Description : P, Q and R can do a piece of work in 18,24 and 36 days on the second day and P on the third day, again R on the fourth day and so on. Then in how, many days will the work be completed? 1. 25 2. 24 3. 22 4. 20 5. 26
Last Answer : 2;
Description : A contract is to be completed in 46 days and 117 men were set to work, each working 8 hours a day. After 33 days, 4/7 of the work completed. How many additional men may be employed so that the work may be completed in time, each man now working 9 hours a day? a) 79 b) 80 c) 81 d) 82 e) 83
Last Answer : work finished by 33 days = 33 117 8 = 30888 man hours 4/7th of the job is finished. remaining work = 1-(4/7) = 3/7 if 4/7th of the work is 30888 hours, then 3/7th of the work = [30888 ... 9 number of men = 198 since, 117 men are already working, additional men required = 198 - 117 = 81 Answer: c)
Description : A can build up a wall in 8 days while B can break it in 3 days. A has worked for 4 days and then B joined to work with A for another 2 days only. In how many days will A alone build up the remaining part of the wall? a) 13/3 days b) 22/3 days c) 7/4 days d) 7 days e) None of these
Last Answer : Amount of work done by A in one day = 1/8th of the total work B can break 1/3rd of the work in one day Therefore, if both of them are working together then the work done in one day = 1/8 - 1/3 = -5/24 ... = 11/12 Time taken by A to finish 11/12th of the work = 11/12 8 = 22/3 days Answer: b)
Description : 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days. a) 4 days b) 6 days c) 2 days d) 8 days e) 7 days
Last Answer : Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day = b Work done by 6 men and 8 women in 1 day = 1/10 => 6m + 8b = 1/10 => 60m + 80b = 1 --- (1) Work done by 26 men and 48 ... 1 day = 15/100 + 20/200 =1/4 => Time taken by 15 men and 20 women in doing the work = 4 days Answer: a)
Description : A and B working alone can finish a job in 5 days and 7 days respectively. They work at it alternately for a day. If A starts the work, find in how many days the job will be finished? a) 29/5 b) 11/5 c) 24/5 d) 21/5 e) None of these
Last Answer : Work done by A in one day = 1/5 and work done by B in one day = 1/7 They are working alternately. Therefore, Work done in first two day = (1/5 + 1/7) = 12/35 Work done in first four day = 24/35 Work done in ... = 4/35/1/7 = 4/5 of the day. Therefore Total days taken = 5 + 4/5 = 29/5 days Answer: b)
Description : A,B and C can do piece of work in 11 days,20 days and 55 days respectively, working alone. How soon can the work be done if a is assisted by B and C on alternate days/ a) 6 b) 7 c) 8 d) 9 e) 10
Last Answer : Work done by A and B in one day = 1/11 + 1/20 =31/220 Work done by A and C in one day = 1/11 + 1/55 =6/55 Work done in 2 days = 31 /220+6/55=55/220 = ¼ Hence, 1/4 of the work is done in 2 days Hence, it takes 8 days to finish the work Answer : c
Description : Ram, Suresh and Shilpa, working together, can do a piece of work in 1 day. Ram is thrice as efficient as Suresh, and Suresh takes twice the number of days as Shilpa takes to do it alone. What is the difference between ... and Shilpa, each working alone, to complete the work? a) 1 b) 2 c) 3 d) 4 e) 5
Last Answer : Let the time taken by Ram, Suresh and Shilpa to finish the work alone be A, B and C respectively Therefore, 1/A + 1/B + 1/C = 1 Also it is given that, A = B/3 and C =B/2 3/B + 1/B + ... between the number of days taken by Ram and Shilpa, each working alone, to complete the work = 3-2 = 1 Answer: a)
Description : Shweta deposits a certain amount on 1st January and 1st July (Same amount on both days) in a bank that offers 5% compound interest, compounded half-yearly. Shweta gains interest of Rs.121 at the end of the year. How much money did Shweta deposit? a) 1200 b) 1300 c) 1400 d) 1500 e) 1600
Last Answer : Let the amount be P Half yearly rate = 5/2 = 2.5% For the deposit on January, Amount = P (1 + 2.5 / 100)2 For the deposit on July, Amount = P (1 + 2.5 /100) We can solve the question by ... Amount in July = 1600 1.025 = 1640 So total interest = 81 + 40 = 121 Required answer is 1600 Answer: e)
Description : A man can do a piece of work in 10 days. With the help of a boy he can do the same piece of work in 8 days. If they get Rs. 11115 for the work then what will be the share of boys? a) Rs.2223 b) Rs.2784 c) Rs.3163 d) Rs.3312 e) None of these
Last Answer : In one day boys can do = (1/8) – (1/10) = (5-4)/10 = 1/40 part so, boys can finish the work in 40 days. Now, Men’s share : Boy’s share = 40 : 10 = 4 : 1 Boys share = (11115 / 5) × 1 = Rs. 2223 Answer is: a)
Description : Kathir and Anand can do a work in 20 days and 30 days respectively. Kathir started the work and left after 4 days. Anand took over and completed the work. In how many days was the total work completed? a) 28 days b) 20 days c) 23 days d) 25 days e) 26 days
Last Answer : a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days
Description : 8 men and 4 women-together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men ... more days will the work be completed? a) 7 days b) 6 days c) 5 days d) 8 days e) 4 days
Last Answer : 1 man = 2 women 8 men + 4 women = 20 women 2 day's work of 20 women = 20 × 6/1 = 20 × 2/x x =1/3 Remaining work = 1 – 1/3 = 2/3 Total number of females = 16 20 × 6/1 = 16 × x ÷2/ 3 x = 5 days Short Cut M1D1=M2D2+M3D3 10x6 =10x2 + 8 x 60-20= 8x x= 5 days Answer: c)
Description : A task was assigned to P, Q and R to be completed by not more than seven days. P alone can complete the task in ten days. Q alone can complete the task in twelve days and R alone can complete the task in fifteen days. ... will remain after four days? a) 3/10 b) 1/15 c) 1/9 d) 5/16 e) None of these
Last Answer : 1day's work of (P + Q+ R) = 1/10 + 1/12 +1/15 = 15/60 2 day's work of (P + Q+ R) = 15/60 × 2 = 1/2 1 day's work of (P+Q) = 1/10 +1/12 = 11/60 2 day's work of (P+Q) = 11/60 × 2 = 11/30 Rem. work of 4 days = 1- 1/2 + 11/30 = 2/15 Answer: e)
Description : 20 workers working 5hours a day can finish the work in 20 days.If the workers went to work for 4hours a day.How many more workers are required to complete the work in same 20days? 1)7 2)4 3)5 4)6
Last Answer : 3)5 Exp: workers required for 4h=>(5/4)×20=25. 25-20=5.
Description : One horsepower is equal to (A) 550 lbf.ft/second (B) 550 kgf.m/second (C) Both (A) and (B) (D) 550 lbf.ft./h
Last Answer : (A) 550 lbf.ft/second
Description : 75%of a number is equal to four-fifth of another number. What is the ratio between first number and the second number? a) 4:3 b) 30:32 c) 7:9 d) 16:15 e) None of these
Last Answer : Let the two number be x & y. According to question, 75/100 x : 4/5 y 3/4 x : 4/5 y 15x = 16y x /y = 16/15 Answer: d)
Description : Three consecutive numbers such that twice the first, 3 times the second and 4 times the third together make 182. The numbers in question are 1. 18, 22 and 23 2. 18, 19 and 20 3. 19, 20 and 21 4. 20, 21 and 22 5. 21, 22 and 23
Last Answer : Answer- 3( 19,20,21) Explanation:- let number be x,x+1,x+2 2x + 3(x+1)+4(x+2)=180 x=19 so numbers are 19,20,21
Description : One-fifth of a number is equal to 5/8th of another number. If 35 is added to the first number, it becomes four times of the second number. Find the second number. 1. 39 2. 70 3. 40 4. 25 5. None of these
Last Answer : Answer- 3(40) Explanation:- (1/5)x =(5/8)y………..1 if 35 is added to first no. , x + 35= 4y so,x= 4y -35 put in eq 1… (1/5)( 4y-35) = (5/8)y y=40 =second number
Description : There are two sets of five numbers each - set P and set Q. P is a set of consecutive even numbers and Q is a set of consecutive numbers. The sum of the numbers of P is 230. The second least number in Q is 33 less ... the sum of the numbers in Q. 1 : 260 2 : 250 3 : 240 4 : 270 5 : None of these
Last Answer : 1 : 260
Description : Ashwin purchased a second hand machine for Rs.1 lakh. Over the first year after its purchase. He incurred an expense of Rs.20000 in maintaining it. At the end of the first year he sold it for Rs.80000. Find his ... account of depreciation. a)12.5% profit b)12.5% loss c)11 1/9% profit d)11 1/9% loss
Last Answer : d)11 1/9% loss
Description : Of the four numbers, the first is twice the second, the second is one-third of the third and the third is 5 times the fourth. The average of the numbers is 24.75. The largest of these numbers is: A.45 B.25 C.30 D.45 E.None of these
Last Answer : Answer – D (45) Explanation – Let the fourth number be a then hen, third number = 5a, second number= 5a/3 and first=10a/3 a+ 5a+ 5a/3 + 10/3 = 24.75 x 4 so,a=9 So, the numbers are 9, 45, 15 and 30
Description : The marked price of a watch was Rs. 720.A man brought the same for Rs.550.80 after getting two successive discounts the first being 10% .What was the second discount rate? A. 12% B. 14% C. 15% D. 18%
Last Answer : Answer – C. 15% Explanation – Let the second discount rate be x% Then, (100 – x)% of 90% of 720 = 550.80 => (100 – x)/100 x 90/100 x 720 = 550.80 = (100-x) = [55080/(9 x 72) = 85 => x= 15 second discount rate =15%
Description : A train starts from Delhi and reaches Lucknow in 24.5 hours. If it travels the first half of journey at 30 kmph and second half at 40 kmph then what is the total distance it travelled? 1) 750 km 2) 800 km 3) 840 km 4) 900 km 5) 920 km
Last Answer : 3) 840 km
Description : The population of a city is 480000. It increases by 8% in the first year and decreased by 9% in the second year. What will be the population of city after two years? 1) 565056 2) 471744 3) 518400 4) 481344 5) 523200
Last Answer : 2) 471744
Description : 501/58 * 291/101 ÷ 31/155 = ? a) 140 b) 125 c) 95 d) 85 e) 110
Last Answer : Answer: b)
Description : 151.1% of 151.1 + 151.1 = ? a) 380 b) 400 c) 350 d) 420 e) 440
Last Answer : Answer: a)
Description : The population of city S increased from 650,000 in 2000 to 700,000 in 2010, and it is projected that the population will increase by the same number from 2010 to 2020. Approximately what is the projected percent increase in population from 2010 to 2020 ? a) 7.1% b) 7.7% c) 8.3% d) 14.3% e) 15.3%
Last Answer : Required percentage = (750000 - 700000)/700000 * 100 = 7.14% Answer: a)
Description : Nithish bought two purses which together cost him Rs.440. He sold one of the purse at a loss of 20% and the other one at a gain of 40%. The selling price of both purse are same. Then find out the cost price of both ... Rs.140 and Rs.300 c) Rs.170 and Rs.270 d) Rs.160 and Rs.280 e) None of the Above
Last Answer : 80/100 * x = 140/100 * y x = 7/4y x + y = 440 7/4 y + y = 440 y = 160 ; x = 280 Answer: d)
Description : Rosy buys Oats at Rs.10/kg and sell it in order to earn a profit of 40%. However, her faulty balance shows 1000gm when it is actually 800gm. What is her actual gain percentage? a) 35% b) 70% c) 75% d) 25% e) None of the Above
Last Answer : Let price of 1 kg rice = Rs.10. CP of 800 gm rice = Rs.8. She wants to earn a profit of 40% on per Kg SP = 10 + 40% of 10 = Rs. 14 per kg. Faulty balance shows 800 gm = 1000 gm (1 kg) She sells 800 gm for Rs.14. Profit = 14 – 8 = Rs. 6. Profit(%) = 6/8 * 100 = 75%. Answer: c)
Description : 3 7 6 28 9 112 12 ? a) 112 b) 448 c) 28 d) 38 e) None of these
Last Answer : First series: 3, 6, 9 (increased by 3) Second Series: 7, 28, 112, 448 (multiplied by 4) Answer: d)
Description : 187.5, 182, 171, ?, 132.5, 105, 72 a) 145.5 b) 155.5 c) 154.5 d) 144.5 e) None of these
Last Answer : The pattern is -5.5, -11, -16.5, -22 and so on. Answer: c)
Description : 12 17 32 57 ? 137 a) 98 b) 95 c) 37 d) 92 e) none of these
Last Answer : The pattern of the number series is 12+5×1=17, 17+5×3=32, 32+5×5=57 57+5×7=92, 92+5×9=137 Answer: d)
Description : The average speed of a train is 1 3/7 times the average speed of a car. The car covers a distance of 616 km in 8 hours. How much distance will the train cover in 13 hours? a) 1340 km b) 1423 km c) 1430 km d) 1936 km e) None of these
Last Answer : speed of the car = 616/8 = 77km/hr speed of the train = 10/7 × 77 = 110 km/hr Distance covered by train = 110 × 13 = 1430 km. Answer: c)
Description : Vinoth could get equal number of Rs. 55, Rs. 85 and Rs. 105 ticket for a Zoo. He spend Rs. 3920 for all the tickets. How many of each did he buy? a) 15 b) 18 c) 16 d) 26 e) None of these
Last Answer : Total money = 55x + 85x + 105x = 3920 245x = 3920 x = 16 Answer: c)
Description : A merchant dealer gives successive discounts of 10% and 20% in that order and makes a profit of 20%. what will be the profit if he offers a single flat discount of 30%? a) 20% b) 16.67% c) 18% d) 14% e) None of these
Last Answer : let marked price be 100. SP with 10%, 20% = 80% of (90% of 100) = 72. profit = 20% so CP = 72/1.20 = Rs. 60 by offering a flat discount of 30%, sales price = 70% of 100 = 70 profit = (70 - 60) ×100 / 60 = 16.67% Answer: b)
Description : In 10 years time, Ram will be 2 times older than his son. 5 years ago he was 9 times as old as his son. What will be the sum of the ages of Ram and his son 3 years from now? a) 46 b) 66 c) 86 d) 76 e) None of these
Last Answer : Let current age of Ram and his son be R,S (R + 10) = 3(S + 10) [2 times older = 3 times the age] R = 3S + 20 (R - 5) = 9(S - 5) 3S + 20 – 5= 9S – 45 3S + 15 = 9S – 45 or S = 10., R = 50 sum of ages 3 years from now = 10 + 3 + 50 + 3 = 66. Answer: b)
Description : Four years ago, the average of a 4 member family was 40 years. 3 years ago, a boy got married to a 23 years old girl, and they had a baby boy last year. what is the average of the family 2 years from now assuming no ... leaves from the family in the next 2 years. a) 40 b) 42.5 c) 36.5 d) 34 e) 35.8
Last Answer : Four years ago, sum of all the family members age = 4× 40 = 160 three years ago, sum of all the family members age = 164 + 23 = 187 last year, sum = 197 (187 + 5 + 5) two years from now, sum = 197 + 18 = 215 hence, average = 215/6 = 35.8 Answer: e)
Description : Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut? a) 4 hours b) 3 hours c) 6 hours d) 8 hours e) 10 hours
Last Answer : portion of the tank filled by the pipe A in 1 hour = ½ of the tank let the portion of the tank emptied because of the leak in 1 hour be 1/x of the tank therefore, in 1 hour , portion of the tank filled = 1/2 - 1 ... 1/2 - 1/x = 1/2.5 or x = 10 hence, it takes 10 hours to empty a full tank Answer: e)
Description : An amount becomes 160% of itself in 5 years through simple interest. At the same rate of interest, how long will it take for the amount to more than double itself if we use compound interest? a) 7 b) 8 c) 9 d) 10 e) cannot be determined
Description : Ashwini has a certain number of Pencils she wishes to distribute in the class. when she tries to distribute 7 pencils to each student, 3 pencils are left out. if the class had 3 less students, each student would have ... How many pencils does Ashwini have? a) 90 b) 120 c) 140 d) 160 e) None of these
Last Answer : Let number of students be X. so, total Pencils = 7X + 3 7X + 3 = (7+2) (X-3) or., 7X + 3 = 9X – 27 or X = 15 total Pencils = 7X + 3 = 108 Answer: e)
Description : The LCM of two numbers is 45 times their HCF. If one of the numbers is 125 and the sum of HCF and LCM is 1150, then the other number is? a) 100 b) 125 c) 250 d) 225 e) 180
Last Answer : LCM = 45× HCF LCM + HCF = 46× HCF = 1150 HCF = 25, LCM =1125. product of 2 numbers = LCM×HCF required number = (25× 1125) / 125 = 225. Answer: d)
Description : A man who makes a profit of 25 percent by selling sugar at Rs. 4.25/kg., lowers his price so as to gain only 5 paise per Kg. In what ratio must his sales be increased so that his total profit may be the same as before? a) 1 : 5 b) 1 : 11 c) 1 : 13 d) 1 : 17 e) 1 : 21
Last Answer : 125% C.P. of sugar per kg = Rs. 4.25 C.P of the sugar per kg = [4.25×100] / 125 = Rs. 3.40. thus, the profit on 1 kg 85 paise by reducing price to 5 paise, to make same profit he must sell, 85/5 = 17kg so required ratio = 1 : 17. Answer: d)
Description : All the words of OLIVE are arranged in dictionary order. Find the position of the word LIVEO. a) 49 b) 55 c) 57 d) 59 e) 61
Last Answer : words starting with E = 4! = 24 words starting with I = 4! = 24 words starting with LE = 3! = 6 words starting with LIE = 2! = 2, LIO = 2! = 2 the first word with starting with LIV will be LIVEO so rank = 24 + 24 + 6 + 2 + 2 + 1 = 59 Answer: d)
Description : What is the remainder when positive integer p' is divided by 3? (A) p' is an even number (B) p' is a perfect square a) If statement (A) alone is sufficient to answer the ... sufficient to answer the question e) If the two statements taken together are still not sufficient to answer the question.
Last Answer : Using (A), we can have p' as 2/4/6/8 etc. we cant determine remainder when divided by 3. Using (B), we can have p' as 1/4/9/16 etc. we cant determine remainder when divided by 3. Using ... be 1/0 (4/16 leave remainder 1, 36 remainder 0). So, we cant determine using both statements. Answer: e)
Description : Is p>q? (A) 0
Last Answer : We can have p = 0.45, and q = 0.41. here p>q We can also have p = 0.45,and q = 10. Here pq. Answer: e)
Description : What is the wholesale cost of a dress? a. The dress was listed at a price that would have given the store a profit of 20 percent of the wholesale cost. b. After as 10% discount on the list price ... question. e) If the data in statement a, b and c together are not sufficient to answer the question.
Last Answer : Let C be the wholesale price, listed Price be P. from (a), P = 1.2C From (b), 0.9P = C + 10. Using statement (a), 1.2C = C + 10, from this we can determine C. From (C), ... even if we combine information from other statements. So (a) and (b) together are sufficient to answer the question. Answer: c)
Description : What is the average score in an exam taken by 500 students where the minimum score is 200? a. Half the students scored above 700. b. Half the students scored below 700. c. The maximum score in the ... . e) If the data in statement a, b and c together are not sufficient to answer the question.
Last Answer : The fact that half scored above 700, and other half less than 700 does not tell the actual distribution of scores to calculate the average. Statement (c) also does not help us determine the average. Answer: e)
Description : Is X divisible by 12? a. X leaves a remainder 2 when divided by 8 b. X is divisible by 3. c. X is divisible by 6. a) If the data in statement a is sufficient to answer the question, while ... the question. e) If the data in statement a, b and c together are not sufficient to answer the question.
Last Answer : From (a), we notice that the number is of the form 8n+2, which means it also leaves a remainder 2 on being divided by 4. So, its not divisible by 12. From (b) and (c) together, the number can be any multiple of 6, from which we cant conclusively say if number is divisible by 12. Answer: a)
Description : 5287 – 176.22 – 78.584 = ? a) 5023.196 b) 5032.196 c) 5302.196 d) 5203.196 e) None of these
Last Answer : 5287 – 176.22 – 78.584 = 5032.196 Answer: b)
Description : 0.003 × ? × 0.0003 = 0.00009 a) 10 b) 3 c) 0.03 d) 0.003 e) None of these
Last Answer : ? = 0.00009 / 0.003 × 0.0003 = 100 Answer: e)