If you could force one group of people to listen to you for 5 mins. which would you choose?

If you could force one group of people to listen to you for 5 mins. which would you choose?
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1 Answer

Answer :

Religious advocates. I’d pick government officials, but I don’t have enough ideas to speak for 5 minutes to them about.
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In a one Kilometer race A beats B by 28 meters or 7 seconds. Find out the time taken by A to finish the race. A. 4 Mins 3 secs B. 3 min 4 secs C. 5 mins D. 4 mins 20 secs

Description : In a one Kilometer race A beats B by 28 meters or 7 seconds. Find out the time taken by A to finish the race. A. 4 Mins 3 secs B. 3 min 4 secs C. 5 mins D. 4 mins 20 secs

Last Answer : ANSWER: A

In a one Kilometer race A beats B by 28 meters or 7 seconds. Find out the time taken by A to finish the race. A. 4 Mins 3 secs B. 3 min 4 secs C. 5 mins D. 4 mins 20 secs

Description : In a one Kilometer race A beats B by 28 meters or 7 seconds. Find out the time taken by A to finish the race. A. 4 Mins 3 secs B. 3 min 4 secs C. 5 mins D. 4 mins 20 secs

Last Answer : ANSWER: A

A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms? A.4 hrs B.4 hrs 5 mins C.4 1/2 hrs D.2 hrs E.None of these

Description : A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms? A.4 hrs B.4 hrs 5 mins C.4 1/2 hrs D.2 hrs E.None of these

Last Answer : Answer - C (4 1/2 hrs) Explanation - Distance covered in first 2 hours = (70 x 2) km = 140 km Distance covered in next 2 hours = (80 x 2) km = 160 km Remaining distance = 345 - (140 + 160) = 45 km. Speed in the ... ..1 hr 45km .? ?=45/90hr=1/2hr Total time taken = 2 + 2 +1/2=4 (1/2)hrs

A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Description : A 1800 km journey of 24 hrs, if 360km is done by van and the rest by train. It takes 60 mins more, if 600km is done by van and the rest by train. The ratio of the speed of the van to that of the train is. a) 2:4 b) 4:3 c) 3:4 d) 5:3

Last Answer : C Let the speed of the van be x km/hr And that of the train be y km/hr 360/x+1440/y = 24 --------------->A Dividing by 24 on both sides 15/x+60/y = 1 ---------1 And 600/x +1200/y =25 Dividing by ... 720/y =9 Y=80 Put y value in A 360/x = 24-18 X=360/6 X=60 Ratio of speeds = 60:80 = 3:4

In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins

Description : In covering a definite distance, the speeds of P & Q are in the ratio of 5:6. P takes 45 mins more than Q to reach the target. The time taken by P to reach the target is. a) 4 hrs 20 mins b) 4 hrs 45 mins c) 2hrs 30 mins d) 4hrs 30 mins

Last Answer : D Ratio of speeds = 5:6 Ratio of time =6:5 Suppose P takes 6x hrs and Q takes 5x hrs to reach the target. Then, 6x – 5x = 45/60 X=3/4 Time taken by P = 6x hrs =(6*3/4)hrs =4.5 hrs i.e., the time taken by P to reach the target is 4hrs 30mins

A bus can travel 25% faster than a van. Both start from a certain shop at the same time and reach poin P, 37.5 kms away from the shop at the same time time. On the way, however, the bus lost about 6.25 mins while shopping at the some such places. The speed of the van is. a) 72 b) 73 c) 74 d) 75

Description : A bus can travel 25% faster than a van. Both start from a certain shop at the same time and reach poin P, 37.5 kms away from the shop at the same time time. On the way, however, the bus lost about 6.25 mins while shopping at the some such places. The speed of the van is. a) 72 b) 73 c) 74 d) 75 

Last Answer : A Let speed of the car be x kmph The speed of the train = 125x/100 =5x/4 km/hr Therefore 37.5 / x – 37.5 /(5x/4) = 6.25 /60 37.5 / x – (37.5*4)/5x = 6.25 / 60 37.5 / x – 150 / 5x = 6.25 / 60 37.5 / x – 30/x = 6.25 / 60 7.5 / x = 6.25 / 60 6.25x = 7.5*60 X=72 km/hr

Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike speed is 20 km/hr and his walking speed is 1 km/hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Description : Senthil started bike at 5 a.m to reach a temple. After going temple, his bike went out of order. Consequently he rested for 45 mins and came back to his house walking all the way. Senthil reached home at 8 a.m. if bike ... /hr, then on bike he covered a distance of. a) 3.12 b) 2.76 c) 4.13 d) 2.14

Last Answer : D Time taken = 2 hr 15 mins = 2 ¼ hrs Time = 9/4 hrs Let the required distance be x km Then x/20 + x/1 = 9/4 (X+20x) / 20 = 9/4 21x / 20 = 9/4 84x = 180 X= 2.14 km Therefore the required diatance is 2.14 km

Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Description : Two pumps P & Q can fill a tank in 12 mins and 15 mins respectively while a third pipe R can empty the full tank in 6 mins. P & Q kept open for 5 mins in the beginning and then R is also opened. In what time is tank emptied? A) 30mins B) 35mins C) 40mins D) 45 mins

Last Answer : D Part filled in 5 min = 5(1/12 +1/15) = 5*9/60 = ¾ Part emptied in 1 min when all the pumps are opened, = 1/6 – (1/12 + 1/15) = 1/6 – 3/20 = 1/60 Now 1/60 is part emptied in 1 min Therefore ¾ part will be emptied in 60 * ¾ = 45 mins

3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is the proportion of solution C in the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

Description : 3 faucet A,B,C can fill a cistern from empty to full in 45mins, 35mins, and 25 mins respectively. When the cistern is empty all the 3 faucets are opened. A,B,c discharge chemical solutions A,B,C respectively. What is ... the liquid in the tank after 5 mins? A) 63/143 B) 72/151 c) 67/173 D) 81/167

Last Answer : A Part filled by (A+B+C) in 5 mins = 5(1/45 +1/35 + 1/25) = 5 (35+45+63/1575) = 143/315 Part filled by c in 5 mins = 5/25 = 1/5 Required ratio = 1/5 * 315/143 =63/143.

A motorboat running upstream takes 4 hrs 24 mins to cover a certain distance, while it takes 2hrs to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? A) 8:3 B) 5:2 C) 3:7 D) 2:4

Description : A motorboat running upstream takes 4 hrs 24 mins to cover a certain distance, while it takes 2hrs to cover the same distance running downstream. What is the ratio between the speed of the boat and speed of the water current respectively? A) 8:3 B) 5:2 C) 3:7 D) 2:4

Last Answer : ANSWER : A Explanation: Let the man's rate upstream be x'km/hr and downstream be y'km/hr Then distance covered upstream by 4hrs 24mints = distance covered by downstream in 2hrs (x * 4 2/5) = y *2 22x/5 = 2y Y = ... = (y+x/2) : (y -x/2) = 16x/10 : 6x/10 = 16x : 6x = 8:3

A boat man lakes 5hrs 30 mins to row a boat 30km downstream of a river and 4 hrs 15mints to cover a distance of 10km upstream. Find the speed of the river current in km/hr. A) 1.5 km/hr B) 3km/hr C) 5km/hr D) 7 km/hr

Description : A boat man lakes 5hrs 30 mins to row a boat 30km downstream of a river and 4 hrs 15mints to cover a distance of 10km upstream. Find the speed of the river current in km/hr. A) 1.5 km/hr B) 3km/hr C) 5km/hr D) 7 km/hr

Last Answer : ANSWER: A  Explanation:  Rate downstream = (30 / 5 ½ ) km/hr  = 30 / (11/2) km/hr  = 30 * 2 / 11 km/hr = 60/11 km/hr  Rate upstream = (10 / 4 ¼)km/hr  = 10 / (17/4)km/hr  = 10 * 4 / 17 km/hr = ...  Speed of current = 1 / 2 (a - b) km/hr  =1 / 2 (60 / 11 - 40 / 17)  = 1.5 km/hr (approx.)

A boat goes 3.5km upstream in 24 mins and the speed of the stream is 1.5km per hour, then the speed of the boat in still water is. A) 4.3 km/hr B) 7.4 km/hr C) 5.2km/hr D) 10.25km/hr

Description : A boat goes 3.5km upstream in 24 mins and the speed of the stream is 1.5km per hour, then the speed of the boat in still water is. A) 4.3 km/hr B) 7.4 km/hr C) 5.2km/hr D) 10.25km/hr

Last Answer : ANSWER: D  Explanation:  Speed of upstream = 3.5 / 24 km/min  = 3.5 / 24 * 60 km/hr = 8.75 km/hr  Speed of the stream = ½ (a - b)km/hr = 1.5 km/hr  1.5 = ½ ( a- 8.75)km/hr  a = 11.75 km/hr ... (a + b) km/hr  = ½ (11.75 + 8.75) = ½(20.5)  The speed of the boat in still water = 10.25 km/hr

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At a fuel check you have 60 US gallons (USG) of useable fuel remaining. Alternative fuel required is 12 USG. The flight time remaining is 1 hour 35 mins. What is the highest consumption rate acceptable?

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Description : What is the Total Elapsed Time on a VFR flight plan? a. From take-off to overhead destination b. From take-off to overhead destination + 15 mins c. From take-off to landing d. From taxi to arrival on the gate

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At a fuel check you have 60 US gallons (USG) of usable fuel remaining. Alternative fuel required is 12USG. The flight time remaining is 1 hour 35 mins. What is the highest consumption rate acceptable? a. 33.0 USG/Hr b. 37.9 USG/Hr c. 30.3 USG/Hr d. 21.3 USG/Hr

Description : At a fuel check you have 60 US gallons (USG) of usable fuel remaining. Alternative fuel required is 12USG. The flight time remaining is 1 hour 35 mins. What is the highest consumption rate acceptable? a. 33.0 USG/Hr b. 37.9 USG/Hr c. 30.3 USG/Hr d. 21.3 USG/Hr

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You make a diversion from the route given in the flight plan and land at an uncontrolled airfield. Within what time after landing should you inform ATC? a. 10 mins b. 20 mins c. 30 mins d. 45 mins

Description : You make a diversion from the route given in the flight plan and land at an uncontrolled airfield. Within what time after landing should you inform ATC? a. 10 mins b. 20 mins c. 30 mins d. 45 mins

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Pipe A can fill an empty tank in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins. If all of them work together, find the time taken to fill the tank? (a) 17 1/7 mins (b) 20 mins (c) 8 mins (d) none of these

Description : Pipe A can fill an empty tank in 20 minutes and Pipe B in 30 mins and Pipe C can empty the same in 40 mins. If all of them work together, find the time taken to fill the tank? (a) 17 1/7 mins (b) 20 mins (c) 8 mins (d) none of these

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What is the Total Elapsed Time on a VFR flight plan? a. From take-off to overhead destination b. From take-off to overhead destination + 15 mins c. From take-off to landing d. From taxi to arrival on the gate

Description : What is the Total Elapsed Time on a VFR flight plan? a. From take-off to overhead destination b. From take-off to overhead destination + 15 mins c. From take-off to landing d. From taxi to arrival on the gate

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At a fuel check you have 60 US gallons (USG) of usable fuel remaining. Alternative fuel required is 12USG. The flight time remaining is 1 hour 35 mins. What is the highest consumption rate acceptable? a. 33.0 USG/Hr b. 37.9 USG/Hr c. 30.3 USG/Hr d. 21.3 USG/Hr

Description : At a fuel check you have 60 US gallons (USG) of usable fuel remaining. Alternative fuel required is 12USG. The flight time remaining is 1 hour 35 mins. What is the highest consumption rate acceptable? a. 33.0 USG/Hr b. 37.9 USG/Hr c. 30.3 USG/Hr d. 21.3 USG/Hr

Last Answer : c. 30.3 USG/Hr

You make a diversion from the route given in the flight plan and land at an uncontrolled airfield. Within what time after landing should you inform ATC? a. 10 mins b. 20 mins c. 30 mins d. 45 mins

Description : You make a diversion from the route given in the flight plan and land at an uncontrolled airfield. Within what time after landing should you inform ATC? a. 10 mins b. 20 mins c. 30 mins d. 45 mins

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Which of the following procedures will not achieve sterilization: A. Hot air at 160ºC for 90mins B. Boiling water at 100ºC for 2 hours C. Autoclave at 121ºC under 15psi for 20 mins D. Dry heat at 177ºC for 60mins E. All of the above will achieve sterilisation

Description : Which of the following procedures will not achieve sterilization: A. Hot air at 160ºC for 90mins B. Boiling water at 100ºC for 2 hours C. Autoclave at 121ºC under 15psi for 20 mins D. Dry heat at 177ºC for 60mins E. All of the above will achieve sterilisation

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Which impression material should NOT be kept in water within on hour: (in another paper it was: 30 mins before pouring) A. Polyether B. Condensation silicone C. Polyvinyl silicone

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Write a program to declare class having data member as hrs, mins, secs. Write constructor to assign values and destructor to destroy values. Accept & display data for one object.

Description : Write a program to declare class having data member as hrs, mins, secs. Write constructor to assign values and destructor to destroy values. Accept & display data for one object.

Last Answer : #include<iostream.h> #include<conio.h> class time { private: int hrs, mins,sec; public: time(int h,int m,int s) { hrs=h; mins=m; sec=s; } ~time() { cout<< hours ... } }; void main() { time t(2,43,56); t.display(); getch(); }

2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Description : 2 pistol were shoot from the same place at an interval of 15 mins and 15 secs but a boy in the train approaching the place hears the second shot 15 mins after the first. The speed of the train(in km/hr),supposing that speed travels at 320 metres per second is. a) 15.166 b) 17.144 c) 18.563 d) 19.188

Last Answer : D Let the speed of the train be x m/sec Then distance travelled by the train in 15mins = distance travelled by sound in 15secs X*15*60 = 320*15 900x = 4800 X=4800/900 X=5.33 Speed of the train 5.33 m/s Convert m/s into km/hr 5.33m =(5.33*18/5) =(95.94/5) =19.188 km/hr

A goat is noticed by a lion from a distance of 350m. the goat starts running and the lion chases him. The goat and the lion run at the ratio of 30km and 31km per hr respectively. What is the distance between them after 12 mins? a) 120m b) 100m c) 150m d) 170m

Description : A goat is noticed by a lion from a distance of 350m. the goat starts running and the lion chases him. The goat and the lion run at the ratio of 30km and 31km per hr respectively. What is the distance between them after 12 mins? a) 120m b) 100m c) 150m d) 170m

Last Answer : C To find out the relative speed of the goat and lion (31-30) = 1 km/hr Distance covered in 12 mins =(1/60*12)km =1/5 km =(1000/5)m =200m Distance between the goat and lion = (350 – 200)m =150m

P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6

Description : P is thrice as fast as Q and Q is 4 times as fast as R. If the journey covered by R is 48 mins, then the time to be covered by Q. a) 12 b) 14 c) 10 d) 6 

Last Answer : A Let R's speed = x km/hr Then Q's speed = 4x km/hr P's speed = 12x km/hr Ratio of speeds of P<Q<R = 12x :4x:x =12:4:1 Ratio of time taken = 1/12: ¼:1 =1:3:12 If R ... mins, then Q takes 3 mins If R takes 48 mins, then Q takes =(3/12 *48)mins =(144/120mins =12mins

A van travels from namakkal to Madurai at a constant speed. If its speed were increased by 40km/hr it would have taken 1 hr lesser to cover the distance. It would have taken further 45 mins lesser if the speed was further increased by 40km/hr. what is distance between the 2 cities. a) 1680 b) B1660 c) 1670 d) 1675

Description : A van travels from namakkal to Madurai at a constant speed. If its speed were increased by 40km/hr it would have taken 1 hr lesser to cover the distance. It would have taken further 45 mins lesser if the speed ... by 40km/hr. what is distance between the 2 cities. a) 1680 b) B1660 c) 1670 d) 1675

Last Answer : A Let distance = x km Usual rate = y km/hr Then x/y - x/(y+40) =1 X(y+40) / y(y+40) = 1 Xy+40x - xy = y(y+40) 40x = y(y+40) ---------->1 x/y - x/y+80 = 7/4 x(y+80) - xy / y(y+ ... (y+80) / y(y+40) 8(y+40) = 7y + 560 8y +320 = 7y+560 Y=240 Substitute y value in 1 40x = 240*280 X=1680 km

A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Description : A girl covered a definite distance at same speed. Had she moved 6 km/hr faster, she would have taken 30 mins less. If she had moved 4 km/hr slower, she would have taken 30 mins more. The distance (in km) is. a) 50 b) 40 c) 70 d) 60

Last Answer : D Let distance = x km Rate = y km/hr x/y - x / (y+6) = 30/60 (x(y+6)-xy) / y(y+6) = ½ (xy +6x - xy) / y(y+6) = ½ 12x = y(y+6) ------------>1 And x/ (y-4) - x/y = 30/60 (Xy - x(y-4 ... = (y+6) / (y-4) 3y - 12 = 2y +12 Y = 24km Put y value in 1 we get 12x = 24 (24+6) 12x = 24 *30 X=60km

Two taps can fill a bunker in 40 and 48 mins respectively and a waste tap can empty 6 gallons per minute. All the 3 taps working together can fill the bunker in 30 mind. The capacity of the bunker is. A) 480 B) 480 C) 680 D) 780

Description : Two taps can fill a bunker in 40 and 48 mins respectively and a waste tap can empty 6 gallons per minute. All the 3 taps working together can fill the bunker in 30 mind. The capacity of the bunker is. A) 480 B) 480 C) 680 D) 780 

Last Answer : A Work done by the waste tap in 1 min = 1/30 – (1/40 + 1/48) = 8 – (6+5)/240 = 8-11/240 = -3/240 = -1/80 (negative sign means emptying) Volume of 1/80 part = 60 gallons Volume of whole = (6*80) = 480 gallons

A large cistern can be filled by 2 pipes P & Q in 120 mins and 80 mins respectively. How many mins will it take to fill the cistern from empty state if Q is used for half the time and P & Q fil it together for the other half? A) 2hrs B) 1hr C) 3hrs D) 4hrs

Description : A large cistern can be filled by 2 pipes P & Q in 120 mins and 80 mins respectively. How many mins will it take to fill the cistern from empty state if Q is used for half the time and P & Q fil it together for the other half? A) 2hrs B) 1hr C) 3hrs D) 4hrs

Last Answer : B Part filled by (P+Q) in 1 min = 1/120 + 1/80 =2+3/240 = 5/240 = 1/48 Suppose the cistern is filled in x mins then, x/2 (1/48 + 1/80) = 1 x/2(5+3/240)=1 8x/480 = 1 x=480/8 x= 60 mins or 1 hr

Two taps P and Q can separately fill a tank in 120mins and 150 mins respectively. There is a 3rd tap in the bottom of the tank to empty it. If all of the 3 taps are simultaneously opened, then the tank is full in 100 mins. In how much time the 3rd pipe alone can empty the tank? A) 100 B) 200 C) 300 D) 400

Description : Two taps P and Q can separately fill a tank in 120mins and 150 mins respectively. There is a 3rd tap in the bottom of the tank to empty it. If all of the 3 taps are simultaneously opened, then the tank is full ... . In how much time the 3rd pipe alone can empty the tank? A) 100 B) 200 C) 300 D) 400

Last Answer : B Work done by the 3 tap in 1 min = 1/100 – ( 1/120 + 1/150) = 1/100 – (5+4/600) =1/100 – 9/600 =6-9/600 = - 3/600 = - 1/200(negative signs mean empting) Therefore the 3rd tap alone can empty the tank in 200 mins

A barrier has four inlets A, B, C and D. The barrier can be filled in 24 minutes through the first three inlets and it can be filled in 30 minutes through the second, the third and fourth inlet also it can be filled through the first and the fourth inlet in 40 minutes. How much time required to fill up the barrier by all the four inlets? A) 10 mins B) 15 mins C) 20 mins D) 25 mins E) None of the Above

Description : A barrier has four inlets A, B, C and D. The barrier can be filled in 24 minutes through the first three inlets and it can be filled in 30 minutes through the second, the third and fourth inlet also it can be ... all the four inlets? A) 10 mins B) 15 mins C) 20 mins D) 25 mins E) None of the Above

Last Answer : C (1/A + 1/B + 1/C) = 1/24 …(i) (1/B + 1/C + 1/D) = 1/30 …(ii) (1/A + 1/D) = 1/40…(iii) From eqn (i) and (ii) (1/A – 1/D) = 1/120…(iv) From eqn (iii) and (iv) A=60,D=120. Let the time taken to full the tank = s S(1/A + 1/B +1/C +1/D)= 1 S(1/24+1/120) = 1 S= 20 mins

One tap can fill a cistern four times as fast as another tap. If together the two taps can fill the cistern in 48 mins then the slower tap alone will be able to fill the cisterns. A) 1hr B) 2hr C) 3hr D) 4hr

Description : One tap can fill a cistern four times as fast as another tap. If together the two taps can fill the cistern in 48 mins then the slower tap alone will be able to fill the cisterns. A) 1hr B) 2hr C) 3hr D) 4hr

Last Answer : D Let the slower tap alone fill the cistern in x mins Then faster tap will fill it in x/4 mins Therefore 1/x +4/x = 1/48 5/x = 1/48 X = 48*5 x = 240 mins x = 4 hrs.