what- KN, LN?

what- KN, LN?
by

1 Answer

Answer :

5.2 cm
by

Related questions

ln your dream, Voldemort is chasing you. 'Avada Kedavra!' he cries. The light is two feet away from you. How do you get away? -Riddles

Description : ln your dream, Voldemort is chasing you. 'Avada Kedavra!' he cries. The light is two feet away from you. How do you get away? -Riddles

Last Answer : Wake up.

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

X and Y are points on the side LN of the triangle LMN such that LX = XY = YN. -Maths 9th

Description : X and Y are points on the side LN of the triangle LMN such that LX = XY = YN. -Maths 9th

Last Answer : Given X and Y are points on the side LN such that LX = XY = YN and XZ || LM To prove ar (ΔLZY) = ar (MZYX) Proof Since, ΔXMZ and ΔXLZ are on the same base XZ and between the same parallel lines LM and XZ. ... get ar (ΔXMZ) + ar (ΔXXZ) = ar (ΔXLZ) + ar (ΔXYZ) => ar (MZYX) = ar (ΔLZY) Hence proved.

X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Description : X and y are points on the side LN of the triangle LMN , such that LX = XY = YN . Through X, a line is drawn parallel to LM to meet MN at Z. -Maths 9th

Last Answer : Here, △XZM and △XZL are on the same base (XZ) and lie between the same parallels (XZ || LM). ∴ ar(△XZL) = ar( △XZM) Adding ar(△XZY) on both sides , we have ar(△XZL) + ar(△XZY) = ar(△XZM) + ar(△XZY) ⇒ ar(△LZY) = ar(quad.MZYX)

X and Y are points on the side LN of the triangle LMN such that LX = XY = YN. -Maths 9th

Description : X and Y are points on the side LN of the triangle LMN such that LX = XY = YN. -Maths 9th

Last Answer : Given X and Y are points on the side LN such that LX = XY = YN and XZ || LM To prove ar (ΔLZY) = ar (MZYX) Proof Since, ΔXMZ and ΔXLZ are on the same base XZ and between the same parallel lines LM and XZ. ... get ar (ΔXMZ) + ar (ΔXXZ) = ar (ΔXLZ) + ar (ΔXYZ) => ar (MZYX) = ar (ΔLZY) Hence proved.

In the given figure, YZ is parallel to MN, XY is parallel is LM and XZ is parallel to LN. Then MY is -Maths 9th

Description : In the given figure, YZ is parallel to MN, XY is parallel is LM and XZ is parallel to LN. Then MY is -Maths 9th

Last Answer : answer:

Pick out the correct statement. (A) Plastic chips are called non-cohesive solids (B) Kick's crushing law is, P/m = K . ln (D̅sa /Ds̅b ) (C) Communition is a generic term for size enlargement operation (D) Energy required in kwh per ton of product, such that 80% of it passes through a 200 mesh screen, is called 'Work index'

Description : Pick out the correct statement. (A) Plastic chips are called non-cohesive solids (B) Kick's crushing law is, P/m = K . ln (D̅sa /Ds̅b ) (C) Communition is a generic term for size enlargement ... per ton of product, such that 80% of it passes through a 200 mesh screen, is called 'Work index'

Last Answer : (B) Kick's crushing law is, P/m = K . ln (D̅sa /Ds̅b )

. Which of the following equations is Rittinger's crushing law? (Where P = power required by the machine, m = feed rate, k = a constant, Ds̅a & D̅sb = volume surface mean diameter of feed & product respectively.) (A) P/m = K/ √Dp (B) P/m = K . ln D̅sa /D̅sb (C) P/m = K . (1/ D̅sb - 1/Ds̅a ) (D) None of these

Description : . Which of the following equations is Rittinger's crushing law? (Where P = power required by the machine, m = feed rate, k = a constant, Ds̅a & D̅sb = volume surface mean diameter of feed & product respectively.) (A) P/m = K/ ... K . ln D̅sa /D̅sb (C) P/m = K . (1/ D̅sb - 1/Ds̅a ) (D) None of these

Last Answer : (C) P/m = K . (1/ D̅sb - 1/Ds̅a )

A lake starts freezing because of the cold atmosphere. It will first freeze A. At the bottom B. ln the middle pan C. At the top surface (Answer) D. Uniformly throughout the water body

Description : A lake starts freezing because of the cold atmosphere. It will first freeze A. At the bottom B. ln the middle pan C. At the top surface (Answer) D. Uniformly throughout the water body

Last Answer : C. At the top surface (Answer)

Out of the following four assumptions used in the derivation of theequation for LMTD[LMTD = (∆t1- ∆t2)/ln(∆t1/∆t2)], which one is subject to the largest deviationin practice ?(A) Constant overall heat transfer co-efficient.(B) Constant rate of fluid flow(C) Constant specific heat(D) No partial phase change in the system

Description : Out of the following four assumptions used in the derivation of theequation for LMTD [LMTD = (∆t1 - ∆t2 )/ln(∆t1 /∆t2 )], which one is subject to the largest deviation in practice ? (A) Constant ... (B) Constant rate of fluid flow (C) Constant specific heat (D) No partial phase change in the system

Last Answer : (B) Constant rate of fluid flow

In under damped vibrating system, if x1 and x2 are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to a) x1/x2 b) log (x1/x2) c) ln (x1/x2) d) log (x1.x2)

Description : In under damped vibrating system, if x1 and x2 are the successive values of the amplitude on the same side of the mean position, then the logarithmic decrement is equal to a) x1/x2 b) log (x1/x2) c) ln (x1/x2) d) log (x1.x2)

Last Answer : c) ln (x1/x2)

ln which season is the highest yield of Maize obtained (a) Zaid (b) Kharif (c) Rabi (d) All of these

Description : ln which season is the highest yield of Maize obtained (a) Zaid (b) Kharif (c) Rabi (d) All of these

Last Answer : (b) Kharif

The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is given by a) L = μd ln(b/a)/2π b) L = 2π μd ln(b/a) c) L = πd/ln(b/a) d) L = 0

Description : The inductance of a coaxial cable with inner radius a and outer radius b, from a distance d, is given by a) L = μd ln(b/a)/2π b) L = 2π μd ln(b/a) c) L = πd/ln(b/a) d) L = 0

Last Answer : a) L = μd ln(b/a)/2π

The potential of a uniformly charged line with density λ is given by, λ/(2πε) ln(b/a). State True/False. a) True b) False

Description : The potential of a uniformly charged line with density λ is given by, λ/(2πε) ln(b/a). State True/False. a) True b) False

Last Answer : a) True

Concentration of the limiting reactant (with initial concentration of a moles/litre) after time t is (a-x). Then 't' for a first order reaction is given by (A) k. t = ln a/(a - x) (B) k. t = x/a (a - x) (C) k. t = ln (a - x)/a (D) k. t = ln a (a - x)/x

Description : Concentration of the limiting reactant (with initial concentration of a moles/litre) after time t is (a-x). Then 't' for a first order reaction is given by (A) k. t = ln a/(a - x) (B) k. t = x/a (a - x) (C) k. t = ln (a - x)/a (D) k. t = ln a (a - x)/x

Last Answer : (A) k. t = ln a/(a - x)

The conversion XA and residence time data are collected for zero order liquid phase reaction in a stirred tank reactor. Which of the following will be a straight line? (A) XA Vs . τ (B) XA Vs ln τ (C) XA /(1 - XA )Vs τ (D) XA (1 - XA )Vs τ

Description : The conversion XA and residence time data are collected for zero order liquid phase reaction in a stirred tank reactor. Which of the following will be a straight line? (A) XA Vs . τ (B) XA Vs ln τ (C) XA /(1 - XA )Vs τ (D) XA (1 - XA )Vs τ

Last Answer : (A) XA Vs . τ

Half life period of a first order irreversible reaction A → B is (A) k/2 (B) ln k/2 (C) ln 2/k (D) ln 0.5/k

Description : Half life period of a first order irreversible reaction A → B is (A) k/2 (B) ln k/2 (C) ln 2/k (D) ln 0.5/k

Last Answer : (C) ln 2/k

What is the value of ln y (where y = activity co-efficient) for ideal gases? (A) Zero (B) Unity (C) Infinity (D) Negative

Description : What is the value of ln y (where y = activity co-efficient) for ideal gases? (A) Zero (B) Unity (C) Infinity (D) Negative

Last Answer : (A) Zero

For an ideal gas, the chemical potential is given by (A) RT d ln P (B) R d ln P (C) R d ln f (D) None of these

Description : For an ideal gas, the chemical potential is given by (A) RT d ln P (B) R d ln P (C) R d ln f (D) None of these

Last Answer : (A) RT d ln P

The expression for entropy change, ΔS = n Cp. ln (T2/T1), is valid for the __________ of a substance. (A) Simultaneous pressure & temperature change (B) Heating (C) Cooling (D) Both (B) and (C)

Description : The expression for entropy change, ΔS = n Cp. ln (T2/T1), is valid for the __________ of a substance. (A) Simultaneous pressure & temperature change (B) Heating (C) Cooling (D) Both (B) and (C)

Last Answer : (D) Both (B) and (C)

For a real gas, the chemical potential is given by (A) RT d ln P (B) RT d ln f (C) R d ln f (D) None of these

Description : For a real gas, the chemical potential is given by (A) RT d ln P (B) RT d ln f (C) R d ln f (D) None of these

Last Answer : (B) RT d ln f

The free energy change for a chemical reaction is given by (where, K = equilibrium constant) (A) RT ln K (B) -RT ln K (C) -R ln K (D) T ln K

Description : The free energy change for a chemical reaction is given by (where, K = equilibrium constant) (A) RT ln K (B) -RT ln K (C) -R ln K (D) T ln K

Last Answer : (B) -RT ln K

The expression for entropy change given by, ΔS = - nR ln (P2/P1), holds good for (A) Expansion of a real gas (B) Reversible isothermal volume change (C) Heating of an ideal gas (D) Cooling of a real gas

Description : The expression for entropy change given by, ΔS = - nR ln (P2/P1), holds good for (A) Expansion of a real gas (B) Reversible isothermal volume change (C) Heating of an ideal gas (D) Cooling of a real gas

Last Answer : (B) Reversible isothermal volume change

The expression, ∆G = nRT. ln(P2/P1), gives the free energy change (A) With pressure changes at constant temperature (B) Under reversible isothermal volume change (C) During heating of an ideal gas (D) During cooling of an ideal gas

Description : The expression, ∆G = nRT. ln(P2/P1), gives the free energy change (A) With pressure changes at constant temperature (B) Under reversible isothermal volume change (C) During heating of an ideal gas (D) During cooling of an ideal gas

Last Answer : (A) With pressure changes at constant temperature

At equilibrium condition, the chemical potential of a material in different phases in contact with each other is equal. The chemical potential for a real gas (μ) is given by (where, μ = standard chemical potential at unit fugacity (f° = 1 atm.) and the gas behaves ideally.) (A) μ° + RT ln f (B) μ°+ R ln f (C) μ° + T ln f (D) μ° + R/T ln f

Description : At equilibrium condition, the chemical potential of a material in different phases in contact with each other is equal. The chemical potential for a real gas (μ) is given by (where, μ = standard chemical potential at unit fugacity (f° = 1 atm. ... (B) μ°+ R ln f (C) μ° + T ln f (D) μ° + R/T ln f

Last Answer : (A) μ° + RT ln f

The theoretical minimum work required to separate one mole of a liquid mixture at 1 atm, containing 50 mole % each of n- heptane and n octane into pure compounds each at 1 atm is (A) -2 RT ln 0.5 (B) -RT ln 0.5 (C) 0.5 RT (D) 2 RT

Description : The theoretical minimum work required to separate one mole of a liquid mixture at 1 atm, containing 50 mole % each of n- heptane and n octane into pure compounds each at 1 atm is (A) -2 RT ln 0.5 (B) -RT ln 0.5 (C) 0.5 RT (D) 2 RT

Last Answer : (B) -RT ln 0.5

The expression, nRT ln(P1/P2), is for the __________of an ideal gas. (A) Compressibility (B) Work done under adiabatic condition (C) Work done under isothermal condition (D) Co-efficient of thermal expansion

Description : The expression, nRT ln(P1/P2), is for the __________of an ideal gas. (A) Compressibility (B) Work done under adiabatic condition (C) Work done under isothermal condition (D) Co-efficient of thermal expansion

Last Answer : C) Work done under isothermal condition

Pick out the Clausius-Clapeyron equation from the following: (A) dP/dT = ∆H/T∆V (B) ln P = - (∆H/RT) + constant (C) ∆F = ∆H + T [∂(∆F)/∂T]P (D) None of these

Description : Pick out the Clausius-Clapeyron equation from the following: (A) dP/dT = ∆H/T∆V (B) ln P = - (∆H/RT) + constant (C) ∆F = ∆H + T [∂(∆F)/∂T]P (D) None of these

Last Answer : B) ln P = - (∆H/RT) + constant

To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to that of vapour phase (B) Vapour phase behaves as an ideal gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Description : To obtain integrated form of Clausius-Clapeyron equation, ln (P2/P1) = (∆HV/R) (1/T1- 1/T2) from the exact Clapeyron equation, it is assumed that the (A) Volume of the liquid phase is negligible compared to ... gas (C) Heat of vaporisation is independent of temperature (D) All (A), (B) & (C)

Last Answer : (D) All (A), (B) & (C)

The expression for entropy change given by, ΔS = nR ln (V2/V1) + nCvln (T2/T1) is valid for (A) Reversible isothermal volume change (B) Heating of a substance (C) Cooling of a substance (D) Simultaneous heating and expansion of an ideal gas

Description : The expression for entropy change given by, ΔS = nR ln (V2/V1) + nCvln (T2/T1) is valid for (A) Reversible isothermal volume change (B) Heating of a substance (C) Cooling of a substance (D) Simultaneous heating and expansion of an ideal gas

Last Answer : (D) Simultaneous heating and expansion of an ideal gas

Which of the following is Clausius-Clapeyron Equation for vaporisation of an ideal gas under the condition that the molar volume of liquid is negligible compared to that of the vapor? (A) d ln p/dt = Hvap/RT2 (B) d ln p/dt = RT2/Hvap (C) dp/dt = RT2/Hvap (D) dp/dt = Hvap/RT2

Description : Which of the following is Clausius-Clapeyron Equation for vaporisation of an ideal gas under the condition that the molar volume of liquid is negligible compared to that of the vapor? (A) d ln p/dt = Hvap/RT2 (B) d ln p/dt = RT2/Hvap (C) dp/dt = RT2/Hvap (D) dp/dt = Hvap/RT2

Last Answer : (A) d ln p/dt = Hvap/RT2

The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x1. x2, where A is a constant. The corresponding equation for ln y1, where y1is the activity co-efficient of component 1, is (A) A . x22 (B) Ax1 (C) Ax2 (D) Ax12

Description : The molar excess Gibbs free energy, gE, for a binary liquid mixture at T and P is given by, (gE/RT) = A . x1. x2, where A is a constant. The corresponding equation for ln y1, where y1is the activity co-efficient of component 1, is (A) A . x22 (B) Ax1 (C) Ax2 (D) Ax12

Last Answer : (A) A . x22

Consider an ideal solution of components A and B. The entropy of mixing per mole of an alloy containing 50% B is (A) R ln 2 (B) -R ln 2 (C) 3 R ln 2 (D) -3R ln 2

Description : Consider an ideal solution of components A and B. The entropy of mixing per mole of an alloy containing 50% B is (A) R ln 2 (B) -R ln 2 (C) 3 R ln 2 (D) -3R ln 2

Last Answer : (A) R ln 2

The thickness of oxide film is y at time t. If K1, K2 and K3 are the temperature dependent constants, the parabolic law of oxidation is given by (A) y2 = 2k1t + k2 (B) y = k1 ln (k2t + k3) (C) y = k1 t + k2 (D) y = k1t3 + k2

Description : The thickness of oxide film is y at time t. If K1, K2 and K3 are the temperature dependent constants, the parabolic law of oxidation is given by (A) y2 = 2k1t + k2 (B) y = k1 ln (k2t + k3) (C) y = k1 t + k2 (D) y = k1t3 + k2

Last Answer : Option A

Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Description : Helium ( R= 0.4698 BTU/lbm-˚R ) is compressed isothermally from 14.7 psia and 68 ˚F. The compression ratio is 1:4. Calculate the work done by the gas.  A. –1454 BTU/lbm  B. -364 BTU/lbm  C.-187BTU/lbm  D.46.7 BTU/lbm Formula: W = RT ln (V2/V1)

Last Answer : -364 BTU/lbm

What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Description : What is the equation for the work done by a constant temperature system?  A. W = mRTln(V2-V1)  B. W = mR( T2-T1 ) ln( V2/V1)  C. W = mRTln (V2/V1)  D. W = RT ln (V2/V1) Formula : W=∫ pdV lim1,2 ∫ = mRT / V

Last Answer : W = mRTln (V2/V1)

What horse power is required to isothermally compress 800 ft^3 of Air per minute from 14.7 psia to 120 psia?  A. 28 hp  B.108 hp  C.256 hp  D.13900 hp Formula: W= p1V1 ln (p1/p2) Power = dW / dt

Description : What horse power is required to isothermally compress 800 ft^3 of Air per minute from 14.7 psia to 120 psia?  A. 28 hp  B.108 hp  C.256 hp  D.13900 hp Formula: W= p1V1 ln (p1/p2) Power = dW / dt

Last Answer : 108 hp

ln single action disc harrow the two gangs are at set single a) less than 90 degree b) at 90 degree c) greater than 90 degree d) at 180 degree

Description : n single action disc harrow the two gangs are at set single a) less than 90 degree b) at 90 degree c) greater than 90 degree d) at 180 degree

Last Answer : c) greater than 90 degree

Minimum number of bits required to store any 3 digit decima ln umber is equal to (A) 3 (B) 5 (C) 8 (D) 10

Description : Minimum number of bits required to store any 3 digit decima ln umber is equal to (A) 3 (B) 5 (C) 8 (D) 10 

Last Answer : Answer: D

For every context free grammar (G) there exists an algorithm that passes any w ∈ L(G) in number of steps proportional to (A) ln|w| (B) |w| (C) |w|2 (D) |w|3

Description : For every context free grammar (G) there exists an algorithm that passes any w ∈ L(G) in number of steps proportional to (A) ln|w| (B) |w| (C) |w|2 (D) |w|3

Last Answer : (D) |w|3

Given an open address hash table with load factor a < 1, the expected number of probes in a successful search is (A) Atmost 1/α ln (1-α/α) (B) Atmost 1/α ln (1/1-α) (C) Atleast 1/α ln (1/1-α) (D) Atleast 1/α ln (α/1-α)

Description : Given an open address hash table with load factor a < 1, the expected number of probes in a successful search is (A) Atmost 1/α ln (1-α/α) (B) Atmost 1/α ln (1/1-α) (C) Atleast 1/α ln (1/1-α) (D) Atleast 1/α ln (α/1-α)

Last Answer : (B) Atmost 1/α ln (1/1-α)

ln a minimum oil circuit breaker the oil is used

Description : ln a minimum oil circuit breaker the oil is used

Last Answer : ln a minimum oil circuit breaker the oil is used to act as circuit breaking medium only

ln HRC fuse the time between cut-off and final current zero is called

Description : ln HRC fuse the time between cut-off and final current zero is called

Last Answer : ln HRC fuse the time between cut-off and final current zero is called the arcing time

The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is 15 N per kN, the maximum speed that the locomotive can attain on level track will be a.43 kmph b.83 kmph c.103 kmph d.107 dynes e.38 kmph

Description : The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is 15 N per kN, the maximum speed that the locomotive can attain on level track will be a.43 kmph b.83 kmph c.103 kmph d.107 dynes e.38 kmph

Last Answer : e. 38 kmph

The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is qN per kN, the maximum speed that the locomotive can attain on level track will be a.103 kmph b.83 kmph c.107 dynes d.43 kmph e.63 kmph

Description : The power of a locomotive is 315 kW and the total weight of the train is 2000 kN. If the track resistance is qN per kN, the maximum speed that the locomotive can attain on level track will be a.103 kmph b.83 kmph c.107 dynes d.43 kmph e.63 kmph

Last Answer : e. 63 kmph

PROBLEM EA Sample of moist soil has a water content of 20.0% and the moist unit weight of 21.09 KN/cu.meter. The specific gravity of the soil is 2.75. Compute the degree of saturation and the value of porosity?

Description : PROBLEM EA Sample of moist soil has a water content of 20.0% and the moist unit weight of 21.09 KN/cu.meter. The specific gravity of the soil is 2.75. Compute the degree of saturation and the value of porosity?

Last Answer : two seconds

What is the name of a small hill beginning with kn?

Description : What is the name of a small hill beginning with kn?

Last Answer : Knoll.

What is the name of a small hill beginning with kn?

Description : What is the name of a small hill beginning with kn?

Last Answer : Knoll.

The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Description : The ball bearing is subjected to a radial load of 4000 N. Expected life for 90% bearings is 9000 hr and the shaft is rot (a) 42.21 kN (b) 37.29 kN (c) 26.33 kN (d) 35.22 kN

Last Answer : (b) 37.29 kN

What is the value of shear stress acting on a plane of circular bar which is subjected to axial tensile load of 100 kN? (Diamet a. 58.73 Mpa b. 40.23 Mpa c. 39.60 Mpa d. Insufficient data

Description : What is the value of shear stress acting on a plane of circular bar which is subjected to axial tensile load of 100 kN? (Diamet a. 58.73 Mpa b. 40.23 Mpa c. 39.60 Mpa d. Insufficient data

Last Answer : c. 39.60 Mpa