Concentration of the limiting reactant (with initial concentration
of a moles/litre) after time t is (a-x). Then 't' for a first order reaction is
given by
(A) k. t = ln a/(a - x)
(B) k. t = x/a (a - x)
(C) k. t = ln (a - x)/a
(D) k. t = ln a (a - x)/x

1 Answer

Answer :

(A) k. t = ln a/(a - x)

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