The Maxwell relation derived from the differential expression for the Helmholtz free energy (dA) is (A) (∂T/∂V)S = - (∂P/∂S)V (B) (∂S/∂P)T = - (∂V/∂T)P (C) (∂V/∂S)P = (∂T/∂P)S (D) (∂S/∂V)T = (∂P/∂T)V

The Maxwell relation derived from the differential expression for the
Helmholtz free energy (dA) is
(A) (∂T/∂V)S = - (∂P/∂S)V
(B) (∂S/∂P)T = - (∂V/∂T)P
(C) (∂V/∂S)P = (∂T/∂P)S
(D) (∂S/∂V)T = (∂P/∂T)V
by

1 Answer

Answer :

(D) (∂S/∂V)T = (∂P/∂T)V
by

Related questions

Maxwell's relation corresponding to the identity, dH = dS = Vdp + ∑μi dni is (A) (∂T/∂V)S, ni = -(∂P/∂S)V, ni (B) (∂S/∂P)T, ni = (∂V/∂T)P, ni (C) (∂S/∂V)T, ni = (∂P/∂T)V, ni (D) (∂T/∂P)S, ni = (∂V/∂S)P, ni

Description : Maxwell's relation corresponding to the identity, dH = dS = Vdp + ∑μi dni is (A) (∂T/∂V)S, ni = -(∂P/∂S)V, ni (B) (∂S/∂P)T, ni = (∂V/∂T)P, ni (C) (∂S/∂V)T, ni = (∂P/∂T)V, ni (D) (∂T/∂P)S, ni = (∂V/∂S)P, ni

Last Answer : (D) (∂T/∂P)S, ni = (∂V/∂S)P, ni

Which of the following identities can be most easily used to verify steam table data for superheated steam? (A) (∂T/∂V)S = (∂p/∂S)V (B) (∂T/∂P)S = (∂V/∂S)P (C) (∂P/∂T)V = (∂S/∂V)T (D) (∂V/∂T)P = -(∂S/∂P)T

Description : Which of the following identities can be most easily used to verify steam table data for superheated steam? (A) (∂T/∂V)S = (∂p/∂S)V (B) (∂T/∂P)S = (∂V/∂S)P (C) (∂P/∂T)V = (∂S/∂V)T (D) (∂V/∂T)P = -(∂S/∂P)T

Last Answer : D) (∂V/∂T)P = -(∂S/∂P)T

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Description : Which is not constant for an ideal gas? (A) (∂P/∂V)T (B) (∂V/∂T)P (C) (∂P/∂V)V (D) All (A), (B) & (C)

Last Answer : (A) (∂P/∂V)T

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The equation relating E, P, V and T which is true for all substances under all conditions is given by (∂E/∂V)T = T(∂P/∂T)H - P. This equation is called the (A) Maxwell's equation (B) Thermodynamic equation of state (C) Equation of state (D) Redlich-Kwong equation of state

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On a P-V diagram of an ideal gas, suppose a reversible adiabatic line intersects a reversible isothermal line at point A. Then at a point A, the slope of the reversible adiabatic line (∂P/∂V)s and the slope of the reversible isothermal line (∂P/∂V)T are related as (where, y = Cp/Cv) (A) (∂P/∂V)S = (∂P/∂V)T (B) (∂P/∂V)S = [(∂P/∂V)T]Y (C) (∂P/∂V)S = y(∂P/∂V)T (D) (∂P/∂V)S = 1/y(∂P/∂V)T

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P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

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P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of the sides AB, BC, CD and DA of a quadrilateral ABCD in which AC = BD. -Maths 9th

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P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

Description : P, Q, R and S are respectively the mid-points of sides AB, BC, CD and DA of quadrilateral ABCD in which AC = BD and AC ⊥ BD. Prove that PQRS is a square. -Maths 9th

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ABCD is a rectangle and p q r s are the mid points of the side AB BC CD AND DA respectively. Show that the quadrilateral PQRS is a rhombus -Maths 9th

Description : ABCD is a rectangle and p q r s are the mid points of the side AB BC CD AND DA respectively. Show that the quadrilateral PQRS is a rhombus -Maths 9th

Last Answer : This answer was deleted by our moderators...

If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th

Description : If ABCD is a rectangle and P, Q, R and S are the mid-points of the sides AB, BC, CD and DA respectively, then quadrilateral PQRS is a rhombus. -Maths 9th

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ABCD is a square. P, Q, R, S are the mid-points of AB, BC, CD and DA respectively. By joining AR, BS, CP, DQ, we get a quadrilateral which is a -Maths 9th

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Last Answer : According to the given statement, the figure will be a shown alongside; using mid-point theorem: In △ABC,PQ∥AC and PQ=21 AC .......(1) In △ADC,SR∥AC and SR=21 AC .... ... are perpendicular to each other) ∴PQ⊥QR(angle between two lines = angle between their parallels) Hence PQRS is a rectangle.

Under which of the following conditions is the relation, `Delta H = Delta E + P Delta V` valid for a system :-

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Last Answer : Under which of the following conditions is the relation, `Delta H = Delta E + P ... and pressure D. Constant temperature, pressure and composition

For one dimensional flow of an incompressible fluid in unsteady state in x-direction, the continuity equation is given by (A) ∂u/∂x = 0 (B) ∂(ρu)/∂x = 0 (C) (∂u/∂x) = - (∂ρ/∂t) (D) ∂ρ/∂t = 0

Description : For one dimensional flow of an incompressible fluid in unsteady state in x-direction, the continuity equation is given by (A) ∂u/∂x = 0 (B) ∂(ρu)/∂x = 0 (C) (∂u/∂x) = - (∂ρ/∂t) (D) ∂ρ/∂t = 0

Last Answer : (A) ∂u/∂x = 0

As the temperature is lowered towards the absolute zero, the value of ∂(∆F)/∂T, then approaches (A) Unity (B) Zero (C) That of the heat of reaction (D) Infinity

Description : As the temperature is lowered towards the absolute zero, the value of ∂(∆F)/∂T, then approaches (A) Unity (B) Zero (C) That of the heat of reaction (D) Infinity

Last Answer : B) Zero

As the temperature is lowered towards the absolute zero, the value of the quantity (∂∆F/∂T) approaches (A) Zero (B) Unity (C) Infinity (D) None of these

Description : As the temperature is lowered towards the absolute zero, the value of the quantity (∂∆F/∂T) approaches (A) Zero (B) Unity (C) Infinity (D) None of these

Last Answer : (A) Zero