Gibbs-Helmholtz equation is (A) ∆F = ∆H + T [∂(∆F)/∂T]P (B) ΔF = ΔH - TΔT (C) d(E - TS) T, V < 0 (D) dP/dT = ∆Hvap/T.∆Vvap

Gibbs-Helmholtz equation is
(A) ∆F = ∆H + T [∂(∆F)/∂T]P
(B) ΔF = ΔH - TΔT
(C) d(E - TS) T, V < 0
(D) dP/dT = ∆Hvap/T.∆Vvap
by

1 Answer

Answer :

(A) ∆F = ∆H + T [∂(∆F)/∂T]P
by

Related questions

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Description : The specific surface of spherical particles is proportional to (where, Dp = diameter of particle). (A) D2 p (B) Dp (C) 1/Dp (D) 1/D2p

Last Answer : (C) 1/Dp

A second order liquid phase reaction, A → B, is carried out in a mixed flow reactor operated in semi batch mode (no exit stream). The reactant A at concentration CAF is fed to the reactor at a volumetric flow rate of F. The volume of the reacting mixture is V and the density of the liquid mixture is constant. The mass balance for A is (A) d(VCA )/dt = -F (CAF - CA ) - kCA 2V (B) d(VCA )/dt = F (CAF - CA ) - kCA 2V (C) d(VCA )/dt = -FCA - kCA 2V (D) d(VCA )/dt = FCAF - kCA 2V

Description : A second order liquid phase reaction, A → B, is carried out in a mixed flow reactor operated in semi batch mode (no exit stream). The reactant A at concentration CAF is fed to the reactor at a volumetric flow rate of F. The volume ... 2V (C) d(VCA )/dt = -FCA - kCA 2V (D) d(VCA )/dt = FCAF - kCA 2V

Last Answer : (D) d(VCA )/dt = FCAF - kCA 2V

Find the Maxwell equation derived from Faraday’s law. a) Div(H) = J b) Div(D) = I c) Curl(E) = -dB/dt d) Curl(B) = -dH/dt

Description : Find the Maxwell equation derived from Faraday’s law. a) Div(H) = J b) Div(D) = I c) Curl(E) = -dB/dt d) Curl(B) = -dH/dt

Last Answer : c) Curl(E) = -dB/dt