B. 41.1 C. 31.4 D. 1.25

Description : What is the gain, in dB of a helical antenna with diameter of λ/3, 10 turns at pitch of λ/4, used at 100 MHz? A. 16 B. 41.1 C. 31.4 D. 1.25

Last Answer : A. 16

In Selective Repeat ARQ, if 5 is the number ofbits for the sequence number, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Description : In Selective Repeat ARQ, if 5 is the number ofbits for the sequence number, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 16

In Selective Repeat ARQ, if 5 is the number ofbits for the sequence number, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Description : In Selective Repeat ARQ, if 5 is the number ofbits for the sequence number, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 16

In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Description : In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the receive window mustbe _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 1

In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Description : In Go-Back-N ARQ, if 5 is the number of bits for thesequencenumber, then the maximum size of the send window must be _____ A) 15 B) 16 C) 31 D) 1

Last Answer : 31

1 15 16 31 47 78 125 ? a) 172 b) 203 c) 139 d) 167 e) None of these

Description : 1 15 16 31 47 78 125 ? a) 172 b) 203 c) 139 d) 167 e) None of these

Last Answer : 15 + 1 = 16 15 + 16 = 31 16 + 31 = 47 31 + 47 = 78 47 + 78 = 125 78 + 125 = 203 Answer: b)

Insert the missing number: 16/32, 15 /33, 17/31, 14/34, ? (A) 19/35 (B) 19/30 (C) 18/35 (D) 18/30

Description : Insert the missing number: 16/32, 15 /33, 17/31, 14/34, ? (A) 19/35 (B) 19/30 (C) 18/35 (D) 18/30

Last Answer : Answer: D 16/32 then 15/33 means -1/+1, 17/31 means +2/-2, 14/34 means -3/+3 next +4/-4 i.e 18/30

A coil is wound with 400 feet of No. 16 tinned copper wire and connected to a 12 volt battery. What is the current if the resistance per 1000 feet of No. 16 tinned copper wire is 4.26 ohms? A. 4.8 amps B. 7.06 amps C. 10.65 amps D. 11.27 amps

Description : A coil is wound with 400 feet of No. 16 tinned copper wire and connected to a 12 volt battery. What is the current if the resistance per 1000 feet of No. 16 tinned copper wire is 4.26 ohms? A. 4.8 amps B. 7.06 amps C. 10.65 amps D. 11.27 amps

Last Answer : Answer: B

A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Description : A two digit number exceeds forty percent of another two digit number by 16. If the sum of these two digit numbers is 72, which of the following is the difference between these two digit numbers ? a) 10 b) 6 c) 8 d) 14 e) None of these

Last Answer : c) 8 Let first two digit no. and second two digit no. be x and y respectively. x = y × 40/100 +16 x - 2y/5 = 16....(i) x + y = 72...(ii) From equation (i) and (ii) x = 32, y = 40 Difference = 8 Answer: c)

Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Description : Ratio of ages of three girls are 5:8:10, six years ago, the sum of their ages was 28. Find their present ages. a) 16,10,20 b) 12,28,36 c) 10,16,20 d) 16,28,36

Last Answer : C Let the present ages are 5x, 8x, 10x. => (5x-6) + (8x-6) + (10x-6) = 28 => 23x = 46 => x = 2 So their present ages are: 10,16,20

Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4

Description : Two students appeared at an examination. One of them secured 18marks more than the other and his marks was 72% of the sum of their marks. What are the marks obtained by them? a) 12.5,23.3 b) 26.7,16.0 c) 13.3,14.2 d) 11.45, 29.45 e) 29.8,15.4 

Last Answer : Answer: D  Let the marks secured by them be x and (x + 18)  Then sum of their marks = x + (x + 18) = 2x + 18  Given that (x + 18) was 72% of the sum of their marks  =>(x+18) = 72/100(2x+18)  => ... 11x = 126 x = 11.45  Then (x + 18) = 11.45 + 18 = 29.45  Hence their marks are 11.45 and 29.45

If somebody choose two digit and three digit numbers and their difference is 989.What will be their sum? a) 1000 b)1010 c) 1006?

Description : If somebody choose two digit and three digit numbers and their difference is 989.What will be their sum? a) 1000 b)1010 c) 1006?

Last Answer : None of the above. Let x be the three digit number and y be the two digit number. x - y =989. x = 989 + y. x is obviously greater than 989 and less than 1000 (since it is three digits). Since y is a two digit number ... 989 + 10 = 999. We can't go any higher, so x =999 and y=10. x+y = 999+10 = 1009

What is the sum of the integers 100 to 1000?

Description : What is the sum of the integers 100 to 1000?

Last Answer : Need answer

The total number of male, female and children working in a factory is 72. They earn Rs.16000 in a day. If the sum of the wages of all male, all female and all children is in the ratio of 36 : 20 : 24 and if the wages of an individual male, female and child is in the ratio 6 : 5 : 3, then how much a female earn in a day? a) Rs 500 b) Rs 1000 c) Rs 1500 d) Rs 1200

Description : The total number of male, female and children working in a factory is 72. They earn Rs.16000 in a day. If the sum of the wages of all male, all female and all children is in the ratio of 36 : 20 : 24 and if the ... 3, then how much a female earn in a day? a) Rs 500 b) Rs 1000 c) Rs 1500 d) Rs 1200

Last Answer : B Ratio of number of male, female and children =36/6:20/5:24/3 = 6x:4x:8x So, (6x + 4x + 8x) = 72 18x=72 X=72/18=4 So, x = 4 Therefore, number of female = 16 Share of all female =20/80*16000 =Rs 4000 So, Share of each female = 4000/4 = Rs 1000

A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share? A) Rs. 500 B) Rs. 1500 C) Rs. 2000 D) Rs.2500 E) NONE

Description : A sum of money is to be distributed among A, B, C, D in the proportion of 5:2:4:3. If C gets Rs. 1000 more than D, what is B's share? A) Rs. 500 B) Rs. 1500 C) Rs. 2000 D) Rs.2500 E) NONE

Last Answer : Answer: C Let the shares of A, B, C, D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively. Then, 4x−3x=1000 ⇒x=1000. B's share =Rs.2x=Rs.(2×1000)= Rs. 2000

A woman aged 25 years is diagnosed to be suffering from pulmonary tuberculosis. She is also 8 weeks pregnant. Antitubercular therapy for her should be: A. Started immediately B. Delayed till end of first trimester C. Delayed till end of second trimester D. Delayed till after confinement

Description : A woman aged 25 years is diagnosed to be suffering from pulmonary tuberculosis. She is also 8 weeks pregnant. Antitubercular therapy for her should be: A. Started immediately B. Delayed till end of first trimester C. Delayed till end of second trimester D. Delayed till after confinement

Last Answer : . Started immediately

Testosterone therapy started in a boy of 8 years and continued till puberty is likely to: A. Increase adult stature B. Reduce adult stature C. Have no effect on adult stature D. Cause hypertrophy of penis

Description : Testosterone therapy started in a boy of 8 years and continued till puberty is likely to: A. Increase adult stature B. Reduce adult stature C. Have no effect on adult stature D. Cause hypertrophy of penis

Last Answer : B. Reduce adult stature

In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg

Description : In a constant pressure process steam is generated from 10 bar and 0.8 dry condition till it become dry and saturated. Determine amount of heat added per kg of steam. From steam table at 10 bar Tsat = 179.9°C hf = 762.6 kl/kg, hg = 2776.2 kJ/kg 

Last Answer : Constant pressure process Final condition of steam is dry saturated Enthalpy of dry steam = hg= hf + hfg =2776.2 KJ/Kg .Given Latent heat of vaporization = hfg = hg - hf =2776.2-762.6 =2013.6 KJ/Kg Initial condition ... hfg = 762.6+0.8 X 2013.6 =2373.48 KJ/Kg Heat added = hg-hw = 402.72 KJ/kg

M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Description : M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last? a) 16days b) 18days c) 20 days d) 22 days

Last Answer : C Work done by M in 8 days = 1/40*8 =1/5 Remaining work = 1-1/5 = 4/5 (M+N)’s 1 day work = 1/40 + 1/24 =(3+5)/120 =8/120 =1/15 Now 1/15 work is done by M & N in 1 day. So 4/5 work will be done by X and Y is, =15 / 1 * 4/5 =12 days Hence total time taken = 12+8 = 20 days

Ratio of diameters of two shafts joined in series is 2. If the two shafts have the same material and the same length the ratio of their shear stresses is a. 2 b. 4 c. 8 d. 16

Description : Ratio of diameters of two shafts joined in series is 2. If the two shafts have the same material and the same length the ratio of their shear stresses is a. 2 b. 4 c. 8 d. 16

Last Answer : c. 8

Ratio of diameters of two shafts joined in series is 2. If the two shafts have the same material and the same length the ratio of their angles of twist is a. 2 b. 4 c. 8 d. 16

Description : Ratio of diameters of two shafts joined in series is 2. If the two shafts have the same material and the same length the ratio of their angles of twist is a. 2 b. 4 c. 8 d. 16

Last Answer : d. 16

Insert the missing number in the following series: 4 16 8 64 ? 256 (A) 16 (B) 24 (C) 32 (D) 20

Description : Insert the missing number in the following series: 4 16 8 64 ? 256 (A) 16 (B) 24 (C) 32 (D) 20

Last Answer : Answer: A Square root of 16 is 4, Square root of 64 is 8, Therefore Square root of 256 is 16.

Of the following terms, which is used to refer to a type of gestational trophoblastic neoplasm? a) Hydatidiform mole Hydatidiform mole occurs in 1 in 1000 pregnancies.

Description : Of the following terms, which is used to refer to a type of gestational trophoblastic neoplasm? a) Hydatidiform mole Hydatidiform mole occurs in 1 in 1000 pregnancies. b) Dermoid cyst A dermoid cyst is an ... d) Bartholin's cyst Bartholin's cyst is a cyst in a paired vestibular gland in the vulva.

Last Answer : a) Hydatidiform mole Hydatidiform mole occurs in 1 in 1000 pregnancies.

Finx the sum of coefficients of all the terms of the exapansin `(ax+y)^(n)`.

Description : Finx the sum of coefficients of all the terms of the exapansin `(ax+y)^(n)`.

Last Answer : Finx the sum of coefficients of all the terms of the exapansin `(ax+y)^(n)`. A. `""^(n)C_(0)+""^(n)C_(1)^ ... ""^(n)C_(n)` C. `2^(n)` D. None of these

The sum of the terms of an infinite geometric progression is denoted by `S=(a)/(1-r)`, change the subject as r.

Description : The sum of the terms of an infinite geometric progression is denoted by `S=(a)/(1-r)`, change the subject as r.

Last Answer : The sum of the terms of an infinite geometric progression is denoted by `S=(a)/(1-r)`, change the subject as r.

What does it mean if you cannot create a rectangle from a sum of terms?

Description : What does it mean if you cannot create a rectangle from a sum of terms?

Last Answer : It means that the sum is a Prime number. It says nothing aboutthe individual terms in the sum.

How do you Factor the sum of terms as a product of the gcf and a sum 36 plus 27?

Description : How do you Factor the sum of terms as a product of the gcf and a sum 36 plus 27?

Last Answer : GCF(36, 27) = 936 = 9*4 and 27 = 9*3So 36+27 = 9*(4+3).

What does the sum mean in math terms.?

Description : What does the sum mean in math terms.?

Last Answer : Sum is the same as add (an addition). For example, 5 + 4 = 9 is the sum of 5 and 4.

What Sum of the terms of Arithmetic Progression If a boy saved 25 on the first day 27 on the second day 29 the third day and so on how many days it will take him to save 880?

Description : What Sum of the terms of Arithmetic Progression If a boy saved 25 on the first day 27 on the second day 29 the third day and so on how many days it will take him to save 880?

Last Answer : On the 20th day, you would reach 880. ---------------------------------------- Sum(AP) = ½n(2a + (n-1)d) here: Sum(AP) = 880 a (first term) = 25 d (common difference) = 2 n (number of ... The sum of an AP can also be expressed as ½ Ã- n Ã- (first + last) since last = first + (n - 1) Ã- difference.

The sum of the first 12 terms of the arithmetic sequence tn=15-3n is?

Description : The sum of the first 12 terms of the arithmetic sequence tn=15-3n is?

Last Answer : tn=15-3nt1=15-3x1=12t2=15-3x2=9d=t2-t1/d=9-12=-3tn=t1+(n-1)xdtn=12+(12-1)x-312+11x-3=12+(-33)=-21=tnSn=n/2x(tn+t1)=S12=12/2 x(-21 +12)=6 x -9=-54

Sum of the powers of the concentration terms in the rate equation is called the __________ of the reaction. (A) Order (B) Overall order (C) Molecularity (D) None of these

Description : Sum of the powers of the concentration terms in the rate equation is called the __________ of the reaction. (A) Order (B) Overall order (C) Molecularity (D) None of these

Last Answer : (B) Overall order